0 like 0 dislike
12.8k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 12.8k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * ** ** * ******* *** x[] = {77,22,88,11,22};
* * * *** * ** ** *** * * size = 5;
    
*** * * * * * ** * * print the array */
* * ** **** * * i = 0; i < size; i++){
** ** ********* ** * ** * **** * * * * ** *** * ***** * * ** ", x[i]); * * * *** ** * *** * * * * **
**** ******** * * ** * **
**** * *** ****** * **** *** * * * ****** * *
* * * *** *** *** ** * *
* * * * *** * **** I need this to happen size-times */
* * * *** **** **** * ** * j = 0; j < size; j++){
** * **** *** * * * * * * ** *** ** * ** * * * from left to right */
* * *** ** ** * * * *** *** * *** ** ****** ** i = 0; i < size-1; i++){
* **** * * * ** *** ***** ****** * * ***** * * * * ** *** ** * i-th element with its neighbor to check if they are in order */
** * **** * * * *** ** **** **** * ** * * * * ** *** > x[i+1]){
* * * * * ***** * * * * *** * * * *** *** ******* ** ** * * * * ****** ******* *** *** *** exchange the values of x[i] and x[i+1] */
********* * ** * * **** ** * **** ** * * * * * ** * ** *** ** * * ** * **** * * temporary; * *** *** *** * * * ** ** *
* ** **** * **** *** * ** **** * * ****** * **** *** * ***** * * * * * * ** * ** * ********* * = x[i];
* * ** *** * *** * ****** * *** * * * * ***** ***** ******* * * *** * **** * ** * * **** * * = x[i+1];
** *** ** * ******** **** * ** * * ** * * * ** * ** * ** * ** * * ** * ** = temporary;
* * ** **** *** **** * **** * ** *** **** * ** ** *** ** * ** **
** ** **** * * ** * * * * * * * **** * *
****** **** * * ** ***
*** ** * **** **
* ** ** * ** * * * ** print the array */
* * * **** ** ******* * *** * ** * sorting: \n");
* * *** **** * * * * * * * i = 0; i < size; i++){
* * * ** *** *** * ****** * * * ** * * ****** **** ", x[i]); ** ** ** **** *** ** * * ** * *** ** ***
* ** ****** * ** *
*** * * ** *** * * ** * *** ** * * ** * *
* * ***** *****
* * ** ** *** * * * * * * *
*** ** **** * * * * * * * ***** * ** ** * * ***
* * * * *** * * ** *** ** * ** ** ***** ***  
*** * * ** *** **** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** ****** * * x[] = {77,22,88,11,22};
** * * ** * size = 5;
    
* ** ** * * ** ***** **** print the array */
** * *** ** ** * ** * ** * * i = 0; i < size; i++){
* * * * * * * * *** * *** * * *** * * * ** * ** *** ** * ", x[i]); *** * * * ** ** *** ****** * *
* ********* * **** *
* * * * ** ** ** ** * *** *** **
*** ** **** ** ** ***
* ** * * * * * * I need this to happen size-times */
*** * * * * * * j = 0; j < size; j++){
* * * ** * ** ** ** **** * *** * * ** *** * * from left to right */
* * * * *** * ** *** *** * * *** ****** *** *** ** i = 0; i < size-1; i++){
*** *** ** * * ***** ***** * * *** **** ***** * ** ** * *** ****** *** ** i-th element with its neighbor to check if they are in order */
* * * ***** **** *** * **** ** ** ** * ** *** ***** * * ** * **** **** > x[i+1]){
*** *** ** * ** * ** ** ** *** * * * * * ** * ** ** * *** * * * *** * * ** exchange the values of x[i] and x[i+1] */
* * * ** * * * ** ** * **** * * * * * * * * **** * * ** ** ** * ** * ** *** * * temporary; * * *** ** *** * *** ***
* ** *** ** ** ** * * *** * * * * **** ** ** *** * * **** * *** ** * * **** * = x[i];
* **** ** **** ** **** *** ** ** ** *** *** * * * *** ** *** ** **** ** * *** = x[i+1];
* * * ** *** **** *** * ** * ** * * **** ***** *** * * *** *** * ** ** * * * *** * = temporary;
* ** *** **** * * *** ***** * ** ****** * *** ** * **
* ** ** * * * * *** * * ** ** * * *** ** * **** *
** *** * ** ****** * *
* * * **** ***
*** * * ** ** **** * ** ** print the array */
* * * * *** **** ** * * * * sorting: \n");
* * ** * * * *** ** i = 0; i < size; i++){
* **** * * ** * ** **** *** ** * * *** ** *** * * ****** * ", x[i]); * ** * * *** **** ** ** * ** *
* ** * ** *** ** * ***
* *** ** ** * *** * ******* ** * *
* * * ** ** * *
* * * * **** ** *** * *
** * * * * *** *** * ** *
*** *** * * ** * *** ************ ** * *  
******* * * * * * * ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * **** *** ** ** * **** x[] = {77,22,88,11,22};
** ** ***** * * size = 5;
    
**** ** ** * ** print the array */
* * ** *** * * ******* i = 0; i < size; i++){
** * * * * *** *** * ** * * *** * * * * ** * * ** ", x[i]); ** ** ** * ** ** ** * ** ** * *
*** * *** *** * * * * **
** * *** *** ***** *** * ** ** ** ** * * * *
* * ** * * ** * * **
* ****** * ****** * * I need this to happen size-times */
** ** * * * ** **** * ** * j = 0; j < size; j++){
** * ** * * * ** ***** *** * * ** * *** ** ** from left to right */
** * * * * * * * * * * ** ** ** * ** * ** i = 0; i < size-1; i++){
* * ** ** * * * * *** ****** *** ** * ******* * *** *** * * * * i-th element with its neighbor to check if they are in order */
** * * **** **** * * * ***** * *** **** ** *** * ** * * * * * > x[i+1]){
* ** * * ** ** * *** *** * * * **** * ** * **** ** **** * * * * * * * * * *** * * * ***** exchange the values of x[i] and x[i+1] */
*** * * ** * * * * ** * *** ** * * * * * * ** * **** ** ** * **** * * temporary; * *** * * * * * ** *
*** ** *** ** * * *** * **** ** ** * **** ***** * ** * * ** * *** * * * * ** ** ** ** *** = x[i];
** ****** *** * * *** * * *** ** * * ** * * * ** ** ** * * ** * * **** * * * ****** * * = x[i+1];
** * *** *** * *** **** ** * * ** * ***** *** **** * * * ** * * ** **** * ** * **** = temporary;
* ***** *** *** * * ******* ** * * ******* *** * *** ** * *** *** *
* ** *** * ** * * * ** *** ** **
* *** * * ** * *
*** * * ** *** **** *
** * ** ******* *** ** * print the array */
* ** ** ** * * * *** **** ** ** * sorting: \n");
*** * ** ** *** * * * * ** * i = 0; i < size; i++){
* ** ** * *** * ** ** *** **** ** * * * ***** * ** * ", x[i]); * ** * ** *** * *** ** * **** ***
* ***** *** ** ***** * *
*** ** * * *** *** ****** ** ***
** ***** * *** * ** *** *
** ** * * * * *
* ****** **** ** ************* *****
* * *** * *** ***** * ** * ***** ** * *** *** *  
* * ** ** ** ** * *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** ** * * * * ** x[] = {77,22,88,11,22};
** *** ** *** ** * ** * * size = 5;
    
* **** * **** ********** * print the array */
* *** ***** *** ** ** ** *** i = 0; i < size; i++){
*** * * ** *** * ** * **** ** ** ** ** ** ** * ", x[i]); * ** * *** *** *** * * * * ****
****** ** * * * ***
* * * ** ** ******* ** ** * **** *** **
* *** * **** * ** * *
* ** ** ***** * ****** * I need this to happen size-times */
* * * ********* * * ** j = 0; j < size; j++){
** ** * ** * * **** * ** * ** * ** *** * * * from left to right */
** *** * *** ***** * **** * * * *** ** **** * i = 0; i < size-1; i++){
* **** ** ** * * *** * * * ** * * * **** ** * ***** ******** * i-th element with its neighbor to check if they are in order */
* * * ** * **** ** *** ** * ** * * * * ******* * * *** > x[i+1]){
** * ***** **** * ** * *** * *** * *** * *** * **** * * * ** * **** *** * * * * exchange the values of x[i] and x[i+1] */
*** *** * *** * * ** *** * **** * * * * * **** ** *** *** * ** * * ** ** *** * * temporary; ***** ** * * *** * * * ***** *
* * ********** *** ** * * * *** * ** * ***** * * *** * ** ** *** **** ***** * * ** **** * = x[i];
** ** **** * ***** * * * * * ** ** * * ** *** * ** ** *** * * ** * * *** **** * * * * * = x[i+1];
** **** ** *** * * *** * ** *** * * * * * ***** * *** ** ***** * * ***** * * = temporary;
*** ** * ** *** ** *** * ** **** * * **** * * *** ** * * * ** * * *
* ** ** * * * ** * *** * *** * * **
*** **** * ************ * *
* * ***** *** ** **** ** ** *
* *** ** * ** * ** *** * print the array */
** ** * ****** * * * **** *** sorting: \n");
* **** * ** * * * * * i = 0; i < size; i++){
* ***** ** *** * * * ** * ** * ** *** ***** ** ", x[i]); * * * **** *** * ***** * * * ** *
* ** * *** * ** *** ***
* ** * * *** ***** * * *** ** *
* * * * ** * * * * *****
** **** ****
*** **** * * *** ****** **** ** * *** *
* * ** * ** * *** * * ******* * **  
*** * ** ** **** **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** ** ***** * *** x[] = {77,22,88,11,22};
* *** * **** ** * *** *** * size = 5;
    
** * * ** ** * ***** ** print the array */
******** * * *** ** ** * i = 0; i < size; i++){
* * *** ** ** ***** ** * *** * **** * ** ** * ** * ", x[i]); *** **** ** *** * * * * * ***
* *** *** ** ** *** * ** * *
* ** **** ***** * ****** * *** **
* **** * ** *** * *
* * * ******* * * ** * I need this to happen size-times */
* * **** *** *** * ** *** j = 0; j < size; j++){
* * * * *** * * * ** * * ** *** *** * from left to right */
** ** * * * ***** ** * * * * **** * * *** i = 0; i < size-1; i++){
*** ** *** * **** *** ** * * * ** * ** ** ** **** * * * * *** ******** i-th element with its neighbor to check if they are in order */
** ****** * **** ** * ** * ** * ** * * **** **** *** *** * ** * * ** * *** > x[i+1]){
** * ** **** ***** ** * * ** ****** * * * * *** ** *** * ********* * **** ** * * **** * * exchange the values of x[i] and x[i+1] */
* * ** * ** ** **** * * ***** * *** * * * * ** *** * * * * * ** * **** ***** * *** ***** ** * temporary; * * ** ** ** * * * * * * * **
* * * *** * * ** ** * ** ** * *** * ** *** ** ** ** * * **** **** * *** *** * = x[i];
* *** * * *** *** *** * * *** **** * ***** ** * * ** *** ** * ** * * ** * ** = x[i+1];
* ** * * ** * *** * ** * * *** * * ** **** * * * ** * *** * **** * * *** = temporary;
** ** ** **** * * *** ***** * * * * ** ** * **** *** * ** *** *
* ** ** **** * * * **** **** **** **** * *
**** * *** ** ** * ** *
* ** * ** ** * *****
*** **** **** ** *** ** * print the array */
** ** ** * * ** *** * * * * * sorting: \n");
* * * * * **** **** * * i = 0; i < size; i++){
**** *** ******** * * ** ******** * * *** **** *** * * ", x[i]); ** **** ***** * * * *** ** **
*** ** * * *** *
* * * *** * ** *** ************** **
* * * * ** *** ** *** ** *
** * *** * *** * **
**** * ** * ** * *** ** *** * * ****
*** * *** ** * * * **** * *** ** * *** **  
* * *** * * * * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * ** * * * x[] = {77,22,88,11,22};
* ** ** *** *** size = 5;
    
* * * ** ** *** print the array */
** ** * ** ** *** * i = 0; i < size; i++){
* ** * * *** * ****** ** ******* * ***** * * * * ", x[i]); * * * ** * * * ** ****** *
**** * ** ** * * ** **
* ** * *** * * ** *** *** ** * ** ***
** ** ** *** ***** * **
**** ***** * ***** * I need this to happen size-times */
* * * ** *** ** * j = 0; j < size; j++){
* * * * ***** * ****** * * ** **** * *** from left to right */
* * * ** *** * ******** * * * * * ** **** * i = 0; i < size-1; i++){
* ** * * * *** *** * * * * ** *** *** * * ***** **** i-th element with its neighbor to check if they are in order */
** ** *** * *** *** *** ***** * *** * * * ****** * *** ** * * ** * * ** ** * > x[i+1]){
* *** * * *** * * *** ******** * ** * ******* *** ** ** * * ** * ** * *** * * exchange the values of x[i] and x[i+1] */
*** ** ****** ** *** * * **** ** * ** * * ** * ** * *** * * *** * ** * * * temporary; * **** ****** ******* *** ***** ***** **
* * * ***** *** ****** * * * ** *** *** * *** * * * ** **** ** * * * * ** * * * ** = x[i];
*** * * * * **** *** * * ** * *** * ** * **** * ** * * * ** * *** * = x[i+1];
** * * * * **** *** * ** ****** ** * * *** * ** * ** * * *** * ** *** = temporary;
** *** *** ** * ** * *** ** ** * ** * * *** * ** * * ** *
*** * *** * * * * ** **** ** * * **** ****
** * ** *** ** * ***
******** * **** *** * *** * *
**** * * * ** ** ** print the array */
** ** * ** * * * *** ** * ** * * sorting: \n");
** ** * * * **** * * * * * i = 0; i < size; i++){
* * * *** ****** * **** * * **** ** ** * ** * ** *** * ", x[i]); *** * * *** ** * * *** * ** ** ***
**** **** * * * *
** ***** ***** * * ******** ***
* * * * **** *** *
* * **** *** * ** ***
* * ** **** *** ** * * *** *** **
* ****** **** *** ** ** * * ** ****** ** *** ** ***  
** * **** *** * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * ** * * * x[] = {77,22,88,11,22};
* ** * ** ** * *** size = 5;
    
** * * ** *** ** * * print the array */
* * *** ** ****** * * * * i = 0; i < size; i++){
* * ** ** * ** * * * *** * ** * * * *** *** **** * ", x[i]); * * *** * ******* * *** *
** * * * ** ** * ******
**** * **** * ** *** ** *
* **** *** *
** * ** I need this to happen size-times */
** ** * * ** * * ** * * * ** j = 0; j < size; j++){
** ****** **** * * ***** *** ** * ***** * * from left to right */
* ** * *** ** * ** * *** *** ** *** * **** **** * * i = 0; i < size-1; i++){
* * * * ** ** ** ****** ** ** ******** * **** * * ** * ** i-th element with its neighbor to check if they are in order */
**** * * *** ** * ** **** * ** * * * *** * *** * * ** * ** > x[i+1]){
** * * * * * * **** * * *** * * ******* * * * ** * * * **** ** * ** ** ** * ** * ** * exchange the values of x[i] and x[i+1] */
*** ***** ** * * ** **** ** ** *** * * **** * **** *** * *** ** * * **** * * * ******* * temporary; * * * * ***** ****** *** * *** **
***** * * * ***** ****** ****** ****** ********* ** **** ** *** ** * ** *** ****** * * ** * *** * = x[i];
* ** * ** * *** ** ** * ** *** * * * *** * * * * *** * * * ** **** *** * * ** *** **** ** * = x[i+1];
** ** * ** *** * * **** * ** * * * *** * * * * * * ******* * * * * * ** = temporary;
******* ******* *** ***** * * *** ***** ****** *** **** * * * * ****
* * * * * * * ****** ******* **** * * *
* **** ******** ** * ** *
**** ******* * * ***
* * *** * ** **** * print the array */
* * ** ** ** * *** * * * sorting: \n");
** ** ** * **** *** *** i = 0; i < size; i++){
* * ** ** * * * ** * * * * ** * ** * *** *** * * ", x[i]); *** * **** *** *** ***
* * *** ** * *** * * **
** *** *** *** * ** * * * ** * * *
* *** * ***** * *
* * **** * * * * ****
**** *** ** * * ***** ** * **** * * *
* * * * ** * ** ** * * *** **** * **  
* * ** * ****** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * * ***** x[] = {77,22,88,11,22};
* ***** * *** ** size = 5;
    
* * *** * ******** print the array */
** **** ** *** *** * * * * ** i = 0; i < size; i++){
* **** ** *** ***** ** * ** ******** ** * ** * * ", x[i]); *** ***** * * * **** * *
** **** * * ** ***
* * ** * ** ** **** * ** ** *********
* * * ****** * ***
* * * * * * * ** ** I need this to happen size-times */
* * * ***** ** **** * j = 0; j < size; j++){
* * ** * * * * ** ** **** * * * from left to right */
* ** * * ** * * ** ** ** * * **** * ** * * * * i = 0; i < size-1; i++){
* * * * * ** * * ** * * * * * * * **** * * * ** ** * * * i-th element with its neighbor to check if they are in order */
** * * * ****** * * ** * * *** ** **** ** * **** *** *** ** * * ** ** * * ** > x[i+1]){
** *** * **** * ** * ** ** * * * * * *** ** ** * * **** * ** * ** *** ***** * exchange the values of x[i] and x[i+1] */
* ** ** ** *** * * *** **** ********* * * * *** * * * ** * * * * ** * * ***** * * ** temporary; * * ** ** ****** ** **** * *** *****
*** ******** ******* ** * * * * ** ** ** * * ** * ** *** ** * * *** * * * *** = x[i];
* ** ** *** ** * * * * * **** ** * **** * * ** *** ** * * ** ** *** *** ** **** * ** * * = x[i+1];
****** * * * *** ***** ****** * * **** ** ********* ** * * ** ** *** * * ** **** = temporary;
** * * * ** ** * ** * * ** * * * ** ** ** ***** ***** ** ** *
* ***** * *** * * ******* ** *** ******* * *
* ***** ** *** *
** * * ** * * ** * *
* *** * ** * * ** *** print the array */
**** ** ** ** * * ** **** ** ** * * sorting: \n");
*** * * * *** * * * * * i = 0; i < size; i++){
* * * *** ** ** * *** *** ** **** * ** ", x[i]); *** ** * *** ** * * * **
** ** * * *** * *******
****** * * *** * * * **** * ** **
** * * ** ** *** ****
* *** *** ** **** ***
*** * ** * * * ** *** * ** ** * * *** **
* * * * ** * * ** * * *** ** * * ****  
** * ** ** * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * *** ** ** ** * x[] = {77,22,88,11,22};
* ** ** * ****** ** * size = 5;
    
* *** * * *** ** * * *** print the array */
*** * * * * ** * *** ** i = 0; i < size; i++){
** ******** * *** * ** ** ** ***** * *** * ** * ** ", x[i]); ** * * * ** ** ** ** * ** ** **
* **** **** ** * ** **
*** ** **** ** * *** * * *** *
*** ***** ** * **** *
**** * ** * ** *** ** * ** I need this to happen size-times */
** ** **** * * ** ** **** *** * j = 0; j < size; j++){
** ** * * ** * ** *** ** * *** * * * from left to right */
* * * ** * * *** * *** * * ** * * i = 0; i < size-1; i++){
**** ******* * ** ** * * * * **** * ** ** * * *** * ** ** **** * * i-th element with its neighbor to check if they are in order */
* * * **** ** * ** * * * *** * * * * *** * ** * * **** * * * * ** *** ** > x[i+1]){
**** * *** ***** **** **** ** * * ** * * ** ** *** * * * * *** * * * ** * ** * exchange the values of x[i] and x[i+1] */
** ** ** * **** * * ** * ** ******* * ** ****** * * * * ***** ** *** *** *** * *** temporary; * * *** ** * *** * * **
* * * * ** ** *** * ** * ** * * ************** * *** *** ** **** * **** * * * *** ** ** * = x[i];
* ***** *** ** **** * *** * *** * ***** * * * * **** ** ** ** ** * ** * ** *** = x[i+1];
*** * * ** ** * * * **** *** ******* *** *** * *** * * ** * ** ** * * ** * * *** = temporary;
****** * * * * **** *** * * * * * * * * ** * ** ****** **
* ** * ** ** ** * *** ** *** * * * * * *
* * *** **** ** *
** ** * ** **** * * ** ** *
** ***** * **** * ** * ** print the array */
* ** * *** * * ** ** * * ** ***** sorting: \n");
** ** * ** *** ** * * * i = 0; i < size; i++){
** * ** *** ** * * * * * *** ** ** * * * * *** ", x[i]); * * * * * * * * * * * * * *** *
* ** ** ** * ** * ** **
* * ** **** ** * * ** * ** **** ********
* ** ** * * ** * *** ** **
** ** * * * ******* *
** * *** *** * **** ** * ** * ****
* * **** *** ****** *** * *** * * * *** *  
*** **** **** * *** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** ***** * ** x[] = {77,22,88,11,22};
* * * ** ** ***** ** * size = 5;
    
* * ** * * ***** print the array */
* * ** * * * * ******* i = 0; i < size; i++){
** ****** **** * * *** * *** *** ** ** **** * * ** ** **** * *** ", x[i]); ** ** **** * * * * * ** * *
***** ** ** ** ** *** *
* ** * ** *** * * *** ** * * * **
** * * ** ****** **** * *
** * ** * *** * * * * I need this to happen size-times */
* *** * * ** ** * * **** * * * j = 0; j < size; j++){
** ** * **** * ** *** * *** * ** * * ** * from left to right */
** *** * * ** * * ** **** ****** * ** * **** ** * i = 0; i < size-1; i++){
** * ** * * * * ** * * * * *** **** *** *** * ** ** ***** * ** i-th element with its neighbor to check if they are in order */
** * ** ** * * *** * * ****** * * * * *** * ** * * * * ** *** *** ** ** > x[i+1]){
**** * **** ** * *** ** * ** ** ** * **** * *** ** ** ** *** * ** * * * * exchange the values of x[i] and x[i+1] */
** ** * * * ** * ** ** * * * * **** ****** ** * * *** * * * **** * * * * *** temporary; *** * **** * ** ** *
** * * ** **** ** *** * *** * *** *** *** * * *** ** ** * * * ** * * ** ** ** = x[i];
*** * ***** ** *** * * ** ** ** * * *** ***** *** * * **** * *** * **** ** ** ******* *** * * * * = x[i+1];
* ** * * * **** * * * * ** *** *** *** **** **** * *** ** * * ** * * ** ** ***** * * * * ** = temporary;
* **** ** ***** ** ****** **** * **** * ** ** * *** * * * ** **
** **** ** *** * **** * * *** * *** *
* ** * *** * * *
*** ** ** *** * ** **
*** *** **** ** ** print the array */
** * ** * * *** * * * sorting: \n");
** *** **** * ** i = 0; i < size; i++){
* * *** *** * * * ** ** ** * *** * * * ** * * * ", x[i]); ***** ** ********* * ** * * *** ****
**** * ** * ***** * **
* **** * * ** ** *** ** * *
** *** *** ****
* * * *** **** *
* * * *** ** ***** ** ******** **** **
** * * * * ***** * ** * * * * *** *** **  
* * * *** * ** ** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 7.7k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 6.8k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 3.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users