0 like 0 dislike
919 views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 919 views

49 Answers

0 like 0 dislike
Hidden content!
// *** **** by HoMingJui on 2016/11/3.

//



#include * *

#include ***** * * *

#include * ** * * * *

#include * ** ***





int main(){
* * *** ** * * **** ** **** x[2],y[2],a,b,c;
* ** * * ** *** * * ** ** * ** %f %f ** * * ** * **** * ** * * ** * ***
** * * ** * * * * ** * * *** * * *
* * **** ** * * ** * * ***** * * * * **
* * *** * * * **** ** * **** *** * *
* **** ***** ***** * ** ** **** %.6f * * **
**** ** ******* ***** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
*** * ** * * *



int main()

{
*** ** * * ******** * ** a1,a2,b1,b2,a,b,c;
** * * * * * * %f %f * ** *** * * * ***** * * * * ***
* *** * * * ** **
* ** * ** * * *
*** *********** **** * * * *
*** * ** **** ** **** %.6f %.6f",a,b,c);


** **** **** ***** *** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
*** * * * * ***



int main()

{
*** *** * * * ******* a1,a2,b1,b2,a,b,c;
* * * ********* * **** ** %f %f * * ** *** ** ** **** ** * * * * * * *
* * * * * * * * **
** * * ** ** * * **** *
* * * *** * **
** ** ** * * ****
* ****** *** ** * * **** * %.6f %.6f",a,b,c);


* * ** ** * * * * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include ** *** * * **



int main(void){


* * ** * * * ax , ay ,bx ,by ,a ,b ** * ***


**** * ** * * * * ** * ** ** ** * **
* **** * * * *** ** * ** *** * ***
* * **** * * ********* ** ** * * * * * * * **** * * * **
* ****** ** ** * * * *** *** ******* ** * * ** *** ** ** * * * *


* * * * ** *** ***** ** - bx) != 0){
* * * ** ** * * = (ay - ** * *
***** * * * * * * * = -m*ax + ay;
* * *** *** = m;
***** * ** * ** = 1;
* ****
* * * ** ** *
* ** * = 0;
* ***** ** *** = 1;
****** ** * * ** = -ax;
** * *


** * * *** ** * = a;
* ****** ** ** * = b;
****** * **** ** * = c;


* **** < 0)
** * * **** ** ** * = -i;
* ** ** if (k < 0)
** *** *** ****** *** * * = -k;


* * ** (i < 1){
* ** * * * * = 1/i;
** ***** ***** * = a*g;
* ***** **** *** = b*g;
** * ** * * = c*g;
*
** * if (k < 1){
* * **** *** * = 1/k;
**** * * ** * ** = a*g;
**** ** **** * ** = b*g;
*** * * *** ** = c*g;

 }
** * ** * * *
* * * * * *
** * ** * * * **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** * * *



int main(void){


* * * ** * ***** ax , ay ,bx ,by ,a ,b * * **


** ****** ** ** * * ** * * * ** **
** * * * * * * ***** ** ** ** * ** *** ** * * * ** * **
*** * *** *** * * * ** * * * * * * * * ** *** ***** *** * *
* ******** ** ***** ** * * *** * ** * * *** *** * * *** * * **** *


* * ******* * ** * * - bx) != 0){
*** * * * = (ay - * *
*** * ***** ** *** * = -m*ax + ay;
* * ** * *** = m;
** ******** * = 1.000000;
***
** *** ** ** *
* * **** * **** = 0.000000;
* ** ***** ** * *** * = 1.000000;
* * * ** **** * = -ax;
** * * *


* ****** ** ** * * = a;
* * * ** * * * = b;
*** * = c;


** * *** < 0)
* * ** * * * * **** = -i;
* * ** if (k < 0)
*** ** * * * ** ** ** ** = -k;


* * *** (i < 1){
******* * *** ** = 1/i;
** * * = a*g;
* * * ** * ** * = b*g;
* * * * * * ** * = c*g;
******
* * ** if (k < 1){
** *** *** = 1/k;
** * * = a*g;
* * * * *** * = b*g;
* * * ***** ** = c*g;
* ***
* ** * ******* * ****
* ** * ** ** * **** *
******** * ** * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
** ***** * ** * *
* ** ** ** *****
* ** * *
i * ** ** *
* a , b , c , * * * * *****
** ; i ** **** ; **
* * ** ** * * , ***** * );




** * *
* ** * * * = *
* * ** **** * * ** = -
*


* *** * ** * * * ** *
*
* ** *
* = ** * ;
* = * ;
*
** * ** *** * ********** a , b ** *








** * 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
** ** *** *** *******
*** *** ****

int main()

{
* ** *** ** * * a,b,c,d,m,x,y;
* * ***** * ** ** ** * ** ** %f %f **** ** * * * *** * ** * * **
* * *** * * *** ** * **
* ****** * *** *** * ** ** *

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include ** * * *



int main(void){


***** * *** ax , ay ,bx ,by ,a ,b ,k,m,c;


* * ** * ** ** * ** *** * * ** * * *** * *
* * * ** **** ****** * * * ***** *** ** * ** * *
** * ** *** * * * * *** ***** * **** ******* * * * * * ** * ***
* * * * ** * * * * * * ** * **** * * * **** * ** * ** * ****


* * ** * ** ** * ** - bx) != 0){
** ** ** ** * * = (ay - *** * *
* *** * * * **** = -m*ax + ay;
*** * ** * ** *** = m;
** ***** * ** * = 1.000000;

 }
** * * ** ****
** * * * ** **** = 0.000000;
** * * * ***** * *** * = 1.000000;
*** ******* = -ax;

 }


** **** * ***** **
* * * ** ****
** ** **** * ** ****



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * ** ***



int main(void){


* * * * * **** *** ax , ay ,bx ,by ,a ,b ,k,m,c;


*** * ***** **** * *** ** *** *
* ***** * * * ** **** ** * *** * *** * ** * **
** * ** * *** * *** *** *** ** *** * * *** ** *
***** * * ** ** * * * ** * * ** * ** ** *** ** * * * ** *** ** *


* * * ** ******* - bx) != 0){
* *** * * * *** = (ay - *
** ** * * ********* * = m*ax + ay;
* * *** *** * = m;
* ** ***** **** = 1.000000;

 }
** * * ** ** ** * *
*** * *** * **** = 0.000000;
* ***** * * ** * = 1.000000;
* * * * ******* = -ax;

 }


* *** * * *
***** ***** * * ***
* * **** **********



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.81
©2016-2024

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 465 views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 488 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users