0 like 0 dislike
6.1k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.1k views

49 Answers

0 like 0 dislike
Hidden content!
// ** *** ***** by HoMingJui on 2016/11/3.

//



#include ** * ****

#include **** ** *

#include * ** * ** *

#include ** ** *******





int main(){
** * ***** **** **** **** * x[2],y[2],a,b,c;
** ** *** *** ** *** * *** * * %f %f * * *** *** ** * *** *** * * * * * ********
* * * *** ***** * * * *
**** * * * ** *** ** **** ** *******
** * ** *** ****** *** ** * * ** ** * *
*** * ** ***** *** * * ** * %.6f ** * *
* * ** * **** ** * * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
* ** *** ***** *



int main()

{
*** **** **** ** a1,a2,b1,b2,a,b,c;
* * * *** * * *** * %f %f * * * * ** ** *** * **** *****
** * * *** *** * *
** *** **** ** * * *** ***
* *** * * *** * **
** * *** ** * * ******** %.6f %.6f",a,b,c);


* * * *** * ** ** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* **** * *** *** *



int main()

{
*** * * * ** a1,a2,b1,b2,a,b,c;
* ** * ** **** * * *** %f %f * ** * ********* *** ** *
** * *** * ** *****
**** * **** * * * ** ** ***
* ** ****** ** * * ***
**** ** *** **
* ** **** * * * * ***** * ** * * %.6f %.6f",a,b,c);


**** ** **** ** * ** * *** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * ** ** * *



int main(void){


* ** *** ** * * * * ax , ay ,bx ,by ,a ,b *** ******


** ** *** ** * ** ****** * * * * *
***** *** * ** ** * **** *** *** *** * ***** *
* * * * * * * * *** * * * * ** * ** *** * **** *
**** * ** * * **** * * * ** ******* * ** * ** * * ** * *** **


* ***** * *** ** - bx) != 0){
*** ** ** * ***** * = (ay - * **
**** * ** * * * * ** * = -m*ax + ay;
*** * **** * *** **** = m;
**** * * * * ** = 1;
* **** **
****** ** * * * ** *
** *** **** = 0;
** *** * * * ** = 1;
** ** ** * *** = -ax;
**** *


* * ***** ******** = a;
* *** * *** * * * = b;
**** ** ** * * *** = c;


* * * < 0)
*** ** * *** ** = -i;
* * * if (k < 0)
* ** *** **** ** = -k;


*** ** (i < 1){
** * ** ** *** * = 1/i;
** **** ** * * = a*g;
*** ** * * ***** ** = b*g;
** * * * **** * * = c*g;
* ****
** ** * if (k < 1){
* * * *** * ** **** * = 1/k;
*** ** * ** ** ** = a*g;
******* ** ** *** * = b*g;
** * * * * ** * **** = c*g;

 }
** * ** ** * *****
* *** * ** *** * * *
* ** ** *** * * ***



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ** * * * **



int main(void){


** ** ** *** * * **** ** ax , ay ,bx ,by ,a ,b **** * *


* *** ***** * * * * * * *** * * ** ****
* * * ******* * * *** *** * * *** ** * * **** * ** **
* * ** ** * * * ** ** * * * * * * * ** *
* *** ** * * *** ** *** * **** * * ** * ** ** **** * * * * * ** * *


* * * ** * ** * **** - bx) != 0){
** * ** * * = (ay - * *****
* * ** * = -m*ax + ay;
*** * ** ***** ** * = m;
* ** ** ** *** = 1.000000;
*
** ** * * **
****** ** ** = 0.000000;
* **** ** * * = 1.000000;
** * * *** ** ** = -ax;
* ** *


* * * * * ** = a;
*** ** **** ** * **** = b;
*** ** ** ** * *** = c;


**** < 0)
*** * ** * ** * *** * = -i;
* if (k < 0)
* * * * * * = -k;


*** (i < 1){
*** * * * * * = 1/i;
* ** *** ***** * * = a*g;
* ****** ** * ** * = b*g;
* ** * * ** * = c*g;
** *
*** if (k < 1){
****** * * ** * * = 1/k;
**** ** * * ***** = a*g;
*** *** ** * * * = b*g;
*** * ** ** * * = c*g;
* * *
* * *** * * ** ** ***
** * ** * **
* * *** * ****** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* * * *** **
** ** * * ****
* * ***
* i ****** **
* ** a , b , c , * *** * * ***
* * * * ; i * ** * ; * *
* * * *** * * , **** * * );




* ** **
* * * * ** = **
* * * * * ** ** = -
*


* ** * * * * **** * ****

* ** * *** * * ***
= ** * ;
= * ;
*
* ** ** * *** * *** ** * a , b








**** 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
** * ****** ** **
** ****** * * * *** *

int main()

{
* ****** * *** **** * * *** * a,b,c,d,m,x,y;
**** * **** * * * *** * *** %f %f * * * * ** * ** * *
*** * * * * *** ***
* * *** ***** * * ** ** * **

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include ** **** **



int main(void){


** * **** ** * * ax , ay ,bx ,by ,a ,b ,k,m,c;


* *** ************* ******** * * * **** ** *
** * ** * * ********* * * **** ** ** ** * * * ** ***
**** * * * * * ** ** *** * * *** ** * *** **** * ** * *
*** ** * * * *** * ** * ****** ** * * * ** * * * ** ** * * ** * * ** **


* * * * ***** ***** - bx) != 0){
*** **** * ** * * = (ay - *
******* ** * ** = -m*ax + ay;
** ** * ** *** = m;
*** * ********** * ** = 1.000000;

 }
* * ** * *** * * *
* *** * * ** *** = 0.000000;
* ** ** ******* *** = 1.000000;
** * * * **** * = -ax;

 }


******** * ** *** ***
** * * ****
** * * ** ** ** ***



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include *** * ****



int main(void){


* * * * ** * ax , ay ,bx ,by ,a ,b ,k,m,c;


* * **** ** ** * * * * * * ** *
** * *** * * * * *** ** ** *** ** ****** * *** ** *
* ** **** * ** **** * * *** * *** * * *** * * * *** *
* ** * * ** * **** *** ****** ** ** * **** ** * * * ** ** *** ** * * * ***


** * ** * **** *** **** - bx) != 0){
* ** * * * = (ay - ******
*** *** * * ** * = m*ax + ay;
** ******** * * * * * = m;
* ** * * * * * = 1.000000;

 }
** * * * ******* *
* *** ** **** *** * = 0.000000;
* ** *** * = 1.000000;
* ** * * ** * = -ax;

 }


* ** * ********
****** **** ** ** ** *
* ** * * * * **



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.109
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.7k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users