Final Exam 3 (20%)

1 like 0 dislike
18.3k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 18.3k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   * * * *  * ** 
#include **  **  *   * * **
char a[100],sum[200],space,i;
int main()
{
     * * ** *  **    ******  *  * ****** * 

**  *   **  ** ***** *** ****  *** *  * * ***  
 * **** ** *  *** *  * **** * ***  * **** ***      **  * ***** '){space=i;}
* *    * * ** ** * ***  *  

 * ***      * *   * * **  * ** * *** * *     
  *  **  **  **    * **   *   **    **   **  ***     * *  * * * ***   *     *  **** 
* *  *****  *   *****     *  


   * *** * *  *    ** *    ** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  ** **  * ** ********** 
**** * * * ***  ***     **
*  *  * *      ** ****
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
 *     ****** ***  ****   *   * *  num1[51],num2[51];
 *  ***** * *** ** ** ***  * i,m;
    *****  ** * *  *  *  arr[51]={0};
*  *   * **    * ****** * *   
   ** ***  ** ** * *   *   * ** * *  %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
  *      ** ************  *** **  *  *  *  **    *** *  *  ***    **  * ** *    
    }
* * ****  * *  *   *        **** (i=0;i<(strlen(num2));i++)
*    ** *   ** *   * ****   
 ** ******  ******  *        ** * ***   *   ***  *** * * **   * *   **   *  ** **    * 
** **** ***    *  **  * *
  **   ** *  *  *****  *      (i=0;i<=50;i++)
* ** *** * ****  ***   *  
* *   ** *   ****    *   * ***  **  ***    *   *         *** 
*  **    *  *   *      * ***  *  **** *** ** *
**  ** *  *  *  * ******  ** *   ** *  ***   ***** *** * *  *  **  *    * *  *    *******  *     **  
     **  ** *   *****  **   ****  *  *  * ****    *** **    **  ***   ** ***  *  *   ** ****
 **    * * **   *** *    ** * * *    ******  * **  *  **  *
    }
  * * * *   **** ****  ** **      * ** *  *  
    {
  *   **  ** * *   ****   *******   **    *  ** * * ***  **  ** 
* ****   * *       **********  * ****    ** *** ******
*** * **     *******  * ** * ** ***    *** * **  * **  * **** * *   *  ** **  *   *
  **  ** * * **** * ** **    *      * * **** * *   **   
****     *****  * *** * * **  **** *  *** ** *** *  * *  **** **  *
* *   *  **    * ** * * *  * *  ** ** **  ** *     ******
***   **      **  ***  * **** *     ** ** **   ***   * *   ****  *** **   *  **   ** **** *
***** **** ***  * * ***** **** ** *  *   ** *   *    ** *** *       ** **  * ***  * *****   * ** *   **  * **
 ** *  ** *   * ** **** **** **    **      * ***  * *
    }
** ***  *  **  *  **** *****    *   0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
  *****  *  **  * ** ** **  * a[n],b[n];
 *  ** * ** * ** *  * **      *  *    ***   **  *      
  ** ** * ***    *   **** * * ***  l1,l2;
* * * * *        *** **  ****** ** i=0;
*  *   **    *     ***  * *  *  **
* *    *  *  * **      *** * * 
***   *   ** *  * **  *  ** *  * * ***   * **    
**   * *  * *   *** **  * ** *** *    ** * ******** * **
  * *  ***  *    * ** * ***  *****  * *     *   *  ***



***  *     ** ***   * *** **  *  **** *    * *****  ***  ***  * * *  ***      *   *** * ** **** * ** *  ****   * ** *  **    **





  **** * * ** *      ** ** *   * * *  * * * ** * *  *    * **



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
 ****    *    *  * *    **    * a[50];

******* *    **  * ****  b[50];

 **** ***  * ***  ** *  *  c[51] = {0};

*  *   ** ** * * ***  ** **  * *   ****** ** *   a, b);

 **** * * * ** *** *    *      i = 0;

* **   ** ** *  *    *** *** len_a = strlen(a);

  ** **  *    *    *** ** *  ** len_b = strlen(b);

 ** *  *** * **  *    *  * = 0; i < len_a; i++)
  *  ** *      **   **    **  
       * * ** *  ****  ****    *    *** ** *   *      *  = a[len_a - i - 1] - '0';
*****   ***** *  * 
** ***    ***  **       ***   = 0; i < len_b; i++)
   *  * *    *     ****  *
 *   *  ***      *  ****  * *  ** *  * *   * ***    * += b[len_b - i - 1] - '0';
**  ******* *** ***    ***   

  ***** * ***  * *    ** * ** = 0; i < 51; i++)
** ** ** *        ****   * ** 
 ** * * *** **** *****   * ** *   **   *  ****  ** *** > 9)
* * * ** * **   ** *    ** *******  * *  *** *  **** **
** * * * * ** *      ***    **  ** * *** **  **  *  * * * * ****  *** * *  **  ** + 1]++;

* **   *** *** *** *   * * ****   ****  * *       ** *******   *****  * *  ****  %= 10;
 **  *  *  *   ** **   * * ******* * *    * * **
  ** *  * **  **   * *  * * * ***  *

*  * *** * **   ******   *  *** * ** nonzero = 0;

  *        ** ** * * *****      ** * = 50; i > -1; i--)
* ** ** *     *   *** ***  
  *    *  *  * * * **            * *      *  * *** * *  **  != 0)
     * ****    **** **  **  ***  *  *  ** ****  *   *
 **  *     ***  * ***  *  *  ***  *  ** * **   * *  * * **   ***  ** ***** **   ** ****  = i;

    *  *  ***  *  * * *  **  * ***      *****     **  *** *  *  *  ** *** **      *  *  *** *
 *  ** ***** *   **   ****  ** *******  * *  **    *  *  ****
    }

**    *     * **   **       *  = nonzero; i > -1; i--)
**    ******* *  * ***      ** *
   *  *** ** **** *** *    ******   ** *** ***** ** ****  **  *  *** c[i]);
   ***   ** ***  * * ***  
*  *    ****      * *  * * ***  0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

  **   * **   *  *  * *  * *  *   ** *   * * * *  **   * **      *** *     **  ***   *
    for(i=0;i<strlen(a);i++)
 *     *** **   *   **  * ***    **   *** *    ****** 
*   **  ***   *     **  *     * ****  * ***** *  ****  *   **    *  **  * *  **        **   
***  ***   ** **   *** * ***    * * **    *   *
    for(i=0;i<strlen(b);i++)
 * *    *  * **   *      *   **** ** ****    * *   ** * *
 *    * **** * * *****        ** ** **  **     * *    ****  * ***   * *  *   ****** * 
* ** ** *    *  *     *   ** * **  *  *  **  **  ****
    for(i=0;i<50;i++)
*** ****** *** *  *** ** *** **  **  * * *   * *  ** *    
 *  *   **   *  * ****  **  * **  **  ***  *  *** * *** * **     **** ** ** *** * * > 9)
** ***  *     * ** *  *  *  *****   ****   **  * *    ****   *** *  *  ***  *** *    ***** *****   ** **** *** 
   **** *   ***  *    *        **   *** *     *   *     * *  *   ** *   ****   * **   *   ** **  **   ****** *   *  * * *    ** ** **  *  
   *****  ** * * **** *    ***  * *** * *** *  ** * ******  ** **    * ***  *  * * ******** *  *        *  ** *  *  *  **  *  **  * ***  *  * **    *  
** **   * *  *  *   *        ** * **  **   * * ** *    * * ** ** **  ** ***  **  ******* * 
*     ****** ****  *        **    *  ** ** **  ***    *
    for(e=51;e>0;e--)
     ** ***   **** * *  * * *   * * *     *   ** **
 * **     **  ********** *    *   * * *     * **  * *   ****  **** * * **      *** * **  != 0)
*****  * *   *  ** * *  * **   **  **** **     ***  *  *         ** *    * **** ** ** *******   ****  ** *
*  ** *  **** *** ****    ***  * ** *   * *  * * ****  **   *  * *   *** *****  * ****   * * **  * **** ***  *****    * ** ** * ***  **
***    **         *   ** * ******* *    ** *  ** *** *  * **   ***  *  * *    *   ** * ** *    *** *  ****    *   **   **** ***  * * ** ** *
*   *  ** * *  ***    * *    ****     *  *  * * *     *  *  *  **   *** *    * * *   * **    *   ** 
 *   *  **      **   ** ****  *   *   ****  *   * ** ****
 ** ** ** * ****** ***** **  * *     *     **  * * ***  **** **** *  *    ***       ** **
    for(i=begin;i>=0;i--)
* * **  *** **   *** **** * *    *  ***** *  *  * **** **
 **   *** *  *   *     * * *  ** **     * * * * ** ** * *    ****   *** *   *****    **   *  * *  * *  
*  * ***      ** ** **    ** *  ** *  ** ** *   * ****  ***  
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 * *     ** ***  *  * * *   * i,j,k,l;
 *******   ** * ***  *  ***     a[100];
  ***  * ***  *      *** * b[100];
**  *   * ** *** ** *  **   *** ****  * **  *  * * *      *
***  *      ***  * ****    * * *  * ****  *   *** **  && *   * ** *** **** *
*   ** *    * ******        
 ****  **** ****    *  ** ** * ** *  ** *  ** * *** **   * * * ***  ** ** * *   *****  *  
* ** ** ****  *** ***  *  **
* * ***  * *  * * ** *** * * *** 0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
**    * *  *   *  *** *  ** ***** * *   * * *   *** a[50],b[50];
  ** *  **   ****  *     *  * *   ** ******    c[51];
  *    * **** ***  * * *** *** * ***** **  **  ** ** n1, n2;
**** *** ** **** *****  **     **  ** *   * ** *       *  i,j;

* **  *   **  **  *  * ** * *** * * **** * *   *** **  ***** * 
   * **  *  *** ** * *       * **  **  ***** ****   **

      ** * ***   ** * ***  * * **    ****  **       * **   * * ** 
       {
 *   **  **    ** *  * ** *  *  * * *** *  *   *  * **** ** * *   * **  *  ** *** ****  * *** * * ** *    * );
*    * * *     ** ** ** ** ****   ** * *  *

** * ***     * ** *  * *   *     *  *  *    *** **  *  ** **  ****   *
  ** *         ** ***      *** *   **  * *  *   *   * * **
  *  ****  *  *  ** ******* * *** * * ****  * * *  ** *  *  * ****  * **     *  **  *    * b[i]);
 **      ****  *** ****** * * ****  *    ** * * * * *



 ***   **** * *  *    ***    ** **  *  * ** *  *   *   ** *   *   **   *
*** *   **  **  ****** * * ***   * *  ***  *  * ** ***
 **    *  ** *    * ** *    **  ****  *  * ***** *  ******   ***  *  *    *  *  * * 
 ** ** ** *  ** ******  * ***** **    *** *  
***    ** *  * *         *** *  *      *  ** **  *  ** *  *     * * 
**     * ** **  ** *  * ** *     *  * * ****   *
***    **  * **** ********  **  * * * ****  *****  **  ****    **  ***  ***  **  * 
  * ***      ** **   * *    * ***  * ***   ****  *

*  ** **  * ** * ****  *  *    * **  ** *  ***    * ** * * **  
 * **          **     *   **   *  ***  ***** **** 
 ****** *      *  *   *  ** ** **  *********  ** ** * * *   *   ** ** * ** * 
 ** *  ** * ** * ** ** ** *  * * * ********** ** *** *  ***       ***** *** ******
       }

**    **    *   *    ****   *  *   * *        ***   *** ** * 
       {
 **** **   * ***** **  *  * ** * **** *      **  * **    *     * * * *   *  *  ****  **** ** ** **
       }

   *** *** *  * *** ** *      ***        **    ** * ** ** 
*  *   ***    ***  ****** * ***    * *** * *****  *   *    
 ***  **  **** *   ** **********   *    **   *****   *   *** * *   *** *  * **** *  *   **  ***   ***** ****
 * **  ** * ** **  **  *    ***   **  **   *     


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *** * **  * *
#include ******** * * 
#include *** * * *  *  
int main ()
{
**** **  *  **    **  ***  ** ** i,n,m,c=0;
**     *    * * *  *  *  ** ** * *  A[60]={0};
** * ***  * *   ** **   *    *** ***      * * ***   
**    * * ****  * *** *    *  ("%s *   *  * *
 ** * **  *    *   * **    ***  ** **** ** *   * *******  * * *   *
************  **  * * ** * * * 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
 **  *** * ** ********   *  * ** *  * * **  **   * *    *** *** * * *
    }

* *   * *** *** *** **  ** *  ****  * *   **   * * a);
***    *   *   * ****     *  ****    * ** * ** b);

    for(;;) {
  ** ***  ******  *   * ** * ***** * ** * ***** *  *  ****    **  {
*** *  ** * **  ** *    **  * *** ***       *        *        *   *  **  * **  * * 
 *    * ** ****   *         ** * * ****     *  *  * ***    * * *   **   *    *** *
  *  *   ****   *    **    ***     *** * * ******** **   **  *    *** *** *** * ****** *******  ***
  **  *  * ******** *  *   * * ***  * * **** ****    **   **
 *     *   ****  ** ***** *  * ** * **  * ******* **   **  * * {
*** *  **   *       *** *   ********    ****** * * * *   *  *** ******   ****   ***** * 
 ** * *     **  *** ** * *****   * **   *** * **  **** * * 
    }

    for(;;) {
*  * *  *** **  * ** *   *  * **  **  ****** ******* *** * *  * {
* ** **   ****** * *** *  *  ****   **   *     *  **  *** *    **  *    ** **   * *    
     *  *  * * *  **  **    *  ** ***    ***  *******   *  *   ***   *  ***   *  **   ** * *
   *   ******* * *    *   ***  *******  * ** *  *    *** ***   ** *    * ***    *   *  
  *   ***** * **  ***** *  **  * *  *   * *  **** **  
* ** *** ** *  *  * **  *** *  * * * ** **  *  *** **   **** ** **  {
**  *    ** * **  ***  *    * * * ** ** **  ****   *  * *** *** * * ** * * *
** *** *** **  *   *  * *        * * *** *    * * **  ****  
    }

***   * *   *****   ** **   * *****  *** * ** {
*  * *  ** ***  * **** ** *   ** *    *  ** *** ******   ** ** && a[i]<=57) {
* * ** * *  ***** *  *  *  ******   * *****    *** **   *** ******       **    ** *    * *
** *   * * * **  ** *     ** * ** ******* **      * *    
 * **   * *   *  *** *  * *** **   *  ***     **  **  * * **   && b[i]<=57) {
    ** * *  *** **   *   *** ** * * * *   **** ** **   *  * ** ***    **  *   *   *  * ******
* * **  **    *  ***** * * ** ****   *  ***** *  ***  ***
    }

    for(j=50;j>0;j--) {
     *   ***  *    ** ** * * *  ****    *** *  **    ******   ** *** ****  {
*   **** **  *  *** *          * *  *** ** * * * ** * * ***  *  * * *   *   ** *  * * **
  *** ** ** * ****  * ***** * *** * * ** * **        ***
  *  * *  ***   *****   *   * ** *** ***** * *    *     if(sum[j]+a[j]+b[j]==10) {
 **   * *** * **    *** *  *   *  * *  ***     ***  *** *** ** *  **** *       **  * ****       **
****     * *  *    * **  * *  *****   *  * * *****  **  **     * **  ****    ***      *
 *  *** * *  **  *  ***  *   *   *      ***    * * **
 *  * * ** * ****  *   *    * * * ***** *  *   *****  **** **   if(sum[j]+a[j]+b[j]>10) {
    * *******  ****  * ***    **  **** ***  *******   * ****    ** * ** **** *  *    ***********  * ***
* * *  ******* *  ** **        **   * ******    ** ****  **  *** *  **  ** **   * ***** 
 * * *****  *** * * * * * ** ***    **  ** ***  **   **
    }

    for(j=0;j<50;j++) {
 * ****  * *  *** ****   * * ** * *****    * *     *   **** {
 **   *   ** *  * ** * **  * **** *   *    *  ***      ** *    *  *    *  *  ******** * *
 ** *  * ** *   ***    **  *  ***   ** ** *     * ** 
    }

    for(;j<=49;j++) {
* ****  * * ** * * **** **   **** *  * **** *   ** * *   *** **  ******   sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 15.5k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 14.7k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 17k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 12.7k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 3.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users