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直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5k views

49 Answers

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// * * * * by HoMingJui on 2016/11/3.

//



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}
answered by (-126 points)
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Hidden content!
**** * ** *** **** *



int main()

{
* * ****** **** ** a1,a2,b1,b2,a,b,c;
*** * * ** * ** ** *** ** %f %f * * * * * ** * * ** *** * ** ** ** *
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** ** ** ** * * 0;

}
answered by (-124 points)
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Hidden content!
** ** *** **



int main()

{
** *** ** ** * ** * * a1,a2,b1,b2,a,b,c;
* * * ********** *** ** * * * %f %f * **** *** * * *** * * * *****
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** * * *** ** 0;

}
answered by (-124 points)
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Hidden content!
#include * * ***



int main(void){


* ** * ***** ***** ax , ay ,bx ,by ,a ,b ** *


** * * *** * ** * ** ** **** * * **
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** * * ** * **** = -m*ax + ay;
** * = m;
* ** **** ** ** * ** = 1;
* * *
**** * * ** ** *
** * * * **** = 0;
** * ****** * = 1;
* * **** * *** = -ax;
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* ** ** * ***** * = a;
* * * * ** ** = b;
*** ** ** ** * * * = c;


* * * * < 0)
** * * **** = -i;
* * ** if (k < 0)
* ** * *** * * * = -k;


* * * (i < 1){
* ** * * ** **** ** = 1/i;
* * * * * * = a*g;
* * *** **** ***** = b*g;
* ** * * ** *** *** * = c*g;
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**** *** if (k < 1){
* *** **** ****** = 1/k;
** * ** * * * * ** = a*g;
* ** * ** * = b*g;
* * ** ** * *** = c*g;

 }
******** * * **** **
* ***** * * * *** *
*** ** ** * *



return 0;

}
answered by (-122 points)
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Hidden content!
#include **** *****



int main(void){


* * * * ** ******* * ax , ay ,bx ,by ,a ,b *** * *


**** *** * ******* * ** * *** ** * * ** **
* * * * *** ** ***** ****** *** ** *** *
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* * ******** ** * **** - bx) != 0){
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* * * **** ** = -m*ax + ay;
* **** * **** * = m;
* * * *** * * * = 1.000000;
***
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** ** * ****** = 0.000000;
** * **** * * * * = 1.000000;
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* * * *** ** = c;


* ** < 0)
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* if (k < 0)
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*** * ** (i < 1){
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* * ** * **** * = b*g;
* * * **** **** ** = c*g;
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******** ***** *** * * = c*g;
* ***
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* ** **** ***** ******
* *** * ** **



return 0;

}
answered by (-122 points)
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Hidden content!
** ** * * ** *****
* * * *** * * ** *
* * *
* i * *
* a , b , c , ** * * *
* *** ; i ** * ; *
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answered by (-87 points)
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Hidden content!
* * * ** ** * *
*** * * * * ** *** **

int main()

{
**** * *** ** ** **** * * a,b,c,d,m,x,y;
* * * *** **** * * * * * %f %f * ** * * **** * ** ** ** * **
** *** * ******* ** * *** * *
* * ** ** ** **** **** *

}
answered by (-103 points)
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Hidden content!
#include ** **



int main(void){


*** *** *** ** * ** ax , ay ,bx ,by ,a ,b ,k,m,c;


** **** *** * * ** ***** *** * * ****
*** ***** * *** ***** *** * ** * *** * * ** *
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*** ****** * ***** * - bx) != 0){
* * ** ** ** * * = (ay - *** **
*** *** * ***** * = -m*ax + ay;
* ***** * * * * = m;
* * ** **** * * = 1.000000;

 }
* ** ** *** * * * *
* * * ** * * * = 0.000000;
** *** ***** ** * = 1.000000;
* ** ** * ** = -ax;

 }


** ** ** ** *
*** * ** * * *** *
******** * ***** *



return 0;

}
answered by (-122 points)
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Hidden content!
#include **** * * * *



int main(void){


* ** * * *** * **** * ax , ay ,bx ,by ,a ,b ,k,m,c;


*** * * ** * **** ** * * **
* ** * ** * * * ***** *** ** ***** *** * ** **
****** **** * **** * * ** * * * *** * *** * **** *
** * * * * ** ** * **** * ** * ***** ** * * ** * * * *** ** * * * *** ***


* *** * *** ** ***** ****** - bx) != 0){
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* ** * ** * * ** = m*ax + ay;
** *** * * * ** = m;
* * ***** * = 1.000000;

 }
*** ** *** * * *
*** * * * * = 0.000000;
*** * ** * *** * = 1.000000;
*** ******* * * ** = -ax;

 }


*** * * * * *** **** *
*** * ** * * * ** **
*** * ** ** * ****



return 0;

}
answered by (-122 points)
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