0 like 0 dislike
4.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 4.2k views

49 Answers

0 like 0 dislike
Hidden content!
// * ** * by HoMingJui on 2016/11/3.

//



#include *** * * **

#include ****** ***** *

#include *** * ** *

#include * * **** **





int main(){
**** * * * *** * * *** x[2],y[2],a,b,c;
** * ** * * * ** * ** * %f %f **** * ** * ** * ** ***** * * ****
* * * * * *** ****** *** * *
* * ** ** *** * * * ** ***** **
* * * *** * ** ** ** * ****
** * ** * ** *** ** ** ** ** %.6f ** *** * *
*** * * * * * * ** ****** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
* *** * ** *



int main()

{
* * * ** ** * * * * a1,a2,b1,b2,a,b,c;
*** ***** *** *** *** * * %f %f ***** ** *** *** * ****
* * * * **** * * *
*** ** * *** * *** *
* * *** * * ** * ** *
** ** ****** * ** ** * %.6f %.6f",a,b,c);


**** ***** ** **** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* * **** *** ** *



int main()

{
*** * ** ****** *** * a1,a2,b1,b2,a,b,c;
** ** * * * * * * *** * %f %f *** *** ** ** *** * * ** ** **** *
***** * *** *** ** * ** *
*** * *** * ** ****
***** *** ** *** * *
* ** *** ** ** *
******* * * * * **** * ** ** * %.6f %.6f",a,b,c);


* * * * * * ** ** *** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * ** *** * ** *



int main(void){


*** ** * ***** * ** ax , ay ,bx ,by ,a ,b * *


* ** ** * *** ****** *** **** * *
** *** *** * ****** *** ** * * ** **** ** *
* ** ** ** *** ** ****** *** *** *** ** * ** * * ** * * **
*** *** * * * ** ** ** * * * ** * * * ** ****** * * ****


**** * * * *** * - bx) != 0){
** *** * * ** = (ay - * * **
** * * *** ** * * = -m*ax + ay;
* ** ** * * *** = m;
* * * * * ** = 1;
* *
* *** *** ** **** ** *
** ** * ** * = 0;
******* ** ******* = 1;
* * ** * ** * = -ax;
* *


**** ** *** * * *** = a;
* * * * *** ** *** = b;
** **** **** * * ** ** = c;


** * * < 0)
****** * **** ** * = -i;
* * * * ** if (k < 0)
*** * ** * *** = -k;


** * * (i < 1){
* ** * * **** = 1/i;
**** ** **** = a*g;
* ** *** * ** = b*g;
* * ** ***** *** = c*g;
* **
* * * * if (k < 1){
* * * * * * * * ** = 1/k;
* * * ***** * ** = a*g;
* * * * ** * * = b*g;
***** * *** * * = c*g;

 }
* ** * *** *** * *** * * *
* * ** * ******
* * **** * ***



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ** * *****



int main(void){


** ** ** * * ******* * ax , ay ,bx ,by ,a ,b * * * **


* * * ** * ** ** * ** * * * * *
* ***** ******* ** ** * * ***** * * *** ***
*** * * * * **** * * ** * *** * * ** ** * *
** ** ** ** * **** ** * * * * * ***** **** * * ** * * *** ** **


* ** * * ** * **** - bx) != 0){
** * ** * ** ** = (ay - * * * *
** * * * * = -m*ax + ay;
** ** **** * * * = m;
** * * * * * = 1.000000;
* ** **
* * *** *******
*** * * *** * = 0.000000;
****** * *** * = 1.000000;
***** * * * ** = -ax;
** * *


**** * ** *** = a;
*** * **** * ** * * * = b;
* *** * * ** * * ** = c;


**** * < 0)
* * * * ***** ** ** * = -i;
*** * *** ** if (k < 0)
** * * ** * ** **** * = -k;


*** * (i < 1){
*** ** * ***** * = 1/i;
** * * * * ** * = a*g;
* * * * *** * = b*g;
* *** * *** * * = c*g;
* *
**** * if (k < 1){
* ** *** * ** **** = 1/k;
* ** ** * * **** = a*g;
**** ** ** ** = b*g;
** * * * ** *** * = c*g;
**** ****
* ** * *** ** ***
*** * ** * * ** * * **
** * * **** ** ** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* * ** * * * **
** * *** *
* * * *
** i ** **
a , b , c , * ** ** *** *
** ; i ***** ; *
** * * ** * *** * , ** * * * );




** * ***
* * ** *** ** = *
** * * ** ** * ****** = - **
*


***** * ** ****
*
* ******* ******
= * * **** ;
= * ;
*
* *** * ** ** * a , b *








* * 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
****** * *** * * *
*** ** * * ***

int main()

{
** * ***** * ** *** * * ** a,b,c,d,m,x,y;
* ** ** * ** ** * ** * ** %f %f *** ** * * * * * * * * * ***
*** *** *** **
*** ** * * *** ** * *

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include ** ** ** *



int main(void){


** ** *** **** ** *** * ax , ay ,bx ,by ,a ,b ,k,m,c;


** *** ** * ** ** * **** * ** ** * ** ** **
** * * * ** * ***** ** * ** **** * ** * **
* ** ******** **** * **** * ** * ** * * * * **** *
* *** * * * ** **** * ** * ** * ** *** * ** ** *** * * **** * *


********* ** ** * ** - bx) != 0){
* * * * *** ** = (ay - ** **
** * *** * * *** = -m*ax + ay;
*** * ** *** * * * = m;
** ** ** * * * = 1.000000;

 }
* * * ** ** * * *** ***
* ** * ** * ** * = 0.000000;
* * **** = 1.000000;
*** * * * *** * * = -ax;

 }


**** ** * * * ****
*** * ** * ** *
**** *** *** * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** ***** *



int main(void){


*** * * ** ax , ay ,bx ,by ,a ,b ,k,m,c;


**** ** * ** ** *** * * * * *
* * * **** * * *** * * * ** * *** ** ***
* * * * ***** * * * *** * * * * ** * * ***** * ** **
* * * * *** ** ** * * ** ***** * ** * *** ** ** * ***** *** * * * *** * * * *


** *** * ** ** *** - bx) != 0){
********** ** * * = (ay - ** **
* * ** * * * ** = m*ax + ay;
* * ** ** **** * * * = m;
* *** ** **** * *** = 1.000000;

 }
* *** *** * * * *
** **** ** ***** ** = 0.000000;
** * *** ** * * = 1.000000;
** ** *** * * ** = -ax;

 }


* * ** ** ** *
* * * * * ** *** **
*** ** ** * **** *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.188
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users