10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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f2=2;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
* ******** ***  **  
int main()
{
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include *  *    *   * 

int * *  *  * *  * *** ***  
int d=1000;

int main(){
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** * * * ** ** *     *   * **** * *  *  **  * **   * = sum + currentdigit;
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* *  * *** ** **  * ****  *   *** *     **    *   * * *  * 

**  * **    * **  ** *   * ***** ** *  **  * *  **    *  *  *    %d\n", numdigits, sum);

 **    **  ** **   ** * *
 * *   *     **** **    *   ** ***     %d", numdigits, sum);
  ** * *    *****  *** **   * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 **  * ***   * **  *    * ****** n,digits = 0,sum = 0;
*** *  **   *  *  *  * **       **** *    * * ** * ***
* ** **** ** ** ** * ** ** * {
*   *** ** *  ***  ***   * * **   ** ***** *  * * *  * = sum + n%10;
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* * ****  * *  **** * ***** *  *     * **  * *  **  
**    * ** ****  *   ***** *   * ********   *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
* *   * ** * *     **    ***** a,digits=0,sum=0;
  **  * *  ***  * *     **** ** *    * *  *  * * *   *
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*******  *  * * **  **    ** (a>0);

**  ** **  *  ** ****  **  *  ****** %d",digits,sum);
 *  ****  *** * * ** ***   *** **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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int main ** **
{
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else f2=4;
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
* **** **    **   * * **  n,digits = 0,sum = 0;
 **  ** * ** *  *   *** **  ****** *  *  *        *** 
 ** * *  **   ** **** * ** * {
** *  ** * *  *** *  ***   **  *  ** ***  *  *   * = sum + n%10;
  * *** *****  * * * * **    * ***    * **    *  **  ******    
***  *  **       *  **  *  * ******  ******* * * *   **** **    
  *** *    *** * **   *** ** * while (n > 0);
 *** ** **  ***** **   *   * *   *   ** ***** * ** *  * **
* *** * ** *  *  ** **    *** **  *   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
* ** * *   * ****  **   * *** a=1,b,c,d,e,f,g;
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 *      ****    *  ** *       ** * %d %d %d\n",c,d,e,f);
 **  **      *   ** ** ***  *** **  ** **   %d",a,c+d+e+f);
*    *   * * ***** *  ***  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*  *   *** **   **    *** ***** *  num,digits,sum=0;
**   *** *   * * *    ** *  *  * ** * * * ***  *      * *  ** 
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 ***      ******  * *   * *** *  *** *
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**   *  *   * ***  **   *  **       **   * ** **      ******   ** * ***** * *         += num % 10;
      * ** ** *****   *  *   * * * *  * * ** **  *** *** * ** * * *   **   = num / 10;
* **********      *  **  *** *  ** * * ***  * ** *    **  *** *    * ***   * 
    }
*   * ** * ***   ** **  **  * **** ** *    %d", digits,sum);

* * ***** * * ** ** **** * *  **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output