0 like 0 dislike
18.4k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

Example input: 

12 28

Example output:

4

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited

edited by | 18.4k views

69 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{

** * ** **** **** ** * n,n2;
***** ***** * ** ** * * i;
*** * ****** ** * * *** ** min,gcd;

**** ** ***** * * * ** * * **** * &n,&n2);

* ******* **** ** * * ** ***
    {
** *** * *** * ** * ****** * * * ** * * *

*** * ** ** * * *** * ** * * ** * * * ** **** ** ** * *** * ** *
* ** ** * ** ***** * **** {
* ** * * **** * * ** ** * ***** **** * * *** **
***** *** ** * * * * ** ** *** * * **** **** * ** ** *

* ** * * ** ** * * i=1;i<=min;i++)
    {
** *** *** ** *** *** * * * * * ** * ** ***** ** * * * *** * * * *
* *** * **** ***** ** * * * * * * * * * *
****** ** ***** * ** ***** * * * * ** * * * **
*** ** * * *** ******* **
****************** *** * ** *

* * ***** * *** * *** * *** * * * gcd);
return 0;
   }
answered by (-167 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * *****
int main()
{
** * * **** n,j,i,gcd;
* * * **** * * * * * ** * ** *
** ** *** *** *** * ** *** ** *
  {
* * ** * * **** ** * * ** ** **** * ** ** *
** ****** * ** ***** ** * * *** * **** * ****
  }
* * *** ** ** * * * * **
***** *** * *** ***** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
 int a,b;
 int m;
*** * * * * ** * ** *** ** * * *
** ** ** * * *** *** ** * * **** ** * * *** *
****** * * * ** * * *** ** *
    {
******* * * **** **** ** * ** *** **
** ***** * *** * * ** *** * * ** *
* ** * **** *** ** *** **** *** **** ** **** * *

* ** ***** ** ****
* ** ** * * ** * * *** ** % b == 0)
** ** ** * ** ** * * * **** **** *** ** * * * * * ** ***

** ** * * * ** * * * ***** **** ** * **** ****** * *** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * **** *
#include * *

int main()
{
**** ****** * ** * * * n1, n2, i, gcd;

***** **** * **** *** * * * ** * *** &n1, &n2);

* * * * *** ** ** ***** ** i <= n1 ***** * * * i <= n2; ++i)
* * * ** * ** * ** *
* * * * ** * * *** * * ** * * * *** * **** **** * n2%i==0)
**** ** ** * * ** * * * * ** * ** * *** ** * *** ** * ** ** *** = i;
* * * * ** *** ** *

* * ** *** * ***** * gcd);
* ******** ***** * ** * *** 0;
}
answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** ** * * * **
#include * ** *** * **

int main()
{
**** * ** ** * *** n1, n2, i, gcd;

* * ** * *** ** *** * *** ********* * * &n1, &n2);

* * **** * *** * * * * ** *** i <= n1 * * *** i <= n2; ++i)
*** ***** **** * * * * ***
******* ** ***** *** *** ** * * * * * * * * * * * * * *** n2%i==0)
* ** * *** * * * ** * * ******* * * * * ** * * *** *** ** * ** = i;
****** ** * * ** ***

* * * * * * * ** ****** * **** gcd);
** * * *** * *** * * * * 0;
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
* * * ** **
* * * *** ***
int * * *
{
int ***
* *** * ** *** ** * ** ** **
* **
{
*
a=b;
b=r;
}

** ** ** * *
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * * * ******** * *** * * a,b,smaller,i;

**** * * ** * *** * * ** ** ** *** ********

* * * ** * *** * **** * *
* * * * *** * *** * * * * * ** *
** * *** *** ** ****** *
* * ** ** * * *** **** ******* * * * *

* ** ** ****** * ** * *** ** **
* ** ** ** **** ** * ** *** * * * ** ** * **** * * * && b%i==0)
** * ** * ** ******* * * * * ** * *** ** * *

* **** * * *** ** ***** * * * ** *

**** ** ** * ** *** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * ** * * ****** a,b,n;
* ** ** * * * ** * * *** * ** * * * * * * * * * * **
* * * ** * *** *** * (n=a-1;n>1;n--)
** * *** * * *** * * ** * * *
** ** ** ****** **** * ** * * * ** * ***** && b%n==0)
*** *** * * * * * ** * ** **** * * ***
* * * ** ** ** ** * ** *
* * ** *** * * * * ********* * ***** *
*** *** * * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* * * * ***** * * *** * x,y,n,a,b;
* **** **** * ***** * * *** * %2d",&x,&y);

    for (n=x-1;n<x;n--)
    {
*** ** * * ***** *** ***** ***** **** * *
*** ** ** ** * ** *** ******* **** ** * ** * ** (a==0)
* ** * * ** *** ** ** * *** * * * *
**** ** * *** ******* * ** * * * * *** ** * **** * * **
* * ** *** **** * * * ** *** ** ** * *** ***** * *** ******* ** (b==0)
** * *** * * ** * ** ** ** * ** * * * * ****** * ********* ****
* *** *** ***** ** ** * ** * ** * * *** * * **** * ***** * *** *** ** * * ** * ** * *
* * **** * *** * *** * * *** * **** * ** * * *** * * ** **
**** * * * ******* * *** * * * * ***
    }
** * * * * ** * ** *** *** * **
* ** *** **** ** * ** 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
int main()
{

** *** * * * *** ** * *** n,n2;
** ** *** * * * * ** * i;
* ** * *** ** ** * * min,gcd;

** ** **** *** * * * ** ** * *** * &n,&n2);

* **** * * ** *** * ** * *
    {
* ***** * ** *** ****** * *** ** **** * ** ** * *

** * **** ** *** ****** * *** *** * * ** * * * * **** * * ** * ** *
* * ** **** ***** * * *** {
* ** * ***** ** *** * ** *** * ** ** * **
* ** ***** * *** * **** * * * **** * * * **** *** ** ***

** *** * *** ** ** * * * i=1;i<=min;i++)
    {
* ***** ** ** ** ** ** *** ** **** * * * ***** *
**** * * * *** **** *** * *** **
****** * **** ** * *** * * ** * ** * **
* ** **** * * ** *** ** * *
    }

** ****** ** ** ******* ** **** * * * gcd);

***** * * * * *** * ** * * 0;
   }
answered by (-167 points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%d%d", &n,&n2);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:27:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%d", gcd);
     ^~~~~~
prog.c:27:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:27:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 24.2k views
0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 4.4k views
1 like 1 dislike
36 answers
[Exam] asked Nov 15, 2017 in Midterm by thopd (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 11.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users