0 like 0 dislike
4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 4k views

49 Answers

0 like 0 dislike
Hidden content!
// *** * *** by HoMingJui on 2016/11/3.

//



#include ** **********

#include * ** *** * ** ***

#include ** * *******

#include ** * ***





int main(){
* **** *** * ** * **** * x[2],y[2],a,b,c;
*** * *** **** ** * ******* ** %f %f * * * *** * ******** * *** ******** *** ** *
**** * ** * *** * ** * ** ****
**** *** *** ** * **** * *** * ** **** *
* ****** * **** * * * ** * ******
**** ****** * ** ** ** * ***** %.6f * * * * *** *
** *** * **** ** ** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
***** ** *** *



int main()

{
*** * * * * * a1,a2,b1,b2,a,b,c;
* * * * **** *** * ** ** %f %f *** ** * * ***** ** * * ** **** * ** **
* **** * * **** ** ** *
*** * ** ***** * *
* * ** * * ** ** ** * **
* ** ****** ** * ** * * * %.6f %.6f",a,b,c);


* *** * ** * * ** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* * * * * ** *



int main()

{
* * * ** ** ** a1,a2,b1,b2,a,b,c;
* * * ** ** **** * * ** %f %f * * ** ** ** *** ** *** * ** ***** **
* * * * ***** **
** ** * ***** *
*** * * ***** * * * ****
* * * * ***** ** ** ** *
***** ****** * ****** *** * * * * * %.6f %.6f",a,b,c);


* **** *** * ** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include ** ****



int main(void){


* * * ** * ** * ax , ay ,bx ,by ,a ,b ** ***


** ** * *** * ******** ** ** *
* * * * * * * * * * ** * * * *** **** * **** **
* * ******* * ** * ** * **** * * ***** ********** * ** * ** **
**** ****** * * *** * * * *** * * ** ** ** * * * ** ***** * *** ***


**** * * **** * - bx) != 0){
* *** ** * * = (ay - * ** * *
**** *** ** * ** * = -m*ax + ay;
* * ***** ** * = m;
** * * ****** ** * = 1;
*
* **** *
* **** *** ** = 0;
** * ** ** **** = 1;
** ******** * ** = -ax;
* * **


** ** **** * * ** * = a;
* **** * **** * = b;
** * * * * * ** = c;


** ** < 0)
** ** ** * ** **** * = -i;
* * * if (k < 0)
** ** * ****** * ** * ** = -k;


*** (i < 1){
*** * *** ** = 1/i;
* * ** ** * = a*g;
* * ***** * * = b*g;
* ** * ** = c*g;
****
** * if (k < 1){
* * * *** ** *** = 1/k;
* * * ** ** * = a*g;
* * * * * * * * = b*g;
* ** * * ** = c*g;

 }
*** **** ** * ***** **
* **** * **** *** * *
*** ** **** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ***** * *



int main(void){


*** * ****** ***** ax , ay ,bx ,by ,a ,b * * *


** * * * * ** ** ** *** * ** * *
* ** * ***** * * * **** ** * * * * *** *
* *** * ** * ** * * * * ** * * * ** *** * * *
* *** * * ** * * ** *** * ** * * *** * * ** * ******* **** * ** * * *


* ** *** * * ** * *** * - bx) != 0){
** * * ** = (ay - ****** *
***** * ** * *** = -m*ax + ay;
** * ** *** = m;
** *** * * ** * * = 1.000000;
* * *
** * *** * ** * ** * *
* *** * **** = 0.000000;
*** ** * *** ***** ** = 1.000000;
* *** * ** * * ****** = -ax;
*** ** **


* * * ********** * * = a;
* * ** * *** ** * = b;
* * ** ** ** * = c;


**** < 0)
*** *** *** * **** ** * = -i;
** * ** if (k < 0)
* ******** ** ** ** = -k;


****** * (i < 1){
** **** * **** * = 1/i;
* ** ******* ** = a*g;
**** ** * * = b*g;
* ** ** ** * = c*g;
** ***
* * * * if (k < 1){
***** *** **** = 1/k;
** * ** ** * = a*g;
* * * * **** = b*g;
* * **** *** * = c*g;
**** **
**** * **** **
** * * * ** * * **
* *** * * * *** ** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
** * * **** * *
** * *** ** *
* * *
** i ** *
* ** a , b , c , * ** * * * * *
*** ; i * ** * ; *
*** ******* , * *** * );




* * * * *
* * * * * * * =
** * ***** * * *** * = - *
*


************** * * *******
*
** ****** * *
= ***** ;
* = * ;
*
* * * ***** * ** *** * * ** a , b *








* * 0 ;






*
answered by (-87 points)
0 like 0 dislike
Hidden content!
* *** * ** * *
* * ** * * * *

int main()

{
*** **** **** * ** * * *** a,b,c,d,m,x,y;
** ** ** *** ****** ** * ** %f %f ***** * ** ** * ** ** **** *****
*** * * ** * * ***
* ** ** **** * ** * *

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include * ** ** **** *



int main(void){


* * ** * ** * * ** ** ax , ay ,bx ,by ,a ,b ,k,m,c;


* ** * * * ** ** * * * * * * * **
** *** ** * ** *** * **** ***** * ** * *
* *** * **** * ** * ** * * ** ** * * ** ** **** ** **** * ** * ** ** *
* * ** *** ** *** * * *** ** *** ** * * *** * * ** * * * ** ** * * * ** *


** * ** * * * ******* - bx) != 0){
*** * ** ** = (ay - ** *
*** ******** = -m*ax + ay;
*** * * ** = m;
* * ** * *** ** = 1.000000;

 }
** * ** ******** **
* * * * * * * = 0.000000;
*** * * ** ** * * = 1.000000;
* ** * ** * * ** * * = -ax;

 }


** ***** * ** ****
** * * ** ** *
* * * * *** * * ***



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ** **



int main(void){


** * *** * * ***** * ax , ay ,bx ,by ,a ,b ,k,m,c;


*** * *** ** * * *** * ** * ** * ** ***
* * * * * * * * *** ***** * * * *** * ** **
* * * *** **** ** * ** ** * * ** *** ** * *** * **** *
** * * * * * * * * ********* * ** * * *** * * ** * ***


**** * * ** *** ** - bx) != 0){
** *** *** ** * ** = (ay - ** **
* * * ** * * * ** = m*ax + ay;
*** * ** * * * * = m;
* ****** * ** * = 1.000000;

 }
* * *** * * **
* ** ** * * * * * * = 0.000000;
* * * * = 1.000000;
** ** ** ** = -ax;

 }


** *** * * *
* * *** *
** *** * * ****



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.113
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users