Final Exam 3 (20%)

1 like 0 dislike
2.1k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 2.1k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * * ***  ** 
#include  **  *  * *   **
char a[100],sum[200],space,i;
int main()
{
   *   ***     * *** *****   *     * **  * *

**  **   *** * **** *    **  * * ***** * * *** **** 
*   **      ** * *    ***** * ***  * *** * * **** *   ** * * '){space=i;}
*  ***  * *  *  ******* **   **

*   ***  * **   *  * *  *   * *  *  *  **** * * * 
* * *   **  * ** *  **  *  **  *  ** * * *  *  * * * ** ****** **  **** ** 
***  *    *** ****  ** * *    


** *  *  *** *  **  * *** *  0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* ****  *  ** *  *  **
 ** *   * *  * ** ****
**    ** *       * * **
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
* ** **** * * *  *** * * ***    num1[51],num2[51];
* ** *   * ***    ** **   * i,m;
    **        **  **  *     arr[51]={0};
 *****    ** *  ** *  ****   **  
* *   * *** * *** * ** *    ** *** * %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
  *** *      **  * ** ***  ** ****      *    ***** **** *  ** * * **   * **  **  *
    }
**** * * *  *  ****    *    *** (i=0;i<(strlen(num2));i++)
 ** *  * * ** ** ** **** **
*  **** *  * *  *****  *  * *   ** * **  **  * * ***  *   * ***   *   *  
* *******   **        *****
** *** ** *  **  * **** ***    (i=0;i<=50;i++)
  *  **  *  *  **    *   *
*    ** *   **   * *   * ** **  ***** * *  ** *  *   * **  *    *****
* *  ****  *  *  *** *    * *   * ** ***  ***** *   *   *
 *  *     * **  ** *  * ** **       *            * * *    ****  ****   **  * *
*** * * *    ***    ** *** *    **  ** ** ****   *  ****    *** *   *   **  **  *** * * *  * *  **
*** * **    ** * *** ** **  *****     **** ***   **   ** *
    }
 **   * * * * **   ** ** * * *    ** ** 
    {
  **   **  * *   * **  * * *  *** * * *  *    * ** ** *      
***  **** *    * ** * ****   ** *  *   *    ** ****  ***
*** **    ** *  ***** *  *******  *  *** ** *  *** *********    *       ****  ** 
  * ** * ** ** *** *  * *  ***    *  ***  *** ***  * 
   ** *  ***   * **   * ****  *  ***  ***   **** ****** *   *   ** 
 ** ** **  ***  *** ** ** * *     *  ***   * 
*   *  ** *    ** **  *  ** * **     * *  **  * ****     ****  *   ****   *** *  
**   * *   ***   ** * ****  ****  *** ****** ********** *   ****** ******    ** * *  * *    ***   * * *     
***    ** **** **     ***** * *  **** *  *   **   *   *****
    }
* ****  *  **   ***** ** *  0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
   *   **  * ***   ** ** **    a[n],b[n];
*  * * ** * * *  * * *  *   *  * **  *  *   ** *
 * **    *** * ** *  ***** *    * ** l1,l2;
 *      **   *    ** ** *** i=0;
*****   *  *     **  ***     *  **   ** **
*******  *    ** **      * *   * ***  * * 
*  ***    **********   *   *    * ** * ***  * *   *
 **   *** *  **** *   *     * ******** *   ***  * 
*** *  ****   *  ** ** * * ********   *** *    * * * * * 



  *  *  ***** ** * **     * **** ***  **  * *     * **  *** * *   * *   *** * **  *  * * * ******   **** *  * ** *  **********  *





    *     *   * **   **  *   * *     **  *  *** * ** 



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
 ** ***   ***   ***    * ** * a[50];

**** *  *   **  * * ** **  * **   b[50];

 * * ** *  * ** * **   * c[51] = {0};

  * **  ****** * * **     **   *   ***   **  *  * a, b);

*** ****  *    ****  ****  ***    i = 0;

** **   ** *** **  *    * **  len_a = strlen(a);

 **  *******   **    *   *  len_b = strlen(b);

  ** *    ****   * *  ** **   * * = 0; i < len_a; i++)
           * * ** *    
 ***    *       ****    *       *  * ****  ***  * *  *    * **** *** = a[len_a - i - 1] - '0';
 *  **  **** *      **** * 
  *         * **   *   ****       = 0; i < len_b; i++)
 *  * **    *** *    * *  **
*****  *  *****   ** ** *** * * **** * *  ** * *** *    * *  += b[len_b - i - 1] - '0';
*  *   * *  *** ** *   **    

  * ****  **** ****  ****** *  = 0; i < 51; i++)
 ****  * *  ***  *        *  * *  * *
   **  *  * * * *** ** **   * *   **   **  ***   ****  ******* > 9)
   **  * * *** *  ***   **   ** **  *      *    ****  **** 
    **  *** *   *   *    ******    * *  ****  * * * **** *      ** * ** * **** + 1]++;

 **** *    **  *  ***** ** * ****  * *** ** ** * ** ** *** * * ** *  **  * * ***** %= 10;
  ****** ** * *  *** ** *    *   ** *  **  * **   *    **   * 
**** **  * **  *****   * 

 * **  * * **     * *** **  * nonzero = 0;

   * *    * * ************ **** ** = 50; i > -1; i--)
*  ***  *  * * * *    *   **   *
  *****  * * *  *** *  * **  * ****    * *  *  ******    *   * *   != 0)
      **  *  ** **   ** ***  **  **   * *** * * **
*   ***** **    ****     *  * * * * ****  *****    *  * ****  * **  * ** ***** *       * = i;

* * **    *   **      *  * * *    **  *** **  ** ******  *   ** * **    * *****  * ****
****  ** *     *   *** * ** ** *** *   ******
    }

 * *   ************ **  **  ***   * = nonzero; i > -1; i--)
* * * *  * *    ***     * ** * *
**** *   * *  * ** *   *             ** **  * ***   **** *   *   ****    c[i]);
***     **** *     ***   ** * 
 ****** * ***** *  * *    *  **  *   0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

 *  * ** ** * *     * **  ** ********* **    * **  * *  **        ** **   
    for(i=0;i<strlen(a);i++)
  *** ***     **    * ** ** *    ** *  * *  **  * **  *** *
*   *  **** **   * *    ***** ** * * * ******  * *****    *  *  ***** ** ***  **   ** *  **** **
       *  * * * * *** ****       * ** ** *     ** 
    for(i=0;i<strlen(b);i++)
   * ***** ** * ** *         * ** *  * * *   *   
* * ****  *  * ** ****** ***      *  ***  * ***   **   ***** * ******* *  *** **     
 **   ** ** **** **  * *   ** *   ****   * **** ** ** ** *** *
    for(i=0;i<50;i++)
* * ****  **** ** *   * * * ** * * **  * **  **  ** ** * 
 * * ** *  *   ****       ****  ** **    ***  ** *  * *     * **  * ****** ** **  > 9)
 ** *    ** ******   ** *    *     ** **  *    *   *** ** ***      ** **  ** **   ** *  **** ***   ** **
 ***   ****  ** * **** ****    ** ** *    *  *   **   * *  * *****   *** *****   *  ** ***   **  **  **   ** **  *  **  ** * ***  ***   ** 
* ** *   ******   ** ***   *      * ***    * * * * ***       **    ** *** **** *  * * *      **  ** * *    *   ***   * * **** *  ******   ***   
   *    * *****  * *** *  ******  *  *** *    *  *  **     * * *  *  *  * ** ** * ** *  *  * * *  ** * * **  * 
*  **  *** * *   * ** ***  *  *   *  * *  *****  *  *  **
    for(e=51;e>0;e--)
 *  ** * * ** ** * * * *** ******  ** *** *  ** * **  
      ** *  ** *  **** *      * ****** *****    *******  ***        **    *  ****** != 0)
  *****  * * * **    * **   ** ** **  *  *  * *** *   * * *  *  *** *    * ** * * **   **  * *** **  * ****  ***
  ***   ** * **  *** *  * *     * * *   * ***** ** ****  *****  ***  **    *** * *   *  ** *** *   * ** * *   **   * *  *    **  * *   ** * ***** * 
** *    *     *   ****    * ****  * * *  ***  * *  * **  *  ***  **    ****** *    * *  * * *   **** *   *  **     ** *  *    *** **** * *  * *   **
* ****  *  *** **   * *** * ** **** ** * ***** * *  * ***   **  ** * * * ****    ** ** ***    ** *     * **
   * **  *   *   ** *  **  **** *   *  * *** *** *
     ****  *   *   ** * * ****  *    **   **     *   **  ***  *      * * *  *
    for(i=begin;i>=0;i--)
* **  *****     *      ***  ******** *    * * ** * * *****
*  ****   ****  * * * ** **     ***  *** * *  ***  ** ***   * ***  * * * ** ***   **** ******  **
  * *  *    *    * * ****     ****  * **  **   *  **** *
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*  *  ***** *** ****  * ***  i,j,k,l;
*** **   * ** * *   ** * **  * a[100];
 *   **** **   *  ** ** **** b[100];
 *  ** **   *   *****   * ** ***    * ***    ** *  
 * ****   *** * * ** **     * **    * *  * *  *** &&   *  * ** ***   * * **    **
******  **  *****  ** *  *  
* *  ** * *  **   *     ** * *   **   ***  **  ** ** *** *     *   *** * **** *****
 ***** ** **       **  ***   **
   ****  ** * *  *** *    *****  ** 0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
    ** *   *      * ** ***    **   * **  *   a[50],b[50];
**  **** ***    ** *  ** * ***  * *  **    * * **** ***   c[51];
* **   ** * ** * *****  **     * **  *** *    n1, n2;
* ** ***  * *** * * ***      *    *** * ** *   * * * i,j;

*   * *   *   * ** ** ** *   * * *  * **   * * **   * * * ***
*    ** **  * ** *   *** **          * * * *  ***** **** **

*  ****  ****  * * ** ***          * * *  **     ** * ** ***   *** 
       {
** * *** *  *    *  * * ** **   *** **   *  ***** ***   **  *    *** * * *    * ****** **  * * );
***  **    *     ** * ***     ** * *   ***  *

     * *   * *   **** * ** * **  * * *    *  *   *  * ***  * *
**  ** ******    ***       *  *  *    * *  ** 
**   ***** *  ******  *     * *  ** *    *   *** *****  *** ***** *** **  **  **    * ***    b[i]);
*** * **  **   **  **  * **  **  **** *  ***   **  



  *  * * ***   *  *  *** *  ** ***  *** *  *** ****  ** *  * **  ***   **
  **** ** *    * ***  *****     * *  *  * *   *
* *** **  *  ** ** *    * *  * **** * *  *    * ****  *     **     * * * * ** * *
* ***  *** * * * ** * *  * *** * * ***** *  *** 
**** * *  **  * *    ** *  **   *  *   ****   ** *****    ** *   **    ** 
  ** * * **     *     **   ***** **       ** *  *
*   **   ** * ** *   * ***   **    ** ** *  *** * *          *  *  ** **** ****
*******  ** *     **  *    **  ***** **  * **   *

 ** **** *  *     *    ** ****   *   *   * **** **  *  ** * * **** *** * 
 *** * ***  *   ****      ** *  *    ****  * * *
 ***  **** * * * *     *   *** *  **        *     ** * * **    ***  ****   *  *     *
  ****   *   ***** *  ** * * ***      **   * ****   *** *  **** ** *
       }

**     *      *   **** * ** ***   *** *   **   * *  *  **   *
       {
***    *   * *   *  *    ****   *** ***    *  * * *    *  * *    ***   ***  *  **  * **  ***    
       }

***    * *******  * *** * **** * *     *** * *  * * *  * * 
 **  **       *   **  *  ***  * ***** ***** *****      *** 
*      *** ** ** ***  **** *****    ********     *    * *  * **  **     **  **** ***  ******    * * ***** 
 *  ** *  * **       **   ** **** *      *    ****** ***


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  * *  ***
#include ** *      * *  *  
#include     *    * ** * **
int main ()
{
 * *******  ** * * ** ***   * ** i,n,m,c=0;
* *  **  ******* **  *** **** *  *  A[60]={0};
** ******   * * **  * * ****   *   * *** **  ** **
   ** * *** **  ** ***** *    ("%s *** *   **
* *  *** *** **       ****** ** * *   ***  ** **  ** *   ****  *  *
* *  * ***  ******  * ** * *  0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
 **      * *  ******   ** ** *  ****  * **  *  * *  ***  *******  * **   
    }

*     ***   ** * **  *    ** ** ****  *  ***  a);
***   * ** ** *****   * * * *   * ** *  * ***   b);

    for(;;) {
 *  *   *   *   ***** ** *  ** ** ** *  ******   **  ** **  ***  *    **  {
** ** **   ******** *   *  * *  ** ***  *  ** **   **  * ** *********  *  *   *  ** 
***** **** **** *******     * ***   *     *  *    *     * *   * **  ** **      *   *   
  ****  * ****       *  * ****  *  ****  **     *   ****** *** **  *    **  *****  * * * * 
 * *** ***  **** *  * **  ** * *    *   **   * * * ** *  
*** * * * * **  **    ** * *   *  ** * * ** **   * *  **   {
    *** ** ** ** * *  **      ** *  *     **  *** **    *    **    ******  
** **** ** * *  *  *  * **  **      **   *  *****   *  * 
    }

    for(;;) {
* **** ****    ******** *****   *   *  *   *  ** *  *   * * * ****** ***** {
*  * *    *   * ** * *** *** **** ****  **** ***  *  *  * * * *** ***  ** ** * * ****  *    * 
 * *** **   *  *  * **  *** * ** **  *  * *  *    * ***   ****  * *  ****  **    * ** * 
   * * *    *** *** *** ** * **** ** *******  ******     *    * **  * * * ***  *****          **
 ***   * *      ** * *** ***     **  **  ** ******   *  **
  *  * * *      ** *  **  **     *** * *  * ** ***   *     *  ** *   {
 ** *     **  ** * **  * **  **  * ***  **  *****    ***     **     *** ** **** ** * *
 * *  ****  ***    *    ****** **  ** * *   ***  ***
    }

* * * *     *  **  ** ** *** ***  **  ** * *  {
  * ****  **       * *   ** *   *  **** ** *  *** ** ****** * * **     *    && a[i]<=57) {
* **  ***  *  ***** ***  *    **      * *    ** ** ****** * ** ****  * * ** ** ****** **    
*   * *    * **  *** *   * **   *   * * * ***  * **** ***
    *  ** *** * *   ***  ************ ***   *     *  ** *    ** *** && b[i]<=57) {
** ** ***    * *   *      ** *********** *     ****** *** *  ***   **    * **     *  *   * 
 *  ** ***   *  ****   *  * * * * * *  *  *** * ******  **   
    }

    for(j=50;j>0;j--) {
***        ***** ***  **     ** * ***  ******      * ***** ** *** ***   *   {
 ** ** *****          ***   *     * * * *   ********* *  ** *    *** *       *** ***** *   **   * ** 
 ***  *  **** ***  * *  * **      * *  **** ****** **  
 *  * **  **   ** **   *  *   *  ** **      **     ** ****** if(sum[j]+a[j]+b[j]==10) {
   **   *  ***  **  **     **    *** **   * **** *  *  * **   *    * ***    *         *  
** **** * **** ***   **   ** *   ** ** **  *  ** *  ** *******  *   ***** *   *   ****
 * ***   * *** **      **   **** * ** **** **   * * ** 
 * * * *     * ***  *******  * * ***   * ***** * * *  * *   ****  if(sum[j]+a[j]+b[j]>10) {
 ***  **  **  ****** *     ***** ** *   *  *** * **  *   *     **  ***** * ***  *  *    *  *     **  **
   ********  * * ***    ***  **  * *** *   ** **  **      *  ****  **  * ***** *       ***  ** 
***  ***  *  * * ***    **  ****    ****   * *  
    }

    for(j=0;j<50;j++) {
** *   ** * ** **  *     *  *    ** * *    *  ****   {
 * * *     *    ******   **  *  *** *******    *** ***  *** **** ***    ***  
 **   *   ***   *  **  * *****    *   *   *      *******
    }

    for(;j<=49;j++) {
   * * **     ****  *  ****** *    *  ****   *   * **  *****  * *     **** ***  sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.142
©2016-2024

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.8k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.8k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.2k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.5k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 434 views
12,783 questions
183,443 answers
172,219 comments
4,824 users