0 like 0 dislike
6.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.2k views

49 Answers

0 like 0 dislike
Hidden content!
// * * * *** by HoMingJui on 2016/11/3.

//



#include ** *** * * ***

#include ** * * ** *** *

#include * *** *

#include * *** * ** **





int main(){
* * * * **** ************** * x[2],y[2],a,b,c;
** * * * **** * **** * ** *** *** %f %f ** *** * * ** * * ** *** * * **
***** ** **** ***** * **** * *** *** ****
** * * **** **** ** ******* ** * ** **
****** ** * * **** * * * ** * * **
***** *** ** * * * **** * ***** ** %.6f ** ** * * *
** ******** *** *** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
* ** * ** ** * * *



int main()

{
* * ** * * **** * a1,a2,b1,b2,a,b,c;
* * * * * * ** ** * **** %f %f ** **** ** * ****** * * ** ** ***
*** ** * * *** * *
** * * * * * * **
** * ** ** * * ** **
* *** *** * *** * ** %.6f %.6f",a,b,c);


* * ** ** **** * * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* * * * *** **



int main()

{
* * * **** * * a1,a2,b1,b2,a,b,c;
* * * * ** **** ****** * ******** %f %f *** * **** ** * *** *
* ** *** **** *****
**** * ** ** * * * *
* * **** *** *** ***** ****
*** *** * *** * *
** ** * *** * *** * ** %.6f %.6f",a,b,c);


**** **** * ** * ** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * * *****



int main(void){


*** * * * * * ** **** ax , ay ,bx ,by ,a ,b ** * **


* ** * * * * ****** **** ** * *** **
** * **** * * * * *** * * * * ***
****** ***** * ** *** * * * ** *** * * ** **** ** * * ** * * ** * **
*** ****** * ** * ** * * * * *** *** *** ** ******* ** * *** **


* * ** * * *** **** * - bx) != 0){
* * * ** * * ** * = (ay - ** * * *
* ***** * ** ** = -m*ax + ay;
** * * * ** = m;
* * * * ***** *** = 1;
* ***
*** * **
* ** *** * * ** *** ** ** = 0;
* * * * **** *** * * = 1;
** ** * * * * = -ax;
* ** **


*** ****** *** **** ** = a;
* * *** * ** ** = b;
** * * *** ** ** * = c;


**** ** < 0)
* * * * * * ** * **** = -i;
** * if (k < 0)
* * *** *** *** **** * = -k;


* * * (i < 1){
*** *** ** ** = 1/i;
* * *** ******* ** = a*g;
*** **** ** *** *** * = b*g;
** * * *** ******* = c*g;
* **
* * ** if (k < 1){
****** * ** ** * = 1/k;
* *** ** ***** = a*g;
* * ** ******** ** = b*g;
** ***** * ***** = c*g;

 }
*** * **** ****
* * ** **** *
* ******* ** * ****



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ** *** *** **



int main(void){


* ** * * ***** ax , ay ,bx ,by ,a ,b ** ** *


** * * *** **** **** * * **** * * * * ** * * * *
*** * *** * * ** *** ** * * * ** * * * ** *
* ** * *** * ** ** * ** **** * * * * * *** * * * * ** * *
** * * * *** * * ** * * * * * * ** *** * * ******* ** * * * *


******* * ** *** * - bx) != 0){
**** * * ** * * = (ay - ** * *
* *** ** = -m*ax + ay;
* *** * * * * ** = m;
* ***** * * * ** * * = 1.000000;
***
***** * *** * * *** *
* * * * * * = 0.000000;
*** * ** * ** *** = 1.000000;
** ** * *** * * * ** = -ax;
* * *


* **** ******** = a;
* * *** * ***** **** * * = b;
* * * * *** ** = c;


* * * * < 0)
***** *** **** * ** * * * = -i;
* * * ** if (k < 0)
* ***** * ** * = -k;


**** ** (i < 1){
**** ****** ** * * = 1/i;
** * ** * * * * = a*g;
**** ******* * * * * = b*g;
* * * *** * = c*g;
* *
** ** * if (k < 1){
* * * * * * = 1/k;
* ****** * * ** * * ** * = a*g;
* * **** ** ** ***** = b*g;
******* * ** ** * ** = c*g;
**** *
** * *** * *** * ****
** ** * * ** * * *
* * * *** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* * ** ***** *
* * *** * * * *
** ***
* i **
** a , b , c , * * ***
* ; i * * ; *
* * ** ******* * * , * * * );




*** * **
* *** *** ** = **
** * * * * = - ** *



****** *** * * * * **
*
* * * *
* = * * * * ;
= * ;
*
* * * * * *** ** ** a , b ** **








0 ;






*
answered by (-87 points)
0 like 0 dislike
Hidden content!
** ****** * ** * *****
***** ** **** ** **

int main()

{
* *** * ** ** ** a,b,c,d,m,x,y;
*** ****** * **** ***** * **** %f %f ***** ** ** **** * *** **** ****** *
** * ** ** ** ** ***
** * * * * *** * ** **

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include ** * *



int main(void){


*** *** * * * * ** ax , ay ,bx ,by ,a ,b ,k,m,c;


** * * *** * ** *** *** **** * * *
* *** **** * * * * * ** * * *** * * ** * * *
* * * * * * ** * **** * * * * ** **** * * * ** * * * ***
* ** ****** * *** ** * * ** ** * **** **** * * ** *** ****** ** * *


**** **** ********* ** - bx) != 0){
* **** * * * * * = (ay - *** *** **
** * * *** ** = -m*ax + ay;
* * ** ** ** = m;
** * ****** *** = 1.000000;

 }
** * ** * * ** * *
** * ******* ** ** = 0.000000;
************ * * ***** = 1.000000;
*** ** * * ** * * * ** = -ax;

 }


* * * ** * * ***
* ****** * * ******
* ** **** * * * ** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * * *



int main(void){


*** *** **** * ax , ay ,bx ,by ,a ,b ,k,m,c;


** * * * ** ** * * * ** * ** ********
* *** * *** * *** ****** * * ** * * *** *
* ** * * *** **** **** * * ** **** ** * * ** ** * *** * * ** **
* * *** *** **** * * ** * * ** * * ** * *** *** * ***** *** ** ** * * ****


* * * * *** - bx) != 0){
* *** ** ** ** = (ay - ** **
* **** * ** **** = m*ax + ay;
* * ** * ******* = m;
** *** *** * = 1.000000;

 }
* **** * **** ** *
** *** * ** * = 0.000000;
* *** * * = 1.000000;
****** ** *** = -ax;

 }


* * ***** ***
**** ** * * * *****
* ** * * * * * *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.58
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users