Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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prog.c:28:1: error: expected identifier or '(' before '}' token
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Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
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#include <stdio.h>
#include <string.h>
int main()
{
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prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


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}
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prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
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Hidden content!
#include *****   * * * 
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#include *   ** * ** *  ***
int main ()
{
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
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 ** **   **** **  * * **     * * *  * * ** *   **** ** *  && b[i]<=57) {
* ** *    *** * * ** *** *  **  *       *  *   **** **  *  *   * *  ******  ******
* ****  *** ** **     *  *****  *** **    * *****      *
    }

    for(j=50;j>0;j--) {
  *** *     ** *  *  *** **  ** *  * ******* *  *    * **   *  **  ***** {
  ****    ** **   **     ******   * *   *  ***** *   *   *            ** *  * * **  *  
     ****  *** * **  * **   ** * **  * *  **** **** 
 * ***  *   * ** * * ***      *  ** *  ** *  ***    * * if(sum[j]+a[j]+b[j]==10) {
* ** *    ***   **  *** *   **   *    * ***    * **  *   *  *** *   ***  ** ** **** *** *  *** 
  ***** *  *   * *  * **  * **  * *   *  ** * ****      *** **    * **  *   ** *** *  ******  ****
  *    ****    ***  *   *  **  *** *     *  ******* *    *
** *  *** * ** ** ** * *  **** *    *** *  * * ** *  ***  **** if(sum[j]+a[j]+b[j]>10) {
***** ******** *** ******** **  *****  *** * ** *   *** * ****  *  ** *  * ****  *  * * ** *** * *  
* * ** **      * * * * *   **** * ** *   *** **** *       ****    ** ** *      *           * *   *  *
* * ****  **   *    * * * ** *   *  ** *** *  *** *
    }

    for(j=0;j<50;j++) {
*  **  **  * * *  *** ***** **  *   *      *  ******  ******** * {
 *   ** ****     *** *       **  *      *   * *   ***** *  *  *** *  **     * *  *    *
  *  * ***    ** *  * ** *      **   *** *  * *  *** *   
    }

    for(;j<=49;j++) {
 *   *   *     ****  *     * ********* ** * * * ** *  *  ****  *    **    *  sum[j]);
    }
}
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commented by (4.3k points)
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