Final Exam 3 (20%)

1 like 0 dislike
6k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 6k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   *     * * * 
#include        ***  *  
char a[100],sum[200],space,i;
int main()
{
 ** * * ***  *    **  **  ***  ******* *  ** 

********    * **      ** * *** * **  *** *    *
     **   **   ** *  ** **** * ***  *  *  * * *** * * *   ***** '){space=i;}
***** ***  * ***   *   * ** 

  *  **** ** ** * * **  *** ** *  **** *** ** *
 *  ** *  ** *    ***   *** *  * ***** ***** *     ** ***     **      **  *
**** *   * *** * ** **     ***


*  ** *    *   * *  *  ** * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** ********* * * *  ***
 **    *        * **
   * * *** *  *** *  **
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
 *  * * * *** ** * *  ** ***   num1[51],num2[51];
*  *    * ** * **    * * ** *  i,m;
* *  *   **    **   * * * arr[51]={0};
   **** ***  * *  ** 
 *** * * ***   **  ***  ** ***  ** **  %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
* **** **  *   * *  ***   *  ** *   ** ***** ******    ****** * ****** *   ** ****
    }
** * *   *     * **  **** * (i=0;i<(strlen(num2));i++)
* * * * ****   *  *   **
** * *** *  *********     * * **  **  *   *** ** *     * ****     *  *   **   *******
****    *  *   *     *    *   *
 * **** ** *  * * *   * *  ** * (i=0;i<=50;i++)
**** * * *   ***** *  ***********
** *      * *  **** ** **   ***  *  **     *** ***   **  ** *  *
  *****  **** ***  **** *** *****    *  ****  ****  **
***     *****  *******  * * **** * **     **   ** *  *** ****   * *   * ***  ****   ***   ** * **   
****  *** * * * *  *   **  **  ** *  *** **    *   * **   * *         *** **  *** *******
    *  *      *******       **** **  * * ****      
    }
  * *       **** *  **  *** ** * * * * * ** **
    {
*  *  *** ***  *** ****   **** * *  * *  ***** *  *   *  *
  **  * * ** *   ** * ** *  *** * ******   *   *   *  * 
*        * ** ****   ** *   **  *** *  *** *      * ***** ** ** **    *    ***** * 
**  **  * ** ** ***  * ***** *   ***  ** ** *      **
 *  ** **** **  ***  ** * ***      **** *  * ***   ******    *
   ** ** ** *  * *  *   *  ** ** * * **************    
 * **   *   * **   **  *     * *   *  *** *   ****     ***    *** * *****  **  ****    ****      * 
 ***** *  *  * *   *  ** *  *   *   * ***   *  * *** * ** ** ** ** *  *     *   * *     ** **** *
  * *     * * ** * * ** *  ** *  *** **** *** * *    **
    }
*** ** *** **      *****  **  *   0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
*     ** *  *  *****  *    ****   a[n],b[n];
*     * *** **  *** *  * *  * **  ***** *  * *** 
 *   * **** *** *** ***  *  *  l1,l2;
* *  *    ***   **  * **  ***  * * i=0;
 * **  **         *  * *   ** *** *  
* * *    **  ** *  * * * *  *** ***  **** 
*  ** **** * *** *   *   * *****  **  * * **** **
 * ** ** *   * ****   **** ***           * *    *
 ***        ** **** ** **   *  ** **    **      *



** *** * ** *    **  **  ** ***  **  ** ****** * *     ** * *** * *  *  *    *  * * *  * *   * *  ** * ** *  * * ** ****





****  *  * *  * ** * * ****  * *********** ***** *   *



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
  *   *****  ** ******   * * a[50];

*  *** * *   * *** *  * *** ** b[50];

 **** * *   **    * *** *    *   c[51] = {0};

 *  ***  ********  *** ** *  * ****** **  * ** ** a, b);

     ** ** ***   * **      * * * i = 0;

   *   **   * *** ***** ***** len_a = strlen(a);

   *   ***    **   * ***     ** * len_b = strlen(b);

       * ***    * *    *     = 0; i < len_a; i++)
*    ** *  *  *  * ****  
*  * ***     *** *** ** *  * *     **   *** * * *  ***   ****  *  = a[len_a - i - 1] - '0';
* * ** * *** *  *   * **
**   * *  *   ***  * ** = 0; i < len_b; i++)
  *  * *  * *** * * **** *      
 **   *** **  * * * * * ****** *  *    ** *   ****    * *** * += b[len_b - i - 1] - '0';
 ** * ** **  **  *    * **  *

* **  *   **   *    **   * * * * * = 0; i < 51; i++)
**     *   * * *  ** * ** * **
* ** ****    * * ***  ***        *** * ***** *     *** ***** *   > 9)
* **     ****  *** ** ***    *   *** **     * **   **
    * * ***** ***  ****  * * * **  * ******   * *  **    * **   *****  **  *** **  + 1]++;

  ***   ** ** *     **  ***** *    * *    *  * **   ** *        *  ****  *  ***  * **** * %= 10;
   *  ****** ** *  * ***** ** *******  *  *   * * *
*****   * * *  *   **  * *** 

** ***  *  ***   ********    nonzero = 0;

 *** * *    ****     **  ****  = 50; i > -1; i--)
   * **    *** ********  *
* **   **   *   *** **** *   *   ****  ****   * **  **** != 0)
     * * * * ** ** *** *** ** * **** ** ***** ***   *  *   
   ***    *  **   *** *  ** *  * *    *   **    * *** **  * *    **** ** * *  ***    = i;

 **   *** ** * * * *  ** *   *  * *  *** ** * * ******* **     ** ** ** ***    *   *   
*  *      ****  **  * *** * *    *** **  * *     *** 
    }

** * * **   * *  * * ***   = nonzero; i > -1; i--)
* *   *******  ******** *   
 *   ***  * *  ****  *  *******   *  * * *       **** *  **  *  * ** *  *   * c[i]);
*****  ******* *         * *  *
 * *****  * ***  *  *** *  0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

**       *** * ***  * **  **  ****** ******  ****  *   *** *   *    **  
    for(i=0;i<strlen(a);i++)
*    ***    *  * **   *  ** ******     * * *  * ***    **
**** *   **   *       *   **  *** *   *** **      **** *  ***** **    ***  **  * ***   ** 
 *  ***   ** * ** *  *** * ***  * * ***  * * **   
    for(i=0;i<strlen(b);i++)
 ***   *     * * ****  ** *** * *** ******   **  * *  
     *****  *           ***  *    ** *    * * *   * * ** **   **  ******     **  ***** *
  *  *  ** *** *  * *  *    * * ***  **  *  *    *   * *
    for(i=0;i<50;i++)
** *** *    * *****  *  * * *****  * *     ***  ** ** *
***  * *    * * **  **  * *    ****  * *    *  ***** ***  * * *  *** ***** ** ** **   *** > 9)
*  *  **    *  *  * **** * *   ** * **** *  *  *   **   *   *** ** * ** ** ** ** **   * *******   * ** * *  **  
  **     **** *** *  ****** *      *  *  * *****    *   * *   *   * *  **  ** *    * * *    **   *    * ***** ** * *** ** ** **** ***
*** * *  * *  * * **   *  *  ****** * *         *  ** ****    ***    ***  *   *  *      *  ** *   * *   *    **   ** ****    ****   
** *      ***    * *    * *** **   * ****       *   ***   *  *    *  **  ******* ****** ****  *   ***
**  *****     ** ****    *  ***  *  * ***  * ** ******  *
    for(e=51;e>0;e--)
*** *    **  **  ** * *  ** *** *  ** *    * ***   *  
**  ** * **** ****   *     **   **    *    ****    *****  *    *         *     **  *   * * *  *       != 0)
**  ***  ** ****   *** *    *** * * *** *  *   ****  ****** *   *  ******* ** **  *   *** *   * **   **   *    *  
****    **     **** ****  *** * *** ** ** * * ** ****   * * *   *** * ** *** * ***  * * ****  *    ***           ** ****     * **    *  ***   *
  * *  * ***         * ** ** *     *** * ****   * * ****  *  ** ***  ******** * ** *** * *  ****** ** *   ***  **** *   *  ** * *     **
**  ***** *** ** * * *   **    **  *****  * ***   * *  ***   * ** ** * *** **** * **   * ***   ***
******   * * *     ** *    *     **** ***    *  * *    **
**   **    *   ****  *  ** **  *  * * *  * ** *  ****** *** * *  ** * *    ** **
    for(i=begin;i>=0;i--)
*  *     * *   ***** ***  **    * *       * ****     ***   *
        *  ** ** * *   ***   ******  **** **  ** * * * ***    *   ** **   *  * ** * * ** *  * *  ** **    ****  *  **
 *   * ** * * * *  ****** *   ****  ** *   * *********** 
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
***  * *   * **  ***** *  **  i,j,k,l;
  **  ** *** * **  **** *  * a[100];
   *** *   **    * **  *    **  b[100];
   * *** ** * ****    * * *** *  ** * * ** **    **  ** *  
 ** * * *  ****     ** *  *    **** ** ** ****  &&  ****    *** ***   ** * * **  
**   ******** ** * *  * * 
    *******  *  *  * ***     ***** *** ****    ** * ****  * *    ** * ***  *  *******     *  ** ** **** 
*    *** ** ***** **  *  *  
 *** * *** *     *     ** ** 0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
  ** * ** **** *  ***  * *   * ***      *   *   * ** a[50],b[50];
   ***    *** **   * *** ** ** *  ******  *********  c[51];
 *  *  ***** *  *  **  **    * * ****   ** *    n1, n2;
***   ***  **** ******** *** *** *  **   * * *  **    i,j;

   * *  ***     *** * *   *   * ** ** ** *  * * *** *
 *  ***  **      ** *** * *  * *** *  ** * *** **  *  *  *

     * *   *     *     *   * *  * **    * *     *
       {
  **  * ** **  * * * * ***  ** *   *   *** ****  * * * **    *     *** ** ****  ********* *    *  );
* * ***** * **  *  * *    **  **   *** **   *

   *  ****  ** **   **  *     **  * ** **  * *  *   **  ***
 ** ***      * **     *    * **  *      * * * *
*  *  ***  **     ** ** ** *    *   * * * ****     * *****  *    * ***     *** *  *  *  ** * * b[i]);
*    ***  *   **  * ** *****         * * *



*** *  ** * * **  * ******* * **   ***  * * * *** ** * ***    *   
 * ***   *****  **** * *  *  **   *** ***
   **   *** *****       * ***    * ***  **  *    *  *  *  *  * ***  *  * ** **  * *
*****    **  **** *  ** **   ** * **   ****** 
     *** **    * *   ***** ** * *    ****  **   *  ***    *** * *  
*   *** * ***        *  *   ***    * *   * 
   *** ** ** ******** **   *  * ****   **   * *  *  *  ****       *** *  *     
********  * *    *   *   *****      ***   **      

 * ** *     *  * ***** ** *  ******  * ** *** * **  ****
*** **     * *  **** *** * *  *          **   
* *    **  *  **    * *** * **   *      * *****      ***  **** * ** *** *    * ***  ***** 
*** *  * ***       ***  **  **  ** *** ** * **  **  *     ** * ***  * ***    ***  **
       }

**  *  * *    ** ** * * * **  *****    * *  * * *        
       {
** **  * * * ***  *  ** **    * * * *** *   **** **   ****  *   ****  **      ****** *****   * ** **  
       }

* *  **  *  ***      ** **   ** * ****  **   ** *  ** **    *    *
 *    ** ** **   *  * *  * **     *  * ***  **   ** * *  *
* * *   ***  **  * **   **    *  ** **  ** *  * * **  ** *****   *  * ** **** * * ** * * ***        ** 
* *  *** *   * **  *  ** **** *****   ****  ****     *  *


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **   * **  * * 
#include  * ***  ****  *  
#include ***** ** ****
int main ()
{
     * * * * ***    *** ** i,n,m,c=0;
* *** **   *  ***  *  ** * A[60]={0};
 ****  ******* **  ***  ***   *    *    *** 
    *       *       *   * *     *** ("%s * ** * * *
**  *  ** **  * *    ****** ***   *  ***   *  *  *  *  **  **   * 
**** *        ** *** * *  * * 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
 **** *  *****   **** **   ** *    * * ** **   ** *  * **** ** * * *** 
    }

 * *  ** * ***  ** *   *  *** *  *****  **   ** * ** a);
**  **  * **  **  * **  *** ****  *  ***  ** **** b);

    for(;;) {
*    *** **  ** **  * *********   ***        *******  *  *  *** * ** {
* * ** * *  **** * * * * **    **    * ** **  *  * **  ****  * ** **  ***    *    
* ** *** * ***  * * *  **  *  * * *        ** ***    *** *** *  * * * *  ** *    **  ** **   *
  **   * *   *   *   ***  *****  **      *  **   ** * *   ********  ****** *** ***
 **    *** *  * *  * ** *   * *  *  ** **  *  **  *** * 
* ** * **      ***** ** * * * ****  **      **   * * * {
 * * ** ** **** ***   *    ***   ***** *  ** *    *   *    *  **** ** *  * ** *  *
 ***** * * ******  ********   *******    * *   **    * *    
    }

    for(;;) {
  * * *    * *    *   *    **  *** *  ** ****  *  *** *   * *** *    {
  * *  **      **  *  **  ***** *  ** ***   ** **  ***** *  *  ** ** *** *     * *** *** * 
 ** * * *** **  ****   ** ***  * **   **    * * ** **   ***  *** **  **  **   * **   * 
 *    * * ** ***    *   *      **    *** *** *** ** * * **  * * *   * *  *   **  **   ******
      * * ** ** ****** *****      ***  *    * *   *      
  *    * *   ** * ** *    *  *** **   * ** ***** * *  *   ** *** * ** {
* ****   **     * *  *  * * ***** ***    *    **  * ** ** *** ***   * *    **** **  ** *   *
*      * * * * *  *  ** *    * * * **    *      * **** 
    }

**  * * * *  *      * * * *    * * ** * * *  ***  {
       *** * *  * ***  *  **   ** ** * ** *    **    *** **** *  *  *  && a[i]<=57) {
*   ******** *   **** * ****  ****  *   *  * ***      ****  ***   **  * ** * ** ***   ** ** *****  *
* **  ** *  ****  *** *******    *    **  *   * * * **  **
 ** *  ******** ** ***     *  *    * **  **  * ** *** * **  **   ** *  *   ** && b[i]<=57) {
 * *   ** *    * **   ***     *  *   ** *     * ***** **   * ** *  * ***   *  *    * **  *   
** * **** *** * *********   ****   **  *  * **** 
    }

    for(j=50;j>0;j--) {
*     ** * **   ** * **   **  ***  ** **  * * *   **  * ** *** *   *  ***    {
**     * ** *   * *** **   *** ** ***  * *  *  *** *** * **      ***  *     * * * ***  * **
****  * *  *** ****  * *  *   ***  * **     *  * *
*  *  * * *  ***  *  ***   *    **  ** **     ** *  * * *    if(sum[j]+a[j]+b[j]==10) {
** *    * **** * **   * *  ** ****  * **      * **    *  * *******  *****   * *** **** *  * *   
**   *  *  ** *  * ****  *   **** *  *  ** *  * **    ***  **  *  * ***   * *  * ** *   * **
*  * * * ** ***    *   * **  *  ** * **   ***   * *     * *
   ****     * *  *  ** *****  **   *   ***** * *  if(sum[j]+a[j]+b[j]>10) {
  ** ** * * ****   *  *   **  ** ***    * *** ** * * **  ***     * **** ******  ** *    * *    **     **    *   
*  **  ****** * **  *    **    **   *     *     ***** *****   ***   * *****   *  ** 
 *****   ** *      * **  *   * *    * *      ** 
    }

    for(j=0;j<50;j++) {
 ** ** *  **    ** *     *   *  * * ** * ********   *    *  *** *** {
 * ** **** ****** ***** ****  ** *    **** * *  *** **    **  * * ***** * *** * ***  *      * * 
** *  *  ** * **  **   *    *** **  *    *    * *
    }

    for(;j<=49;j++) {
****  ** * ** *   ******   * *   * *  ***  *    *   ****** *** *      sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.208
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.3k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5.6k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5.9k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 4.6k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.2k views
12,783 questions
183,443 answers
172,219 comments
4,824 users