0 like 0 dislike
12.8k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 12.8k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * * ** **** x[] = {77,22,88,11,22};
* **** * * *** * * * size = 5;
    
* * * * ***** * * print the array */
* ** * * * ** * ** *** i = 0; i < size; i++){
*** * * *** * * * * ** *** *** * ** * ********* * ** * ", x[i]); * * ********** * * * ** ** **** **
** ****** * * **** ** ** *
* * **** *** * ** * * *** ****
*** * *** * ** ***
* * ***** *** ** * * * I need this to happen size-times */
*** * * ** * ** * *** * * j = 0; j < size; j++){
* ** * * * * ********* *** ** *** * * * * from left to right */
* *** * ****** * * * * ** *** ** ** **** i = 0; i < size-1; i++){
* *** ******* *** * *** **** * * * ***** *** ***** *** * * *** i-th element with its neighbor to check if they are in order */
* ** **** **** * *** * ** ********* *** ***** * ***** * **** ******* ** > x[i+1]){
*** * * * ** * * *** * * **** *** *** **** * *** * ** * * *** ******* ** ** ** ******* exchange the values of x[i] and x[i+1] */
** ** ** ** * * * ** *** **** * * * *** ** *** *** * * *** *** * *** ** * temporary; ********* * * ** * **** * * ** * ** ***
***** * *** * **** * * * ** ** * *** * *** * ** **** * ** * ** **** * * *** ****** * ** ** * * = x[i];
* * ***** ** * * * * ** *** ** * ** * * *** *** * * ** ***** * ** ** * *** ** = x[i+1];
** * * **** * ** ** * * *** *** * ** *** * * * ** * ** *** * ****** ***** * ** * ** = temporary;
*** * *** ** * ** * * * * ***** * * * * * * * ** * * *
* * * * * * ** * * * * ** * *** * ** *** * **
**** * * * * * ** * ******
*** ******* * ***
** **** ** * print the array */
* * * * ***** ** * * **** ** **** sorting: \n");
* *** ** *** * **** ** ** * i = 0; i < size; i++){
** *** *** *** *** *** * *** * *** * * * * * ", x[i]); * * * * ** ******* **** * ***
* **** ** ** ** ****** *
**** ******** * * * * * * * ** **
*** ** *** * * **
* *** ** *** * *** ***
*** ***** * * * * ** ** * * **
**** ****** ** * ** *** * ** ** * * * * **  
* ** * * ** ** ****** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * ** ** * ** * * * * x[] = {77,22,88,11,22};
* *** * * * * * *** size = 5;
    
** ** * * ** *** print the array */
* * * **** ** * * *** * * i = 0; i < size; i++){
* ***** * * * **** **** * ******* * * * ** **** **** ", x[i]); * ** * * *** *** *** * * *
* * **** ** * * ** *
* **** * * ** * *** *** * ** * * * * *
* ** * * ** * *
** * ** * ********* ** * * * I need this to happen size-times */
** * *** *** *** **** * * * j = 0; j < size; j++){
** ** * *** * * * **** * * * * **** from left to right */
******* * ** * * * ** ***** * * * ** * i = 0; i < size-1; i++){
* ****** * * *** ** * * * * * * ** ** * ******* *** * ** * * * * i-th element with its neighbor to check if they are in order */
* * * **** **** * * *** * * *** ** ** * ** * ** * *** *** * * ***** * > x[i+1]){
** ***** ** * ** * * * * *** ** ** ***** **** ** * ** ** * ** ** * *** * ** * ** ** * exchange the values of x[i] and x[i+1] */
*** **** * * *** * *** ** * * ** * * **** * ** **** * ** ***** *** temporary; * * ** * * * * * * ** * ***
* * * * * *** * * ** ******* * ** ** * ****** * **** * ** * * * ** **** ** * * = x[i];
* ***** * ***** **** * ** * ** ** * * * * * * * ****** * * * *** ***** ** = x[i+1];
*** * * ** ** *** * **** * * **** * * * * ** ** **** * * * * *** * ** *** * *** * * ** = temporary;
*** ******** * ** ** * ** * * * * ** **** * ** **** *** *** ******* * *
* ** * ******* ** ** ** **** ** *** **
* ** * * * *
* * * ** * ** * **
* *** *** ** **** print the array */
* ** ** * ** * * * ** * * * * * **** sorting: \n");
***** *** *** *** * *** ** i = 0; i < size; i++){
*** ** ** ******** ** ****** **** ** * ** *** * **** * ** * ", x[i]); ** **** *** * * * * * ** * *
** *** ******* ** ** ** *
*** * * * *** ** ** * * **** * ***
***** * * * * * *** *
* ** ** ** ******
* * ** * * ** ** * *** ** *** ** ***
* * ** ****** *** ***** * * **** ** * * ** *  
* * * * * * * * *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** **** * ** **** ** *** * x[] = {77,22,88,11,22};
* * * * * * ** * ***** * * size = 5;
    
* **** * ** print the array */
* * ** * * ****** ** ** i = 0; i < size; i++){
* * * * ******* ** *** * * * * ** * * * * * ** * * * * ", x[i]); ** * **** ** * * ******** **
* ***** * ** * *
* * * *** * * * *** * * * ***** ****
* *** * *** * **** *
** * *** * *** *** I need this to happen size-times */
* ** ** * ** ** ** *** * * j = 0; j < size; j++){
* * * ** ** * ** **** * * ** ***** ** ** * * * from left to right */
**** * ******** *** ** **** * * * *** * * * * i = 0; i < size-1; i++){
* ** ** ** * * ***** ** **** ** *** **** ** * * * *** * i-th element with its neighbor to check if they are in order */
** * * ** * * **** * * ** ** **** * ** *** *** **** ** ** > x[i+1]){
***** * * ** * **** *** ** * *** *** * *** *** * * *** **** ***** ** * *** exchange the values of x[i] and x[i+1] */
**** *** * ** * * ** * * * *********** *** * ** **** * ***** *** * ** * ***** * temporary; * **** * **** ** *** * ** * *
* ** * **** ******* * * ********* * *** ***** ** ** ** * * * ** * * *** *** * ** = x[i];
* * ** * *** *** * * * * ** ** ** *** *** * * *** ** ******** ** *** ** ** * = x[i+1];
**** * * * ** *** ** ** * ** ** ** ** * **** ****** ** ** *** ** ** * *** * * ** = temporary;
* ** ** * ** * ** * * ***** ** * * * ** * * * * ***
**** ***** * **** ** * * * * * * ***** ***
******* * * ** ** * *
****** * *** * * * * *
** * * ** * ** * * ** * print the array */
*** * * ** * *** ** * * * * ** *** ** sorting: \n");
**** ** * * * i = 0; i < size; i++){
** * **** ** *** *** * ** * * * *** ******** * ", x[i]); **** * *** **** * ** * *** ** *
* ** * ***** * *
* * * *** * * ** ***** *** *** **
* *** * * * ****
** **** * * * *** * **
**** *** ***** ** *** ***** * **
** * * *** * ** ** * **** * * *** *  
** *** * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * ** * ** x[] = {77,22,88,11,22};
** ** ** ** *** * ** size = 5;
    
* *** **** **** ** * print the array */
* ** *** ** * ** ** i = 0; i < size; i++){
* ** **** ********** ** * ** ** ****** ** * * * * * ", x[i]); * * ** * * * ** * ** ** *
***** * * * ** * ***
***** ** ** * ** **** *** ** * * *** * ***
*** * * ***** ***
* * *** * * *** ** I need this to happen size-times */
** ***** ** * * * *** * j = 0; j < size; j++){
** * *** * * * ***** ** * *** ** from left to right */
**** ******** * ** ** * ** ** **** * i = 0; i < size-1; i++){
* **** * * ** * ** ** * ** * **** * * * * * ** *** * *** ** * * ** i-th element with its neighbor to check if they are in order */
* * ****** ****** * * ***** * *** * * * * ** * ****** * * * * **** > x[i+1]){
* ** *** ** * ** * * * ** ** ********** *** ** * * * ** * * * * ** *** * *** exchange the values of x[i] and x[i+1] */
* * * * * * * *********** **** * ******** ** ** ** **** *** * * * *** * * temporary; ** * * ** * * * ****** *** ** * ** * *
*** *** ** ** ** ** ** ** *** * * ****** ** * * * ** * * ***** * * ** *** * * **** * * ** *** = x[i];
***** * ** * * *** * * * * *** ** * **** ** ** ** ** **** * * * * * ** *** * * = x[i+1];
** ** * ***** ******* * *** * ***** * * * * **** *** * * * ** * * * *** *** * * * **** *** = temporary;
** ***** * *** * *** * ***** * * ** * ** ***** ** * * ** * * *** **
* ** * *** * ** *** *** ** *** ** * *
* * ** *** * * *** * *
******** * * * *
****** * ** *** * print the array */
* * ******** * * * *** *** * ** sorting: \n");
**** * ** *** ** * *** * *** i = 0; i < size; i++){
* * * * * ** * ** ** *** *** * ** *** * ** * * *** ", x[i]); *** * * *** * * * * * * * ** *
** * * ** ** * *
*** *** * * *** ** *** * *** * * *
* *** * * * *** **** **
** * * ** *** *** *
** * * *** * *** * * ** * * ** **** *
** * * * * * * **** * * * ***** ** ** **  
** * * *** * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * **** * *** ** ** x[] = {77,22,88,11,22};
** *** ** ****** * **** size = 5;
    
*** ** ** *** * * ** * print the array */
* *** * ** * * * * i = 0; i < size; i++){
* * *** * * * * * * * ********* ** * * * ", x[i]); ******* * * **** ** ** * ** *
** *** * ******* ** *** *
** *** * *** ** **** * ** ***** ** *
** * ** *** ** * *
** * *** * * * * *** * I need this to happen size-times */
* * ** **** * * **** j = 0; j < size; j++){
*** ** * * ** ** *** ** ***** ** ** * * from left to right */
* * *** **** * ** ** ** ** ** * * * ******** * i = 0; i < size-1; i++){
** * ** * ** *** * * * * * * * ** * ** * *** ** ** *** *** ** ** i-th element with its neighbor to check if they are in order */
*** * *** **** * ** *** * ** * ** * * * * * * * ** * * > x[i+1]){
* ** * * *** ** * *** * ** ** *** **** * *** * ** **** ** * * * * * * * ****** * exchange the values of x[i] and x[i+1] */
**** * * ** *** ** * * ** * ** ** *** * *** * ** * *** ** * ** * ** ** * temporary; ***** ** ***** * *** * * **
******* * * * * * * **** *** ** ** **** ** * ** ******** * * * *** * ** ** * * * * = x[i];
** * *** *** *** **** * * *** ** * *** * * ** * * ** * * * * ** **** ** *** * = x[i+1];
* * * ** * * * * * **** * * * * ** * ** *** ** * * ** ** * ** **** * ** ** ** ** *** = temporary;
* * *** * ** ** ******* ** * * * * **** *** ** * *
* * * * ***** * * * * *** ** ***** *** * **
**** * *** * ** ** *
* *** ** ** * * ** ** *
**** * * ******** ** ** print the array */
***** * * * * * *** * * ** *** sorting: \n");
* * *** ** * *** * ** * **** i = 0; i < size; i++){
* * ** * ***** * * * * * * * * * ** ** *** * ", x[i]); * ******** * * * * * ******** * *
** * * * * ** * *
*** * ** *** * * ** * * ** ** * ** * ** * *
* ** ** * *** ***** *** *
*** ** ** **** * *
** * ** * ** * * * *** * **** **** * *
* * * ** * * ** * ** * **** **  
*** * * **** ****** ** ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * * * * x[] = {77,22,88,11,22};
**** **** * * * ** * * size = 5;
    
** * * * * * ** *** *** print the array */
*** **** *** * * * ** * i = 0; i < size; i++){
**** * ** *** * *** * ** * * *** ** ** **** * * *** * ", x[i]); * ** ******** ** **** ****** * *
* * *** *** * *** * *
** ** * * *** * * * ****** * *
* * * * *** *** **** *
* * * * * * I need this to happen size-times */
* * * ** * * * ** * ******* * j = 0; j < size; j++){
* * **** * **** ** ** **** ***** * * * from left to right */
* ** * * * *** ** * ***** * **** * * *** ** ** i = 0; i < size-1; i++){
* ** *** * ** ** * * ** * ** * *** * ** ** * ** *** * ** * * *** i-th element with its neighbor to check if they are in order */
* *** * * **** *** **** * * * * ** * ** * *** *** * * * ** > x[i+1]){
** * * * *** ** * ** *** ** * * * ** * * ****** * ** * ** * ** *** ** * *** * ** **** * exchange the values of x[i] and x[i+1] */
****** ** **** ** **** * * *** ** * * ** ***** * *** * ** * ****** * * * * * ** * temporary; * * ** * *** * * * * * ***** *
***** * ** * ** **** ***** ** * ** * * **** ********* *** * *** * * *** * * * = x[i];
**** *** ** ** ** * ***** * ** ** * *** * * ** *** *** *** * * * * ***** * * = x[i+1];
** * *** * * ** ***** **** *** ** * ***** * * * * ** * **** * **** *** ** ** = temporary;
* * * * * ** *** * * ** ******* *** ** **** * ** ***
* *** ** *** ** * **** *** * ** * **** *
**** *** **** ** * * ** **
* * * ** *
** *** * * *** * print the array */
* * * * **** * * ** *** ** * **** * ** sorting: \n");
** ** **** *** ** ** * * i = 0; i < size; i++){
** ******* ** **** *** ***** * *** * *** **** *** * ** ", x[i]); ** ** * * * * * * *****
* *** ***** * *** *
** ** ** ****** * **** ****** ***** * *
* *** ** * * ******** *
****** * * ********* * **** ***
* ** * *** ** * * ** *** *** *** *****
* * ****** ** ** * ** * ** * * *  
******** * ** * * ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** * * * ** ***** * ** x[] = {77,22,88,11,22};
** **** * ******* * * size = 5;
    
* * * * ** ** ** *** print the array */
****** ** *** * * * *** i = 0; i < size; i++){
* *** ***** ***** ** * * * * ** ** * **** ** * * ", x[i]); * *** *** * *** * * * * *
* ** ** *** * *
** * ** ** * * ** ** ** * * *
* ** * ***** **** ****
*** ** ** ** * ** ******* I need this to happen size-times */
* * ** * *** * **** ** * * j = 0; j < size; j++){
* ** ** ** * * * * ** * * *** ** * from left to right */
** ** *** * * * ** ** *** ** * ** * **** * * ** * i = 0; i < size-1; i++){
* * ******** * * ** * ** *** * * ** * ***** ** * * ** * * * * i-th element with its neighbor to check if they are in order */
** *** * ** ** * * *** * ** * ** *** ** * * * ** * * ** * > x[i+1]){
***** ****** **** * * * ** *** ** ** * * *** * **** * * *** *** * * **** * * *** * ** exchange the values of x[i] and x[i+1] */
* * *** * ****** * * * * ** * ** *** ******* * ** ** ***** **** *** * * * ***** * * * temporary; ** *** ** * * * * * * * *
** * **** *** *** ** * ** * ***** ** ** * * * ** * *** * * ** ** * * = x[i];
* *** * * * * * ** ******* * * ** ** * * ** * *** ** * * *** * * * * * ***** * **** * * = x[i+1];
** ** * * ** * ****** * * ** ** ** * * ** * * ** ***** * * ***** *** * * ** * * ** = temporary;
**** ****** ** *** * ** ***** ** * ** ** *** ** * ***** *** *** * * * ***
* * *** * ***** **** * * * * **** ***
* * * * * **** **
* ** * * ** *** *
* * **** * * ** * * print the array */
** *** ** * ** * ** * ** ** * sorting: \n");
** * *** * ** ** * *** **** i = 0; i < size; i++){
** ** ** * ******* * * * * ** * * ** * * **** ** * *** ", x[i]); * * * * ** * *** * * ******* *
* **** *** * * *****
* * ** **** ********* *** *** * * ** *
** * *** ** * * * * ***
* ** * ******* * * *** **
* * *** ** * *** * ** ** ** * ***** * *
** * * * * *** ** * **** **** * * **** * ****  
** ** ** ** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** **** *** * * * * x[] = {77,22,88,11,22};
* * ** * * ** * *** * size = 5;
    
** * ** * **** * print the array */
* ** ** ** ** * * i = 0; i < size; i++){
* ** * *** * * ** ** ** **** * ** ***** ** * * ", x[i]); * ** * * ** * * *** * * ***** * *** *
****** *** * ****** * * * *
* **** * * ** * *** * * * * * * **
** * ** * ** * * ** **
**** *** ** * * * * * I need this to happen size-times */
**** * * * ******** * * ** ** j = 0; j < size; j++){
* * ** * ***** *** * ** ** ***** * ***** ** from left to right */
*** * ** ** * * ***** * ** *** ** ****** * ** ** i = 0; i < size-1; i++){
* * ******* * * ** * * ******* **** ***** ****** * *** ** * ** **** * * i-th element with its neighbor to check if they are in order */
* * ** *** * ** * * * **** ***** * ** * ** ***** * *** * * * * *** ** > x[i+1]){
* ** ** *** * * ** *** **** * *** *** ** * * * * * ** *** * * * ** ** ** **** exchange the values of x[i] and x[i+1] */
*** * * * * ***** * * ** ** ** * ** *** **** ** ** *** * * * *** ***** * * * ** ** * * *** temporary; *** **** * * **** **** **** * **
* * * ** *** ****** * * **** *** * ** *** * * * * * * * * * *** ** ** ** ** ** = x[i];
* * ** * * *** * *** ** ** * ** *** * * ** ** *** **** * * * *** * ** ** * ** * * = x[i+1];
* * ********* ** **** ****** ** * * * * * ** ********** ** ** * *** *** * *** ** * ***** * * ** * * = temporary;
* * * * * *** *** * * * ****** * * * ** * *** ** *** ** ** ** ****
* *** * * * *** * * *** * * *****
* * * * *** * ** *
** * * * ** **** *
* * ** ** * **** ** * print the array */
***** ****** * * * *** ***** sorting: \n");
* ** ** ** * * ** i = 0; i < size; i++){
* * ****** ** ** *** * * ** * * * * * *** * * *** ** ** ", x[i]); ** * ** ** ** ** * ** ** **
****** * *** * *** **
* * * * **** ** **** ** *** * * ***** **
* ** **** * * * * * ** *
***** **** **** * * * *
*** ***** * ** *** ** ** ** * *
** * *** ** ** * **** *** ** ** *** * ** * * ***  
*** *** * *** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * **** * **** x[] = {77,22,88,11,22};
** * * ** * *** * size = 5;
    
* * *** *** * * * * print the array */
** ******** * ** ** ** * * i = 0; i < size; i++){
* ** * * ** * ** ** * **** * ** * * * * * ", x[i]); * * * * * ** *** * * *
** *** **** *** ** ** *
* * * **** ** ** * *** ** **** ***
**** * * *** **** *
** * * *** ** * I need this to happen size-times */
* * * ** * * * * ** * * ** j = 0; j < size; j++){
****** ** * * * ** *** ***** *** *** ** from left to right */
***** * ******* ** *** * ** *** ** **** * *** ******* * i = 0; i < size-1; i++){
** *** * * **** * * * *** * * * * * * * ** * * *** *** * **** **** *** * i-th element with its neighbor to check if they are in order */
** * ** * ** * *** * * * * * *** *** *** ** *** * ** ******* ** * * *** > x[i+1]){
* ** ** ** * ** ** * * * * ** * ** *** **** * * ******** * ****** * * * ** *** * * exchange the values of x[i] and x[i+1] */
* ** * ****** * * * * * * * * * * * ** * *** ** ** *** ***** ***** * ** * temporary; * * *** * * * ** ** * *** * **
** * * ** * ** ** * ** ** **** ** **** **** ***** * **** * * * ****** * ** ** ** ** * * ** = x[i];
*** * ** ** ** ** * ** ** * ** ** * ** ***** ** * * * ****** * * ** ***** * ** ** * = x[i+1];
* * * **** * ** ** ** * ****** * ** ** * * *** * * * ** ** * * * * ********* * * * * * = temporary;
** * **** * * * * * * *** * ** * * ** * ** ** * * ** ** *** * *
* ** * * ** ** ****** ** **** * ** ** * *
*** ** ** * ** *******
*** * ** ** * * * *
* * * ** * * * *** ** print the array */
** *** * * * ** ** * * * sorting: \n");
** **** * * ******* i = 0; i < size; i++){
* * * * * * ***** *** * * * * * *** ** ", x[i]); *** * ** * * ** *** * *
* ** * * * * ** *
* * * * ** ** * ** **** ***** * * * * *
*** ** ** ****
* ** * ** * ******* **
* ** ** * ** * ***** * * * ** **** **
****** *** * **** ** **** * ******** * *****  
* ** * * * * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** ** *** * *** x[] = {77,22,88,11,22};
** * ** *** ** * * * size = 5;
    
** * * * * * * ** ** print the array */
*** ** * ** * * * * * i = 0; i < size; i++){
* ** * * ** * * * * * **** *** * * *** * ** ", x[i]); * * ******* ** * *** * ** * *
* * *** ****** ** **
* * *** *** *** ** ** * * **** ** *
**** *** * *** * * *
* ** * ** **** I need this to happen size-times */
*** * * ** ** * * ** * j = 0; j < size; j++){
***** * * * * * * ** ** * * ** ******* *** ** from left to right */
* * ** ***** *** * * * * *** ** * * *** * * i = 0; i < size-1; i++){
* ** * ************ * *** ** ** * ** * ***** * * * ** ********* ** * * i-th element with its neighbor to check if they are in order */
* *** * ** * * ** *** * * ** ** * * * * * * ** * ** * ***** ** ** > x[i+1]){
** * * *** ** * * ****** ** **** **** * * * * ** ** * *** ** ** * *** * * exchange the values of x[i] and x[i+1] */
* ***** * ********** *** * ** *** * *** * * ** **** * * ** * * ** * *** * ** * * * ** ** ***** *** temporary; ** * ***** *** * * * * * * *** * ***** *
* * * * ** * * **** * ** * * *** * *** **** * * * * * ** * ** ** ** ******* ** * * = x[i];
* * ******** ** ** ** *** ** *** * * **** * * ** * **** * * * ** *** * * * = x[i+1];
* *** * * * ** *** ** ** **** * **** ** ** ** * **** * ** * *** * *** ** * * * *** * * * = temporary;
**** * ***** * * * * * * *** ** ** * **** * ******* ** **** * *
* ** * ** * * ** ** **** * * ** ** ** ***
*** *** *** ** * * **
** * * *** * * *** ** *
* ** ** ** *** * * print the array */
* *** * ***** ** *** * ** ** sorting: \n");
* * ** ** * *** ** i = 0; i < size; i++){
** *** **** **** * * ***** * *** *** ** *** * * ** ", x[i]); * ** *** **** *** * *** ****
** * * * * **** * * *
**** **** * * ** **** **** * * **
* * *** * **** * * ** *
* * ** * * *** * * *
* *** * * * * ** ** * * * ***** **** * * **
* ** *** * * ***** * * ** * ** * * ** * ** * **  
* ***** * * * * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 7.7k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 6.8k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 3.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users