Final Exam 3 (20%)

1 like 0 dislike
2.1k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 2.1k views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * *** ** *** * 
#include ** ****** **  **  *  
char a[100],sum[200],space,i;
int main()
{
    ** *  *** *** * ** **   ** ***    *****

   * *    ** * *  *   ***** *  *** **  ** *    
  *  *   ** ** * **   *** *   **** *  *****  * *  ***    '){space=i;}
* *   ***** *  *  * **   ** ***

* * *     **** ***   *   ****** * ** * **    ***** * 
* * *** *  ***  ***    ******  *   ** *   *** *  * *   **** ****  * * 
 **     *** **** ******* *** 


***  * ** * **  *** **  *  * *  * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 * *  **     * *   **  * 
*   *  *** *   *  *  
  ***** * **  *** *** 
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
* *  *   **** ** **** * *   num1[51],num2[51];
* * * * *    *********   * i,m;
*    *  * ** * ** *    *    arr[51]={0};
**  *   *     *    *  *  * ** 
*    *** *  *   * ****      **  *    * %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
 * ** * * **  * **** *** * ***   ************     *  ** ** ** ***   **** **
    }
* * **   ** * *    **  *  *  (i=0;i<(strlen(num2));i++)
***  * * * **  * **  *  * * 
 *** * **    ** **  ****** *   **  *  ****** ****** *  * *** *  *    **  **** * **
 **  ** **  *  **      ** ** *
* *  * *** ****  ** * ******* (i=0;i<=50;i++)
 **    *  *  * *****    
 * **  **    *  *   *****  **        ********* **** *  ***      
   * ****  *  *** *   *    *** *  *   *     *******  
**   * ********* * *** ***** ** *   *    ** * ***   * *  ***     ** *  *  *  * ***** ****     * ** *  * *
 * ***   * *** * * *  ** *   **       **  *  *  *   * *  **** *  *    * ** * * **  * * **     **
**  * *** **  ** * **  *  *****  **  *     * * ******
    }
    ** ** ** ** *  * *** *  * * * * *  ***     * ****
    {
**** * *   **   * ** ***** * ** **** **   *****   ***  * *   * 
    * ** **     *** *  **  * * *   ** ****   *** *  
*  *   *** ** ** ********* *** ** *****  * * **  *  * *   ** *****  *  *** *  ***  * ***  *** 
***     *  *    ***   * * **** ***   ****    *  *****  *
  *  *  **    * * **  *      * * ** *  ** *****  * ** ** **   ******** *
* * * *  **   **  *****   **   *  * * *****  **    *
* *  * * ****** * *   **  *   *      *   ***  * **** ***** **  *    * *  *  * **  *      *
   *****   * ** *  *       ** *** *    *  *  *  ** *   * **  **  *** **  * * ***  **  * ** *   *  **  * 
 **   ** * * * *    ***  * *******  * *    * **  *   **
    }
*      *       * *   **  *     0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
** *** ** *    *  * *   *    a[n],b[n];
   *         ***  **    ** ** ** ** ****   * *** **   *
 *** *  *  **** ***  *  *** l1,l2;
** ***  *** *   **    ***  i=0;
 *      **   * ** * **      ** *
       **   ************  **  *** * 
*   **  *   ** * ***      *  **** *  *  *  * ***  * 
 **   ** *  *     ***** * *  ** ******   ****    ** *
** *   **** ** *   **   * *      *  * **   *    *** 



*  * * ***  *  ** *    ***** ** *   * *  * * ***  *  * *** **   *** ** ** *  * ****    ***  *** **   ** *****  **    





* *   **** **  * ** ***   * *     *  **      * * **  *



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
*** * * *** * **   ** ***      a[50];

*  *    * *    * *  ****  **  ** b[50];

 **  ** ***   * *   * **** *  c[51] = {0};

  **  *** *    ***  *  ******          ** *  * ** a, b);

*  ****** * *** ***  * *** ***** ** i = 0;

  * * **** *** *** ** len_a = strlen(a);

**    * *   * ** *    * ******  *   *  len_b = strlen(b);

 ***    *** * *  **  *  ** = 0; i < len_a; i++)
 *  ***    ** * ***  **     ** 
 ** ** * *** ***   **   * * ** * * ** ****  * ****   **   = a[len_a - i - 1] - '0';
 ***  **  *    ****   * * ***
*    *  **    *   ***** * *  * * = 0; i < len_b; i++)
  ******  ******  ** * ****
**    * ***** * ** ** *  *  *    *  **  **   * * * *     ** ** += b[len_b - i - 1] - '0';
** *** *  * *    *****

 *     **** ** * *  ** ** *      * = 0; i < 51; i++)
**** **  *** *    * *    * * *
***   ******  *** *******  * **    *   ** * *****  *** > 9)
     *  *** *        * *   ** *   ** *** * *  *   * ** *   * *
 * *  *  ***   * * *******  ** ***   *  *** * * **   *** * * **    **  ****   *  * *   + 1]++;

 *** **  **  **  * ***   * ** * *   * *  **      ***      * *   ***** * * *  *  ** %= 10;
*  **** *      ********* ***  *** * *  *** **  *    *
**  *   *** ******* * ***  *

* *    **   *    ** ** * *       nonzero = 0;

 ***** * *      * *** *  *** * ** = 50; i > -1; i--)
*  ***  **  *    *** *      ** * 
* *   *  *   *      **  **  * **   **  *    * *   * ****** * * * != 0)
*  * *****    *  ***      *   ** ** **   ***  ******* * *  * 
*  **  *  **    **  *** *  **    *  ****  * *  ** ******  ** ***  ** ***  ***  * *** ***  ** *  = i;

* ** *   *  *****        ** *  *   *    *  * * *   ***  *  * ******* ***  *   **  *  
** * *  ***** ** ***       **  ****   ** ********  * ***
    }

    **    **** **** * **  ***   = nonzero; i > -1; i--)
  * * * *   * ******* * ******
* **  **   ** *    ******   ** ****     * * ****  ****  *   * * *    * ****** c[i]);
  *    *    * *  **** *  *
*  *  ***** **  *  * **** ** *      0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

     *** * *  **** **    *  * *  ***  *  *    *** * *********** ** ** *     * ** 
    for(i=0;i<strlen(a);i++)
  * ***  *** * *  * *** ** * ***** * * * * *   * * **  
**  **   *  ***  ***** **  * *  * *  *      * **   *  * ****  *    ** *** ** *   *  **  
* *     ** *  * * ****   * * * ***   **** *******  
    for(i=0;i<strlen(b);i++)
*  ***  *   ** **   ** * ** ****  * **  *    ** ***** *
   *   * **** **       *  **  ***** *  * **** **** *  ** ****  *      *** * ** * **     ** *
 *  * *  *  *     * ** *** *      *  **  *  * ** * * 
    for(i=0;i<50;i++)
  *  ***   * *  ***** ****  * *   **    * *    * 
* *  ** *  *   ** ** * *  **   ***  ****** * * **  * ****  * **  ** *  *****     *   ***  > 9)
* * ******    *      * ***  * * * ***     ** * * ******* **  **** ** *** *******  *** **  *** ** **    **
*  *   **       * ***  * * ** **** *** * *    ** *  * * ** * ** * ******* *** ** *  ***** *********** ****  ** *  **  * ** * ****     
 *   **** ** **   *  *    ***     *   ** ** ********  * *  ** *** **  * ***** **   *  * *  **  *** **    * *  **  **  *  ****** ** *  *  * 
 *    * *  * *** *  **  * *** ** * ** * * **  * ****** ***** * *    *  ** ****  * *** * * **** * ** * *    ** * *   **** 
*   **** ***  ** *** * ** ***** ** * **    * **    ** *** 
    for(e=51;e>0;e--)
* * **** *  ** *   ** * *  ******   *  *      **   **  *
   *** * *   *      **     **   **  **** **  *   ** ***** * ** *   *  * *   ***   != 0)
   *     *   ** * *   ****** *  ** **** ***  *** *  *  *******  * ******      * *** *  *****  * ****    
**  *** **   * * ********** *   ** * * * *****    *** *    * * * ** * *      *    * * *  * *   * ** ***        **  **   *** *   *   * ***  *   
*    * *   **  * ***  *   * * * ** *   * **** **  *    *   * **  ***   * *** *****  *    **   * * *    ** *  *    *   ***   ** *  ** ** * *    ** **
**   * **    * *  **  *** * *  *** * *       ***    ** ** *  * **** * * *  ****   **  * * * *    ****
**  * *      **** *  *** * *     *** *  * 
 *  * *  *  *** *  *******  * ***** ****** *  *   *  *  * *  ***   * * * * *  ***   *
    for(i=begin;i>=0;i--)
** **     * *** *    *   *    * *  * * ** * *******   *
*  ***      *   * *  **** * **  ** ******    **** ******  ** * ** ***  * * *  *  **  **    ** ***   * **** *   
 *  *    ** * ***  ** *** ** * *  *    * **  ***   *
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** ***** **  * ****   *  **  * i,j,k,l;
* * * ***** ** ** ***   ** *** a[100];
**   * * ** *  ***        * ** b[100];
 ***   *   *    * **  *     **** **  *  * *** * *    ***
  *** *****         * * *   ** ****  ****   ***   && **** *  ** * *   ** *  **
* * **   **   *   ****  * **   
   *   * **** **   *  **** *     * **     *   ****  **  ** *  *** *   ******** *   **  *****
* ** * ** *** *     *  * **
*  *   *** * ***   ****   **  0;
}
answered by (-229 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
**      *   ** *  ** *** **  *       * ***** *  a[50],b[50];
*  * ** ** * * * * *   * *   ** * *******   *  *   c[51];
  * *  *****    ** **  *******    ***  **     * n1, n2;
  ****** **********  *  * ******  * *** * *     i,j;

    * **  *** * ** *     ***  ***  *    ******   * *       * 
*  **   **  *  * ***   * ***  *    *     *  ****  *   **

*   ** ***   * * ***  ***    * *  * ** *    **   ***** *** **     **
       {
* * ****   *       * * * * ** * ** *  ** ** *   **  *    * * **** **   *  *   *   **  ** ** ** );
**   *** *** *** **    *   * **  *  ***    ** *

  *   **  *  ****    ** * *******     ***  ***  *  * ***   * * **
* ** * ** * **** * *  * *   * **   **  *   **  * ****
***** *  ***  *  *    **   * *  *    **  *    **   *      * *   *    *    **  *****   * ** * b[i]);
  ***** **  ***  ** * * ***** **  **    ** ***



*** * *    *    *** * ***  * * *   ** **  * ******  * **  * *** * * *  *  
*  *  * **  **  **    ***** *  **  ** **** **
 **   *  ** **   * *  *  ****** **** ***   ***  ** * * *  ** ***      ***** *     
****** * ***  * ******   **** *  *  * ****  *
  *** *  *  ***   * * **** ** *  *   *   *   * *  *** *********    
*      ***   * * *** *  * ** * * **** * *
**  ** *    *** * ** *    **    **  ***   *    **** * ****  **  *  ** **  *** *** * 
      *   *      **** * * * * ****  *  *  *** * 

*  ****  *   ***  **   * ***** ***              ** ***  
 *  * **   **    ***    ***   **  ** *  * **** **
*      *    *** *   ** * *     * ** ** ** ****  *     ** **  ***** ****** * * * ***
  ** *  *  *    ****  *    *   *** *  **   ** ** ** ****** * * *   *     *** ** **   * 
       }

*  **   * **** * *     ** **  * ** ***  * *  *  *** * **  **    * **
       {
 * ***** ***** ******  ***** *******  * **   *** **   * *   ** *  * **   * ***   **   *  * * **
       }

  **   * *  *    * **   ** * *   ** *  *  ** ***   *****
* **  **  ** *   *     **** **    *** ** * *** *   
* * **  **   * * *   *   ***  ***    * *  **      *    *     * * * *** ** *   * ***  * **    ***      
*** ** *  *      * ****    *    *** * *** *        ** *


    return 0;
}
answered by (-193 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * * * ******
#include  ** *          *
#include **  *   *   **** 
int main ()
{
**** ** ** ** *** *   *  * i,n,m,c=0;
 * ** **** * *  ** * ** * A[60]={0};
 * *  *   **** * *  *   **   * *    * **** **
 **   *  ****  *  * *  **    ("%s  **  *  * ****
 *    ** *  * * * * *  **  ** **  ** *   * *** *  *  ** *   * ****   *   
*    ** * ** *   ***** * *** **  0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
 *   ****  * *****   ***      *** * * **** * ***** ** * *     ** **
    }

**     * ** **  *   **  ***   * ****   *   * ******* a);
*** *** * *  ** **     *     **  *  *   *****  b);

    for(;;) {
   ** ***    *   ** *** *****    * * ** * *  ***   ** * **   *  ** **  * {
*** *  *  * ** **       *   *  *      *  **  ** **  ******  ** **  **  * ***       * 
 ****  *  **  *  *  **  * *  *** ****   ****  * *  *  **  **** *        * *       * *     *  
 ** * *** ***  *  * ****    *        **   *** **  * ***** ***    * **  ** ***  ** ***
  *  * **  *** * * *  * *   *    * *      * ** ***   **
***    ** *  * **** *** *****  *  *****       *  ******  ***   *  {
****    * * * ** * *  *  * ** **   **  * * *   ***     ** *** **  **** *** *   **  
*****  ******** *  * **   ** *  **** ***   * *****
    }

    for(;;) {
***** *   *   *** ***     * *** * ** * * *****  *****      ** ** *  **  {
 ***      *     ** **  * **   **  ***  *** * **   *  ****  ****    *  **   **    * **
**    ***    **  * * ********** * * * *** *   * ****   ** *     *  *** * * *    **   * ** **
*  ***   *  ******  *  * **** * *  **   *  * **  **     * ***   * **  *** ***   *    * *
 *  **   ** **** * *   *****   ***   ** *** * *    * ****  * 
********      * * ** ***   ** * **  * *  *  *  * **** * *   *   {
* **  **  * * *    *     *  *****  * ****** **** *****  *** * * * *    *     * *
   *  *** *     *** *****   * * *  * *** **  *
    }

         * ** * * *** ****  ***   *   ** * *    **  {
 **** *  * * *  ****** *  ****** **   **** *  ** ** ****    * && a[i]<=57) {
 *** ****** ** *  ***  *** * *  *  *   *   *   **  * *  * ***    *   ** *** ****  * * ** *
 **  ***  *  *  * * ** ** **    ******  *   * ** ***
 *  ****  * * * *  ***    *  * * *  * **** **** ******   *  && b[i]<=57) {
  *     *        **  *   ***  **  **  **  **  *  *** *  *  **   ***      ** **   ** **  
 *    *** *  * * * ***  *   ***   ** ** *     **
    }

    for(j=50;j>0;j--) {
*    ** * ****     ** *    ****    **** * * * * **  *** *** ***     * * *** {
  ***  * **  *     ***** ****  * **       ******        *     ** *  **   ***** * ** ** ** * 
* *   * *** ***  ** * *** ***  *****   * *  *** * * *** 
 ***  * ***** **    * * ** ****   *** *****   *  ** * ** if(sum[j]+a[j]+b[j]==10) {
 * *   *  ********* *  * **** *** *  * * * *** * **   * * **  *    * * ***   *  ** *** *** *
    *  ** *   ***  *  *  *** * * * ***** ********  *  *** *  * * *    * *** **  ** ***  **
*   ****  *    ** *  ***  ** ** * *  *    ** **    ** *   ***
   ***   *** **** ***   *****  ***   ** **  ** * * *  * *** if(sum[j]+a[j]+b[j]>10) {
** * ****  *  **  *  ***  *** *     ** ** **  *  *       * * **** * **   *    ****** * * *  *  *  ** * 
 **** ** *****  **  *  **** * *** **   * ****  **   **** **** **   * **     * * *   *** 
  ***  ***** * *  ***  **  *** *** **  * *  ** * 
    }

    for(j=0;j<50;j++) {
**  * * ** *** ** *  *****  *** **  ***  **  ** * *** *  ***      {
**   **  * *  *  * ** * * * * ***    **   **  *    **  * * **  **  * **   ** *
   * * *  * * *** ** **  **         * * *** ****  **
    }

    for(;j<=49;j++) {
 ******* *  *********    ***** * ****     *  *  **** *  **   *  *  *   sum[j]);
    }
}
answered by (-120 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.73
©2016-2024

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.8k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.8k views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.2k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.5k views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 431 views
12,783 questions
183,443 answers
172,219 comments
4,824 users