10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
** **  * *  *  ****** ***
int main (void)
{
int  ****  *
*  * * **  **    *****   *  *  
* ** 
  * *  
 **  *
*  **
     
**   *
* ***
 **  
**  *****  ** ***  ** *  * ***
if * *** * **** * *** ********   *
 **
else ** ** ***** **   *
f2=2;
else if * **
**   
else f2=4;
    **  **** * ** ***  *  * 
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
   **   * ** * *    *    * a,b,c,d,e,f;
    * ** ** * *  *  * * * *  count=1;
  *  ***    *** *  ** **    ***  * *  **** ******* ***   
 *  **    ** ***** ****  * *  ** *  **
 * *  ***       *   **   *    *  ** * 
** ***  *    **** ***   *  *  **    *  * * **
  ** *** **     ***   **  *  * *  *   **    ** **
**** **  * * * * * **    * ***  
   *** ** *** **   **  *   *   **   * 
    {
     *   *** *  * * ** ** * ******    *** *  *  ***  ** *** *  
 * *    * * ** **  **** * ** ********* * * *  * * * *** * *
    }

 ***  ***** *  * ***** * * *** *   *  * *  * %d",count,f);
** *  * *  ***** *****  *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
** *** *  ****   *****
int main()
{
  * * * ****    *   *    * n,digits = 0,sum = 0;
     *  ** *   * ** *** * ***    * ** ** *  ******  * 
 * *  *   *  **  * *     * * * {
***** *     * *   * *    *** ****  *  ** * *   *  ** *** * = sum + n%10;
* *****  *    **  * **     *  * ****     *   ***  **        * 
**   ****** ***   *****    *  **  ** *  **  ** *  **   **** ***   *
 *** ***  * ******  ***** ***** * while (n > 0);
 ** *****  *  ** *   *    * *  ***    *** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include   ****  ** **  

int **  ****  ****   ** *  *
int d=1000;

int main(){
  ** * * ** **   ****    **  **   ****** *  * * ** ** 
    ** **  * **   * ***   *  ** ** ****

  ***  ** **    ** ** **  ****    **      **   *   ** *    **** *   = a/d;
   *** * *******    *  *  **    * **** ******* ** **  ** ** *  * **  *   *   *  **    *  *
  * *  * *** ***  *  ****  **    *  *     * * *  **   ** ***    = sum + currentdigit;
* *   * **** ** **** ** *  ***   * *  **  ***         = a - (currentdigit * d);
   *     *    * ** *******    **   * * * *  * * *** *     ** **

* *  * *     **** *  ****** *  *   *  * *      * *      * ** **  *  %d\n", numdigits, sum);

*   * ** * * ** **** *****
*   *  **    ***       * *    *   *** %d", numdigits, sum);
* *     * * ** ****  ***  * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
  * *  ****  ***   ***  * ***  n,digits = 0,sum = 0;
 *  * ****   ****  * **** ***  * ***** * *****    **  **** 
 ** *  **  **  ***  *     **    {
* ** **   *** *   ****  *  **    *  ** * * * * *** * * **  *** *  = sum + n%10;
* *  * **  *  *    *****   ***    *    ***** ** * *** **  ** 
* ***   * *   *** *   **** * * *  * *   ** ** * *** **  *
 ****** *** ***   **  * **  while (n > 0);
** ***  **  **** ** *** ** *   *    * * **  *** 
    *** *** ****   ** **** * *  ** *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
* * **** *    **  *     *   ** ****  a,digits=0,sum=0;
 * *** *  **    * **  ** ** * *   * **  ***   * *   * **  * 
***    ***    * *   ** *  **   {
 * ** ***** ***  *** **    ** ******  ** *** * ****  * ** ** *      
* *   *    ****** ** ***  ** ** * **  *   *  * **   *   * **  **
 * * * * ****** ***    * **** *  * ** *  * ** *** *  ** *     **
 **  *** * *   *** ****   
**** *    * **  * **    ** * (a>0);

**  ***   * *    ** **  ***   *      %d",digits,sum);
 *   * *  *     *** *  **   * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
   ** * **      
int main **  *
{
int  **  *** *
** *       *  * ***  **  *  **
   *   
  * * *
   * **
      **
 *** *
   ** **
 * 
* *   * 
   **********    * * *** * *** 
if ***      
*  * 
else   ** *
  **  
else if  *  
 *    
else f2=4;
**     ***               
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
   *****  *  **   **  *  **  ** n,digits = 0,sum = 0;
*** * *  **   ***  *** *  * ** **   *****   ****  * *  *** 
 *      **   ****  ** ***  ** *  {
*     *  **  * * ** ****  *   *   ***   ** * * *  **  * = sum + n%10;
*  * *****  *   *  ****   *** *  *   *   **   * *   ** **
* *  * **   *    **    * ***  ** ** * * ****   * * **  * **  
**   * *    ** * * * *  ***  while (n > 0);
 * **** *  *  * **  * *   ****      ** ** * *** **  
   *  ******  ** ** ** ** **     * *     d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
** * *** * ** *  *****  *****  a=1,b,c,d,e,f,g;
  * *** ************ ** * *** *  *   * *   *      **   *
*    * * *    * * ** **** **  
  *  * ** ***   **  * * **  * ** ** * * *
 * * *** **  **** *  **** *  * *
   ***** ** ***  **  **   *** 
***    ***  * *            *  **  
    }
 *   ** *** * *     ** *  *  *   **
  * *** **   **       *   *  *    
**  **          **  *   *   **    **
 *  * * *   ***     * * *  ** 
*  ****   ***    ** ***  * *** ** * **** %d %d %d\n",c,d,e,f);
* ** *  * * **   * ** *   **** * ** * *  %d",a,c+d+e+f);
 * **      **** ***  *    *        ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
  *  ** ******  *  **** *** * *   * num,digits,sum=0;
  ** *   ** *   ** ** ** *  ******** * * **** ** ***  ** * ** ** ***  
* * *  * *  *   *  ****  *   ****    **    ******* **   **  **  ** * ****  &num);
 *   *    *  **** *   **** *****  **    
***   *  *  ***   ** ** * ****
   ****** **  * **  * *** * **** *    *  *  ***** ***** ***** *  ***** *** *** += num % 10;
* *  **  ** *****   ** *  **    *  ** * * * **   * *  * * *  * *    *****   * *   * ** * = num / 10;
 * *      **** *     **   *  * *  *** * ** * *  **  *   ***    ***       *   * **
    }
***** * ** *    *  ** **  * *   ***    %d", digits,sum);

 *   *    * ** **    **** * **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output