Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] đã hỏi trong Final Exam
ID: 42300 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn
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trả lời bởi (-286 điểm)
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trả lời bởi (-32 điểm)
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trả lời bởi (-168 điểm)
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trả lời bởi (-329 điểm)
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
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trả lời bởi (-285 điểm)
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#include<stdio.h>
#include<string.h>

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trả lời bởi (-301 điểm)
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trả lời bởi (-229 điểm)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


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trả lời bởi (-193 điểm)
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prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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Hidden content!
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{
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trả lời bởi (-32 điểm)
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
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**  * ***   * **  * * * ** *  *  *  ** ** ***  *   *  *   *****    **  * * **** *   *   
*   ** *  * *    **    *****   ** ** ****  *  ** * * **
*** **  ** *** *   ***   *     *  *  ** * ***  ** ****  **** * {
         **  **   ** ** * *** *** * ****         * * **     *   * *   ***  *****    **
*   *** **  * **  *   * * *   **   ** * * *** ***  *  
    }

    for(;;) {
****  *      *  **   *******   * ******  ******** *  **** *       *   {
 *  * ** *      *   *   ***  **   **  ***  ****************     * ***  *    *****   *  ** *  ** *  
  ***  ***  ** ****  ******* *  *      * *  **** * * *  * ***   * **   *       *  *  *  *
*   ***   ***   * ****  **    **  **    *   * *    **  * ** * **   *****  *   *   ** *****
   *******     * * *******    ***** ****  ** 
* *  ** **** *   ** ** *  ***   *     **   *        *** ** *  * {
**  **            **     *  * *     * *     **** *   ***** **   * **  * * *   ** ***  * *** 
**  *  *** ** * *   ** ***  ** * ******  ****    * **** 
    }

 *** ******** * *   * * * * ***   * *  **    * {
** ***** *   *******   ***  *  * *        **  **  ****** ***   *   ***  && a[i]<=57) {
**  ** ***** **  ** ** *  ***   ***  * *****    **   *    **** * ***  * ***     ** *
****  *      *  **     * *   * ***   * *****  *         **    *
 ***  * ****    * ***  *   ***** * ** ******  ** *    * ** *  ** ******* && b[i]<=57) {
 *      *** * ***         *** *  *    ** *    *   **      *     ***** * * *   * ****   *
**  * ***  ** * ***** ****   ** * * * * **  ***   **  * *** *
    }

    for(j=50;j>0;j--) {
**    *  *  *   * **  *   *** *  ***    **   ** *****   **  * ***** *  ** {
***  ***** *****     *  ** * *  **   ****  **  **   *** ***** **   ****** * * ** * * *     *** 
 ** ***   * * *  *  *  * *  *** ** *   * * * *  *** 
* **   * * * *     * ***** **  ** * *   ** * ** **  *  ** if(sum[j]+a[j]+b[j]==10) {
*  * ****  *** *   ***  ***  * *   * *** ****  * *** * * **** * ** **** ** * ** **   *** *** * *   *
  *  ****  ** **  ****  *   ****   **      **  *** **   **    *** **   *  * * *   *** **  *   
* * * *****  ** *   * **   * *  * **    *  * *  *  
 ***  *   * ***** * *  *** **** * *  *****  *    *  * if(sum[j]+a[j]+b[j]>10) {
** * *  *  **     * *  ** * ** *   * * ** ***   ******   ***  ** *  ** ****  ** * ***  ******    * 
  *** * *  *  * * *  * * ** * * ***** **   **** **  **     *** ***** * * * ** ** ****  ***       **
* *  *   * ***  *** *  ***   *** **       * *  * *  
    }

    for(j=0;j<50;j++) {
**    *** ***  ** **  *  * ** *  ***   * * * ** * * *    *  * * *** {
***    * **  ** * *** *   **** *** **  * ** *** *** *********     *****   ***** ***
  * *** * *  ****** *  ***** ***   * *  **     *  ****
    }

    for(;j<=49;j++) {
   **  **   **** ************ * * ***** * **  * * * **   *  ***** *** ** sum[j]);
    }
}
trả lời bởi (-120 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
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