0 like 0 dislike
9.2k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 9.2k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
******* *** ** * * * x[] = {77,22,88,11,22};
***** * * * * * * size = 5;
    
* * * ** * **** ** * print the array */
* *** ** *** ** * * * ** i = 0; i < size; i++){
*** * ** * ** * * * ** * * * ** * * * **** * ", x[i]); ***** * * * * *** * ** * *
* * ***** ******** * ** *
*** * ** *** ** * ** ** * ** * * *
* *** *** **** ** * * * * *
* *** * ** *** * ** * * I need this to happen size-times */
*** ** * *** * * j = 0; j < size; j++){
* *** **** *** *** ** * ** *** * *** * * from left to right */
** * **** * * * * * * * * ***** * i = 0; i < size-1; i++){
** ** * *** ** **** *** * ** ** * ** * ** * * * ** *** * * * * * i-th element with its neighbor to check if they are in order */
**** * * *** ** ** * **** * ***** * * ** * * *** ***** * * *** ** * * * * * > x[i+1]){
* * ***** * * ** * *** * * ***** *** * * * *** ** * * * ** ***** ** * ** *** ***** exchange the values of x[i] and x[i+1] */
*** * ** **** * *** *** ** ** ** ** * * ** *** ** * *** * *** * * ******* * * temporary; * * *** * *** * * * *** ***** * *
*** * ***** **** * * * ** ** * * ** * **** * * ** *** * * * ** *** * *** *** * * = x[i];
* ** ***** ** **** ** * ** * * *** ***** * *** *** * **** * **** ** ** * * ** *** * ** ** = x[i+1];
* * ** ******** *** * * **** ** * * ** * * * ** **** *** *** *** *** * *** ** * *** = temporary;
* ** *** * ** * ** ** * **** * *** ** ** * ******* * *
** * ** *** * * **** * **** * ** * ** * * * ***
******** ** ** * * * * *
** * * ******** *
* ** * * * *** ***** ** print the array */
* * * *** **** sorting: \n");
** * ** * * * *** **** i = 0; i < size; i++){
** ** * * ** ** * * * ***** ***** * * * **** ** * ", x[i]); **** * * ** * ******** * * *****
* * * * ** **
** *** *** **** **** * ** * *** ** *
* *** * ** ** ** *
* * * * ** *** *** *** *
* * * * ** * * * * *** * ** *** *
** ****** ** * ***** * ** *** *  
**** ** **** *** * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * ** * * x[] = {77,22,88,11,22};
** ** * ***** * * * * size = 5;
    
*** * * *** print the array */
** ***** *** ** * *** ** i = 0; i < size; i++){
** *** ***** * * * * * * * ** * * ****** * ****** *** ", x[i]); * ** * * ** * *** ** * * *
***** ** ** ** **** ***
*** * ********* *** *** * * *** *
*** * * * ****
** * ** ** ***** * * ** ** I need this to happen size-times */
* * * ** *** *** * * * j = 0; j < size; j++){
* ** * ** ** *** * ** **** *** * *** **** from left to right */
* * ** *** ** * * ** **** * * ** * * ** *** i = 0; i < size-1; i++){
* *** * ** * * * *** * * * ** * *** ** ** * * * * *** * i-th element with its neighbor to check if they are in order */
* * *** ** * ** * * * * *** * * * ** * *** ** ** *** ** * * > x[i+1]){
*** ** * * ** * *** ** * * *** *** * **** ** * * **** ** * * **** ** **** ** ** * exchange the values of x[i] and x[i+1] */
* * * **** ***** * * ***** ******* ** ** * ** * ****** **** * * **** * * ** ** * * * * temporary; * ** * * * ** ** *** * *** *
** * * * *** **** ** *** ** ** * *** * ** * * ** * * * *** ** *** *** **** **** ** * * * ** * * * * = x[i];
* * ***** ** * * ** * ** *** * * ** ** * ** ** * *** ** * ********** ** *** * = x[i+1];
* **** ** *** * * *** *** * * * * ***** *** *** ** ** *** ******* * * * ** ** * ** = temporary;
** *** ** * *** ** ***** ****** * **** * *** * * * * **** ** *** *
* * * * * * * **** ** ** * *** * *** *
***** *** * * ** * *
* * ** * ***********
**** ** * ***** * * *** **** print the array */
*** ** * * ** * **** * * **** * sorting: \n");
* ** * * * * * **** **** i = 0; i < size; i++){
* * ** * * ***** ** * * * ** * ** * * ***** ***** ", x[i]); ** * * * * ****** **
****** ** * *** **
**** ****** * * ** **** ** * ***** ** *
** * ** ** *** ** *
*** * * * ** **** ** **
* **** **** ** ** * * * ** * *** *** *
* **** * * * **** ** ** * * * * ** * **** ** *  
* * * * * **** ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ****** * * * *** ** ** x[] = {77,22,88,11,22};
*** * ** ** * *** size = 5;
    
***** * * * * * * print the array */
*** *** ** ** * * *** ** i = 0; i < size; i++){
****** **** ** * **** ***** ** *** ***** **** * * ", x[i]); **** * ** *** * ** ** ** ****
* ** * *** * * * *** *
*** ** ** * ** *** * *** * * * *******
**** * * *** * * * * * * *
* * *** **** ******* * I need this to happen size-times */
** ** *** ** * ** ** * ** * * j = 0; j < size; j++){
* ** * *** * * * * ** ***** * **** * from left to right */
*** * ** *** * ** * *** * * * ** ** *** * * * i = 0; i < size-1; i++){
* * * ** ** ** * ** ** ** ** ** * *** *** ** * ** **** **** * * * * * * i-th element with its neighbor to check if they are in order */
* * * * ** ** *** **** * * *** ** ** ** ****** ** * * ** > x[i+1]){
****** **** * * ** ** ** *** **** * ** ****** ** ** * *** **** * *** ** * * **** exchange the values of x[i] and x[i+1] */
** ** * * ** * * ** **** * ******* ** **** ** ** **** ** * ** * * *** ** *** * ** * ** * * * * * *** *** temporary; ***** * * *** * * * *
* ** * * * ** * **** ***** *** *** ** ** ** * ****** ******* * **** * * * ** ***** * *** * = x[i];
** ** * * * ** * *** ** * * ********* *** *** * ** ***** * *** *** ** * = x[i+1];
* **** * ** **** * * * * * *** ******* *** **** * * * ** * * * * * *** * * = temporary;
* ** * * * * * * * ** ** ** * * ** *** * * * ** ** **** ***** * * *
****** * * * * *** ****** ** ** *** * * * * **
* * *** * ** ** ** *
** * ** * **** *
* ** * * * *** * * print the array */
* * * ******* * * *** * sorting: \n");
** *** ** *** ** * * i = 0; i < size; i++){
* * * * ** * ** ** * * ** ** ** * ** *** * **** ** ", x[i]); ** ** * * * * * ****** ** ** ** *** **
* * *** *** * **
* ***** *** ** *** * *** * * * *
* * * * *** * * ***
* * * * * * ** ** *** *
*** ** *** ** * * ** * ****** *** * *
* * * ** ** ** *** ***** * * * ** * ** **** **  
*** * * * * * * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** ** **** ** * * x[] = {77,22,88,11,22};
* * * **** ** ** *** size = 5;
    
* ***** * * * * * print the array */
* * *** * ******** ** * * * * i = 0; i < size; i++){
* * * *** *** * **** ** ** * * ** * *** **** * * ** ** *** * ", x[i]); ** ** * *** ** * * * *** * *** **
* * ** **** ** * ** * *
* *** * *** * * ** * *** ***
** * * * * ****** * *
*** * * ** * *** I need this to happen size-times */
*** ** * ** ** * j = 0; j < size; j++){
* * * * * *** *** ******** * ** ** **** *** from left to right */
* * ** *** * ** * * * * * * ***** **** i = 0; i < size-1; i++){
** ** ** **** * * * *** * *** * ** ** * * * * * ******** * * i-th element with its neighbor to check if they are in order */
****** * * *** ** **** **** * *** * * **** ****** *** * * ** * ** * * > x[i+1]){
** ** *** * *** * ** * * * * ** * * ** *** * * ** * *** * ** * * * ** ** * ** exchange the values of x[i] and x[i+1] */
*** * ** * * *** * * * * ****** * ** ** ** * * * ** * ***** * ** * * **** * ***** * ** ** temporary; * * * * * ** * ***** * **
* * ** * * * **** ** ***** **** * *** **** ** ** * * * ** * ** * * ** *** = x[i];
* * ***** * ** * * ** * * * * ** ** * **** * * ** * * * *** * ** ** * = x[i+1];
** ** ** *** **** *** ** * * * * * **** ** * ** * * * *** * * ** * **** * ** * * * * = temporary;
* * ** * * * * * * * ** * ** ** * **** ** * * * *
** ** * **** * * * ** * * * ***
* ** ** * * * *
**** * ****** * ** *
* * ****** *** * * ** print the array */
* ******* *** ** * * * * * * sorting: \n");
*** **** **** ** * * i = 0; i < size; i++){
*** * *** ***** **** ********** * * * *** *** ********* ", x[i]); *** ** ** * ** ** * ** ***** * *
** **** *** *** **
* * **** * ** ** ** * * *
* *** **** * *
** * * * ** * ** ***
* * ** * *** * ** * ** ***** * * * *
* * * * *** * *** * * *** * * ** * ******  
* * * * *** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** **** * ** * * x[] = {77,22,88,11,22};
* ** * * * ** *** *** * size = 5;
    
**** ** ** **** ** **** print the array */
* * ** ** ****** *** * i = 0; i < size; i++){
* *** ***** * * **** * * *** ** * * * * ** * ** ** ** ", x[i]); *** *** ***** *** * ** ** * ***
* * *** * * **
* * ** * * * * * *** * * * * ******
* *** * * *** ** * *
* ** * *** ** * **** I need this to happen size-times */
** * * * *** ** * j = 0; j < size; j++){
* ** *** *** ** * * * * *** * * ** * * ** * **** from left to right */
**** ** * * * ** *** *** * * * ** ** ** ** i = 0; i < size-1; i++){
** ** **** * ** * **** * * ** * * * ** * ** * ** * ** *** **** * *** i-th element with its neighbor to check if they are in order */
* * * *** * * * * * ****** * * ** *** ** ** *** *** * ** > x[i+1]){
***** **** ** * * * ***** *** * ** * ** *** * * ** * **** ****** * * * * ** ** ** exchange the values of x[i] and x[i+1] */
* * * ****** ** * * **** * **** ** * * * ** ** ** *** * * * * * * * ** ** * *** **** temporary; ** ****** * * * * ** * ** * *
** * * ** *** * *** * * * ****** * *** ** ** * * * * * * ** * * * ******* * * ** * = x[i];
* * * * ******** ** **** ****** *** * * ********** * ** ** *** **** *** * * **** ** ** = x[i+1];
* * * * * ******** * ** ***** * * *** *** * ** * * **** * * * * * ** *** * **** * ** ** ** = temporary;
* * * * * * * * ** ** * ** ** * *** ** * ** *
* ** ***** * **** ** **** ***** * ** * **** **
* ****** **** *** ** ***
** * *** * *** ** ***
* ******* * * *** ** * print the array */
* * * * * *** **** * ** ** * ******* * sorting: \n");
* * * * *********** *** ** * ** * * i = 0; i < size; i++){
* * * ** * * *** * * ** * ** * * * * ** *** ", x[i]); ** * ** * * ** * * ***
** **** * * * * **
* *** ** * ** ** * * *** * * * **
** ******* * *** ****
*** **** ** * * * *
**** **** * ** * *** ** ** * * * ** ** *
** ***** * **** **** **** ** ** * *** *** *  
* ** * **** ** *** **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** ** * ** **** ** ** x[] = {77,22,88,11,22};
** * * ****** ** ***** size = 5;
    
*** ** * * * **** print the array */
* * ** ** * ** * ** * i = 0; i < size; i++){
* * *** **** ** * ** ** **** * * * * *** **** ", x[i]); ** * * **** *** ***** * ***** *
* *** ** * * * **** *
* * *** * ***** * * ** * ****
* ** ** ***** ** ****
***** * ** * * ** * * * ** ***** I need this to happen size-times */
* *** ** ** * * * ** * j = 0; j < size; j++){
* ** * **** * **** * ** ** * * *** * * * from left to right */
* * *** * * ** ** *** ** **** * * ** * i = 0; i < size-1; i++){
** * ** ** * * *** ****** * ******* * * * **** ** **** * * *** * i-th element with its neighbor to check if they are in order */
* * ** ** * ** ** ** * * * ** ***** **** **** *** ***** ** ** > x[i+1]){
* ** *** * ** * *** * * * * * * ** **** ** *** ** *** *** *** ** *** ** ** *** * * exchange the values of x[i] and x[i+1] */
* * * * * ** * * * * * ** ****** ** * **** ** *** **** *** ** **** ** * *** **** temporary; ** ** *** ** * * * ******* *
* * ** * ** ** * ** ** ** * * * ** * ***** *** * * ** * ** ** * *** * * * * = x[i];
* * * * * ** * ** ***** ** ** * *** ***** ** ** *** * * * * * ** ** *** ** * *** = x[i+1];
* * ** **** * ** * *** * ** * *** * ** * **** * * * * ***** * ** * *** ** *** * = temporary;
** * * * ** * ** * * * * *** ** ** ********
*** * ** * * * *** * ** * **** * * * **
* *** ** ** * *
* * * *** ** * * * * *
* *** * ***** ** * * print the array */
* ** *** **** * ********* * ** ** sorting: \n");
*** * * * * * ** * * * i = 0; i < size; i++){
* * ********** **** * * ** ** * * ** ** **** ", x[i]); * *** * * * ** * * * **
* * ** **** * ** * * *
* * * ** * * * ** * ** ***
** * ** * **** * * *
*** * * *** ***** * *
* ** ** ***** **** * * *** * *
* ** ******** * ** ***** * **** * * * ***  
* ** * *** * * * ** **** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * ** **** * x[] = {77,22,88,11,22};
** * * ** * ********* * * size = 5;
    
** * * * * * ****** print the array */
* * * ** ******* ** i = 0; i < size; i++){
*** *** * * *** *** * ******** *** * *** ****** * ", x[i]); ** ** * * * * ** * * ** * *
* ***** ** *** *** ******
* *** ****** *** * ** ***** **
** * ** ** * * *** *
** * *** * * ** ** I need this to happen size-times */
** * * * * ** ** *** j = 0; j < size; j++){
** * * * * * ****** ** * * **** * ** * from left to right */
* * ** * *** ** *** * **** ** ** ** * * * * i = 0; i < size-1; i++){
* ** * ** ** * * **** ***** ***** * * * * *** * * ** * * *** * * ** ** * i-th element with its neighbor to check if they are in order */
**** ** ** * ** **** ** ** * ** * **** * ** * **** * * * ** * * ** * * > x[i+1]){
* *** * * ** ***** * * *** * * *** * * * * * *** * ** ** * * ***** * * * *** ** exchange the values of x[i] and x[i+1] */
**** *** *** ** * * **** ** ** * ** * ** **** **** * * * * * * *** * * * ** temporary; **** * * ***** * ** * * ** * * *
** ** * ******** * ** ** * * * *** ** *** * **** * ** ** * ** ** **** * * ** ** * * * * * * *** = x[i];
* * **** * * *** * ** * ** *** * * ** * **** * * * * ** * * * **** * ** *** ** = x[i+1];
* * * * * * * **** *** *** ** *** ** ** ** * * *** ** ** * **** *** * *** ** ** ** * = temporary;
* * * * * * * * * *** **** *** ** * * * * ** * * * * *
* *** *** * ** ** **** * * *** * * * **
* * * * * *** ** *** ***** *
*** *** * ** *** *
* ** ** *** *** *** * * print the array */
**** * * * * * ** **** * * *** sorting: \n");
* ** * **** * **** *** ** i = 0; i < size; i++){
* *** * * * **** * *** *** ** *** ** * *** ** * ****** ** ", x[i]); ** * * ** * **** ** **** * * **
* * *** * *** ** ** ***
** * * **** **** ** ******* * **** ****
** ** * ***** *** ****
** ** ** * *** *** ***
* * ** * * * * *** ***** ** * * * *** * ****
****** * * ** * *** * * * *** *** * *  
* ** ** ** * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * ** ** x[] = {77,22,88,11,22};
** ** * * ** * *** *** ** size = 5;
    
* ** * ** * * * * ** * ** print the array */
* ** ** * **** **** * * i = 0; i < size; i++){
* * **** ** * **** ** * * * * ***** ** ** * * * * * * ", x[i]); * ** ******* ** * ** ** **** **
* * * *** *** ** ** *** ***
* ***** * ** ** ** * * * * ***
* ** * *** *** * * * *
**** ** ** ** ** I need this to happen size-times */
****** * **** ** **** *** j = 0; j < size; j++){
*** * * * *** * * **** *** * * *** from left to right */
* * * *** * ** * * ** * ** ** * * ** ** * **** i = 0; i < size-1; i++){
* *** * * *** **** * * ** * *** * * * * * * * * * **** ****** * * * i-th element with its neighbor to check if they are in order */
*** * ** * ***** * * * **** ** ** * ** * **** * ** ** *** * ** ** * * * > x[i+1]){
****** ** * * * ** *** * * * ** * ** * * ** ******** * * **** ** ** * * * * * * exchange the values of x[i] and x[i+1] */
* ****** ***** *** *** * ** ** *** * ** * ** ** ** ** *** * ** * * * ** ** **** temporary; ** * ** ***** **** *** *** * * ***
** *** ** ** * * * ** * ** * ** ***** * **** **** * * ** * ** * * * * **** **** * * = x[i];
** * * * * ** * * * ** *** * ****** ** * * ***** ** ** *** * * *** *** ** * ** **** = x[i+1];
** * * **** ********** *** * * * * * * ** * ** **** ** *** * ** * * ** * **** * * *** * * = temporary;
* * **** *** * * ** * * * * ** ** * **** ** * **** **
* * * * **** * ** ** *** *** **** ******
* ** **** ** * **** * *
** ** *** * * **
** * * ****** * ** print the array */
* *** ** **** ** * *** *** *** sorting: \n");
*** ** ******* * * **** i = 0; i < size; i++){
** * * * * **** * ** * ** *** ***** *** ****** * *** * ", x[i]); *** *** *** ** * * ** * * * ****
* **** * *** **
** * ** ** ** ** * * * * * * *
******** * ****** *
** ******* **** ** * **
********* * *** *** * * *** ***** * ** **
* * * * *** *** ** ** * * * ** *** * **  
** * ****** **** ** **** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * **** ** * * * ** * x[] = {77,22,88,11,22};
**** ** ** ** * * * ** ** size = 5;
    
*** *** * * * * **** ** * print the array */
* * * * **** ** * * * * * i = 0; i < size; i++){
*** * * * **** * * *** * *** ** * ********* ", x[i]); *** ******** * *** * * ** * * * ** *
** * * * *** ** * ** * *
** ** *** **** * **** ** * * * ** *
** * ** * * * * ** * *
***** ** * **** ** *** I need this to happen size-times */
** ** * ** *** ** **** * * j = 0; j < size; j++){
******* **** *** ***** * * * ** * ** ** ** from left to right */
** * * * ** * **** ** * * * ** ** * * **** i = 0; i < size-1; i++){
*** ** ********* ******* ** * ** *** **** ***** **** ***** ** * i-th element with its neighbor to check if they are in order */
** ** ** ***** * ** * * ***** ***** **** * ********* ** * ** * > x[i+1]){
* * **** * * **** ** ****** * * * ** * * ***** ** * *** *** *** * * * *** * **** * ** exchange the values of x[i] and x[i+1] */
* * *** * * * * * ** *** ** * *** * *** *** * *** **** *** * * * ** ** * ****** * temporary; *** ** * * ** *** **** * ** * * ** * *
* * * *** ***** ** ***** *** * ***** *** *** **** * * * ** * ******** ***** * *** * *** * * *** * = x[i];
* * * * ** *** * ** **** ** ** ** * ** * ** ** * * *********** * * * ** ****** *** = x[i+1];
** ***** * * * **** * * ** * * * *** * ** **** **** *** *** ** * * * * * * * * ** * * ** = temporary;
** * * **** * **** ** * * * ** ** ** * *** ** ** * * ** *
***** * * ****** * * ******* ***** ** * * ** * *
* *** **** ** ** ******* *
** ** ***** * * ** *** * *
* * ** **** ** * *** *** * * print the array */
* ** * ** * ** * * ** **** * ** * sorting: \n");
* *** * * * ** * ** i = 0; i < size; i++){
* * **** * *** * **** ****** *** ***** ** * ", x[i]); * * *** * *** *** ** ** * * *****
*** * * **** * * *
** ***** * * * *** ***** *** ** ** **
* ** *** *** * *
* * * * * * *** *
** * * * ** * ** * **** ** ****** * *
* *** *** * * * * * ** ** * ***** ** * **  
*** ** ***** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ** ** * * * **** * * * x[] = {77,22,88,11,22};
* *** ** **** *** *** * size = 5;
    
* * * *** *** ** print the array */
**** * ***** * *** *** i = 0; i < size; i++){
****** ** ** ** * ** ***** * * * * ** *** ** ", x[i]); * *** * *** *** * ** ** **
** * ** **** *** * **
* ** ** * *** ** * ** * * **
* ** ** * ** *
* * * *** ** ** *** * I need this to happen size-times */
*** **** * **** * * * ** * * * j = 0; j < size; j++){
** * ** * * * * *** * ** * ****** * ** **** ** ** from left to right */
* ** ** *** ** *** * * ** *** **** * *** ** ** * i = 0; i < size-1; i++){
* *** ** ** ** * * * * ** * * * * **** ** * * * * i-th element with its neighbor to check if they are in order */
* * * * * * ****** **** ** ** * **** * * ** * * ** * * * * **** **** > x[i+1]){
** *** ** * ** ** * * **** * * * *** * ** * * ** * *** ** ** ** *** * ** ** ** ** exchange the values of x[i] and x[i+1] */
*** **** *** ** *** * * * * *** * * **** * **** * * * * ***** ** *** * * ***** * temporary; *** * ** * ********* ** * *** * *
*** ** ** ** * * ** * *** * ***** * * * * * ** *** **** * **** * * * * * * * * = x[i];
* *** ** * * * ***** ** ** * ** **** * ***** **** ** * ** ** * * * * * ******** *** = x[i+1];
*** *** ** * ** ** * *** * * ***** ** ** * **** * * * * * ** ** *** * * * ******** * * = temporary;
** ** ** *** * *** **** * * * ** ** * **** *** ** ** * **
*** * **** ** ** **** **** * ** ** *** * ***
* * ***** * *** * *
* ***** * ** * *** ****
* **** **** ** **** ** * ** *** print the array */
* ** * * * * * * ****** ****** ** sorting: \n");
** ********** ** * * * i = 0; i < size; i++){
***** ** **** *** * ** * * * ******* * *** * * * *** ", x[i]); ** ** * * * * ** * * ** *
*** ** * * * *** ** **
*** * * * * ** * * ******** * * ** *
*** ***** * *** * ** *
*** ** ****** * ****** ***
* * * ***** ****** **** * *
* ** ** * ** * * * *** ** * * * * * *  
* * * **** * * * * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.194.143
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.8k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.1k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users