0 like 0 dislike
3.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.2k views

49 Answers

0 like 0 dislike
Hidden content!
// ** ** * ** by HoMingJui on 2016/11/3.

//



#include ****** * * **

#include * * * *** *

#include * * * ** *

#include *** * ** ** *





int main(){
*** ** * ** * * * ***** ** x[2],y[2],a,b,c;
* **** * **** ** * * * * ** %f %f * * * * * * *** * *** ***** * *
* *** * ***** ** * ****** ** * ** *
**** * *** * * * * * ** **** ******
*** *** * * *** ** * * ** *
*** * * * ** **** *** ** * * * ** * %.6f * ** ** ***
** * * ** *** * *** * * ** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
** ** * * ***



int main()

{
* *** * * *** * a1,a2,b1,b2,a,b,c;
* ** *** *** * * * **** %f %f * * ** **** ** * * *** *** *
* * **** ** **
* *** * **** * * * * **
** ***** * **** * ***** *
*** * **** * * * ** * ** * ** *** %.6f %.6f",a,b,c);


*** *** ** * ** ** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* ** * * **** *



int main()

{
*** ** * * * * * * a1,a2,b1,b2,a,b,c;
* * ** **** * * * * ** ** %f %f * ***** ** *** ** * * * * **** * *
*** * * * ** ** *
* * ** * * * ** *
** *** *** *** * * * ** * *
*** * * * *
** *** * ** **** ** * * * *** %.6f %.6f",a,b,c);


* ** * **** ***** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * ** ** * ***



int main(void){


* *** * * * * * ax , ay ,bx ,by ,a ,b * * *


* ** *** ** * * ******** **** * * ***
** ** * * * * * * ** * ** ** ** **** *** * **** ***
******** ** ***** **** ** * * * ** * ** * * ******** * * **** * **
* *** * ** ** * *** ** * * * ****** ***** * ** * *** * *** * * *** ** * **


* ***** ** * ** ******* ** - bx) != 0){
*** * * * * * *** * = (ay - **** *
* *** * * * = -m*ax + ay;
** * *** ** = m;
* * * ** *** * * * = 1;
* ** *
** * * ** **** * * * *
* * * ******* ** = 0;
* ** ** *** **** *** = 1;
* * ****** * = -ax;
* *******


* ** * * *** = a;
* ** ** * * * * ** = b;
**** *** * * * * * = c;


*** * * < 0)
****** **** * ** = -i;
** * * * * if (k < 0)
* ***** * * * * * = -k;


** * ** (i < 1){
* *** **** * = 1/i;
** * * * ** * * * = a*g;
* * * * * * = b*g;
** ** * * ** = c*g;
*
* * if (k < 1){
** ** * * ** * * *** = 1/k;
* * ** *** * * * = a*g;
* *** ***** ** = b*g;
*** ** = c*g;

 }
* * ** *
* * * ***** * * ****** *
* ** * * ****** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** *** *



int main(void){


* * * * *** * * **** ax , ay ,bx ,by ,a ,b * * *


** * * *** * ** * ** * * *** *
******* * ** ** ** * ** ** **** * * * ** * ** *
* * * * **** ****** * * **** * ** * ** * * **** ** * ***
* *** ** ****** ***** * **** *** * **** ** * * * * *** ** *


* ****** ** * ** ******* * - bx) != 0){
* * * * ** ** = (ay - * ** **
* ***** ** ** *** = -m*ax + ay;
** ** * * ***** = m;
* *** *** ** *** = 1.000000;
* **
**** **** * * * *
* * *** * * = 0.000000;
* ** ***** * * *** * = 1.000000;
* * * * * * = -ax;
** **


** * *** ** = a;
* ****** ** * ** ** = b;
*** ** ****** ******* * = c;


** *** < 0)
*** *** *** *** * = -i;
** **** * if (k < 0)
* * *** ** *** *** ** * = -k;


* ** ** (i < 1){
* * ** * *** ** * ** = 1/i;
* ** * * ****** ** = a*g;
* * * * * ** * = b*g;
* * * * ** * * ** = c*g;
*
** * ** * if (k < 1){
** * ** ** ** ** = 1/k;
*** * *** * * = a*g;
** *** * ** * * = b*g;
** ** ** ** * * **** = c*g;
* * **
***** *** ** * * * ***
**** * ** ** **
* * * **** ** ****



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
** * * * ***
*** *** * **
** ***
* i * *
** a , b , c , * * * * * **
* *** ; i * * ; *
***** * ***** ** , * *** );




* **
* * *** * = **
** ** ** * * ** * * * = - **



** * *********** **** * **
*
* * * *** ** ** *
* = * ;
* = * ;
*
* * *** * ** ****** * a , b *








* 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
* * *** ** **
** * * ** * * * * *

int main()

{
***** *** ****** * a,b,c,d,m,x,y;
* * ****** *** **** ** * ** * * %f %f * * ** *** * ******* ** ** **** * *
* * ***** * * ** ****
** ** ** * * ** ** * * ***

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include ** *** *** *



int main(void){


* * * * * * * ax , ay ,bx ,by ,a ,b ,k,m,c;


* ** *** * * * * ** *** ** ** *
**** * * ** * ** *** ******* * * * ** * ** * ***
* ** ** * ** * * *** * ** * ** ** * ** ****** * *****
*** ** * * * * * * * *** * *** * ** *** * * ** *** ** ** *


******* *** * ** * - bx) != 0){
** * * ** ** = (ay - *****
* ** ** ****** * * = -m*ax + ay;
* ** ** * ** = m;
** ** *** ****** = 1.000000;

 }
* *** * ** ** **
* * ** *** ** = 0.000000;
* * ** * * * * = 1.000000;
* * * * * * * = -ax;

 }


* ** * ** * * * ** *
* **** * ** * * *
** * * * * * * * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** ** *



int main(void){


*** * **** ** ax , ay ,bx ,by ,a ,b ,k,m,c;


** ** * * * ** ** *** ***** ** *
** * ***** * * **** ****** * *** **** ***
***** ** * ** ** * **** **** ** ** * * *** * *** *
****** * * ** **** * * *** *** * * * **** ** ** ** * *** * * ** ** * * **


* * * *** * * * * - bx) != 0){
* ** * * ** ** = (ay - *** * *
** * * ** ** = m*ax + ay;
** * *** * = m;
* * ** * = 1.000000;

 }
* ** * * **** **
* *** ** * ** = 0.000000;
* * **** * * * = 1.000000;
**** * ******* = -ax;

 }


* ***** * ** * ** *
* ***** * ** **
**** * ** ** ** *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.220
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.8k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.5k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users