10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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*   *     **   *    *  * ***   * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
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* * * *  ***   * * ***  *** while (n > 0);
 * * ** ** *   * **   * *    * *     * ***  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include  *  *  ***  **  *

int      ****  ** **** * 
int d=1000;

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  ** * *   ****    *   ***   *  ** *  * %d", numdigits, sum);
*   **** *****  *        *  *  ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
   * ** *** ** **  **  *  n,digits = 0,sum = 0;
****** *    * *   * ** * **** * **  *  ***   * ***  * 
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  * *  * *      * *  *  *   ** ***** **  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
**     *****  * ****** **     *** a,digits=0,sum=0;
**      ***     *** * **** * *  * **  *  *  **    
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  ** **  **  *   ** ******    *  %d",digits,sum);
*  * ** ***  ** *  **       **  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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{
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else f2=4;
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
    ** ****     ***    ****  ** n,digits = 0,sum = 0;
** * * *** ** ****  ** *  ** ** **  ** *  * ***** * * **   *
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*** ***   * **  ***    *  *  **** ****    * *******    * * 
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******    *        *  *  *****    while (n > 0);
*** *   *  ****** *  *  *   *    * * *  *  *  * * **
 * **     ***  * *  * *  *** *  **   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
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**** *  * *** *   ****  ** **  * *   %d",a,c+d+e+f);
*   **   ***** * *  *  *  *  *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
**    **      **  **  * *   *** * * num,digits,sum=0;
        * ****  *  *******     **  *  *  *   ****    * ** *  * ** ***
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*  * **   ***    **** ** * *   * *  ****   ***    *   **** ** ****   **  **** *
    }
  ******* ***    * *** * *** **  *  *  ** %d", digits,sum);

* * ** **** ** *** **  * **   **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output