0 like 0 dislike
2.7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 2.7k views

49 Answers

0 like 0 dislike
Hidden content!
// * * ***** * by HoMingJui on 2016/11/3.

//



#include ** ** * * *

#include * ** ** ***

#include *** * * **

#include ***** * * * **





int main(){
** * * *** **** * ** ***** * x[2],y[2],a,b,c;
*** * ***** * * ** * * * * %f %f * ** *** * * * * * * **
**** * *** *** *** ****** * **
* **** ** * ** * * * *** ** ** ** ** **
**** * **** * ** ** ** * ** **
* * ** ** ** * * ** * *** * %.6f **** ** ****
** *** ** * ** * *** *** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
** * ** ***



int main()

{
***** * ** ******* * a1,a2,b1,b2,a,b,c;
**** ** * * * ** * ** ** *** %f %f ***** * ** * ** * * *** **
** * *** *** **** **
*** * *** *** * * * *
* *** ** ********* * * * **
** * **** * **** ** * * * %.6f %.6f",a,b,c);


** * ** ** *** **** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
*** *** ** ***



int main()

{
* *** * ****** *** * a1,a2,b1,b2,a,b,c;
** ***** * ** * **** * * %f %f ** * ** * *** * * ***** * *
* ** ** ***** * *
** **** ** *** ** *
* * * * * ***** * *
**** ** * ** **
* ** ** * ** * * * %.6f %.6f",a,b,c);


* ** * ** * * * * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * * * ***



int main(void){


* * ** * * * * ax , ay ,bx ,by ,a ,b * **


* * * **** *** * * * ** *
* ** *** **** * *** * * ********* * ** * * ** * ** *
*** * ** *** * * ** *** ** * * * ** * * * ** * * ** **
* * * * ********* * ** * * * * ** ** **** **** ** **** ** **


*** * **** ** * - bx) != 0){
* *** ****** * = (ay - * * *
**** * ** * = -m*ax + ay;
***** * * * *** ** = m;
* *** ** *** **** = 1;
*****
** ** ***** ** **
* * * * * * * = 0;
* * ** * ** * = 1;
* *** * * *** = -ax;
*


* * * * * * = a;
** *** ** * *** * = b;
** * ** **** ** * * = c;


* ** * * < 0)
** * * * * ** ** * * = -i;
*** * if (k < 0)
* *** * *** *** *** * = -k;


* *** * ** (i < 1){
***** ***** * * * * = 1/i;
* ***** *** * ** = a*g;
* * * * * ** * = b*g;
** ** * *** *** * = c*g;
** *
* ** * * * if (k < 1){
* * ** *** * ** = 1/k;
** ** * * *** = a*g;
* * *** * * ** * * = b*g;
*** ***** ** **** * = c*g;

 }
*** * ** ** * * ***
* * * * * * * * * *
** * *** ****** ** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * ** *



int main(void){


*** * *** * ** * * ** ax , ay ,bx ,by ,a ,b **


** **** ** * *** * *** ** * * *
* ** ** ****** ** ** ** * * ** ** ** ** * * * **
* * ** ** * *** * * *** * ***** **** ** ***** * * *** ** ** *
** ** * * **** * ** ***** * * * *** * ** * * *


* * * * ** ** ** * - bx) != 0){
** **** ** ***** * = (ay - ** * *
* * *** * * * ** = -m*ax + ay;
***** * * ****** * = m;
* ** *** **** * ** = 1.000000;
** ****
* ** ** * * ****** **
**** * * ** ****** = 0.000000;
* *** * * ** * = 1.000000;
** * * * * ** *** * ** = -ax;
* **** *


* * * ****** = a;
* *** * ** ** * *** = b;
* * **** * * *** * = c;


** *** < 0)
***** * * ** ********** = -i;
** * if (k < 0)
** **** ** ** * ** *** = -k;


** * (i < 1){
** * ******* ***** = 1/i;
* * * * *** * * = a*g;
** *** * ** **** *** = b*g;
* ***** * * * = c*g;
* * *
* * *** ** if (k < 1){
* **** * ***** **** = 1/k;
* * * * * = a*g;
*** * ** **** * * = b*g;
***** ** ** * * ** = c*g;
** *
* * * * *
** ** * * *** **
* *** ** * ** *** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
** * *** ***** **
* *** * * ** *
** *
** i * *
*** * a , b , c , * **** * * **
; i * * ; **
** *** ** * ** , **** );




** * *
* *** * * *** =
**** * * *** ********* = - **



* ***** ** **** **
*
* * * ****
= ** * ;
= ;

** *** ** * * ** * ** ** ** a , b * *








0 ;






*
answered by (-87 points)
0 like 0 dislike
Hidden content!
****** *** *** **
***** *** * *** ***

int main()

{
** ** * * * *** *** a,b,c,d,m,x,y;
* * ** * ** ** ** * ** ** * %f %f *** *** ** * * ***** **** *
* * * ** * * ***** *
* * *** * * ** ***** * **** * **

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include * *** ** ** * ** **



int main(void){


** ** ** ** * **** ax , ay ,bx ,by ,a ,b ,k,m,c;


** * ** * * *** * * ** * * ** * **
* * * * * ****** ** * ** ** *** ** * *** * * * *** **
* ** *** ** * * * * ** ** ** * * * * *
* ** **** **** * * ****** * * * **** * **** *** ***** ** * *** * *


* * *** ** * ** *** * * - bx) != 0){
* ** ** * ** = (ay - * ***
*** * **** *** ** * = -m*ax + ay;
**** * * **** = m;
** ** * **** = 1.000000;

 }
* * * ** ***** ** *** *
* * * * ** * * = 0.000000;
* * * ** * *** = 1.000000;
** ** * ** ** *** = -ax;

 }


*** * * ** * *
* ***** * ***** *** *** *
* ** ***** **** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ***** *****



int main(void){


* * *** * ** ** * * ax , ay ,bx ,by ,a ,b ,k,m,c;


**** ***** * **** ********** * * * * * *
** *** * * *** **** ** ******** * * ** * ****
***** * ***** * *** * * **** * ** * ** *** * * ** ** * **** *
*** * * * * ** ******* *** * ** * * ****** ** ***** * * ** * **


* * * * * ** * ** - bx) != 0){
* * *** * * = (ay - *
** * * * * = m*ax + ay;
** ** * ** ***** = m;
*** * *** *** ** = 1.000000;

 }
* * * * * ** **
****** ******* ** ** * = 0.000000;
* * ** * * * ** * = 1.000000;
* *** ** ** ** *** = -ax;

 }


** * * ** * * *
** *** * * ** ** * * *
* * * ** * ** *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.29
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.4k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users