Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] đã hỏi trong Final Exam
ID: 42300 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn
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trả lời bởi (-286 điểm)
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Case 1: Wrong output
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trả lời bởi (-168 điểm)
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trả lời bởi (-329 điểm)
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
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trả lời bởi (-285 điểm)
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Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
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#include<stdio.h>
#include<string.h>

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trả lời bởi (-301 điểm)
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trả lời bởi (-229 điểm)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


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trả lời bởi (-193 điểm)
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0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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{
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trả lời bởi (-32 điểm)
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

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   *   *** **  **     *  ** * *******   * *  *     *  *  * *** *  * *** ** * **   **
* **  * *** * *       ************  ***  *    * * * ** *   ****  *  **** *** ** * * 
* *    ** **    *  ***  * **** **  ** *****   *  *
  **  ** *  *  * * * ******   ***  * * **** * *  ***** *  ***    {
**  **     *** * *** *   * **      * * *   **** *  *  ***  *** *** **  **  ** * *  *     
*   * *  *    ** * *  **    **** *  *** *  *   * *   
    }

    for(;;) {
   **** * *** *    **** * ** *****   ***  *  ** ***** * *    ** ** * *** *  {
 ** ***   ***  * *  * ****  *** *   ** ** * *     *****  *   ***     *      * * *  **  **** ** *
 ******   ** ****    * *** *  ***            *******   * *** *  *     *  *  *  **** 
  **** *** * **** *   * *   ***  *** ***    *  ** **  * ** *** * *****  * *   ***   *  *** * 
** *   * *   ** **   *   * *** *    *** * *  * *****  
** *** ** *  **   *  ****  *  **   ** * * **  *  * *  * * *    ** {
     ** ***   * **  *  *    ***** * *********  * *** ** *    ***  ****     *
 ******   ***   ** ***** *** * ** **  *****  *****
    }

* *** ****  * *  * * *  ** * **  * ** ****  {
 **  *  **    **     ****** * *   ***  *   ** *  *     * ****    *  * && a[i]<=57) {
  *** *  * **  *      ****     *** * * * *    ** **    *  * * *   ** *   *******     *** **** *  
 * **  **   ****  *** *   ** ** *  **  ****   *     
 ***   *  *  * *        * **  ***  ** ** *  * **** *  * **   **  * *  && b[i]<=57) {
**** * ***      ** *  ******   * *   *    ***  **  *  *  **    *    * ***  *   * ***  * **    *   *   * *
 *****      *  ** ** ** ***  * ** ** ******** *   * ** 
    }

    for(j=50;j>0;j--) {
    * * *** *  *  * *   *  * *  ****  * * * * *   ** ** *   * ***** *** *   ** {
**  * *     *   *     * ** *  **** ***  *     * ** ******* *  *****  **  *** * * **** ****
  **** ** * *  **  *    ****  * * * ** *  *   *  *
 ** ** *   *  *   *    **     * *     **  *      **        if(sum[j]+a[j]+b[j]==10) {
   *  * *   ** *****  * *  **    **  *  **** *  **   *     **    * **  *      ** *   ********* **  ***   
**  * ***** *   * *     * ** * **   *  **    ** **  *  **  *    **    **  ** **  ** **   * * ***  
 ** **  ***** **** * ***   *    *** *   *  *** **  *   **
*  *   *** *** * *    ****   ** **  *  ***   ***  * * *     **  if(sum[j]+a[j]+b[j]>10) {
   * **  *  ****** *    *   **  *     *     * ** * *  * *** *****  * ***  *********  * *  *      *    *  * * **
     ******* **   *  ***   *** **       **  ** **** * *   * **    ***    ******  
*  **  * *  *** * **** * *** *******   * ********* 
    }

    for(j=0;j<50;j++) {
** *  ****** * ***  *  ******* *   * ***   ***  * {
***   **** ***  *  * *   *  ** * ***   * ** * * **   * *    **   ***** ***** * ** * 
 * ****     *** * *   *  ****  **** *   * * *** *    * ****
    }

    for(;j<=49;j++) {
*  **   *  **   *   * * ** *** ****** *  *   *  ***  * * *   *  *     sum[j]);
    }
}
trả lời bởi (-120 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
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