10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
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{
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f2=2;
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else f2=4;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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    }

  * ****** **   ** ***  * *** *  *  **  ** %d",count,f);
*** ***  ****    * *  *    *       0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
*****  * * ** *  *
int main()
{
     * *****  ****  ** * n,digits = 0,sum = 0;
 *  *** *  *  ***  * ** *   *** *** *   ***  **** ** 
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* * *      ** **  ****   *** * while (n > 0);
  ***** *  **   * ** ***   *  *   * ** ** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include **  **   ** *  *

int  *   *  ** **  *  ***   * 
int d=1000;

int main(){
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***     * *        * *   *  ** * *****  * **  * *** = sum + currentdigit;
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*  ** ** **  ** ** ******     ****   *  * **   **   ****     **

** **        *******    **  * * ***    *  * ** ** *  ** ** * * **     *  %d\n", numdigits, sum);

    * ***** *  *** **** *   
* * ********* * ** * ****  *  **     %d", numdigits, sum);
    **** * * ****  ***    *****    * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 ** *       **   *** ***     n,digits = 0,sum = 0;
*  *   *    * * ****  *    *  ********  **  ***  ** * * 
**  * *  *      * *  *          {
 *  **** *** *** * * ***** ** *  ** ****  * ***  *   * = sum + n%10;
*   *** *   **  *   ** **  * ** **** ****     **
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   * ** **   *  ***** *     while (n > 0);
  * *  *  *     *   ***   ****** * ** ***  ** ***   ** *****
* *   *  *   * ** *  ** **** *** **   **** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
   ***  ** *******    ***   *  a,digits=0,sum=0;
 * **** *** **** **      ** ******* ***** * *
* *** **    *  ***   ** *  **** {
   *** * **  ***   * * *  **    *    * ** **** ** ***  **  * 
*  **** * **   ** *   * * **  * **  *** **   ***   ** * * **
  *     **  **** * * * ****   ***   *  ****  *** *  ** **
***  **** *  *   *   * ** ** *     
*    *  **** * *   * * *  (a>0);

**     ***  * *** *  *****     **  **  %d",digits,sum);
 *    *  ***   * *****  *  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
   *   **  * ***  *     
int main * *  *
{
int ****  * ** 
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else if   
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else f2=4;
      **     ** ** * *  
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
  **  **********   **** **   *  n,digits = 0,sum = 0;
*     **   ** ***  ***  ** * * ***  ** ** * *    * *  * **
 **** ** ****   ** **** *  {
*   * *    ** ** **  * * * * ******      **  = sum + n%10;
**  *     *  *****     ***   *** ***   * *  * ** ** *     * 
***    ***    ***    * * * *** * *  ***** *   *  *** **
 *** * ***    **   ** ***  while (n > 0);
   **     * * **   ** * *    * * ***  ***      *   *
  **  * *  ****   ****** ** * *   ** *    d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
    *  **  *  * *  * * * *  a=1,b,c,d,e,f,g;
 ***  * * ** *   ****** * ** *  *   **       * *  ** ** 
 **  *  *  ** *** *****    ***** *
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    }
   *  **     *       *    *
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 **      * **   ***  *  ** *** **  ** ** 
* **    *  ***    ***  ***        
 *      * ****  ** ***************      %d %d %d\n",c,d,e,f);
**  *** ***   *    * ******  **  * **    * %d",a,c+d+e+f);
 *    * ***    *  **  *  * *        0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*  * * *** *** ***    *** * *    ** * num,digits,sum=0;
 **  ****  *  *   ** *      **** * ******  *    ***** *****    **  *  * 
* **  *  **  *  * *** *    *  * * **   *   **  ***** ***      *   **  ***   * &num);
        **** **  *   * ********   *  **  ** 
* *** *    ** * *    *  
    *  ** ** *   * ***  ****  * * * * * * **    **   *   *** *  ****  ** * * += num % 10;
 ** ** ***  *   *  *    *  *   ***   *   ** ** * *      ****   * ** * * = num / 10;
  *  *   ** *** *  * * ** ***  **  **     *     *** *  ********    *  ** * *  * *     
    }
  ****  *  ** ***  *   *  * * *   *  **  %d", digits,sum);

*  *** ** ****     * * * ***     *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output