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直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 915 views

49 Answers

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// * ** ** by HoMingJui on 2016/11/3.

//



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}
answered by (-126 points)
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Hidden content!
* ** ***** ***



int main()

{
* **** **** * * a1,a2,b1,b2,a,b,c;
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** ** ** ** * * ** 0;

}
answered by (-124 points)
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Hidden content!
** **** * * *



int main()

{
*** * * ****** a1,a2,b1,b2,a,b,c;
** * * * * *** * ** *** %f %f *** * *** * * * * * ** ** ****
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*** * * * *** 0;

}
answered by (-124 points)
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Hidden content!
#include * *** ** *



int main(void){


* * ** * *** * * ax , ay ,bx ,by ,a ,b *


** * * * ** * ** ** ** * * ***
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* * * ** **** *** * = 1;
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* * * *** * = b;
* **** *** * = c;


* * ** < 0)
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* ***** * if (k < 0)
* * ****** * * * * = -k;


* * ** (i < 1){
* * * * * * * * = 1/i;
* * * * * = a*g;
* ** ** * * = b*g;
*** * * *** * * * = c*g;
****** *
* **** * if (k < 1){
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* * **** * * * ** = a*g;
* * ** * * ** * = b*g;
*** ******* *** ** * = c*g;

 }
** ** ***** *** ***
**** * * ***** **** ******
* ** * *** * ****



return 0;

}
answered by (-122 points)
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Hidden content!
#include * * *** * * * ***



int main(void){


** ** ** * ***** ax , ay ,bx ,by ,a ,b **** *


** ** * *** * * * * * *** * * * ** *
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*** ** **** * * ** * * * *** ** * ** * * *** *** ******** * ** * ** **** * *


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**** * ** ** * * = (ay - ** * *
* * ** * *** **** * = -m*ax + ay;
**** ** * *** = m;
** * ** * *** * = 1.000000;
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* ** * *** = 1.000000;
* *** * ** **** ** = -ax;
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*** * * * * **** = c;


* **** * * < 0)
* * *** *** ** * * = -i;
* * ** if (k < 0)
**** * * * **** = -k;


*** (i < 1){
* *** ** ****** ** = 1/i;
**** * * * = a*g;
* * * * ** *** * = b*g;
* * * * ***** = c*g;
* ***
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** * * *** ** = c*g;
******
* * ***** * ** * * *
*** * * ** * * *
* * ** * * * *



return 0;

}
answered by (-122 points)
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Hidden content!
** *** * ** * * * **
** * ** **** **
* *
** * i * *
*** a , b , c , ** * *** *
* *** ; i * ** * ; ***
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* **** * * **** * * a , b * **








** 0 ;






answered by (-87 points)
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Hidden content!
* ****** * * **
* *** *** *

int main()

{
** **** * * ***** * * a,b,c,d,m,x,y;
* * * **** ***** * **** * ******* %f %f * **** ** ** * * * ** *** **
** ** *** * *** ****
* ** **** ** ** *** ** * **

}
answered by (-103 points)
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Hidden content!
#include * * * * * * * *



int main(void){


* * * **** * ** * * ax , ay ,bx ,by ,a ,b ,k,m,c;


** * * ** * * ** * ** * * *** *
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* **** * * * * * ** - bx) != 0){
** * * * * = (ay - * * **
* * * ** * **** * * * = -m*ax + ay;
* * **** ** * * = m;
* ** ** * *** = 1.000000;

 }
** ** ***** * *
*** ** * * * = 0.000000;
** *** *** *** ** = 1.000000;
** **** * * ** = -ax;

 }


** * * * ** ***
*** * ** *
** * * ** * * ***



return 0;

}
answered by (-122 points)
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Hidden content!
#include ******** ********



int main(void){


** * * *** *** * ax , ay ,bx ,by ,a ,b ,k,m,c;


****** ** ** * * * * * ** **** **** **
* ** * *** * *** *** ** *** ** * *** *** * *
* * *** * ** ** *** * * * * * *** * * * *** *
* ** *** ** ** * * **** ***** ** * ** **** * * **** * * *** *** ***** ****


* * ** *** ****** * - bx) != 0){
** * ** * *** * ***** = (ay - ***
*** ** **** * * * * ** = m*ax + ay;
* ** * * * * * * * ** = m;
**** *** * *** * = 1.000000;

 }
* ** ****** * ** ***** *
* * ** ** ** * * * = 0.000000;
************ * = 1.000000;
* * * ****** ** ** * * = -ax;

 }


* * *** * * *
* **** ** * ** **
* * * * * ** * ** ** * ***



return 0;

}
answered by (-122 points)
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