0 like 0 dislike
985 views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 985 views

49 Answers

0 like 0 dislike
Hidden content!
* ** * * **


** ** * * ** ****** * *


** * * ***


* * ** *** * ** **




* * ( *

** *** ** * *
*** * * *** * ** * * ** **** * * ** *
= d -
= c -
* = f * b - a * e ;
= 0 -
** **
*
* *** ** *** * **** * ** **** = - * * * * *
**


** ** * *** **** * *** * **
* * *
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
** *** * * * ** * * * *** ***** * *** *
* * * ******* ** * * **** * *
*** ** * **** ** *** * * * *** ** * * *
* * *** ** * * **** ** ** * ****
* * * * * * * * * *** ** * * * ** *** * **** **


* * ** ** * * * *** * **** (a-c!=0)
*** * ** * ** * **** *** *
**** * ** * ******** ** ** * *
* * ** ***** * ** ** ** **
******** * ** *** *** * ** * ***
** ** ** ** * * ** ** ** **
* * *** ** **** ** * ** * (a-c==0)
**** ** * * **** **** ******
****** ** ** * ** * ** **** * * * *** ** * * **
** *** * ** ** * * **** * ** **** *** * * * *
** * ******** * ** * * * ** ** *** * ** *** ** * *
** *** * ***** * *** * * ** *
* ** * ** *** ("%.6f ",e);
* * * ** * * ** * * ** * ** ("%.6f ",g);
* * ***** * * * ** ("%.6f",f);






* * * ** **** ** ** * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
#include * ** ** * * ** *



int main(void){


**** * ******** * *** ax , ay ,bx ,by ,a ,b ***** **


** *** * * * * * ** *** ** ** ** ** * *
* ** * *** ***** ***** ** ** * **** * ** **** * ** * *
* ** *** * ****** ****** **** * * *** * * ** * * *** * **** **** *
****** ** * * * ** ** * ** *** * *** ** ** ** * ** *** * * * ***** *


** **** * **** ** * ****** - bx) != 0){
** ***** * *** = (ay - * *
* * * ** *** ****** * = -m*ax + ay;
*** * * ******* ** = m;
***** ** *** ******** = -1;

 }
* ** * ** * * ***
* *** * * **** * * ** = 0;
** * * *** * = 1;
* ***** ** **** = -ax;
**** *


* **** * ********* ** = a;
* * ** ******* = b;
** * * ***** ** * ** = c;


* **** * < 0)
***** * ******* ***** * = -i;
** * ** * if (k < 0)
* ** * *** * * * * * * = -k;


********** (i < 1){
** * ** * ** = 1/i;
* ** ** * * * * = a*g;
** * ***** = b*g;
* *** * ** * * * = c*g;
* **
** *** if (k < 1){
* * * ****** ** ** = 1/k;
*** * ** * * = a*g;
* * * *** * = b*g;
******* ** *** ** * = c*g;
* **
* ** * ** *
** * ** *** *
**** * * * *** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* * **** * * *


** * * * * *** * *


* ** * **** * *


*** ** * *** *




( * )
**
* * * ** ***
** * **** * ** * ** ** **** * ** *** **** ****
= *
** = c - *
= f * b - a * e ;
* = 0 -
* * *

* ** ** ** * ** = 0 - * = 0 - = *
*
*
* ** **** * * * * *
* * *
**




* * ** *** ** * ** * **
* *
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include ** * *





int main()

{
* * *** *** *** * * * * * * * * *
* * ***** * *** ** * * ** ***
* **** ** * ** * * ****
*** ** * ** ******








******* *** * * * **** * * %.6f %.6f",a,b,c);

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
* *** * * ** *


*
***** ***** * * * * *** *** ** * * * t = 0, a, b, c, a1 , * *


*** * ** **** ** *** ** * ** %f %f * * ** ** ** * ** * **** ****




******* ** ****** *** * = y2 - y1 / * * y2 - x2 * **
*** * * ** ** * ** * = - * / * - * * *
** ** ** * * *** * * * = - * ** - ** * *
*** * **** * * * *** * = a /
* ** ** * *** ***** = b / c;
* * * * ** ** * * * *** * *** * * * * *** * * *


*** 0;
*
answered by (-105 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** *** **** ** * *

int main (void)

{
* **** * *** ** ********* x1,y1,x2,y2;


*** **** *** * ******** a,b,c;


** ** ** ** * ** *** * ** *** * %f * * * * * ** **** ** ****** ** *
* ** * * ** * **** * ** ** **
* * ** * ******* *** * ****** * ***** **
**** * ** ** * * * ** ** **




* * ** ** *** ** ** **** ** %6f %6f",a,b,1);
***** * ** * * * ** *** *** 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* ** * *** * *** *** * * ** * *** **
** * * ***** ** ** ******* **
* ** * * ** ** * * ** *** ** **
* * ** ****** *** ***** * *** * ** * ** ** *
* * ** *** ***** *** ** * * ** *** *


* * **** * ****** * ** * ** * ** (a-c!=0)
* ** ** ** ** * * * ** * *
** * ** ** ** ** *** ** *
** * ** * ** * * ** * *** *******
** * * * * * * ** * ** ****
*** * *** ***** * * * * ** * *
*** * ** ** ***** ** * ** (a-c==0)
** * * * ** ** ** * ***** * ** *
** * * *** ** * * * * * * * * * ** * *** *
******* * * * ** * ** * ** * *** ** * * * *
* ***** *** * * * * **** ** * ** * * * * * * * * *** * *
*** *** ** ****** ** * * * *** **
** * * ******* * * ** ("%.6f ",e);
* *** ****** * * * ("%.6f ",g);
* *** * * ***** ("%.6f",f);






* ***** **** * ** ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* ** * * * ** *





int ****

{
** * **
* ** **** *** ** %f %f * **** * * ** ** * **** ** *
* ** * ** - x2 == 0)
*** * *
** * **** ** ** ** *** = x1;
*** ****** * ** * = 0;
* ** ** * ** * * = -x1;
** ** * * * * *** * %f *** * *
* * ** * **
** if(x1 - x2 != 0,y1 != 0)
** **
* ** **** * ** * = (y1 - ** * - x2);
* * * **** ** *** * = y1 - (a * x1);
** * ** * * * * = -((a * x1) + c) / y1;
* * * ** * * * * * %f ** ***** * *
** * ***
* * ** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
**** * * * * *


* * ** * ** * ****


* * **** ** ** * *


**** * *** ***** **




* ( *** )
*
* ** **
** * * *** * * * * * *** * * *** * ** ** ** ** * *
* = d -
* = c - *
= f * b - a * e ;


* * ******

* * ** ** * ** ** ** = 0 - = * * * -



* **** * ** *
*
**
answered by (-276 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.233
©2016-2024

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 507 views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.2k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 537 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users