0 like 0 dislike
923 views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 923 views

49 Answers

0 like 0 dislike
Hidden content!
// ** ** * * by HoMingJui on 2016/11/3.

//



#include * * *

#include ********** * *

#include * **** ***

#include * * * ****** * *





int main(){
** * ** * ** ** * x[2],y[2],a,b,c;
* ******** * ** *** * * ** * %f %f * * ** ** ** * ******* **** * ***** * *
* * ** ** * **** * ** * * * ** ** **
***** * * * ***** ****** * * ******
* * ** **** * * ******* * *** *
*** * * * ** * ** * * * * * ** ** * * %.6f ** * ** * *
** **** * * * *** ** ** * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
** ** * * *



int main()

{
* * **** ** * ******* a1,a2,b1,b2,a,b,c;
** **** * * ** **** %f %f **** ***** * ** ** * * ** *
***** * * * * *
* **** * * * * *
* * * * *** * *** *
* ** * * **** ** * ** %.6f %.6f",a,b,c);


* ***** ** * * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
** * ** *** **** *



int main()

{
* * ** a1,a2,b1,b2,a,b,c;
*** * * * * ** **** *** * ** %f %f ** ** * * ** ** *** *
** * * ** * *
** * * * * * ** * *
*********** * *** ***** *
* * * * *** **
*** * * ** ** *** *** *** * * * %.6f %.6f",a,b,c);


* * ** ** * ***** * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include ** ** * * *



int main(void){


** *** * *** ax , ay ,bx ,by ,a ,b * *** *


* *** ** ** * ** * ** * ** ** * *
**** ******** ** * **** * **** ** * * ** * ** * * *
** *** * ** ** ***** ** ** * * ****** ** ** * *
***** * * * ** * * * * * *** ** * * ********* *** **** * ** * * ** **** ****** **


**** * ** * **** - bx) != 0){
** * * * = (ay - **
** * * *** * = -m*ax + ay;
* *** * * * ** = m;
* * * **** * *** * * = 1;
* ****
* * ******** * * ** **
* * ** * ** * ** = 0;
*** * * * *** * * = 1;
*** * * **** ** = -ax;
* ** ** *


*** ** * * * * = a;
* ** * ******* * = b;
** ** * ** = c;


** * < 0)
*** * ******* * * * ****** = -i;
** * * if (k < 0)
* * * ** * * * = -k;


* ** ** (i < 1){
* * * ***** ** = 1/i;
* ** ** ** = a*g;
**** * ** * * * = b*g;
* * * ** *** ** * * = c*g;
* ** *
* * **** if (k < 1){
* ** ** * * *** * = 1/k;
** ** * * * * * = a*g;
** ** * ** * = b*g;
* ** **** ** = c*g;

 }
** * * ** * * *
* ** * ** ***
* **** * * * *** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ** *** * **



int main(void){


** ****** * * ** * ax , ay ,bx ,by ,a ,b *** * *


* * * * *** * * *** **** ** ** * ** ***
*** * *** **** * * ***** ** *** * * ** **** *
*** ** * *** * *** ***** * * * * * ** **** * * * *
* ****** * * ** * ** **** ** *** * ** ** ** * *** **** * * ** ** **


** **** ** ** **** ** ** - bx) != 0){
** ** * ** **** * * = (ay - ** * **
*** * ** * * * = -m*ax + ay;
* * ** * * * ** * = m;
* ******* * * * = 1.000000;
* *****
*** * * ** * *** **
****** * ******* = 0.000000;
* *** * * ** * *** * = 1.000000;
* **** **** ** *** * = -ax;
** **


** ****** * * * = a;
* **** ****** * = b;
** * *** * *** * = c;


* * * ** < 0)
* **** ** ***** *** *** *** = -i;
** ** * if (k < 0)
** ** * * * *** ** ** = -k;


* * ** ** (i < 1){
* * * *** ** = 1/i;
*** * * * * * = a*g;
*** * ** * * ***** = b*g;
** * ** * ** ** = c*g;
* * *
* * if (k < 1){
** *** * ** **** ** * = 1/k;
* *** ** * * * = a*g;
***** * *** * = b*g;
* * * ***** * * = c*g;
** *
* * ** ** ** ** *
* * ***** * ***
* * * * * ** * * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* ** * **
* * ******** * * **
* ** *
* i * * **
** a , b , c , * * ** ***
* ; i ** ** * ;
* ** * * , * ****** );




*** ** * *
** * * ***** = *
** ** * ** ** * ** * = - **
*


* *** ** * * * * **
*
***** * ** **
= * * ** ;
* = ** ;
*
* ** * * ***** * * a , b * **








* 0 ;






answered by (-87 points)
0 like 0 dislike
Hidden content!
* * * *** * * * *
* *** * * * * * *

int main()

{
****** *** ** ***** a,b,c,d,m,x,y;
** * ** * *** ** * **** * %f %f ** * * * ** * *** ** ** *** * **
**** ** * * ** * ** *
* **** *** * ** * * ** * *** ** *

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include ** *** ** * *



int main(void){


* *** * **** ** *** * ax , ay ,bx ,by ,a ,b ,k,m,c;


* * ** **** * ** *** * *** * * ** **
* * * ** **** * ** ** * ********* *** * * * * * *
******* * * * * * * ** * *** * * * * * * * * ** * ******
* * *** *** **** * ** ***** *** * * *** ** * ****** ******* * *** * * **


* ** * ****** *** * - bx) != 0){
***** ** ** *** * = (ay - ** ** *
***** *** ** * ** = -m*ax + ay;
* * *** = m;
* ** * * * * * = 1.000000;

 }
* * * *** ***** **
* * *** **** ** = 0.000000;
*** * ****** ** * = 1.000000;
* **** **** = -ax;

 }


** * * ** **** ******
**** * **
** **** * * *** **



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * *** ***



int main(void){


*** * * ** ** * ax , ay ,bx ,by ,a ,b ,k,m,c;


* ******* ** * * * * ** ** * *
* ** * * *** ***** * *** * ****** ** * ***
** * * ** * * * *** *** * ** * ** ** ** * ** ** ******* **
* * * ** *** * ** * * *** * * * ***** * * *** *** ** ***** * * ** *


* ** * ** ** * **** * * - bx) != 0){
* ** *** **** = (ay - * * ***
*** **** ** = m*ax + ay;
* ** * * * *** = m;
*** * * ** * = 1.000000;

 }
* ***** * ** ** * * * *
* * *** ** = 0.000000;
* * ** * = 1.000000;
* * ****** * *** ** = -ax;

 }


* * * ** * ***
** ** ***** ****
* ** * * ****



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.150
©2016-2024

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 466 views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 489 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users