0 like 0 dislike
7.4k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 7.4k views

49 Answers

0 like 0 dislike
Hidden content!
// *** ** by HoMingJui on 2016/11/3.

//



#include * * * * * *****

#include * * * ** ***

#include * ** * **

#include ***** ** *





int main(){
** ** **** * * * x[2],y[2],a,b,c;
** * ** * * * *** * ** **** * ** %f %f ** ** ** ***** * * * ** ** *
* * * ** * * ** *** *** * ** *** ** *
* ** **** * ** ** *** ** ** **** * * **
**** ********* ** ** ** *
** * * *** * * ** ** **** * *** * ** %.6f ** *
*** *** ** * *** ** * ** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
* ** **** **



int main()

{
* ** *** * *** ** a1,a2,b1,b2,a,b,c;
**** ****** **** * %f %f ** * * ** *** * * * ** * ** *
* *** * ** * ** * * **
**** ****** *** *
**** ** * ** ** **
* ** * * * ** * ****** * ** * %.6f %.6f",a,b,c);


***** ** * * * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* * * * ******** *



int main()

{
** *** * * * a1,a2,b1,b2,a,b,c;
** ** *** ** * * * *** **** %f %f * ** * * * ** * * * **
**** * * ** * * *
** * * * * * ** * * **
* ***** * * * ** ** * **
***** **** * ****
* *** ** ** * * * ** **** %.6f %.6f",a,b,c);


*** ** * ***** * * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * * * * ** *



int main(void){


* **** ** * * * ax , ay ,bx ,by ,a ,b *****


**** ** *** * * * **** * ** ** ** *
* ** * * ** * **** * * ** * * **** * *** ** * * * * *
* * ** ** * ** * ** * * *** * * ***** ** *** ** ***** ** ** * ***
* * * *** ** ** * * * * * * * *** * ** **** ** * * * ******


** ** ** * ** *** * * - bx) != 0){
* * * *** * * = (ay - *
** * *** * * = -m*ax + ay;
* * * **** = m;
** * **** * ** = 1;
**** *
**** *** **
* * ** *** ** = 0;
* ** * ** * ** = 1;
** * * * * ** = -ax;
** * *


* *** ** ** * *** = a;
* **** ** *** * = b;
** * ***** * ****** = c;


** < 0)
*** * ***** ***** = -i;
** * * * if (k < 0)
** * * ** ** *** *** = -k;


* *** (i < 1){
*** ****** * * * = 1/i;
* ** * *** * * = a*g;
* ** **** ** * = b*g;
* * ** * *** = c*g;

* ** if (k < 1){
* * * * = 1/k;
** ****** ** = a*g;
** ***** * * = b*g;
* * ********* * ** * * = c*g;

 }
** ** **** ** ** **
** * * *** * ***
** ** * * * * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * **** *



int main(void){


* * * * * * * * ax , ay ,bx ,by ,a ,b ***


******* ** ** * *** ** **** * * * ***
* * **** * * * ** * ** * ** * * ****** * * *** * ** **
* * ** * * * * * ** * ** ******* ** * * ** * ** ** **
* *** * * ** ** * *** *** * ***** * ** * * *** ** *** * * ***


* * ** * ** - bx) != 0){
* * * **** ** *** = (ay - *** **
*** *** * * ** * * = -m*ax + ay;
****** * * = m;
*** * ** *** *** = 1.000000;
* ***
* ** * ** * * * ***
** * * * ** = 0.000000;
** * * * * ** = 1.000000;
* **** * **** ** = -ax;
* ***


** *** * * * * **** = a;
* * ** ** * * = b;
**** **** **** ******** = c;


*** *** * < 0)
****** *** ** * * *** = -i;
* ** if (k < 0)
** *** * *** ** * * = -k;


***** ** (i < 1){
*** ******* *** = 1/i;
*** ** * ** **** = a*g;
* * * * * * * ***** = b*g;
* * *** * ** ** * = c*g;
** *
* * if (k < 1){
*** *** * ** = 1/k;
*** *********** * = a*g;
* ******** **** ** *** = b*g;
* * ** ** * ** = c*g;
* *
**** * *** *** *
*** *** * * ** * * * ** *
* ** * *** * **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
*** * ****** ***
* ** * * ******* *
*
* i * **
* a , b , c , **** * *
** * ; i ** * * ** ; **
* ****** * * , ** * * );




** * * *
******* * = **
** *** ********* * **** = - *



***** * * ** ** * * **

* * * * * *
* = * * * * ;
= * ;
*
*** *** ** * *** * * * * * ** a , b *








* 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
* * * *** **** **
**** * * *** *** ** *

int main()

{
* ** ** ** ** * * * a,b,c,d,m,x,y;
*** *** ** * * * * * ** ** %f %f * * * * * * * *** * **** ** *
* ** ****** ****** * ** * *
* * **** ***** * *** * * ** *

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include *** * ****



int main(void){


* * ***** * * ax , ay ,bx ,by ,a ,b ,k,m,c;


* ** ** * * ** * * * * ** **** *** * *
** *** * * ********* * *** *** * * ** * * * * **
* * * * * ***** * * * *** * *** *** ***** * * ***** * * * * *** *
* * ***** ****** ** ** * **** *** ***** *** * * * **** *** *** * ** *


* ***** ** *** - bx) != 0){
**** * * * = (ay - *
*** * * ******* = -m*ax + ay;
* * ****** * * *** * = m;
* *** * ** * * ** = 1.000000;

 }
* * **** * * * * *
***** * ** ***** = 0.000000;
*** ****** = 1.000000;
* *** * * ** * * = -ax;

 }


** * ** **
* * ** **
* * * *****



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ** ** *** **



int main(void){


*** * *** ** * ax , ay ,bx ,by ,a ,b ,k,m,c;


* * **** ** ** * *** ** ***** * *** * ****
* * * ** * * * * * *** ***
** * ** ** * *** * *** * * * * ** * * ** ** * ** * ** * * * *****
* ** **** * ******** * * * *** *** **** ** * ** *** *** * * * * *


* *** * ** *** *** ** - bx) != 0){
* * *** * **** = (ay - **** *
*** * * **** = m*ax + ay;
** * * * = m;
* * ********* ** = 1.000000;

 }
** * **** *** ** * *
* ** **** *** * ** = 0.000000;
* * * * * * * = 1.000000;
*** ** * ** * ** * = -ax;

 }


*** * ** * ***
* ** ** ** *** ** ** ***
* ** * ** *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 13.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users