Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] đã hỏi trong Final Exam
ID: 42300 - Xem được từ: 2018-01-17 14:00 - Hiệu lực đến: Không giới hạn
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trả lời bởi (-168 điểm)
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trả lời bởi (-329 điểm)
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
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trả lời bởi (-285 điểm)
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#include<stdio.h>
#include<string.h>

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trả lời bởi (-301 điểm)
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trả lời bởi (-229 điểm)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
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trả lời bởi (-193 điểm)
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prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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Hidden content!
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int main ()
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}
trả lời bởi (-32 điểm)
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
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* **    ** * * **      **      *    * ** **  **   *   *      **** *  *  * ****   *     ** ***
**        ***  * * **  ** * * **  ********* ** * *  *** * *  *  ***  *  *  **  * **
*  **  ****** *    ****** *  *    *  *** *  **   
 *    **  ** *****  ** *** **** *     *********   * ***   *        *      {
 *  ***       ***    * **  *******   ****  *   ****** *    *   **   ** * *    *
   * *   ** * ** *    **  * **  ** * *    ***** *** * 
    }

    for(;;) {
 * **** **   *    **** * *   ***     *  ***   ** * *  *** * * ***** * *    {
*******  *  * *  * * *   **     *   **** * ** **** *  * *  *****  *** * *   *  **  * *  *
 * *   *   *     ****     *   *  ** *** *   ** ** *** ****** ** * **** * **  **  **** *  **** **
 *  * *   *     *  **     **   **  **********  *   ** ***   **** *  *     *** **  *  ** ****
 * *****  ****** *     * * * ****** ***  * *  *** 
 * *  *  * *  * ** *  *   * ****  *  **** *** * * **  *   {
   * * ********   *** * * ******* ****    ****     **  * **  ***   ** * **     ***** 
 *  ******     * *      *****   *** ** * **  * *  * ** *  
    }

*** ***          ** *****  * *******   * {
**   **  *  ***    **   *   *  *   *   * * *** *** ** **     *     && a[i]<=57) {
**  *  **   *   *  * *****    ********* *  ** * ***      *** ** **  **   ****  *********** ***  
  *  *   *** ***  * ***  * ***    * *    *   *** * *
  ** ** ******* ****  ** *   * *  * * * **     **   ***  ****   ** * && b[i]<=57) {
**    * *** * *  *  *     **** ** *   * ***       * * **  ****  ** *  * *   * *   * * *  * ***
 * *  *** ** * *   **   ** *    * ****  *** *  ***
    }

    for(j=50;j>0;j--) {
*** * ******* *  * ***  ** *  ******** *    ***** ** ** *  ** *     *** ** * ** {
     *  ** ********     ***   *** *  *  ***  *** *      ***** ***** * * *  * * ** *   *  ** **
*** ***   ** ** * *  **  * * **** *     * * ** *  * ** 
   * * *    **   *  ****  ***  ** ***    ***** * *** * if(sum[j]+a[j]+b[j]==10) {
  ***** **  *   ** **** *****  *******  *  ***** *  *** * ***    ****  ** * **** *   *    *  *  
   ***    **    **   ** **   * * *     *   *   * **  *  * ** **  * *   * **  ** * **  ** *
 ***** *   * ****  ****   * * *** *  ** * **    *** **   
 *** * *   *  **   * ** *    *** *      ** *       *    *      if(sum[j]+a[j]+b[j]>10) {
  *** *   **  *  *  *  ***     **    *  * * ** *  * **   ******* ** *   ******** **  *  **
*  ** * *  *** ** ** *** *** * *   ** *******         ** *  * ** ** * ** * *  **  ** **   **
* * *  ***  * *   * *** ** ***   * *    * * * ** * * * * * 
    }

    for(j=0;j<50;j++) {
 **    **  *    **  *   * ****  *  ****  ** * *    *  * **  {
    * *   **    * * **  ***** * *  *  **  ** ***  *     ******* *   ****** ****  *** *   **
**  ** ** ******   ***  * **** *  ***  *      *  **  
    }

    for(;j<=49;j++) {
 *   * ****** * * ******* ** *   **     *  ***  * *  ****  ** *** **  ***** sum[j]);
    }
}
trả lời bởi (-120 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
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