Final Exam 3 (20%)

1 like 0 dislike
10.6k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 10.6k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **  *  ***  ** *
#include  ** * ** *** *
char a[100],sum[200],space,i;
int main()
{
 *  *   *   * * **** *** ** *  *  **  * 

*  *    *   *   * * **  ** **   **           ** **  
  *  *** ** **  *      ***  *** * **  *** ******** * **   '){space=i;}
***** **    * * ***  *  **

      ******  ***  *    **  *  *  *     **    
     ******  *   * **  * *** * * *** * ** *** * ** * *** ** * *    * *  
***    ** * ** *  ** ****   * 


* *  **       * ** ** *  *  ** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**** * **  ** * *  ***
* *  *     *    **  **  
 ****  ** ** *  * ***
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
  * ** ** **      ****   **   num1[51],num2[51];
****   **   *     **    *****  i,m;
*   **** * *   ** ***  arr[51]={0};
 ** ** ***  * **** * ** * * 
  * * *  * ** *****   *  * **     *  ***   *   %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
*  * ***      **  ********** ** *   * * ** **  *   **** * * *  *  *   ******  **** *  * 
    }
*** *    *  * ** * *** *       * *   (i=0;i<(strlen(num2));i++)
**  ****   ****  *     *  * *
 * *** * ** * ****  *  *   *** *   *  *  *** *   **  **  **** * * * *** ***   ******  
 *** ** *     *** ** *** *     
** ** **  *  *  **** *   ***  *  (i=0;i<=50;i++)
  * *  *** **** *** 
 ***  **  ** **     ** *     **    *  ** *  *     *  
*** ****  *      ***    **   ** *       **  *  *   ***
** *    **  * ** ****  **** *** *  * * ********  ** *  **   *   * **  ** *  * *   * *  
 **  *   *****    ****** *** * ** *  *   **** ** ****  *     *   **   ***  **  *  ** 
**  * ******     *   *  ****   *** * ***   *** ***** * ***     
    }
 **    * *  *** ***       *   *    *    ***
    {
 ** * *  ** ****  **  ***  * ***** * **** * **** ***   *  *  
 *    ** * *    *** * ***  *  * *****   **    * * **  **
***      ** **  ** *   **    * ****   *** ****   * *  *  **  * ***      ***  * ** * ** **
  ** *  * * * ***  *   * *      ** *****  **  * * ***
**     * *  *** * ** ****** *   *** * * **   * *** *   *      * ***   *   
*  * *  *   ***  *  *  *  ** * *  ***     * ***** **
*** **   * ***** * *  *     *    ** *  *       *  *  * ***   *  **  ** ** ** * * *  *** * *** 
***       **   ** * *  * ** *       **** **    **  ****    ***** **  **   *    ** ** * * **       *** *  
**  * *  * * ****   **  *  *  ** *** *  *** 
    }
***   *  ****  * **** **   * ** **     0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
 ******** *  *       **   a[n],b[n];
  *  *   *       ** * *     ** * **   ***  * ** **
    ***** *** *    *  *  **      l1,l2;
 ***** ** ** *  ****         i=0;
 ****   ****       * * *    ** *  **  **
  *   ** * *   *  * *** ***    **   *
** *   *  *** **** *  ***  * *   ****   ** ****
**   ** * ** *   *  *****    **  * * **  ** ** * *
   * * * * **  **  ***** **   *       * ****  



** * **  **  **    ****      *   *** *  * ***** *  ** *    * *        * **  * *****     * * ***    *** * *   * ** * *****  ** *





  * * ***   *   *   * ****** ***  ***** *** *   ** *



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
   *  **   *  *********   * a[50];

*  **   ****  *** **    * * **  b[50];

  * * ** **    *** *  * * * * c[51] = {0};

    * *  * **** **  *  * * **   * * ***  a, b);

 ** **   **   *****   * ** i = 0;

* ***  * *  **  ** **** *        len_a = strlen(a);

  *  *   * **  *  * ** * len_b = strlen(b);

* * *     *    *  *   *** = 0; i < len_a; i++)
*   ***   **  *  **** *   *** 
*****  *** * *  *  * * * **  ***  * * ** ***    **  **** = a[len_a - i - 1] - '0';
 **   ** **  ** * * *** * *
      *       ****   **     *** = 0; i < len_b; i++)
**     * * *   *** ***** *** ***
  * * *   ******     ***    *** *  ** **  **    *  *  ***    += b[len_b - i - 1] - '0';
*  * **  * * ***  *   *  

  ** ** *     * ** * **  ** ***** = 0; i < 51; i++)
**** *  **  ***** **  *  * 
* ** * * *   ** *****  * ***   **   ** **  ***  * **  * ** *  *  > 9)
 ***   ** **       *  ***** **  **   *** **  **   *  ***  * 
 *   * **    * **     ******  ****** *  ***   *    ******* ***          ******* *    * + 1]++;

    ***     **    **** *** **  * *** * **   ** * ****   * **  ***   *****   ****    %= 10;
***  *  ********* *  ***   ** * ****       *** **  
* * * *      **       ***** 

 *****  *  * ******     **  ** **  nonzero = 0;

  * * *  *  *  * ****** ** ** = 50; i > -1; i--)
 * ** *   * **** * *   * *  
**       *    **      ***  *  *   * **  ** **  **  **** ***  != 0)
  ** * *** **  *  *  *** ***  *** *        *  * 
****  *    ***   *** * *  * **  ****  ******  *** *     *     *  ***  ** ** *  * * = i;

*   *  ******  *  *  * * * * ***   ** * *  * ** ** ** *** * ***  ***** *     ***    
 *    * * **  * *  ** * **  * ** **   ** * *  *  *
    }

 ******* **  *      *    ** ** = nonzero; i > -1; i--)
**  ** *** ***  * ** ****  **
** ***     * *** * * *   *  ***  *** *  *     *    ** * *  **   **  ** * c[i]);
***     ** **  * ** * **** 
*  * ***** **** *  *    * * ***     0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

  *   ****** *** * * * **** **   * *  *  *  **   ********  *    *** ** *** **  **
    for(i=0;i<strlen(a);i++)
 *** *  * ****  * **   *** *  *  **    **  * ** **   
*** * ** *           *** * *****   **  * *  *   ******* ***  ***  * **   *  *  *  *** ***   **  *
   ** *****    **     ***** ** *  *  *   * * *****   *
    for(i=0;i<strlen(b);i++)
  * **** *** *  *** *** *  ***** ** * * *  ** ** ***   **
*  *  * *** ** ** **      **  * *  *****    *    ******  *  ** ** *  * ******  
 ***  *** **   ********  * *  * ** ***  **  * *   * * 
    for(i=0;i<50;i++)
 ***  **  *    **      **  ***  * **  * **     **** **
*  * **  * ***  * ***       * ***   *** *    *** * **  ***  *** * * ** *     **  *    *   *** > 9)
 ** * *    * ** *      * ** *** * *    * **  ** *******     *   **     ***** ***   **  ** ******     **    * * * ***
* ****   ***  ****   *  **  *  ** ***   **   ** * **   *   *   *   **  **     * * *    *  *  * ***   **  *  * **  **   **   **   ***  *** **  **        * 
 * *   *********        *  ***** * * *   ** *  ***** * ****   * * ** ***   * *   **** ** *   * **   *** *  ** * *** ** **       * * *    *    * 
* ****  * *        *    ***  *   * **** ****  *** *    * **  ***  *  ****  ****   * * *******   *   * ***    ****
  * **** **      *  **** *  * *   ****     **  ***  **     ******
    for(e=51;e>0;e--)
*     **   *****  *** * *       ** **  **  *****
*** ***  *   *  *** *****      **  * **  * ****   * *******  *** *  *  ** * **  *** * != 0)
 * ** * *    *** *****   ***     *  ****  **   * ** ***   **    ***  * ** ***********    *** ******   *  * ** *  **    *
          ****   *  ******   **        * *  **   ***      * *  *   ***  * *** ****   ***   ** ***  **  *  * ** * *  * ** *     ******** *
**  ** *  *****       ***** **  *     **** ***** ** **** ** * *  * ** *  * **    * **  *** **** * ***  * *   *** **** * **  * **      *  
** **  * ******    *** *   *  ***    *   *****  * *  *  **  *  **** * ** *  *** * ** * * ****  *** ****  * 
**   * ***  **    *     *  *      ***  **** *  **   **
***  *  *    *** *    *   *  ** *  *****  *** **  **     * ******   *** **** 
    for(i=begin;i>=0;i--)
***  * *** **   * * **  * *** *  *  ********  * * **** **
  **** *  *          *  * *** *  *   *    *     *** **      ****  * *   *   ***  ** ****** **** *  * *  * ** 
***   * * **  **   **  *  * **  ****     * *** * *  ****
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 *  **  **** *     * **** ** i,j,k,l;
   ** **  *   * * * ****** ** a[100];
  **          *  **  ************ b[100];
*  ***** **  * ** *   * ** ** *  *  *  * *  ****** ** **   
   **         ********  * * ****     * ******   ***    &&   *   ****  **** *  * 
*  * ****** * **  ***   * **
****       *   *  ****** ** ** **  ***** **** *  **    * ***  ** ***  *  ** ** *   * ***  ** *
 ** ***   * **   *    ** * *
**    * **  * ***  **      **  * 0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
 *  * ***     *** **  ** * * *** ****  *** a[50],b[50];
    **   *  ******       ***  * *  * * *  ** ******  c[51];
** ***  * *  ***    **** * **** * * *  ** *** *  n1, n2;
  ****** *** *   *  *    * ** *** **** ***  i,j;

*********     *  *   ** * ** *  *  * *** **   ***    ** **   
*  * ** ***  ****  ***   *** *    **  *  **** * * **  **

   **** **  * *    *** * *    ** ***   **  * * * ** *******  *  *
       {
  * * **  **  *** * * * *  * * *    *******  ***  ** *  ****  **     ***     *   **     * **** * );
*  **  **  * *  ** * **   **   *     * ** 

 *  *    *  *  * ** *   ** *****     ***   **  *** ** *     **
  **  ** * ** **** * **   ****  * ****   *  ** * 
    * ********  **   ** * ******** ****** * *  *  **     * ** ** **********  * *   *******   * * *     b[i]);
***   *      *** *  *  *** *** ** * ** * ***  ** * ****



*  * *** *       ***  *    * *****  * ***   **        ******  *  *
* * *   * *   ** ** ** *  **** **   ** ***** ***  *
    *   ******  ***  *   * * *****  *  ** ***** *     *  *** * * *   *   ** *     *** * ** ******
   *  * ** *   **  ****  **  * * *  *  **  **
*  *   *  *** *** ** *** *   ******  *    *  *** **    *   * 
 ****** ***** *  * * * ***   ****  *     * 
*  **   *  * *  *** ******   *  *  * ******   *** ** *  *  * ** *    *****   **   *  ** 
     *  *   * *  ** ***   **     *    ***

**        ****  * ****  *  **  **  *   * * *  ** * ***   ** **   *
 *    ******    **  **   *   *** *   * * * ** 
**    ****   **** *** *   * **       *  * *  *        **    * *    *  ******    *
 * *  * *** *******  *  * *******  * * *  ******* *** * ** *  *  *     *   * * * ** 
       }

* **   **   * * * **  ****     * **    *     *  ** *   ***    *  **
       {
* *  ** *   **  * * **  *   *****   ****  *  *  *  * * *****       * * ** *  **  ******   ** * ** 
       }

*  * * * ***  *** ***  *   **** * *****  ** * ** *     ** ******  * ** **
 **   ** * *****     ***   ***  * * ** *   *** **** ** 
 ** *  * ** *** *******     *** * **  *  * *  * *   **  *  **  **  * ** ** ** **  **   * **    *** 
      ** **  ** * ****    **  * ***  * ** **   *** * * *** ** **


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   **    **** 
#include   * *** *    * **  *  
#include   * *** *** **
int main ()
{
*    *     ****  * ****  **   **   i,n,m,c=0;
**   * * *     * *****  ****** **** A[60]={0};
 *  **  *    **  * *  ** **   * ***   *   * ** 
 * *******  * ** *  **   ("%s *  *   **** *
*** **** **  *  * *  ******   * * * ** ** *** *** ***** *   *  ** * 
 ** ***     ** ****  ** * * ***  **** 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
* *** *  *        *** **  ** **** * * ** *** *  *** *  ** *** * * *
    }

  ***  *** * *  * *   * ** ***  *** a);
 * *  **  ** *****  *  *    ***   *      **** b);

    for(;;) {
  ** * * ****  ** **      *** ** * **  ***  ***  * * ******    * ***   *   {
* ******* *  *****   **** **  ******* * ***  ****  ***** **  * *** **  *   ****   *   * ****
*   * * **      * * * *  *  * *    * * ****** ***  *  **  *   *      * * **** *      **
   ****  ** ***  * **  **   **  ***   * **  *   ***     ** * *    **     **  * *   *  *  * 
*    * ****** *    * * *  * **  * ***** **  ******   ***  
*** *   *  *   *  * ****  * *  *  *   ********   *  *   **  *** * {
*  * *  * * ***  * *** **   * *   * *  ****  **  *****   * ****  * *   * * ** *  * ***
**  * * * * * **  *     *  ** **  **   **     **   *** ***
    }

    for(;;) {
** *  ** *  **   * ****** ** * **** ****    * * * ****** * *** *** {
*** * ***  ** * **  ****** ** *** **    *** *  *  **   *     * *  *  * *** **  *****  
** ***  * ** ** * ** * **    *   ****   * ************ * ** * *  ***  * * *** ***  *
**  * ****         * **   * * ***  *   *  ***   * *  * * *    * ** * ** ** * * * ****  ****
 * *** ***  *  *   *** **          *  **    **  * *** ** * 
 *      ****** **      **  * * * ** * **** ****     * * * * {
  * *  * * * *   *** *   **** * * *****  *****     * ****** ** *    **  *  ***      **   
*      **  **  ******* *   ** * * *** *** *** * * **
    }

**** * *   ***    ** *** ** ** ** *   *   *  * *  {
* ** *** **  ***  **  * *  *  *   ***  *  ****     *   *    *      **  && a[i]<=57) {
  * * ***** ** *   * **     **    * ** ** *  **** ** *   *    * *    **   **** *   *  **** 
*  **   *  *   *   * ****** *****  * * * ******* ** 
 * * * ******   ** ***     *   *** * **    ** * ** ****  ** *   && b[i]<=57) {
** **  *  ** ** ** *     ***  ****** * **  *   * *** *  * **  *  * * **  ** ** * **  ***
 ** *   ** * **  * **** **  *  * * ****  * **** *  * *
    }

    for(j=50;j>0;j--) {
   *   *  **** * **  ****  * *   **  **  **   *** ***          ** * {
  **    ****  * ***   * **    *   *       ** *  **** * **  *      ***      **  ** **  * * ** **
 * *** ***     ** *  ** **   ****  ******  ** *  *  
  * *  *     *********** ********    ** * ***  *** **   *  *   if(sum[j]+a[j]+b[j]==10) {
  * **  * *  **   * ** ** * ** *  * **     *    ** ***     *  * **   **  ** *** * **** **** *****
**  *   * ** ****** * *     * ** ** ** **  ** *  **  ** *** * *  * ****  ****  ** ** **  ***
     ****   **  *  *  **  *  *** ****  * *   *  * *   *  ** *
* * **  ***   ** *  *     *     *   *  * * *  ** * *** if(sum[j]+a[j]+b[j]>10) {
*** ** *  * **  * ** * * **   *      *   *  *****   * *  ***  **  * * **  *  * **   * * ** ** *  ***** 
 * *** * * **       ** ******  * ******* *  * *** * * *** *      * *   *    ** *
 *** ******  ***    *     * * * *   **  ***** * *******
    }

    for(j=0;j<50;j++) {
 **     **   **     *** *      ** **  ***   *      * * *  ** ***** ** {
  * * *** **    * ******   *  * *  **      ***   * * *     *  ** *** **  ***  **  *
*** **** ****  **     ***  **** * * ******   **     *
    }

    for(;j<=49;j++) {
 * *   * *    *   *  *  *** *** *   ** *** **  *     * *  **  ****  * * ****  sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.160
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.5k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 9.2k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.2k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 8.2k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users