Final Exam 3 (20%)

1 like 0 dislike
11.7k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 11.7k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** ** **  *  **** *
#include   ** **  * ***** 
char a[100],sum[200],space,i;
int main()
{
 ** *****  * *** **      ***  **  * **  **   

*        *  ** ** *   *   *** *     * ** **  ** *    
  *****  * * * * * * **     *    *  *******  * ****  * *  *      * '){space=i;}
***  *** *  *** *  * ******  *** 

***** *  *     ** * * * * *  *  **  ****   *
  **** * ***   **   *  *  *  * **  * *   ** **      *** *   *   * ***   ******
*  * *  * ** *    * **  *    *    


 **   **   ***  ** *****    *   0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * **    *   * * * *** *  
*    *                  
 *  ** **** ****   * * *
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
 ** *** * ******* * * ***   **  num1[51],num2[51];
* * * **   ** *      **  *  i,m;
** ***  ***    *** * ** ** *   arr[51]={0};
* **  * *  ** ****  **   ** 
* ** * **    *** *       *   **  *  ****  %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
* **** *   *  **  ******  **  **  ***** **   *  *  *  *** ******     *   * *       *  **
    }
 **  *** * *     * **** * ***  (i=0;i<(strlen(num2));i++)
 *   * ***   * * * * **   * * *  
    * **** ***** ***  **  * *  *  *  **  * ****  * *   * *    *    ***  ** * *   *   
** **** **** *     * *****  ** **
* ***** * *      * * ***  (i=0;i<=50;i++)
** **  ** * ******* ***  *
 **  * ** *   ***  **  *  **  * **   ****  *** ** ***  * ** ****  
* **   *   *    **    * * * **  ***** **** **  ****  *  **   
*  *  **  * **  **  *  ***  **** *  ***  ***  **       ***  * *   ** *********** *   ** *  
*  **    * *   * ***** * **** *** *  **  * ***    ** *  *  ***   **   * ****  *   *****  ****  *  ** 
 **   * *  *  **   ***   **  ** *         **   ** * *
    }
 *    * * **** * *      * ** ***  **  *** *** 
    {
**   ** **** *** * *     * * *    *    * **** ***  * * 
 * ****  * * **  *   ***** *** * * **   ** *  **** *    
 ** ***  *  *** **** * ** ***  ** *  ****   **  ** ***    * ******** **** * ** ** **  * *
* **   **  *** ** *** *****   **** *   * **** ** * ***   * *
    ****  *  **   * **      ****** * *   * ** ****** ** *  ** ***
* * * **  **** * *  * *    ** ** *****  **   * ** *  **
* ****  *****  **    ** *    *  *      *  * * ****   *   ******  ***** ** **  ***** * ****
* ****     ***  *** *** *** * *    ** ** * **  **  *   * **    *** *  **  **       *     **     *   * * ***  
  **      * ** ** *  * * *  *  *  **** *  * *    *
    }
 *  **     *****   **   *****   * 0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
* *  ***   *     **** * *    * a[n],b[n];
 *** *     *  *   ***  * * **** * * * ** ** ** *  *
 * * * **  ***   *  * ** **  l1,l2;
**   * *   * *   *  * ** ** i=0;
***  * **     ** * * * * *  *
    *  *   * ***  **  * * *   *
* *  *   *     ** *** * **** * *  *  ******  * * **  * 
****** *   * **   ** ***  ** ***** **  * * * *** *    
*       * *  * * * ****  *  *     **   * * *    **   ** 



 **** *   ** * ** *   * *  *** ***  ****  *   **  *  * *    **    *    **  * *  *   ****    * ** * * ** * ** 





  ****  *   **     *    * *  **      *** **   **   *****



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
     **** *   ***   *  * * * * ** * a[50];

 ****** ** *** *   *      ****  b[50];

    *  ***** *        ***  *  c[51] = {0};

 *** ** ** ** **** * *    *      * ******* ** ***   a, b);

* ****     ***  *  ** **** ** i = 0;

** ** **          * **   *** len_a = strlen(a);

  * * * **  *   * * * **    ** len_b = strlen(b);

** **  **** * ** ** *  *  * *     = 0; i < len_a; i++)
  *  *   *** ** * **** ****  
* * ***  *   *  * * *** **     * * *   * *** * * = a[len_a - i - 1] - '0';
     *** ** * **   * *** 
** ****   *  *   * * * *** *** *  = 0; i < len_b; i++)
 **  * *  *    *
*   **   ** *   *  ****  ***   ****  * * ***  ** **   **   * += b[len_b - i - 1] - '0';
*   **  *   * *** ****  *  *

  *   **   * **  * ****  = 0; i < 51; i++)
  *** *** *  ** *    **   *  
**  *** ****** * ***** ** ** ****  * *   *  ***  **     *** * > 9)
 *  ****     *  *  ** **** *  *   ** ** * * ***  ***
          * *     *** **  ****** *    ** **  * * ** *** * **   * ******** *  *   **** + 1]++;

 *****      * *    *  **  *  *** ***    * ** ** ** *** *   **** *   * *  ** *  *  * %= 10;
*  ** *   ** ***   ** **   * **   ***   ** * **    *****
********      *** ***********

  ** *   * ******* * * **  **  nonzero = 0;

   ** * **  **    *    * *     * = 50; i > -1; i--)
** *    *  *****  ** ** *
 ****** *    ** *** ****** **  *** * ** **   *   != 0)
* **    *** *   *  *   *  *  * *** * * **  *  * 
 ***  *** *  * **     *** * ***** * ** *****  * **** * ** * *  * *** * * * * *   **  * = i;

 *  *  **   *********  ** *  * *       * * *   *  ****    ** ****  **** *****  ** 
**  * *  ** ** * * * *********** *  *** ** **  * ***   
    }

  * ***    * ** *  ***  * * * = nonzero; i > -1; i--)
****  ** **** ***      * * *
*  * ***  **   ** **  *  *  *         *** **** *** * *     ***  * ***  c[i]);
     *    **  ****  **  *  
        * ** *   **   ** *  * *  0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

  * * *      *** ****    ****** ***      **        **     * *    **** **  * * **
    for(i=0;i<strlen(a);i++)
***    *****  * ** *** ** *  * * ** **     ** ***   *
* *  **     ** *     *  * * *** *   **   **** ** ***  **  **      *   * ***  * * ** ***  **
***  * *** *** *** *    *  ** * *  *******  *** *****   *
    for(i=0;i<strlen(b);i++)
   ******* **** ***   **  ***** ***    *  ** * * *** * 
 ***  *****   *     ** ***   ** * * ** *      * *  *   ***** * * *  * *    ***** ** * * * ** ***
      ** **** **   *  ***** **   *  *** ** *** *****
    for(i=0;i<50;i++)
 *     ****** ***  ***   ***  **   ** ****  ****  ** 
* ** * * ** *** * *   ****   * **** ** *  *   *** ****  ****   * ** * * *    *  ** > 9)
*** *  ** *  ***   * **    * **** *  *    **  *  **   *  * *    *** *** ** **** *  *     *     *  ****   
  **  **  *  ********* ****** **     *  *  *  **  **********  * *  * ** ** ** ***    **   * ***  ***   *  * * ** ** *   ***    *  *    * ** ** ** * 
* * ** * ***   * *          ***   * * *    ** ****  ** **   *****       **  ** * **** * **    * *   **  ***** *** **  *    *  * * *   ** **** *   *
* ********      * **  *  *** *  * **  ***      *** **       * *   ***  **** * * *  *  ****  * *** **** *    * ****
   **** *** * ** **       *  ** *  **** *** **  **    
    for(e=51;e>0;e--)
 *** *   *** ********** *** ****    * ***       * 
***  *    * ** * **   * ** ***   *** *  ****  *  *** *  *****  *   **  ****  ** *** * != 0)
  ** *  *** *  **** *   *  **** *** *  *   * * *  *  *** *    **      *** **  *   *****    ** ********
     **  *    *** * *** *  *  *   * *  * ** **    *** *   *    **** * ** *    ** ***** **   * * * **  * *   ***     * ** ***   * * **** * *  ****      ** 
*****    **  ***  * ** *  * **  *   *  ** * *  ****  ** **** ***   **   * ** ** *              *  ***   ** *     ** *   ** * *  
* * ** ** * *    ****  ****    * *  ***  **   *   * *  *  * * * * ** *  * *    *** * *  ***  **        *
*   **** **  *** *****    *    *   **  *  *  *  *** *
**   *  **   ** * *** * *   ***** * ***  **    * **** ***              **  ** *   
    for(i=begin;i>=0;i--)
** ***     *   ****   * ***** **   *  *   ****** * 
* * *  ** *   *  *** *  *  *  **   ***    *   ** **** * *  *  *  ** *   * * *  * **   * * * *    * ***   
  *   * *   ** *   **  ** ** * ** **** *** *** ***  * * *  ****
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 *  ***  *  *  *   *  **   i,j,k,l;
 *  *   **   ****** * * ** *   a[100];
* *  * ****   **** * * * *     *  b[100];
* ** * *** *****  ** * ***** *   * *  ** ** * *** **
  ** ** *   * **   * ** *    *   *  *  *** **       ** *  &&  **   * ***  * ** * ****
  **  *** * **   **   **** ***
* ** *  * **    ** * * ****  *   * * * **  * ** ** **** ** **      **** *** *  ****     * **
* ** * *** *** ** ** * 
* *  **** * *** ***     *  *   * 0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
** * * * **** **  *  **   **  ** * ***  *    **   a[50],b[50];
 *** *    ****  **   *** **  **  ***   * * **   **  c[51];
 ** **  *    * **        **  **    ** ****      *  **   n1, n2;
 *** * *  *  ***    ****  **** *** * **    * *      * i,j;

   * * *  * **  ******  **** **  * ****** * *    * ***  ** 
*  ** **  *      * * *   *  *** ** ***** * *    * **

  **  ***  ** * ** * *   * ***    *  **  * * ** * ** ***  *  * ***
       {
  *    * ***     *** **** * **  * **  * *   **** ** *    *   ****   ***** **  **   ** ***  * *****    );
*    ** * * * *******  * *  ** **  * *** *    

* **   ** ** *****  * **   * **************   * **     * ***** 
**  * * *    *   * * *  ***  ***      **  **   * * 
**         **       *    ** **  * *    ** **      *  *       *     ** ****    **   b[i]);
*  * **  *  ****   *** ** **   *    ** * * 



 * *****   *  * *  ***   ***   *** * **** **  * * ** ** * * ***    
   **   ***  *    * ** * ***  * *  *****   *  
* *  ** * * ** * ***  *   ** ***  *** **    ** *  *     *   ***   *  *  ** *      *  *** 
*  * *  ***   **  ** ****  **** **   * *   ***  **
 *  ******  ****** *  **    **  ** * ** * ****   **** ***  
***  ******   ***** *  *  ****   *  *  *  ***   *
 **     ** *****   ** *  **   ** * **   ** **   ****    *    ** * **   * *  **  *   
    **    *** *   * * **     *** * **  ***** *** 

    ****   **    *  * ** * *  * ** * ***   *  ** *   ** *  *  **
 **    ** ** * ** **   * * ** *  *      
  ** ** * *  *   *        *******   ** **  ** *** ***   ** * *  *   *  *  **** *** *
    ******  *  * **  ***        ***  ** * *** ******* *  *  *****       * *  * 
       }

 *****  ** *** *    **     ***  * ** * * ****  *   **  ***   * * * *
       {
 *** *** ** *    * * *     ** ** ** **   *  *  *   * * *     **   **   *    ***  **      
       }

  ** *    ***    *** **    * * ******  * ** * *   * *  
** * *   *  * **  ** *  ***** **  *  **   *   * *  * * * ***
*****   ** **   * *   ** ***  *    *   *   * **   * **  **      ***** * ** * ***** ****** ** *** *  ** **
 *** ** ***   ***  ** ** * *  * *   **  *   ***   **


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *  *** *  *  
#include *****  ** **  * 
#include * **   ** **** 
int main ()
{
*****  *       *   **  *  * *  *   * i,n,m,c=0;
** ** ******  ** **** * A[60]={0};
   ** *  ****   * * *    * *  *   * ****  **
   *     *   * *****  ****    ("%s ***** * **  
    *  ** **  ** * *  ***  *      ******** *     *** * *  
*   * **   **   *     *  *     0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
 *   ****  *   * * ** * *** *  *  * *   ***** * * *   * *     **** 
    }

 *           * **   ** ** ****** * **   * * a);
 *  ***** *******   *   *  ** *   **** *** b);

    for(;;) {
* ***  **** **      * ****  **  **** *   *  * * * ***  *   * ***   *  *** {
 ****    *   **    ** * ***** *   ** *  *            **** * * *** * **  * * **** ** * * **  
*  * *** ******  * * * **    * ***   * *** * *** ***** ***   ***     *  * * * *   ** **    *  
** ** *     * **  ** **   **  ** ** * * **   ****  *    *** * *** *** ** *****      * *** *  *
 *   *   ** * ****  ** ***   **  ****  **    ** *** 
* *   * * *   *  **  *** *   *** ** *  *  * * *** *    **   *     {
**   ** *  ** * **** **** *   * **  * *   *** **  *  ******  ***  *  **    *
  *** ***  ***  * * *   * *** **  *    * ***  *****
    }

    for(;;) {
**     *  * *    * *   *** *   **** * * *****  * * * * *  ** *** * *   {
      *  *  * ** ** *  *  * *   ***   **** ***  *  ****   **** *** ****   *****  *
   * ** * * ** * * * *   * * **  *  *  ****  ***  ** ** * * **  ** *  * *        *   *  
******* ****  ** **** **** *******     *  *      ** ** * ** ** *** **    *   *   *    * 
  ***  **  *** ****   ****** * * ** *   ** **     
*    *** ** *** ** *** * * *** * *     ** ***   * ***   * {
** * *   ** *    **** ** **   ** **    * * *   * **  *  ***  ** ** **  *  ** *  ** 
   *****   * * ** ** *     ** **     ***   ******       * *** * *
    }

* *   * * **    ***    ***  ** * *    * * {
   ***    *******  * *        * * *** ***  * * ** ** **  * *  && a[i]<=57) {
* *   *** ***   * *  * *     ** ****  * * * **   **    * ** * **  * *  **    ***  ***  *  *****
*** **** *    *  ***  * ** *****  ***     * *   *** *
* **** **  *    *    * *** ** * * * * ** * **  ** * **   && b[i]<=57) {
****  *  **  **  *  *  ** * *** *     * ** ** **   **  *   * ** ** ****  *   ** *  *  * *
***   *     **  **   * ***   ***  ****** ****  ***   
    }

    for(j=50;j>0;j--) {
 ******  * **** * **** ** ** *****    *     **** *   * ***  *  ** **    {
   **    *   ** *   * **     * * ** *   * * *   *  * ** *  * **  *  **** **    *  * *** *
 * ** * * ***  *  * *    *  * ** **  *  ** *****  
*     *    *     * *     ***  *  * *  ** ***  *** *     * if(sum[j]+a[j]+b[j]==10) {
     ***   *   *  **  ** ** *  **  ** * ** * * *  **   *  **   * ** ** *  * * *  **     **
 ** *  ****  ******** * ** *** ******* *    *******  * ** ** ** **** *  *   ** * **   *  *
*  ***** * * ****   * * * ** ****   ******* *   *   ** 
 * ** **  **   *   *    *   ***  *  *** *****  * * **  if(sum[j]+a[j]+b[j]>10) {
* ** ********* * ** ****   *  **  ***   *  **   *   *** *   * *  *** * *  **    *   ** * * *   *** ****  
     * ** **  ** *** * ***  ***** *  **  * *****   *   *   *** *  * *  *  ** ***
* **   *   **  *  *   * * **       **    **  * 
    }

    for(j=0;j<50;j++) {
  *  *  *   ** * **      ***    ***  **  **    *  *  ** ** * * * *  **** {
* * * **   * **** *  ***  * *** * **  *     ** *  ****   *** ***   *         *  
* ****       *****  *   ***** * ***** * *  *  *    *
    }

    for(;j<=49;j++) {
 * * *   *    ***  ***** ** ***  ***  *** *  ** **  *  * *** ****** * ***  sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.71
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.3k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.2k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.3k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 9.2k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 2.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users