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Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
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46 Answers

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#include <stdio.h>
#include <stdlib.h>

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answered by (153 points)
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

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answered by (153 points)
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

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answered by (153 points)
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

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answered by (153 points)
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

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answered by (153 points)
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

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answered by (153 points)
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

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answered by (153 points)
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

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answered by (153 points)
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#include <stdio.h>
#include <stdlib.h>

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answered by (153 points)
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

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* ** * ** * * * * * * **** ******** ** *** **** *** * ** ** * ** ** * * * * * = x[i+1];
****** ** ** * * ** *** ****** * * *** ** * * ***** * ** *** ** * **** * *** * ** ** * ** * = temporary;
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*** *** * * * * print the array */
* ** *** ** ** **** * ******** sorting: \n");
* * ** *** * * * i = 0; i < size; i++){
* *** * ***** * ** ** *** * * *** * **** ** * ", x[i]); * ** *** *** * * * *** **
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* ** ** *** *** ** ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
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