Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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prog.c:28:1: error: expected identifier or '(' before '}' token
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Hidden content!
#include <stdio.h>
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


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}
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prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
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Hidden content!
#include  * * **  **  **
#include *   **  **   *  **
#include      *     * *
int main ()
{
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
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  *    ** ** * *** ***  ** * **  ** *** * *  **** *    **  * ****** && b[i]<=57) {
 * ****      * **** *   * ** *** * *  **  *** *** *** * *    ***** **    **  *** ***  
  ***    ** ***  ** ** * *******  ***   *** ** *     **
    }

    for(j=50;j>0;j--) {
***   * ***** *  * **** ***   **     * ***  ** *** * *  * *     * ****   *  {
  *   *   **** * * ** **    * **** ***** **   *  **  * *  *  ** * * *  * ** *   ****   **
* * * *****   *  * ** *   ** **   **   **  *  *    
  ***  *   *** *  *  ***  *     * **** ****    *  * * *   if(sum[j]+a[j]+b[j]==10) {
 *          **  *  **      * **  *  **  *    * *   *** ** **  *  ***** * *     
     ** *    ** *    ** **  *****   **  **      ** * **  *     **    ** * * **  ***   **  **  ** 
 **  * *   * * *** ** *  *        **** **   **  
*** * **** ** * *  ***   *  *  *   * *  *  *    ** *  ***** if(sum[j]+a[j]+b[j]>10) {
**   *  *   * **     ** * ** *  ***    *** *** ** * * *  *    * * *  **  * *  *** *  **** * *** ***
 *  ****  *  *** **   *  *** * *   **     ** *   **** **  *  ***   * *      * *** *****
***  * * * **  ***     * * *** * *  *   ** * * ** *
    }

    for(j=0;j<50;j++) {
 ***   *       * **   **  ** * **** * ******* **   * ** ** *** {
*** *    **  ***   *** * * ******** *****  ***   *  ** **    *** ***  ** *   * *  ******   **  * ***
 ***  * ** ** **  *     ** * ****** * **    * ****  *
    }

    for(;j<=49;j++) {
* *** *  *  * ** **    * *  *  ***  **  *     * **  **  *  **** *   sum[j]);
    }
}
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