Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
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#include<string.h>
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#include<stdio.h>
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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prog.c:28:1: error: expected identifier or '(' before '}' token
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Hidden content!
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


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}
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prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
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Hidden content!
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int main ()
{
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
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  **** * * *  ***       **  *  *******  * *  *  *       ***** ** *    ***  * * *  *  *
 ***** **  * **   * **    **  *   *  *  * *    *** ** 
     ** * ***** *  ****** ****  * * *   ** **  **  **       *   && b[i]<=57) {
*  ******  *  *  ** * *****   ****  **** *  * **** * *   *****   **  ***** *** *    *   *** **
 ** * *** *    ******* **  *  *   ****   **  ** ***  
    }

    for(j=50;j>0;j--) {
* *   *  ** *** **      **** * **      ****  * * ** ** ** *  ** *  * ** *  *   {
* *  * * ***     * ** ** *     ***    **    **** *** ***  ** * *  ******   *** * * ***** 
**  *  *    *    *  *** ** *    ** **  ***   ***  ****
** ** ** *  *** **** **       ** * ***     ****** ** ** * ** * if(sum[j]+a[j]+b[j]==10) {
****  * * * * ***** * **** ** *    * * * ** * * * * **        * **        ** *****  * *
*** * * *   ***   *    **  ** **  ****  ***  **  *  *  *   **    ** **** *  * *   *****  ** 
*  *  *   **       **  *  **    *  * ***** *  * * ****   *  
    *   **       *** ****** **       *** *  ***   * if(sum[j]+a[j]+b[j]>10) {
      * **    * *** **    *  *** * ***** * * * ** **   *****    * *  ** *   * **** ** ** *   **  
 ** *      *   ** *  ** **** ****      *** ***** ******  *****  * *   **      * *  * ** 
**  *  *   ** * *  *** *   ***   ***  ** *  ***** *
    }

    for(j=0;j<50;j++) {
******* * * * *    * **    ****   * *  ** **  ** *    ** *****     ** {
*    *   **  ** ***   **** * ** *** *   *  ****** * *******  *****    **    ** ******
*      *  ***     *** *  *     ***    *   **  *  *
    }

    for(;j<=49;j++) {
*  *   *** ***   *****   *   ****   *** *** *** ** **  *** **** ** ** ** * sum[j]);
    }
}
answered by (-120 points)
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commented by (4.3k points)
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