1 like 0 dislike
18.3k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數),計算其總合。C語言不提供大數資料型態,但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 18.3k views

32 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * *** ****
#include ** ** ** **
char a[100],sum[200],space,i;
int main()
{
***** ** ** * * * * ** * ** **

** ** *** *** *** * * ** * ** * ***** *
** ** ** * * * * * *** ** ** ** *** *** **** * * '){space=i;}
* *** * *

** ** * * * * *** * ** *
* * * *** * ** ** ** * * * * * *** * * *** ** * * * * ** ***
* * * ** * *


**** ***** * **** * ** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
*** * * *
** * * * * ***
**** * * **
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
* * * *** ** ** * ** ** * num1[51],num2[51];
** ** * * * * ** * i,m;
* * * * ****** ** ** arr[51]={0};
* ** * *** *** * ***
* ***** * ** * * * ** *** %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
*** * ** *** * *** * ** * ***** * * ** ** * * * * ***** * ** ** ******
    }
* *** *** ** * ** (i=0;i<(strlen(num2));i++)
* * ** ** * *** * * *
* * * * * ** ***** ** * *** * **** ***** * *** ** ** * * * *** *
** * * ** ** * * * *
* * ***** ** * * ** * ** (i=0;i<=50;i++)
** * * * * * **** * * *
* *** * * ** ** * * ** * **** * ** * *
** * ** * ** *** ** *** * ** **
* ** * * * **** * **** *** *** *** ** * * ** *** * *** * *** * * * * ***** * * *
** * * * * * ** * *** * **** * ******* **** * **** ** * * * * ** * *
* **** * *** * ** * ** * ***** * ** *** *** *
    }
* *** *** ***** * ** * * * * * *
    {
** *** ** ** * * **** ** **** ** *** ** * * * ***
*** * **** ** * ** * * ** * *** * * ** * * ***
** * ** ** ****** * ** ********** ** ** * * ** *** * **** *** *
* * *** ** ** * * ***** * * ***** *
* * * ** * *** ** **** ****** * * * * *** ** * *
* * * **** *** * * * * ** **** ** ********* **
**** * **** *** * * ** ** ** ** **** ** * * * ***** * *** ** * ** * ** *
***** ** ** ** * ** * * * * * *** ** * *** * * ** ** **** * * * * ** * * *
* ** * ** *** **** * *** * * * ** * ****** *
    }
* * ** * ** **** * * * * 0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
** * ******** ** * * ** * a[n],b[n];
* ** * ** *** *** *** *** ** * **** *** * ***
** ** **** ** ** * *** ** * ** l1,l2;
* * **** *** **** * * * i=0;
** * ** * ** *** * ** *
*** *** * ** ***** * * ** * **
* * * * * * * **** ** *** * ** *** ** ***
*** * ** *** *** * *** * * * ** *
***** ** * *** ** * **** ** * *



** *** * *** ****** *** * ** * * ** * ** * *** ** ** * *** * * *** * * * * * **** *





*** * * *** * ** ***** * * * ** ***** * ** * *** * *



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
*** ** * *** *** ***** * * a[50];

* ** * ** * * * ** * b[50];

* *** ** * * * ** ** c[51] = {0};

* ** * ** * * * *** * * ** ** * a, b);

* *** ** ********* ** * i = 0;

* * *** * * ***** ** len_a = strlen(a);

* ** * * * ** ** * * len_b = strlen(b);

** * *** ** ** * * * * ***** = 0; i < len_a; i++)
** ** * ** * * ** *****
* * * *** ** * *** ** **** ** ** ** *** = a[len_a - i - 1] - '0';
* * * ** *** ******* **
* ** *** ***** * * * **** * = 0; i < len_b; i++)
******* *** * * * ***** * * *
* * * ** * *** **** * **** * ** ** * += b[len_b - i - 1] - '0';
* ***** * * * * ** **

* * * *** *** * *** = 0; i < 51; i++)
* * * * ** * ***** *
* ** * * * **** * * *** ***** ** * * * * * > 9)
* * * *** * **** ****** * ** ** * ** ***
** *** *** **** ** * ** * ******* ** ** * * * ** * ** ** ** + 1]++;

*** *** * * * * ** ** ** * **** * * * ** * ****** **** *** *** * ** * * %= 10;
* *** * * * ** *** * * **** * ** ** * *
**** * ** ****** **

** * ** * *** nonzero = 0;

* * ** * *** * * * = 50; i > -1; i--)
* **** * ** *******
*** * * * * ** * ****** **** ** *** * * != 0)
* * * * * * * *** * ** *** ** * ** *
* * * * *** * * * * *** *** ** *** ** ** * * * * ** * * ** ** = i;

* * ** ** ******** ** **** *** * * **** ** * * ** ******* *** * * * *
**** * ** * * ** * * * * ******* *** **** **
    }

* ***** **** * ** * ** = nonzero; i > -1; i--)
* * * *** ** *****
** *** * * * **** * ** *** * ** * * **** ** *** * * ** c[i]);
*** ** * *** * * * **
** * * ** ** **** ** ** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

** *** * *** **** ** ** ** ** * ** * ** * ** ***** *** **** ***
    for(i=0;i<strlen(a);i++)
* * * * * **** ** ** ********* * **** * * **
*** * ** **** * ** * ** * ** * * * * * * * ** * * * *** *** *****
* * *** * * ** ** * * * ** ** **** ** *
    for(i=0;i<strlen(b);i++)
* *** **** *** * * * * ** * * * * ** * * * **
* ** ** * ******** * ** * * *** ***** * * ** *** * * * *** ** * * *
* ***** **** ** ** ** *** * ** * *** * * ****
    for(i=0;i<50;i++)
*** **** ** ** ** ** * * ***** * ***
** *** * ** * **** * * ** * * * ** * *** * ** ** * ****** * ** * * *** ** > 9)
** * * * * * ** *** ** ** * * * ** ***** ** ** *** * * * * **** * ** * ** *****
** ** ** * **** * * ** * * * * ** **** ** * ****** **** ** **** *** ** ** * * * *** ***** ** * * * * * **** **
** ** * ** ******* **** * * * ** * * ***** *** * ** ** * * * * *** * ******* * *** *** * **** * ** * *
* * ** * ** * * * *** * * * ** ** *** ** ***** * * *** * ** * * * * * **** *
* *** * *** ****** **** * * ** ** * *** * ** *
    for(e=51;e>0;e--)
* * **** * ** *** *** ****** * * * * *
* ** * * * * **** ** * **** ** * ** * * * * ** *** * * ** * ** != 0)
***** ** * * *** ** *** * * ** ** *** * * * * * **** * ****** ** * *** *** *
* * ** ** * ** ***** * * * * ** * **** * * *** * * ** ****** * ** * ** * ***** ** *** *
* * * * * * **** *** * **** * ** *** *** * * **** *** *** ** **** * *** * * * * ** ** * *** *** *
** **** ** * *** ** * ***** **** ** * * * * * *** * * ** **** ******* *** *** * *
* * *** * * **** *** * * ** **** *
* * * * ** *** * * * * *** * * * ** **** ** ** ** *
    for(i=begin;i>=0;i--)
** * * *** *** * ** *** ** * *****
** * * * ****** ** ** * **** * **** * * * * * ** ***** * * * * * ***** *** * **
** *** * * * * * * * *** ** * ** *
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** *** ** ** ** * i,j,k,l;
* * ***** **** * ****** * ** a[100];
**** ** **** * **** * ** b[100];
* * ** **** ** * **** * * * *** * * * **
***** ** * * * * * * ** * * * * ** * *** && * * * *** ** *
**** ** ** * *** * ***
* * * ** * ***** * **** **** *** * * ** ** ****** * * ** * *
* * *** ** ** ** ** **
***** * ** * ** ** 0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
* ** *** **** * * ** *** * *** ******* * ** * a[50],b[50];
** * * *** * ** **** * * ***** c[51];
* *** * *** ** *** *** * * ** ** * ** n1, n2;
* ** * ** *** * *** ** ** * **** * ** i,j;

* ** * ** ****** * * * * * *** * ***** *******
** ** * * **** *** ** * * ** * ** * * * *

****** ** * * ** ** * * * * * ** ***** ** * * *
       {
* ******** * ** * * *** *** ** **** *** ** *** *** * * *** * * * **** *** * );
* * * * * * * * ********** * * * *

** * ** * * * ** * ****** * ** * * ** *
* **** ****** ** *** * * **** * *** * ****
* * * ********* * * ** * *** * ** * ** ******* * *** * * * * * * * * ***** b[i]);
** * * * * * *** ** * ** * * ** *



*** **** *** * ** * **** *** * ** ** * * *****
* * *** *** * * ** * * * *** * *
* ** * ** *** ******* * * * * ** * ** ** **** * *
* ** * ** * **** * **** * *** **** *
* * ********* * * ** *** **** * * **** * **** * ** * *** *
** ***** * *** * * ** * * ** *** *
** * ** ***** * ***** ********** **** * * *** ** ***** * ** *** * *
* * ***** ** ** *** * * *** *** *

* ** ** * * * * * ** ****** * *** * *** *** * * * *
*** ** * * * *** *** * ** ** *** *
*** * * **** *** * **** *** *** **** ***** * * * ** * ** ****
** *** ***** ** * **** ** ** *** * * ** * *** * * * ** * *
       }

* ** * * * * ** ** ***** **** *** * ** * **
       {
* * ** *** ****** * * ****** *** *** ** ** * * ** **** *
       }

* ** * **** * *** ** ** * * **
** ** * ** ****** * ** **** * * * * *
***** * ** * * * * * * * ** **** * *** *** *** * * * ** ** * * * ** ** *** ** ** *
* * *** ** * * * *** ** **** * * * *


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
0 like 0 dislike
Hidden content!
#include * ****** ***
#include ** **
#include ** **** ** *
int main ()
{
* * ** * * ** * i,n,m,c=0;
* ** ** ** ** ** * * A[60]={0};
* ** ******* * **** ** * * *** ** * *
* ** * ** * * ** * ** * ("%s ** ** * *
**** *** * ** *** ****** * * * ** ****** * * * ** **
** ** * * ** * * * 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
**** * *** ** * * * ** ***** **** * *** ** ** *
    }

**** ** ***** ** * ** ** * ** * * ** * * * * a);
* * ****** ** * * ** * ****** * b);

    for(;;) {
*** ** **** * *** * * ** *** ***** * ** *** * * * **** *** {
*** *** ** * ** * ** ** ***** ** * * * * *** ** * * ** * ** **** *
* * ** * ** * ** **** ** ****** * **** * * * * ** **** *
** * ** ** *** ***** * ** * ** ****** * * *** * ** ** * *********
* ** * ** * ** * * * * * * * * * * * * **
** * ** ***** * ** **** ** ** *** * ***** * * ** * * ** ** {
* * ** * ** ** * * **** * ** * * *** * *** * *** **** ** * *** **
** * ****** *** * * * * ** * * * ** ** **
    }

    for(;;) {
* *** ******* ** * ** * *** ** * * * *** * {
* ** * * * * ** * *** ** *** * *** ** ** * * * * * ****** ** * * *** *** *
*** * * * ** ** * ** ** *** ** * ** ** ** **** ** ** **** **** * ** *** **
* * * ** ** ** * ****** ** **** ******* * * ** * ** ** ** * ** * ** **
**** ** ****** ** ****** * * ** ** * ** *
* * * * ** **** * ***** ** ** * ** ** ** *** * ** *** * {
** *** ** * *** ** * *** * * * * * * **** ** * *** ** * * *
** ******* *** *** ** *********** ********** * *
    }

* * *** ** * ** * * **** ** * * {
*** ***** * * ***** * ** * ** * ** * *** ******* * * * && a[i]<=57) {
* * * * * ** ******* * ** **** ** ** * **** *** * * * * ****** * *
* * * * ****** * * ** * *** ** * *
*** * * * * * *** ** * * * ** ** ** ** * * ** * * * ** && b[i]<=57) {
** * ** *** * * *** * *********** * ** ****** * *** *** ** ****** * * * **
* ** ** ** * ** * ** *** * * ** **** **
    }

    for(j=50;j>0;j--) {
*** * ****** * ** * * ** *** ** * ** ** * ** * * * **** * * * ** {
** ** **** * ** * * *** * *** ** * **** * * * * * ** * * *
*** * * *** * ** **** ** ** * *** * * * * * **
* **** **** ***** * * *** *** ** ** * * ***** if(sum[j]+a[j]+b[j]==10) {
** * *** ** * * * * ** * **** * * *** * ** * * * * * * * * * **** * *
** *** * ** * * * * * ** * **** ** * * ** * * ** ** * ** * * ** * *
* * ** * * **** * * ** * ** ** *** **** ****
* * * * * **** *** ** ***** * *** ***** * if(sum[j]+a[j]+b[j]>10) {
*** ** ** ** ** * * * **** **** ** * *** **** * ** *** ** *** ** ****** *
* *** * ** * ***** ** * ****** * * * ***** * ***** * * * * * * *
* *** * * * *** ** *** * ** **** ** * *
    }

    for(j=0;j<50;j++) {
* ** ****** ** **** * * ** *** ** ******* * ** * * {
* ** * * ** ** * * * * *** * * * *** ** * * ** * * * ** ***
** ******** * *** ** *** * *** ** ** * * ***
    }

    for(;j<=49;j++) {
* * * * **** **** *** * *** * ********** * * ** ** * * * * * * ** sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15.5k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 14.7k views
1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 17k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.7k views
0 like 0 dislike
8 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users