0 like 0 dislike
7.1k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 7.1k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** ** ** ***** x[] = {77,22,88,11,22};
* * * *** size = 5;
    
* * * ** * * **** * print the array */
**** * ** ***** * ** ** i = 0; i < size; i++){
** ** ** * * * * * * ***** ** * * **** **** ** * * ", x[i]); **** * * *** * *** ** * * * * *
** * *** ** *** *** *** ***
*** ** * * * ********* * *
** ** * * ****** ****
* ** * * ** * ** * I need this to happen size-times */
* * *** ** * **** * j = 0; j < size; j++){
** ** **** ** * * * ** * ** * * * ** * * ** from left to right */
***** * ** ** ** ** * **** * ** ** * * ** i = 0; i < size-1; i++){
* *** ** *** * ** **** * * * * * * * ** **** **** * *** ** ** i-th element with its neighbor to check if they are in order */
* * **** * ** ** *** * *** * * *** *** ** ** ** ** * * * > x[i+1]){
*** ** ** * * *** * * * ** *** * * **** ** **** ** * * *** *** * * * * * *** *** *** exchange the values of x[i] and x[i+1] */
**** * * ** * * * * * **** ***** *** ** * ** ****** * **** ** * * ** *** *** * temporary; *** ** * * * ** * *** ** ** *
* * * *** ******* ** **** ** * *** * *** *** *** * * * * ** * ** * * **** * * * *** * * = x[i];
* ***** * * *** * * ** ** ** * * * ** *** *** * * * ** ** * **** ** ***** * ** * * * * = x[i+1];
** * * * *** * * ** **** *** *** * ****** * * ** ** **** **** ** * ** *** **** * = temporary;
* * * * * *** *** ** *** ** * *** *** * * ** * *
*** **** * * ** * * * * * ** * *** ** * *****
* * * ****** * * *
*** *** **** ** * * *
**** ***** * * * *** print the array */
** * **** * * * ** ** ** sorting: \n");
* **** * * *** ** ** *** *** * i = 0; i < size; i++){
****** *** ****** * * ** ** * * * * * * ** * ** ********* ", x[i]); ** * ** * * ***** ******** ***
* * ** **** ** * ***
*** * ** ** ** *** ** * * *** ** ***
** ** ***** *** ** **
* ** *** **** * *** **
** ** * * * ** *** * *** ** * *****
* * * * * ** ** * *** *** *** * ** * *  
*** ** ** ** *** ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** ** *** * * * x[] = {77,22,88,11,22};
* * * * * * size = 5;
    
* ** *** * * * ** ** *** *** print the array */
* *** * * ** *** * ******* i = 0; i < size; i++){
* * ** * **** *** ** * *** * * * ** **** * ** * ** ** *** ", x[i]); ***** ** * * * ** ** ** **
* * * **** * * * ** *
** * * * * *** * * ** *
* **** *** *** ** * * *****
** * * * * * * I need this to happen size-times */
** ***** * * *** * ** * * * j = 0; j < size; j++){
** * **** **** * * ** ** **** ** **** * * * *** *** **** from left to right */
* * * ** ******* * **** ** * **** ** ** * *** i = 0; i < size-1; i++){
* ***** *** * * * * * * *** ** *** **** ** * * * ** * *** **** ** ** i-th element with its neighbor to check if they are in order */
* * * **** * *** ** ***** * ** **** * ***** * * * ** * ** * *** > x[i+1]){
* ** * * ** * ***** * * ** *** *** * ** ** ***** **** * * *** **** ** * ** ***** exchange the values of x[i] and x[i+1] */
* ** * ****** * *** * * ***** *** * **** *** ** * * * * * *** ** ** ** * ** * * * **** ** ****** * ** temporary; * * * ** ** * * * * ** *
****** * * ** * *** * * ** *** * * **** * * ** * * * * ** * * *** ** * * *** * * * * * *** * ** ****** = x[i];
* * *** * *** ** ** * ** ** * * * * ** * * **** ***** ** ** * ** * * * * = x[i+1];
** * ** ** * * *** * * * ** ** ** * * **** ** * * * ** * ** * * * * *** ***** ** ** * * ** * * = temporary;
* ** ** ** ** ** * *** * *** ** *** ** * * ** * * *** * *
** ** * *** ** ** *** * * * *** * *** **
*** * ** * ** * * * *
*** * *** * * * * ** *
* *** * ** ** * print the array */
* ** * * * **** * ** ** ***** sorting: \n");
* * ** * * * * * ** ** * i = 0; i < size; i++){
** * * * ** * * ** * * * ** * * ** * ", x[i]); * * **** ** * * * * * ** * ***
* ** * * ** ***
** * ** *** ** *** * ** *
* ** ** * * * * ******
*** * ** * * * ***
* * * ** * * ** ** ** * ** * * *** ***
* ***** * * **** ** ** ** * ** **** ** ** *  
* *** *** *** * * **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** * * * x[] = {77,22,88,11,22};
**** ** * *** * * *** * * * size = 5;
    
* * * * *** *** * * * print the array */
* * *** * ** ** * * * * i = 0; i < size; i++){
* ** * *** ** * * ** * *** * ** * * ** *** ** * * * * ", x[i]); ** * * * *** **** *** **** * *
* *** * * * * *** *
* * *** * * * ** *** * * *
* ** * * * ** ***
*** ** * ** *** * I need this to happen size-times */
* * * * * *** * ** * * * j = 0; j < size; j++){
******* * * ****** * * * ****** * ******** * from left to right */
* *** * * ** ** ** ** **** * ** * ***** i = 0; i < size-1; i++){
* * ****** *** * * ** ******* *** * *** * * * ***** * * * * i-th element with its neighbor to check if they are in order */
** *** *** ** * * * * *** * *** * * * *** ** *** * *** * * * ** * > x[i+1]){
* ** * ********* * **** *** ** * **** *** * ** * **** * * ** *** * **** * * ** ** exchange the values of x[i] and x[i+1] */
* *** **** **** ** ** * ** ** ** *** * ** ** * * * * * ** ***** * *** *** * *** temporary; * * * ** * * ***** * *****
** * * * ** * * *** *** *** *** * * * *** * ***** *** *** ** * *** * ** * * * * * **** *** = x[i];
** ** ***** * ** * ** * ** ** ** * ** * ** **** * ***** * ** * ** ** * *** **** *** * = x[i+1];
* * ** * ** * *** * * * *** ** * **** * *** *** *** *** ** *** ** * * **** * * ** = temporary;
* **** *** *** ** **** * * * * ** * * ** * ** * * * * *****
*** *** **** ** * * *** * ** * * * ** * **
* ** *** * ** * *** * **
* * *** * * ** * * ** * ***
* * * * ** * *** * print the array */
* **** * * * * ******* * ** sorting: \n");
** *** * ** * * * * * i = 0; i < size; i++){
** ** * **** * ***** * **** * ** * ", x[i]); ** ** *** ** ** * **** * * ***
* * *** ** ***** **
** * ***** ** ** * * * ** * * ** ** * ****
****** *** ***** ****
*** * *** * ** * * *
* * ** * * * ** *** ****** * * ** ** **
********* * * **** **** * * * ** * **** ** *  
* **** * ** * ***** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ** *** * * * *** * x[] = {77,22,88,11,22};
*** * ** * ** * ** size = 5;
    
*** ** *** * *** * * print the array */
* * *** ** * ** **** * * * i = 0; i < size; i++){
*** ** * * * * *** *** * **** *** * * ** * * * ", x[i]); ** * * ****** * * *** ***** * *
** * * * ** * * * *
*** * * * * * *** ** * **** *** ** ***
* * ****** * *** *** *
* * *** ** * ** * *** I need this to happen size-times */
**** *** ** *** * * * * * ** j = 0; j < size; j++){
* * ** * * *** * * * * *** ** ** ** **** * ** from left to right */
** * * * * ** * * ** * * * **** *** ** i = 0; i < size-1; i++){
** *** * * * * * * * ** ** ** * ***** * *** * * ****** * * ** * ** i-th element with its neighbor to check if they are in order */
*** ** * * * * ****** * * * ** * * * * ** * *** * ***** * > x[i+1]){
** **** ** * *** * ** * ** ** * * * **** ** * * * * *** * *** ** * * ** **** ** * * * * ** exchange the values of x[i] and x[i+1] */
** ** * * **** ** ** * * * *** * ** * * * ** * ** ** * * ** *** **** **** * * * *** temporary; ** ** * ***** ******* ** *** *
* * * * * * ***** ** * * * * * * * *** * * * ******* * * * * ** ** * ****** *** * ** * = x[i];
** * * * ** * ** * * * * *** *** *** **** **** * * ** ** *** ****** **** ** * = x[i+1];
**** * * * ** *** ** *** * **** * * *** * *** * *** ***** * ** * * ** * * * **** = temporary;
* ** ******** **** * * * * * ** ** ** *** *** **** * **
**** *** **** *** * * * **** * **** *** *
* * * * ** * ***** * ** * *
****** * * ** ****
** * * * * ******* * *** print the array */
******* * * * * * * * **** ** * * sorting: \n");
* ** * * ***** * ** *** i = 0; i < size; i++){
* ***** * * * ** *** ** * *** * ***** * ** ", x[i]); *** * ** *** ** ** *** **** **
* ** ** * * ** ** * *
*** ******* **** *** * ***** * * * * ** ****
*** * * ***** *
* * *** ** * ** ** **
**** * * * * * ** *** * * ** ***** * ** *
* * * ** ** *** * * **** ** ** * ******  
* * * * * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * *** ***** ** x[] = {77,22,88,11,22};
*** * ** * ** ***** * * size = 5;
    
**** ** * * * ** *** * print the array */
** * **** * ** * * ** *** * i = 0; i < size; i++){
** *** * * ** * * ** * * * *** * * * *** *** * *** ", x[i]); * * *** *** ** * * * * * * * *
*** * ******* * *****
* * * * **** * *** * ********* * *** **
******* * * * *** *
* * * * * *** * *** I need this to happen size-times */
*** *** * * ** **** ** j = 0; j < size; j++){
* * * *** ** ** ** ** * *** ** * ** * * from left to right */
** ******** * ** * * *** * **** ** * *** ***** * *** i = 0; i < size-1; i++){
*** ** ** * ** ** **** ** * ******** ** * * * * * * ** ** ** i-th element with its neighbor to check if they are in order */
* *** * ** ** * ** * * * ** * * * * ** **** * * ****** ** > x[i+1]){
** * ***** ***** * **** * *** * * ****** ** * ** * ** ** * ** * * ** * ** * ** ** * * * * ** exchange the values of x[i] and x[i+1] */
* *** ** * * ** * ** **** ** ********* ** *** ** * ***** **** * ** * **** *** * temporary; * **** * * * ****** * * **
** **** * * * * **** *** * * * * * **** * ***** ******** * * * * ** * * * *** * *** ** * * ** * *** = x[i];
* ** ** * **** * * ** * **** *** * * **** **** * ** * *** * *** ** *** * * ** * = x[i+1];
** * ** *** ***** *** * * * ** * * * * ** *** * *** * ** * ** * * * **** ** * ** * ** *** ** = temporary;
* * * *** ****** * * ** *** ** * ** * ** ** *** * * *
* ** **** ** * * * * ** * * ** *
** ** **** * * * * *
* * **** ** ** * **
* ** * *** * * print the array */
** ** *** * * *** * *** * * * * sorting: \n");
* * **** * **** * * *** i = 0; i < size; i++){
*** ** ** * *** * * ** * *** **** * ** * ** * ", x[i]); ** * * * *** *** ***** * * * ** **
* * * **** ** ***
*** ** *** ** ** * * ***** ** **** ** **
* * ***** ** *** * ****
* *** **** ** *** * ***
**** * **** *** ** * **** *** ***** *
** * * * ** ****** ** **** * ** **** ** *  
* * ** * ** **** ** * ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** *** * * * * x[] = {77,22,88,11,22};
*** * ***** * *** * * size = 5;
    
** ** ** * * print the array */
* * * * * ** ******** * * ** i = 0; i < size; i++){
** * * * * * ** *** * * **** * *** * *** * * ", x[i]); *** * ***** * ** ****
* ****** * ** * * ** **
** ** * * * * * * * *** * ** *
* ** * * ***** **** ** *
* * * * **** ** **** * I need this to happen size-times */
**** * * * ** ** * * j = 0; j < size; j++){
* ** **** * **** * * * ** ** **** ** from left to right */
* ** * * * *** ** ** *** **** * * ******** ** i = 0; i < size-1; i++){
** * ** * * ** * * *** ** *** * ***** ****** * * * * **** ** * * i-th element with its neighbor to check if they are in order */
*** ** * ** * * **** * * ** ***** ** **** * * * ******* ** * * ** > x[i+1]){
** * * ** ** *** *** ** * ***** ** *** * * * *** * **** ** *** * *** * ** * * ** * exchange the values of x[i] and x[i+1] */
* * * * **** * ** **** ** * * * * ** * * ** ** *** *** * * * * ** ***** * * ***** * *** temporary; ** * * **** ** * ***** ** ****** ** *
** * ** ** * * ** * * **** * ** ****** * * * ** * * **** * ** * ** * * * *** ****** = x[i];
* ** ***** ** *** ** ** * * *** ** * * * * * ** * ****** *** ** * ***** ** * * * * *** = x[i+1];
** * ****** **** * * ** *** * ***** ** ** * *** ****** **** *** ** * ** ***** * *** * **** **** *** = temporary;
* ** ** ** * ** ** **** * ** * **** *** * * * ** *** * * * * *
* * ** ** ** ** * ** ** **** * * ** *** **
*** ** ***** * *******
** ** * ** ****** *
* * * **** ** * *** * print the array */
** * **** * ** * * * ** * * * * sorting: \n");
** ** * ***** * ****** *** i = 0; i < size; i++){
* ** *** * * * ** ** *** * ***** *** * * * ** ", x[i]); ** * ** * * * ******* * * *
** * ********* * ** * *
* *** * ****** * ** ** *** * *
**** * * *** * ** * *
* ** * ***** * * ** *
* * * *** * ** *** **** * * ** ***
* ** * ** ** * * * * * * ** ** * ** * *  
* * ***** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * * * * **** * * x[] = {77,22,88,11,22};
** *** ** ***** ** * * * size = 5;
    
** *** * * ** * print the array */
* *** * *** *** * *** *** * i = 0; i < size; i++){
*** * ** ** * ***** ** *** ** ** *** **** ***** **** ", x[i]); **** ** ** * * * * **
* *** *** ** *** ***
** *** * * ** ** * * * * * ** ** ** *
**** ** * * **** *
** * ** * *** ** ** I need this to happen size-times */
* ** * * * * ** * j = 0; j < size; j++){
** ** ** * *** ** *** * * ** * * * * ** * from left to right */
* ** * ***** *** * * * * * ** * ** * i = 0; i < size-1; i++){
* * ** * * ***** * * * ** * * * * *** ***** * ** * * * * ****** * i-th element with its neighbor to check if they are in order */
* ***** * * ** *** ** * * ** * * ** * *** *** *** * * * *** ** **** * ** ** > x[i+1]){
* * *** **** * *** ***** ** *** * * ** * ** ***** *** * *** *** ** ** * ** * exchange the values of x[i] and x[i+1] */
* * * *** * ** ** ** * ** * * ** * ** * * * * * *** ** ** **** ** * * ** ** ** * * * * temporary; ** * * * * * ***** *** * *
**** **** * * ** ** * **** ** * * ** * ** ** * * * * ** * ****** *** **** * * = x[i];
* * * ***** *** * * ** * ** * * * * * *** * * * *** * *** * *** * ** * ** = x[i+1];
* ** * ** ** **** ** * * ** * * *** ** * ***** **** * * * ***** *** * ** * *** * ** * = temporary;
* * * ** * *** * * * * * ** * ** *** * * * ***** * ** *
** * * * * * **** * ** * *** **** * * * * *
* * * ** * * *
** ** ** ** *** ** ****
* ** * * *** ** print the array */
* * * *** ********** ** * ** * * sorting: \n");
********** * * ** ** * i = 0; i < size; i++){
* * *** **** * ** * * *** * **** * * * **** *** ** ", x[i]); * * ** * * * * * ** * *
* *** ** ** ** * *******
* * * * * ** *** * **** * ***** **
*** ** ***** ** ***
***** *** * * ***
** * * * *** **** ** * * *
* * ******* ** **** * * * ** **** * * *** ** ****  
*** * * **** **** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * *** * **** ** ** x[] = {77,22,88,11,22};
* * * * **** * * * size = 5;
    
* * * * ** *** ** * print the array */
**** * ** *** **** ** * * * * i = 0; i < size; i++){
** ** * *** * *** * * * *** ******* ** * ** ** * ****** *** * ", x[i]); ****** ** ** * * * * * ** *** ** ***
* * * * * * ** ** ** *
* * * ** * ****** ** * *** *** *
** * * * **
** ** * ** ** ** * * * I need this to happen size-times */
******** * * * *** *** j = 0; j < size; j++){
*** * * * * ** * * * * * ** * ** * * * * * from left to right */
* * * **** * ** * ** * * * *** ***** * * * * i = 0; i < size-1; i++){
* ****** **** * * ** * ** * * ** *** ** * **** * * ** * * ** ** ** **** * i-th element with its neighbor to check if they are in order */
* * * ** * * * * ****** ** * * ** **** * * * ***** * * * ** * * > x[i+1]){
* ** **** * * ******** * ** * * ** * ** * * **** ** ** *** * exchange the values of x[i] and x[i+1] */
* * * ** *** * * * ** ** ** * ** * ** * * ** *** * * ****** * * ** * * ** * ** temporary; * * * * ***** ** *** ** *
* * * * **** * * * ** ** ** * * * * * *** ** ** * ** * * ********* ** *** * **** = x[i];
* * *** ** * *** *** * * * *** * ** *** * * ** * ** ** * * *** *** * * ** ***** *** *** ** = x[i+1];
*** * * * * * ** * * * * ******** * *** **** *** **** * * ** **** * ** * ** ** = temporary;
** * * *** * ** ** ** ** * * * * * ** * ** * ** **
*** ** * * ***** * *** ** ** * ** ** ** * * *
* ** ** * * * ** * * * *
* *** ** * **
* * ****** * * print the array */
* * * ** *** * * * * ** ** sorting: \n");
* *** ** ** * * **** ** ** i = 0; i < size; i++){
* * * ** ** *** * * * *** ** ***** * ** * * * * ", x[i]); * ** ** **** * *** ** *
* * ** *** ** ***** **
* ** * ** * ** * **** ** * * ** ** *
* * ** ** ** ***
* ****** * ** *** * **
* ** **** * ** **** * * * * ** ***** ** *
* * **** ** * * *** * *** ** ** * ** **  
** * * * * * **** * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ****** *** * x[] = {77,22,88,11,22};
** * ** ** ** * * * size = 5;
    
**** * * ** *** ** * print the array */
*** ** ** * ** * ** *** *** i = 0; i < size; i++){
** * **** * *** ****** * * * * * *** ** * * ", x[i]); * * ** ** ****** ** * * *** *** ** *
*** ** * *** ** **** * *
** * ** ***** ** * ** * * * * *
* ** ** ** **** * * *
** * **** *** *** ***** I need this to happen size-times */
* * * **** * ** * ** j = 0; j < size; j++){
* *** * * * **** * * ** *** **** ***** ** * * from left to right */
** * *** * * *** * **** ** *** *** * * *** * i = 0; i < size-1; i++){
* ** *** * * *** *** ** *** * ** * * **** * **** * * ** *** * * i-th element with its neighbor to check if they are in order */
* ** * ** * ***** * * **** * * * ** ******* * * * * * > x[i+1]){
** * * * * * * ** * *** **** * *** ** * * * **** ** * ***** * ** * * * * ** * * * exchange the values of x[i] and x[i+1] */
* * * ** * ** * *** ** ***** ** * *** * * * * * ***** **** ** * * * * ** * **** ** *** temporary; ** * ** * ** * * * *** * *** *
* *** ** ***** * * * ** ** ** * ****** ** * ** ** ** * * *** ** * *** *** ** *** * * = x[i];
** * * *** * ***** * *** * * **** * * ** *** **** * ** **** * * * * * * * * * = x[i+1];
* ******* * * * *** * * * ** ** * * * ** * ** * * *** * *** * * ****** *** * = temporary;
* ****** * * * * ***** ** * ** ** * *** * ** *** * ** * ***** **** * *
* ** ** ** * ***** *** ***** * * ** * **
* * * *** ** * ** *
**** *** * *** *** *
******** * * ***** * * print the array */
* * **** *** * * * * ** ** * sorting: \n");
** **** ** * * * **** * ** i = 0; i < size; i++){
* **** * * * * ** ***** **** ** * *** ******* * ** ", x[i]); * * *** ** * * ** **** * * ** ** *
*** * ** * * * ***
*** *** **** ** * * ** **** * * * * ***
* **** * ** ** *
* ** * * * * ****** *
* * ** *** * * *** * ** * *** *** * *
** * * *** * * **** * **** * * * *  
** ****** ** ********** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * * * * * * * * x[] = {77,22,88,11,22};
* * * *** * ** * * size = 5;
    
* * ** * * ** * print the array */
*** * * * * * * ** i = 0; i < size; i++){
**** * * * *** * ** ** * * * ** **** * ** * *** ** *** * ", x[i]); **** *** * *** **** * ** ** * **
*** **** **** * ** * ****
** **** ******* * * ** * **** * **
** * *** * * ** * *
**** * *** * * I need this to happen size-times */
* ** ** * ** * *** j = 0; j < size; j++){
** * * ** *** * * **** * * * ** ****** * * from left to right */
* * ** *** * *** * * * ** **** ** ********* * * * * i = 0; i < size-1; i++){
* * ** ** ** * ** *** * *** ** ** ******** ***** * *** ***** ** * *** i-th element with its neighbor to check if they are in order */
** ***** ** * * ****** ** *** * *** * *** *** **** * ** *** ** ** * * * > x[i+1]){
***** * * **** * * *** ** ** * ** * ** * ** * * ** **** * ** * ****** * ** * * * exchange the values of x[i] and x[i+1] */
** * * ** * *** ** * ** **** * *** * ***** ** * ***** * * *** * * * **** * ***** **** temporary; *** * * ** **** *** * * * **
* * ** * ** * *** ** ** * * ** * * ** ** * ****** * *** ** *** *** * ** = x[i];
* ** ** * ** ** ** * * * ** * *** *** ** * * * * * * * * * *** * * *** = x[i+1];
************ *** * **** *** *** *** * * * * * ** * * ** * * * * * * * *** * * * = temporary;
* * * *** *** ** * ** ** * * ** *** * **** *** *** ***** *
* ** * *** * **** * *** * * *** ** **
* ******* ** **** * * **** ** *
*** **** * * *
* **** *** * * * *** * print the array */
*** ** *** ** * * **** *** * * **** sorting: \n");
* ***** *** ** ****** * i = 0; i < size; i++){
* * *** ** ** **** ** *** * ** *** * * * ** ** ** * ", x[i]); *** *** * * * * ** * ** ***** **
*** **** * * *** **** *
* * * **** * ***** *** ***** ** ** *
* * * ***** *** *
******* * ** * ** *
* * ** **** * * **** **** ** ***
* * * ** *** * ***** ** * *** ** ** * ** * ** *  
** **** *** * * * * ** ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.14
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.2k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 3.8k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users