0 like 0 dislike
6.3k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.3k views

49 Answers

0 like 0 dislike
Hidden content!
// * ** *** by HoMingJui on 2016/11/3.

//



#include *** * *** ***** *

#include ** * ** **** **

#include * * * * ***

#include *** * *





int main(){
* * * *** ** ** * x[2],y[2],a,b,c;
* *** * *** ** *** ** *** * * %f %f *** ** * * * * *** ** * * * *
* ** ** ** * ** * *** ** ** * * **
* ** * ** ** *** * * *** * * * * *** **** *
* ** * ** * * ****** **** **
* * * ** * ** * *** *** *** %.6f ** ** *** * * *
*** * **** *** **** * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
* * * * * * * *



int main()

{
***** * * * * * * a1,a2,b1,b2,a,b,c;
** ***** *** *** * * ***** %f %f * * *** ** * * * ********* ****
**** * ****************
** * *** * **
* * * **** ******** ***** * *
* **** * * * ** * ***** **** %.6f %.6f",a,b,c);


* * ** *** ***** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* * **** * **



int main()

{
***** * * * **** *** ** a1,a2,b1,b2,a,b,c;
**** * * * * * *** * * ** %f %f ********* *** ** *** * ** *** **
* * **** *** ** * *** *
** * * * ** * * ** ***
** * ** * * ** ****** *
* * *** * ** *
**** ** * * * * * %.6f %.6f",a,b,c);


* ** ** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include ** *** * ****



int main(void){


** * * *** *** * ax , ay ,bx ,by ,a ,b * * *


* * ** ** * * * **** *** ** *** **
** * * * ******* * ** * **** * ** * ***** * * **
* ** ** * **** * ****** * ****** ** *** * * ** * ** ** *
* * * ** * *** * ** *** * * * ** *** * * *** *** * * * * * **** ** **** * * * ***


* * * * * * * *** - bx) != 0){
*** * *** * **** = (ay - ** ***
******* ****** *** * = -m*ax + ay;
** * * *** = m;
**** ********** = 1;
*** ***
* *** ** * ** * *
* * ** ** *** = 0;
* ** * * **** = 1;
* * * ** ** * * * = -ax;
** **


*** * *** ** * ** = a;
* ** * * * * = b;
* ** * *** * *** = c;


* ** < 0)
** ******* * ** = -i;
*** * * if (k < 0)
*** * ** * * * * = -k;


*** * (i < 1){
** * ** * ** * = 1/i;
****** * *** * = a*g;
* *** ** * ** *** * = b*g;
*** * ***** * * * * = c*g;
* *
**** ** if (k < 1){
** *** ***** * ** * = 1/k;
** * * * *** ** ** = a*g;
*** ** ** * ** = b*g;
*** **** * = c*g;

 }
** **** ** *** ** * *
* *** ** ** * ** *
** * * *** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include **** ** **



int main(void){


*** ** ** ** **** ** **** ax , ay ,bx ,by ,a ,b ** * **


* * ****** *** * * * * *** ** * **
* * * ** ** * ****** * *** * * **** * *** ** * *
******* * * **** * ******** * * *** * **** * ***** * * *
** * **** *** ********* * * *** ** ** * **** ** ** * ***** *** *** ** **


** * ** *** * **** * - bx) != 0){
** ****** ******** * * = (ay - ***
****** ** * * ** = -m*ax + ay;
***** * * * = m;
** * * * ** *** = 1.000000;
****** *
*** ** * * * *
* ** * * * = 0.000000;
** **** * ** ** = 1.000000;
*** * * * * * * = -ax;
* *


* * * ** * ** ** * = a;
* * * ** ** ** = b;
* ** **** ** * ** = c;


** * * < 0)
* *** ** * **** **** * * = -i;
** ** * * if (k < 0)
* * *** *** * ** *** * ** = -k;


(i < 1){
** ***** ********* = 1/i;
* **** * ** *** *** = a*g;
****** *** * *** = b*g;
* *** ** * * * * = c*g;
* *
* * *** if (k < 1){
* *** * * * * * = 1/k;
* * * * * * * * = a*g;
* *** ** * = b*g;
* ****** *** * * = c*g;
* *
* ** *** ** * ** ***
*** * * * * ******
* *** ** * ** ** ** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* ** ** * * * * *
* * *********
* ***
i ** *
** a , b , c , ** * * ** *** *
* ** ; i * *** ; * *
* ****** * * * ** , *** );




* *** * * **
* * ** *** ** = *
* *** ***** * **** * ** = - *
*


* * ** * * * * * *
*
* *** ***** **
= * *** ;
* = ** ;

** ** **** * ** * * a , b








* * ** 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
* * * *** ****
* * * ** * * * **

int main()

{
** * ** * * *** *** ** ** * * a,b,c,d,m,x,y;
* * * * ***** *** ** * %f %f ** ** * * * * * ** * * *
** *** *** ** * *** ** *
***** ** * * * ** * ***

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include *** * ** **



int main(void){


*** *** * ** * ** ax , ay ,bx ,by ,a ,b ,k,m,c;


*** **** ** **** ****** * * * * ** *
* * * * ** *** * * ******* * * ** ** ***** * ** *
* * *** * * * **** * * * * ** * * * ** * ***** * ***** *
* * **** *** * * ** * * ** ** * ** * * **** ***** *** * * ** *


* *** *** **** * * * * - bx) != 0){
*** * **** * * * * = (ay - * ***
** *** * *** ** ** = -m*ax + ay;
** ** *** ***** * = m;
* **** * ****** *** = 1.000000;

 }
*** * ***** ** *
*** * *** * *** ** = 0.000000;
** * ** * * * ** * = 1.000000;
* * * *** ** = -ax;

 }


** ** **** ***
* * * ** ** * *
*** *** **** ** **** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * *** ** * *



int main(void){


* * * ******* * **** ax , ay ,bx ,by ,a ,b ,k,m,c;


********* * * *** ** ***** ** **
* * ******* * ** * * * *** ** * * * ** ** * * * * ** ***
** ****** * * * ** * ** ****** ** *** ** * ** *** ******* * *** * **** **
*** * * ** * * ******* ******** * * * ** * ** * *** * * * * *** *** *** * * **** ***


** ** * ** * - bx) != 0){
** **** ***** = (ay - *** *
* ***** * * * = m*ax + ay;
** * *** * ** = m;
* *** * ** * * = 1.000000;

 }
*** ***** *** *
* * ** **** * ** = 0.000000;
** * * * * ***** = 1.000000;
***** ** **** ** = -ax;

 }


***** ***** * * * ****
* ** ** * ** ** *
* * * *** * *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.184
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users