0 like 0 dislike
3.7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.7k views

49 Answers

0 like 0 dislike
Hidden content!
// *** * * * * by HoMingJui on 2016/11/3.

//



#include ** * * * *

#include * ** **** *

#include *** * ** ** * *

#include *** ****** ***





int main(){
*** *** **** * ** * ** * ** x[2],y[2],a,b,c;
***** * *** * **** * * *** * * ** * %f %f * * * *** * * ** * ***** *** ***
* *** *** * * ** *** * * * *
** * * **** ** * ** * * * * * * *** * **
* * *** *** ** * *** **** * *
*** * **** ** * * * * * * ** *** %.6f * *** ** *
**** * ** * * * * * * ** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
* * ** * * ***



int main()

{
* ** * * * **** * a1,a2,b1,b2,a,b,c;
** ** ** * * * %f %f * *** ** ** * *** ** * ** * *
**** * **** *******
*** ** ** * **** ** *** *
* * * ** * ****** * ***
* * * * ** ** * * * ** * %.6f %.6f",a,b,c);


* * ** *** *** ** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* ** * ** * ****



int main()

{
** ** ** * ** * * a1,a2,b1,b2,a,b,c;
* * ***** ** ** * * *** * %f %f * * **** ** ** *** * * * * * **
* ** * ** * * ** * *
* *** * * * ** *
*** * ** * **** * * **** **
* * ** * * *** * ** *
* * * * * **** *** %.6f %.6f",a,b,c);


***** * * **** ******* * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * ** ** * * **



int main(void){


* *** * ** * * * *** ax , ay ,bx ,by ,a ,b * **


** * * *** ** * ** ** * ** *
* * * ** ** ** ******* *** ** * * ** * * * * * ** * ***
* * ** *** * ** ** * ** ** * * ********** * * ** * *
** * * * ** *** * * * *** * * ** * ** **** ** * *** * ** ***


* *** ** * * * ** ** - bx) != 0){
* *** * **** = (ay - * *
*** * ** * * ** = -m*ax + ay;
** ** * * * ** * = m;
** * * *** *** *** = 1;
* *** *
** * *** ***** *
**** * * *** * ** = 0;
** * ** * * = 1;
*** ** * ** * ***** = -ax;
* ** *


** ** ** *** **** = a;
****** * * *** = b;
* ** * **** = c;


** **** * < 0)
* ** * *** * * ***** = -i;
*** *** if (k < 0)
* ** **** *** * **** = -k;


****** * (i < 1){
* * * *** *** = 1/i;
* ** *** ** **** = a*g;
* * * * * ** = b*g;
**** * * ** ** *** * = c*g;
** * **
**** if (k < 1){
** *** * * = 1/k;
* * * * * ** = a*g;
** * * * **** ** = b*g;
* * ****** ***** ** = c*g;

 }
** ** ****** * *
* ** * * *** ** *
* ** ***** ** ** ** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * *** * *



int main(void){


** ** ** * ** ax , ay ,bx ,by ,a ,b ***** *


* * **** * ** * * * *** * ***** *** * **
*** * **** * ** ** ***** ******** * * **** ***
** * * * **** ** * **** *** ** * **** ** * * ** **** *
** ** * ** * * ** * * *** ** **** * * * * * * * **** ****** * *


** * * * ** - bx) != 0){
** **** *** **** * = (ay - *** **
* * ** ** ** * * = -m*ax + ay;
* * ** * ** * *** = m;
*** *** * **** * = 1.000000;
** ***
* ** **** * * ** * *
** ** * * * ** * * * ***** = 0.000000;
** * *** * * * * = 1.000000;
** * ** *** * * * = -ax;
*******


* *** ** *** = a;
** *** ***** * ***** * = b;
** * ** * * * * *** * = c;


* * * ** < 0)
*** ** * **** * = -i;
* *** if (k < 0)
** * ***** ****** ** * = -k;


* * * ** (i < 1){
* ** * **** * = 1/i;
* * ** * = a*g;
****** * *** * ** = b*g;
** **** **** ** = c*g;
* *
* ** if (k < 1){
* ***** ** * * * = 1/k;
*** * ** * *** = a*g;
***** ****** * * = b*g;
* * * * * * * * ** = c*g;
**** *
** ** * ** ** ** *
** ** * * * * *
** * ** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* * * * * * *
******** **** ***
* * *
* * i **
** a , b , c , ** * * **
***** ; i *** ;
** ** *** * * , * ** );




**** *
* *** *** =
* * *** * * * **** * * = - **
*


** * ** ** ***
*
* **** **** **
= * ;
* = ;
*
**** ** * ** * a , b **








* 0 ;






*
answered by (-87 points)
0 like 0 dislike
Hidden content!
*** ** * **** ** **
* * ** **** *** **

int main()

{
*** * ** ** ** ** a,b,c,d,m,x,y;
* *** * * * * * *** * * * *** %f %f * * *** * ** ** * * * *** ** ** **
***** * * * * ** **** *
* * * ****** * * ***** ****

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include * * * *** **



int main(void){


** * ***** ** * ** * ******** ax , ay ,bx ,by ,a ,b ,k,m,c;


* ***** * * * * *** * * * ** *
*** * **** ** ***** * ** *** * * ** *** **** ****
* * ** * ** * * * *** * ** ** * ** * ** ** *** ** * * * * ** **
* *** * ** * *** ** * * ** * * ** ****** ** * * ** ** * *


* * * *** ***** * - bx) != 0){
**** ** * = (ay - * ***
** ** * **** * * = -m*ax + ay;
*** * ** ** ** = m;
* * * * * * *** = 1.000000;

 }
* *** * *** ** ***
** * * ** *** * * *** = 0.000000;
* ** ** ** * ** = 1.000000;
** * ** * ******* = -ax;

 }


** * **** *
***** ** * * **
**** * * ** * **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * **** *** *



int main(void){


* * ** * ax , ay ,bx ,by ,a ,b ,k,m,c;


* * **** * ** *** *** ** ** *** ** *
**** ** ** * * *** ** ** ** *** * * * *
**** * ** * ** *** * ***** ** * ** ** * * * * * ** *** *
* * **** ** *** ** * * * ** *** ** ** ** * * ** *** ** * * * ** ****


* ** ** * ** * *** - bx) != 0){
* *** * *** * = (ay - ****
* ***** * ** = m*ax + ay;
* * * ** ** = m;
*** *** ** ** = 1.000000;

 }
***** *** * * * * *
* ** ** * * * = 0.000000;
* * * *** * * = 1.000000;
* * * ** ** ** = -ax;

 }


** * ** * * * *
* * *** *** * *** *
* * ** * * * **



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.113
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.1k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.3k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users