Final Exam 3 (20%)

1 like 0 dislike
7.2k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 7.2k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   ** ** * ** *
#include ****  * **  *  ***
char a[100],sum[200],space,i;
int main()
{
* ******** *     **  * *      *** *  ******* *

*  ****** *** **** * * *  *** *****  ***   **  
*** ***** **  ***     *   * * * ** **  **** ****** ** *     '){space=i;}
 *****  * ***** * *  **  *    * 

 *** *    * *   ****** *    **   * ** *   *
 * ******     ** * *****  * ** ** *  **** ***    * ******       * *** ****     
** *  * * ***  **   *   *  **


 * *   *  **** * ** *   ***    0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *   * **   * * **   ** 
**** *  * * *  ****    
*  **** *  **    ***  *  
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
 *   *** *** **   **  *  **  num1[51],num2[51];
* *  **  **   *   *  *  * *   i,m;
**    **   *  *   *** * * **** * arr[51]={0};
      *** * ** ***** *** ****
 *** *****  ** *   *** **   *  * * ***** %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
 ****  *****    ** *  ** ****    *** **     * ***  ** *  ***     *** ** *  ***  * * ***   
    }
***   * **       ***** *** (i=0;i<(strlen(num2));i++)
     * ** * **** *  ** *
*  *  * *  * * * ***   *    ***** ***** *  ***  ** *** * *   *** ** *   *  **   *
 * ** * ** *  ***    *** *** 
 *  * *  * *        *  *  **** (i=0;i<=50;i++)
 *** *** **** ****   *  **   *
** *** * **  *  *    *    ***     *     **    * ***** * *** **   * * *   
  ** ****** *    *  * * **    * * * *    **** * *  ** 
** *  *   **   *  **** ****    **** ** ** *  *       *****  *   ***    * *    **** ** *     *     
   *   * **  *  **    ** ***   * ** ******  ***  *    **    * * *   **** *** ***  *   ****** 
 *   ***  *     *  *      ******  ****** *  * ** **     *  
    }
     *  *  * ** *   *********    *  **   *  *   * 
    {
 **  *  *  ****    * * * ** ************* ** * *    * *** ***  
* *    **    *    * *  ** * **   **   ***  ***** * **   *  *
* *   * * ** ***  * *** * *    *      ** * **** *** **    * * *   * ** * *** *     
 * *  * ***** ** * ****  * ** * *  ****** * *  * ***  
 **   *  **** *******  *** * * *    *  *   * **** *      *   ****
 *** **** * **   * ** * *  **  *  *****     ** **
***  *  ***   *  * ** * * **  *** *    *  ***   **   ** ***   ***  * ***   *** *  *** ***** 
 * * **      * *****   **   *  **** *** ***   **  * *   *   ** **  *     ** *******  *     * ** * **    **  *   ***  
*  *    *   **** *  * **     **** *** *** **     ** *  ** **  
    }
  *   *** * **  *      *  * **    * 0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
   **     ** **  * * **** * ** a[n],b[n];
* *     ***  ****   * ** *   *  * *  *  * ****** *   
***** **   ** *** ***** ** ** *  l1,l2;
**   *** *** ***   * *   * ** ** i=0;
 ** ***  ** *   * *   *    *** * *  * *
* *** *  ***  * ***       **  *     
 *  *   *** * * **  * *      ** **** * * ***** *
* *  **      * ******  ** * *   ** * ***         
**  * *   ******* ** *** ** ** *    * **** ** *  *   *



 **  ***  * * * * ******      *  * *** *    * * * * * **    ***   **    *   **  * * *       ******     * * * *





  *** **** *  * ** *  ** **    *  **   **  *   ** ****



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
*  *   * ** ****** *   ** **   a[50];

* ***      *   ** *   **  *** *  b[50];

 * **  *  ** * *    *   * ** *   c[51] = {0};

*  **    * **   **  **     *     **** ***** ** a, b);

*   *   *  **  *  * *****  * i = 0;

***     **    * * ** ** *** **  *   len_a = strlen(a);

 ****  * *   *  * *   *  len_b = strlen(b);

   * * * **  * *   **  *  ***  ** = 0; i < len_a; i++)
*   ***  *** *   * *** *    
 **   ** *   **   **   **   ***    *  *   * ***  * = a[len_a - i - 1] - '0';
 **  *  ***  **  **  *  **
* * *    **    **    ** = 0; i < len_b; i++)
* * * *** *  *     *  ***** ** *  
**  **     ** **  * **  * *   *  *   * ** * ** ** ***   += b[len_b - i - 1] - '0';
**  * *      **  *** * **** ****

**  **   ****  * * * * ***  ***** = 0; i < 51; i++)
 ** **  *  *  *  *** ***** 
*  ** *  *   ******* ** *** **  *    ****   *    ***     **  **  ** > 9)
*** * * ** **** *  **  *    **  * **   *    *** **     
    **   * *** ***   **** * ** *  * * * * ***   * **     * *       *   *  *     ** **   *  **  + 1]++;

 *** ** * **  *  * ****  *   * * *** * * * ***** ***** ** *   *     *********     * %= 10;
   ** * *   *  ****   **    ***** *   *  *   *** ** *  *** **
  ** *   ** *  *  *   * * * 

*   ***   * **   *  * **  *  nonzero = 0;

* ******* *   * *  ***      ***** = 50; i > -1; i--)
     ** *   ****  * *  * 
    *    * * *     *****   *** *  *  * ***     *     != 0)
* *   * ** * ** * **** *  * * **  ** * *** ******* ** *   
* *  ******  *  *  * ***    *  *     *       ** ** *****  **** * *  ****   *  *    = i;

**     * *   * * *   *  **       ****  ***   * ** ***    *   * * ****  *  **  *  * 
 *** ** *    *** *** *** *** * **  **    **** ** 
    }

 *    **   ** ** *    *      *  = nonzero; i > -1; i--)
  ***   * ** ****  * * **
  * *  ** * *  ***    ********* * * *   ****   ** *  ** *** *** **  ** c[i]);
 ** * ** * *  *   * *** * **
* ***  ****    *  *     *  * ***** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

 * *******     * *   *** ** ** ** *      ** *   *  *  *     ** ** * **   **   **
    for(i=0;i<strlen(a);i++)
* ** * *   ***  *** *   *  * * **     * * *  *   * **
**** *** *   *  * * * *** *** ** * * * * ** *    * **  *** **   **   * ****   ** ** * *
 *****  ****  *     ***    ** ***   * *  **   *** * *
    for(i=0;i<strlen(b);i++)
 *** * *  *    * *   * ** ** **  * **  *  **   ** *  **
 *  ******* *    * **    **   *** * *** *   ****** * ***  **   **** * ****  *  ** **
  * ****** *  * ** *    **  **  * *** *    **    *   **** ** 
    for(i=0;i<50;i++)
 **  *  *  * ** ******   *  ****       ** * * ****  *  *
**  **  ***** ******* *** *  ** **  ** **  **   ** ***  **** *  * *  * **  **  * * * * * > 9)
   ******** ****   ** * * * ** * *   ** ****   ****  *  **  * * ** ******   * ** ** ***  * *     ** * ****  *
* *** *** **  *    * ***  **     ** ****  ***   * **  *  *   ****    * ****   ***  **   *  * * * *  *   *** *   *******   * *** ** * **  *   *
  ****  *** **  ******** * ***  * * *   * *     *   ****** * *   ** ****    *         * *  * * * ** ****** * * *  ** ** *  * *    *****
 * * *** *  *  *** ** ** *  *  ** **   ***** * ** **** * *  **   *** ** * * *    *  ** ***  * **    **    *   *   *
 ****    * *     ** * *   *  *  * *    **   ** **** *   
    for(e=51;e>0;e--)
 * * ***  * ** * **   *  *  *   **     *** ****** * 
** *  *  *  *  *  ****  * *    ** **     * ***   * ** *** * *   **** *  * != 0)
**  ** * *** *      * *** * ***  * *  * * * ****** ** * * *  ** ** * **   ** **    ***   ** **** ** * *     
 **** * *  *  **  ** ***   *   *    *  ** ** * *    *   ****  *        * * **** * ***** * ** *  **     *  ** *     **  * *      
*  *** *** *********   * ******* *  *  *  *   *    *** ***   **  *    **  *   * *  * *   ***** ***    **** **** * * ***      *   * * *  ** *  
 * * **** ** **** ** **** ** *  *******    **       ***** ** *  *   * **** ***   ** *** ****    *  ****     * **
*  ** ** ***** *****    **  * *   *     *   * ** ** **  *
  *   *  ** * ******   **    *     **  * ** * * ****** *****    * * * **  *    *
    for(i=begin;i>=0;i--)
 ****    **  ** **      **  ** * ****** **    
 *********  * *** ***  ****  * **** * *   ** *** * ** *     ******* **    *   * *** * ** ** *    * * * ** 
    * *        ** *   **  *    **  ***   ***   *  *
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
  *  ***  *  ***      *  *   ** i,j,k,l;
 *  ** * *** *   * **  **  a[100];
  * * *     *   *   * *** b[100];
    *  ***   **   ********** * * **** *  **  **     ***  *** * 
  * * ** * ***** *    ****   *****  *** ****  **** *  * * *** &&   ** *** **** ****   **** * 
 **** ** *  *    * *  **
*  **** * * ** * **  **   *****   *   *   ** **** *** *  *  ***    *  *  **  *  *    ** *   * *
 ***  *  **   ***  ***     * * 
*  ** * ****    **** ** **  0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
 **  * **  * *  ** ** **  *** **** *  * *** * ***** * *    a[50],b[50];
       * * ****  *    ** *  **** *****  **** * * c[51];
**      ******  *** * *** ** *** **  *   * **      n1, n2;
   *  * **** *** * *** * *   ** ***** *  *  * i,j;

  **    *  ***** *     * ***  * ** * * ** * *   * * **
** **** ** *  *  ** * * * *    ***** * **** * *

 *  *****  * * **  ** ****   ***  ** **      * *****  **           
       {
 *** ******    * ** * *  *  * **** *     *    *    ***  * **       ***   * * *   **  *    * **   ** ***** );
******  *   * * **  * * **  *** **** **  **

*   *** * **  *** ** **   *   ** **    ** *** *  *   **  ***
 * ** * ** * *        **  **  *  *  *** *****
 *  ***    ** ******  *** **     **** * *    ** **** **** *    **        *** **  **** *** b[i]);
 ** *   *     *    * ***    **   * ***    *  *



* * *  * ** *    * ** ** *  *   * ********* *  *  *  * ** * * * *   ***
* ***  ** * ****** * ******** ** **** *****  *
  *  * **  ** ** *******  *    * *******    *    ****  *****  *  * ** **  ***  *** ** 
*  *** *     **        * ***   **  *  ******* *   * * * 
  *  *   * **     *  *  ** ****     *   **    * * **  * *   *  ******   
  **** * **  ****   *** *    **  **** *          * *
 *  ***  *  * * *  * *     ***       *   *** * ** **  ** ** *   **  * **   *  **      ** ** *
* ** ** **    ***   ***   **  **   **    ****

 **** ** *  *    *  * *   *****  * **  ** *** *   **  * * * ***
*     *** *   * ***  *   **  * **  *  *** ***** * *
**  *   * * *   ** *** *  **  * **   *    * *   **  *  *** *** * ** *   * * * * *
*   *      **     ******** *  *** *         * ****         * ***        *   ** 
       }

 **   *** *  *** * *  *  *   *    *    *** *** *** ******** * * ***   
       {
* ****   ** *   * ****  * ** * ****  *  *     * *  *** ** * * * * *******   * *** *** * * 
       }

* *  * ** *** *  ***  * * * *  *      *  *** *   **
 *  * ** *  *   ** * **     *  *  ** ***   ** *  ** ***
  * * ***** **  ******   * **  *     ** **** *  **   ** ****  *    ***  *** ***   *    **         * *** *  * **** **
 ***  * * ** *   * **** * *** *** ****  *   **   * * **** *


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***** **  *   
#include **  ** * *** ** *  
#include **** **   *    *  *
int main ()
{
  ** ****  * ***   *  *   i,n,m,c=0;
 ***** * ***    **    **   A[60]={0};
**   *  *  * **   * * *  *  *  ** * ***  ** * ***** 
   ** **  * ***** * *** ****    *  ("%s   ***** ***
 **  * * *  * *  **   * ******   ***  *  ***** * * **     * *** * * 
    *   ***    * * **** * **  * 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
* *  *  ** *  * * ** *   **  *  * ****** ******  *** ** ** * ** * * ** *   **
    }

**  *** *     * *  *  ****    **     * ****  *** a);
    ***   *** ** ****  *  * ****** *   ** b);

    for(;;) {
** *** *  **   ** ** *    **  **       *  ***  * * ****  **      * *     *** ** {
*** * **   ***** * **  ***   *  *  * ****         *** * *  *  ****   * *   ** ***
** *  * ** * *   *  *  * *** **   ***  ** ** ** *  * ****** * *   * **   *   *** *
  ** * *  *** *    ****  **** ****      ***** *  *   ** ** *   * ***  **  ***  * * **
 *   * * *   **  *  * **     ***** *   *** *      * 
 * *  **  *      *     ** **   * **  **  *** *  * *   *   *** ** * {
    *  ** **  ** *   *  * *  ** ** ****** * *****  **  *  **  *   **      * *** *  **  * *  ** 
 ***  *** ** ****** *   * ** ** ***  ***       *    *
    }

    for(;;) {
  *  *     *   * *   *  *   **** * *** **** ***** * * * *     * ***  *** {
 *  * * ****  ** ***  **** *** * ** * ** * * **  **   **  * *  ***** *   *** *    
* * ***** *      **** **** ** *** *      * *** **    ** * *  * ****      * *   *  ** 
***** **   * *     *  *  *  *** **** ***  * **** * *  *****  * *      **  ****** *       **
* **    ** ** **  * **  *      *****   * * ** *   * *******
    *** * * * ***  *** * **  *****   *** * **  ***  * * ** * {
*  * * *        ********   *      *  **      **   * * *  ***   *** *    *** **   
**** ** **    ***  * *  ** *   ** ** *   * * ** 
    }

 *** ***   *   *           *     ***   *   **** {
    *    * ****   *  * **** * ** ***  ******      *****  * && a[i]<=57) {
   ** * ***  ** *  *  *    **    *    ****   **  ** *  ** *  *   ***  ******     ***    ***
  *       * ** *   * ****  ****  *  * ***** **** **  * 
    ***   * * *******  ***** ** *    *  * ***  **  * ***  ** ***  **   && b[i]<=57) {
****  *  *** ****  * ***   **  * * *****    **  ** * * ***** **   **   **   ** 
*  ** ** * ***   **       **** ***    *  *   ** *  *** *  *
    }

    for(j=50;j>0;j--) {
**** ** **   ** * ***  *  *    *** *    **** ****  **** **********   {
*  **     *** * * *       * **  * *   ***     ***   **  ** **   * ***       **    *    *  
**** * *** **  * * ****   * *   ******     * **** * *** 
* ****   * *       **  **   * *   * ***  * ***  * ***  ****  * if(sum[j]+a[j]+b[j]==10) {
*  * ** * *  **      ***** * *     ** *   *** * *  ** ** * ** * *    *******  ***** *   *  *      *
 *   **      **   * ** *      * ** **  *  ***  * *** **** * ******  ** *   **  *****   ***  *** ***
 **   * ** **** *  **   ****** * * ** ** ** *  **** *   *
 **    ** ** * *   ******* * *  * **  **  * ****   ** if(sum[j]+a[j]+b[j]>10) {
* ** * **** ** *  ******   ***      * * ***  **** **** *   ****  * * ********    ***  * *  
* * **   ** *****       * *    *   *  *** **    ****     *  ** *  * ** **  * ***    **   
***   *  * * **    * ** * ***  * ** **    ****     * *
    }

    for(j=0;j<50;j++) {
* **** **  ** *   **** * ** *  * *     * * **  *  * **   {
*****    **  * **  ** *  ***** *** *  * ****  **         *  ** *  **** *   *    * *    **  
** *******  **    * *  **  *  * * ** ** * *** * * *** **
    }

    for(;j<=49;j++) {
    *****  **** ***     **  ** *  *** **  * ***  ** ** * **   * **  * *   sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.182
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.3k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.3k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5.6k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users