0 like 0 dislike
7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 7k views

49 Answers

0 like 0 dislike
Hidden content!
// * * * * by HoMingJui on 2016/11/3.

//



#include *** * * *

#include ** *** * ****

#include ** ** **** *

#include ** *** * *





int main(){
** * * ** ** ** * ** * x[2],y[2],a,b,c;
** **** *** ****** ** ******* **** %f %f ** ** * ** ** ****** ** * ** *
* *** * ** * ** *** ** * ** * **
**** * * *** * * * ** ** * * ** *
** *** **** * * ** ** ** *** *
* * **** * * ***** ** * ** * ** * * %.6f * * **
* *** * ** ** *** ** * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
** ** *** ****



int main()

{
** * **** *** ** *** a1,a2,b1,b2,a,b,c;
* * ** * ** * * %f %f * * * ** * *** ** * ** * *
* * ** * *** ** ******
**** * * * ** ** ******
* ** * * * ***** ** * * *
* * ********* * * ** **** * %.6f %.6f",a,b,c);


** * * * ** * * ** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* * ** ******* *



int main()

{
* ** * * * * * ** ** a1,a2,b1,b2,a,b,c;
*** * * * * **** * * * * * %f %f * ** * *** * ** * * *** **** **
** * * ** * * **** *
* ** *** * * ** ** ** **
* * * * *** * ** ** * * *
* *** * ** ** * **
* * * ** ** * * **** * ** %.6f %.6f",a,b,c);


* * ******** ** **** ** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include ** * *



int main(void){


*** *** ** * ** ** ax , ay ,bx ,by ,a ,b * ** * *


*** ******** ******** *** ******* **** * *
* *** *** ** ** * ** ** * * ** **** * ****
** * * **** **** ** ** * ** * ** **** ** ** * ** ** **** * **** **
**** * ** * * **** * * * *** * ** * ** * ** * * ** ** * * * **** *


**** ******* * * - bx) != 0){
** * ** = (ay - * *
* * ***** * ** = -m*ax + ay;
***** * * *** = m;
* * ******* ** ** = 1;
* * *
* * ** ****** * *
* ***** * * = 0;
* * * *** * * * = 1;
** ** **** * * ** ** = -ax;
** *


*** ** * *** *** = a;
* * * ** * * *** = b;
** * ** * * = c;


** ***** * < 0)
* * * *** * ** * * * *** = -i;
** *** * if (k < 0)
* ** *** * * ******* * * * * = -k;


* (i < 1){
* * ** * * * ** = 1/i;
* * * **** * = a*g;
** ***** ** * **** * = b*g;
** * **** *** **** *** = c*g;
** ***
** ** * if (k < 1){
* * *** **** * *** * = 1/k;
* ** ** * * = a*g;
****** * ******* * = b*g;
**** ** * * * = c*g;

 }
** * **** ** * * *
** ** * ** **
*** * * * * * *** ***



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include *** ** *



int main(void){


* * * * * * ax , ay ,bx ,by ,a ,b *


** ** ****** ** ** ** ** * *** **
***** * * * ** * *** * *** *** * * ** *** **
***** *** * * * *** ** * * * * ***** ** ***** * *** **** *** ** **
** * ***** * *** ***** * * * ******* * * * * * * * **


* *** ** ***** * * * * - bx) != 0){
** * ** * **** ** = (ay - ** * ***
*** **** * * = -m*ax + ay;
* ** **** ** = m;
* * * *** * * = 1.000000;
** * ** *
* * *** * * *** ***
* ***** * ** * = 0.000000;
* ** * **** * *** = 1.000000;
******* ** **** * = -ax;
***


** ** * * * *** = a;
** * **** ** * *** = b;
* * ***** * **** = c;


** * * < 0)
* ** ** * * * * * = -i;
* * * * if (k < 0)
*** **** * ** * **** * = -k;


*** (i < 1){
*** * * * ***** ** = 1/i;
*** * ** ** = a*g;
* * **** * = b*g;
* *** **** * *** = c*g;
*** *
* * * *** if (k < 1){
** * ****** ** * ** = 1/k;
** ** *** *** * ** = a*g;
* ***** * *** * ** = b*g;
* * * * * = c*g;
** *
* **** **** ** ***
* ***** ** ** * * * *
**** ** ** **** ** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* * * ** * *
*** * ** *** *
** * * *
** i * ***
a , b , c , ** * *** * * ***
** *** ; i * *** * ; *
* ** * **** *** , * * *** );




*** * * *
*** ***** * = *
* * ** ***** ** * * * = - **
*


*** ******* **** ** **

*** ********
** = * ** ** ;
* = * ;
*
* ***** ** *** * **** * a , b








* 0 ;






*
answered by (-87 points)
0 like 0 dislike
Hidden content!
* * ** * *
*** * * *** * *** *

int main()

{
***** * **** ** * ** * * a,b,c,d,m,x,y;
* *** ******** * * * * ***** ** **** %f %f * ** * ** * ** * * **
* * * ** *** ** * ****
********* * * *** ** * * **

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include **** *



int main(void){


* * ** *** **** ax , ay ,bx ,by ,a ,b ,k,m,c;


**** * * * * * *** *** * ** ** *** **** ** *
* * * * * *** *** * * * * ** * * ** * * ** **
* * *** * **** * * * * *** * ** ** ** * * ** ** * **
* ** *** * ***** * * ** * * **** *** * * ** * ***** ** ** * * **** * ****


** * *** ****** * - bx) != 0){
*** * ****** = (ay - * * **
* * ** ** * = -m*ax + ay;
* ** * * * ** = m;
* *** ** **** ** * = 1.000000;

 }
* * ** **** * * *
** * * *** *** ** = 0.000000;
* ******* ** * * ** = 1.000000;
* * ** ** *** = -ax;

 }


** * ** * * ** ****
** ** ** * *** **
*** **** **** ** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** * **



int main(void){


* * ***** * * * ax , ay ,bx ,by ,a ,b ,k,m,c;


* ** * ** ** *** ** *** *** * * * *
** * * *** **** * * * *** ** * * ** * **
* ** ** *** ** * * ** * ** *** *** * * * ** * ***
* ** ** ** *** ** * * * * * ** * * * *** * ***** * * * *


* *** *** ***** ****** - bx) != 0){
* * * * * ** ** * = (ay - * *
* * ** **** **** = m*ax + ay;
** ** ** * *** * = m;
** ** ** ** ***** *** = 1.000000;

 }
* * * * * * *
* * ** *** *** = 0.000000;
* ** *** * * ** *** = 1.000000;
* * * * * * * ***** = -ax;

 }


* ** ** * * ** * *
* * * *** *** * * *
*** * ** * ** ****



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.7k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 12.5k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users