0 like 0 dislike
10.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 10.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * * * * * *** * x[] = {77,22,88,11,22};
* ** **** * * * * * size = 5;
    
* *** * ** **** * * ** * * print the array */
**** ** * ** * * * * * * * i = 0; i < size; i++){
** * *** *** * *** * * * ** * ** * **** * ** ** ** ", x[i]); ** **** * ** * * **** * **
* * * *** * ** * * *
*** ** ** * ** * * * * * * ** * ** * * ** * *
* * ** * * ** **** **
** * ** *** ** **** I need this to happen size-times */
** * ** *** * * * * j = 0; j < size; j++){
*** * ***** * *** **** ***** * * * * ** from left to right */
**** * * ** * * ** ** * ** * * ** ** * * i = 0; i < size-1; i++){
* * ** ** ** ** * ** * * *** * * *** * ** ** * * * * * * i-th element with its neighbor to check if they are in order */
* ** * * *** * ** ** ** ** ***** ***** * * * * ***** ** ** ****** > x[i+1]){
** * **** * *** * * * * ** **** * * **** * *** **** * * * * * **** * * *** * ** exchange the values of x[i] and x[i+1] */
* * * *** ** *** ** ***** * * * *** * * ** * * * ***** *** temporary; ** ***** ***** *** * * ** ** * ***
* *** ** *** * ** * ** * * * *** ** * ** ** * ** ** ** **** **** * * * * **** * = x[i];
* * ** ** ** *** *** ** * * ***** * * *** * ** ** ** * * * * ** * * * ** ** * * ***** ** = x[i+1];
** * * ** * ** * * *** **** ***** *** ** ** * * ** * *** ** ** **** *** * *** * * * *** * *** ** = temporary;
* * *** * *** ** ** ** * ** * *** * ** *** * *** * * ** * * *
** ** ** * *** ** * **** ** * * * *
* * * * * ** ** * * *
* ** * * ****** * **
* * *** * * * ** print the array */
***** * * * * ** * *** * * * ** sorting: \n");
** * *** ** ** ** *** i = 0; i < size; i++){
* * ** * * ** * * * ******** * * ** * * * * ", x[i]); * * *** * * ** * * * *** * *
* **** ** * * ** ***
* ******** * **** ** **** * ** ** ****** *
* ****** * * * ** * * *
* ** **** ** ** *** **
* * ** *** ** * **
** *** * * * * * * ** ****** **** ** * * * ** ***  
* * *** * **** * * **** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** *** *** **** * **** x[] = {77,22,88,11,22};
* * * ** * * *** * * size = 5;
    
*** ** * * ** * ** * print the array */
* ** ** * * *** i = 0; i < size; i++){
* * ** *** * *** * *** ** * * **** ** ** * * ** * ** *** ", x[i]); **** * * * * **** * *** ***** ***
* ** ** * * ** ** * *
*** * * **** **** *** **** * * * * *
* ** * ** * ** * *
* * *** ** * ** I need this to happen size-times */
*** ** * * * **** ** ** j = 0; j < size; j++){
* * ** ** * ** * * * ** ****** ** * ******* * * from left to right */
**** * * * ** * * * * * *** * ******* * ** i = 0; i < size-1; i++){
*** ** ** ******* * ** * * *** *** * * * * ** ** ** ** **** i-th element with its neighbor to check if they are in order */
****** *** ** ** *** ** **** ******* ** * ** **** *** * * * ** * *** > x[i+1]){
* **** * * * ** ** * * * ** **** * * * * * ** **** * * ** **** ** ** * exchange the values of x[i] and x[i+1] */
* ** * * * * * *** ** ** * ** **** * ** * ** *** * ** ** * ******** * * * * * ** temporary; ** ********** ** ****** * * * * * *
* * ******* ** * ** *** **** ** ***** *** *** * * *** * ** **** *** ***** * *** * *** * * * ** ** = x[i];
* ** *** ** * * *** *** * * * ** * * ****** ** ** * * * * *** * * * ** **** * ****** = x[i+1];
** * * * ** ****** *** * ***** * *** * * ** * * *** * * ** ** * * ***** * ** *** = temporary;
* **** * * ** * * * *** * * * *** * * * * * ***** ** * **
****** * * ** ** * * * * *** * * ** * *** *****
* *** *** * * * ** * *
*** * ** * **** *
** *** * ***** print the array */
*** * * ** **** ** ** * ****** * * *** sorting: \n");
* * ** * * * **** *** ** i = 0; i < size; i++){
**** * * * *** **** ***** ******* * * ** ** * *** * ", x[i]); *** *** * ** * *** ***** *** * * * * *
** ** * ** ** *
* * * * ***** ** ** ** * * ** ** *
******* * ** * * ** *
* ** ** *** * * * ** *
* *** **** **** **** ** ** *** * *
*** * * **** * * * ******** * * ******  
* *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * **** *** x[] = {77,22,88,11,22};
* * *** * * * * ** ******* size = 5;
    
** ** ** * * * *** *** ** print the array */
* * *** * * * ** * ***** i = 0; i < size; i++){
**** ** ** ** * ********** * ** * **** * **** * ", x[i]); ** * ******** * * * ** *
**** ** ** * *** ** ** **
*** * *** * **** **** ** ** * ** * * *
**** * * *** *** ****
* * ** *** ******* * I need this to happen size-times */
* **** * ***** * ******** j = 0; j < size; j++){
* ** ** * * ***** **** **** * *** * * from left to right */
* ** *** ** ******** ** * ** * ** * * i = 0; i < size-1; i++){
** *** ***** * * * **** * * *** * *** *** * * * *** *** * * i-th element with its neighbor to check if they are in order */
** * **** * * * ** ** * * * * **** *** ** *** ** **** ** ** * * > x[i+1]){
* * *** **** ** ***** *** * * ** * * *** * ** * * *** ** * ** * * *** * **** * *** * exchange the values of x[i] and x[i+1] */
* * * * * *** * ** * * * *** * * *** **** * * ** * * ** * * * * ** ** * ** ** ** ** temporary; *** * * * * * **** * **** * ** * ****** *
* ** * * * * * *** **** ** * ** *** * * ** * * *** * ** * * = x[i];
* * ** ** * * * * * * **** * ***** * * * * * ** ** *** ******** ******** * * *** * ** * = x[i+1];
**** ** ** * ** * ** * * ** ** ** **** * * * * * * *** ** *** * * * * *** **** * * = temporary;
* * * ** * *** * ** ** *** ** * * ** * ******* ** * ** * **** * ** *
* ** * *** ** * * ** * ** **** ** ***
** ***** ****** **
** * ** * ** ** * *
* * * * ** * * *** print the array */
*** *** * *** * **** ** * * ****** * * * sorting: \n");
* **** * ** *** * * ** * *** * i = 0; i < size; i++){
***** * *** *** ******** * * * * * ** ** * * ** ", x[i]); * * **** ** * **** * * * ** **** *
** *** * ** * ** ***
* *** * ** ** * * * *** *
*** * * * * ** * **
** * * * * * ** *** *
* ** ** * *** ** **** * ** ** **** *
** *** ** **** ** * * ** * *** ** * * *  
* ** * *** *** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * *** *** *** x[] = {77,22,88,11,22};
* * ** ** ** * * * size = 5;
    
* * * * * ***** * print the array */
*** * ** ** * * *** * * i = 0; i < size; i++){
** **** * * * ** ** ** *** * **** ** * * * * **** ***** ", x[i]); * * *** * *** * ***** *** * *
** **** **** * *** * * * * *
* **** ** ** ** * * * * * **
**** **** * *** ** *
* * **** * * ** I need this to happen size-times */
* ** * * ** * ** ** ** * j = 0; j < size; j++){
* * ** **** ** *** * * *** * *** ** ** from left to right */
***** ** * **** * * ** * * * i = 0; i < size-1; i++){
* *** * * ** ** ** ** * * *** ** * ** *** *** * ** ** ** * **** * i-th element with its neighbor to check if they are in order */
* * * ** *** *** * * * * * * * ** * * ** * * * * * * * * *** > x[i+1]){
** *** ** **** * * * * * ***** *** ** *** *** * * ** * * ** * ** *** *** * ** exchange the values of x[i] and x[i+1] */
*** ** * ** ** ***** *** *** **** ******* ** *** ** * * * * * ** *** * * ** ***** ***** * temporary; *** *** * * **** * * **** **
** * * ** **** * * ** * ** * ** * ** * *** * *** * * * * ** * * ** *** * * ** ** * = x[i];
* * * ****** * * *** ** ** * **** * ** ** * * ** ****** ***** ** **** ** * * ** * * * * = x[i+1];
*** * * ** *** ** * ****** * * *** * ** *** *** *** * * * ** * ** * **** * * ** * ** = temporary;
* *** * ** * ***** ** ****** **** * * * ** * * * * *
* *** ************ **** * * ***** ** ** ** **
* *** *** *** *** *
** * ***** ** * * * * *
** **** * **** **** *** *** * print the array */
* ** * * **** * ** * * * ** sorting: \n");
* *** * ** ******* ** ***** * i = 0; i < size; i++){
* * * ** * *** * ** *** **** * * * * ** * * * * ", x[i]); *** * * * ***** ** * * ** ***** **** **
** * *** ** *
* ******* ***** * ** ** ** **
* * **** ** ** * * *
* *** * ***** * * **
* * ** ** ***** ******* * *** **** *
*** **** ***** *** **** * * * ** ****  
** ** ***** * * ** * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * * *** * *** x[] = {77,22,88,11,22};
* * * * * * * * size = 5;
    
* ** * * * ** print the array */
* * ** ** * * ** * ** ** i = 0; i < size; i++){
** * ** * ******* * ****** *** * * * * * ** ", x[i]); ** * *** * ** **** * ***
* * * * ****
* ** ****** **** * * * * * ******* * *
*** * *** ** * ** * * *
****** ** * * *** * I need this to happen size-times */
** * * * ** ******* * j = 0; j < size; j++){
** *** **** * * * * * * * ** * * * ** * * * * **** from left to right */
** * * * * * *** ** ** * **** *** ** ****** i = 0; i < size-1; i++){
****** ** * * *** * ** *** * * ** ******* * * * ** * * * i-th element with its neighbor to check if they are in order */
* * *** * **** * * * ***** ** ** ***** ** * *** ** * ** *** * > x[i+1]){
** *** ** ** ** *** * * * ** * * * * * * * * * * ** ** * *** * * * * * exchange the values of x[i] and x[i+1] */
** ** * ** *** *** ** *** * ***** * ** ** *** **** **** * * *** *** ** * * * temporary; * ** * ** * ** ** * *
** ** * ** ** **** **** ** * ******* *** * * *** * * * ** * * * * * * * * *** ** *** **** ** = x[i];
* *** * ** * * * * * **** * * **** * * ** ** ** * * * * ** * * ** ** * = x[i+1];
** * ** ** * * **** ** * * * ** ** * * *** ** ** * * ** * *** ** ** * * * * *** = temporary;
* * *** ** * *** ** *** **** *** * * ** * * * * * ***
*** * * ** *** ****** **** ** ***** * *
* ** * ** * * **** *
* * * *** * * *
** ** * **** * ***** print the array */
** ** * * ******** * *** * sorting: \n");
* * ** ** * ** ** * * i = 0; i < size; i++){
* * * * ** ** * **** ** * *** *** ****** ** * * * ******* ", x[i]); * * *** ** ** ** **** *** * *
****** * *** * * * **
**** *** *** * * * * * * ** ***
********* * ** ** ** **
*** ***** * * * * ** *
* * ******** ***** * * * ** ** ** ** ** ***
*** ****** *** **** **** * * ** * ** **  
* * ** * * * * ** * **** ** * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * ***** *** *** x[] = {77,22,88,11,22};
* * * ** * * ***** size = 5;
    
** * * * *** * * print the array */
* *** * *** * * ** i = 0; i < size; i++){
* **** ** ****** * * * * *** ** ***** * *** * * *** * ", x[i]); * ** * *** *** * * ** *** * * **
** * *** ******* ** ****
* *** ** ******** * ** * * **
* *** ** ***** *
*** ** * * **** * *** I need this to happen size-times */
* ******* ***** * * *** j = 0; j < size; j++){
* * *** ** * * * ** ****** ** ** **** * * from left to right */
** * * * * * * *** * * * * * * **** * i = 0; i < size-1; i++){
* ** * * * ** ** *** * **** ** ** ** ** * * * * * ** * * * **** i-th element with its neighbor to check if they are in order */
*** * **** ** * ** * * * * ***** * * * * *** ** ** * * ** * *** * ** > x[i+1]){
*** ****** * *** * * * *** * ******* * * ** * ***** * * *** ** * *** * ***** ** *** * exchange the values of x[i] and x[i+1] */
** ** * * * ** *** * * * * ** ** **** *** * * ******* *** * ** *** * ** *** * * * ** ** * temporary; * * * * ** * ****** ** **
**** **** *** * * *** **** * * * * * ** *** * * * * ** * * ** * **** **** * = x[i];
* *** ** * * * * ***** *** *** ** * * * * * * * * * ** * * ** **** ******** *** * * = x[i+1];
* ****** *** * ** ** * *** * * * * * *** * ** ****** * ****** * = temporary;
** * * * * ***** ** * ** *** ** * ** ** *** * *** *
** ** *** * * ** ** ***** ** ****** ** **
* *** * *** *** ****** * ***
** ** ****** * * ** * **
* *** * * ** * ** ** print the array */
**** *** * * *** * * * * * ** sorting: \n");
** * * * * ** *** *** * * i = 0; i < size; i++){
* *** **** ** ** ***** * * * * ** * * * ****** ", x[i]); * * ** * * ** * * * * * ***
* ** * ** ** ** ***
* ** * * ******* * ***
** * ** * * ** **
* *** ***** ** *** **** **
* ** * *** ***** * *** * ** * * ** * *
* *** * * * * * ** *** * ***** * * ** **** ** **  
* ** ** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ******* ** *** ** * x[] = {77,22,88,11,22};
* ** * ** * * ** * size = 5;
    
* ** * * ******* ** ***** * * print the array */
* * *** ** * ** * * * * * i = 0; i < size; i++){
** * * * * ** * * * ** ** ***** *** * * ** *** * ", x[i]); ** * * * ** * ** * * * * ** *
* * * * ** ** * ** *
* *** * * * * ** ** * ** * ** **
* * * ** *** * ** * *
*** ***** * *** * ** I need this to happen size-times */
*** *** ****** ** ** ** j = 0; j < size; j++){
** * * **** ** * * * * * ** *** **** *** * ** * from left to right */
******* **** ** * *** * ** ** ** * * *** * * * * i = 0; i < size-1; i++){
*** ** * * ** * * *** **** * * * * ** *** *** * * **** ******** * i-th element with its neighbor to check if they are in order */
** * * ** * **** * * ***** ** **** * ** * ** ****** * ** * ** * * **** ** * > x[i+1]){
***** ** **** * *** **** ** * * ** *** * ** ***** * ******** * * * * * ** * * ** ** **** * ***** exchange the values of x[i] and x[i+1] */
** *** * ****** * * * ** ** * * ******** ** **** * * * * * **** * * * * * * * * * **** * * ** * * temporary; ** **** * * ** * * *** * * ***
* * ** * ** ** * * *** ****** * ** * ** * ****** * * * ** * ** * * ***** * * * **** ** * * = x[i];
* ** ** * ** *** * ** ***** * ** * ********** * ** ****** * * **** * * ** **** * = x[i+1];
* * *** *** * **** * ** * *** * **** * * * * * *** * ** * ***** *** * * * **** *** ** * = temporary;
** *** * * * * * * *** **** * **** ** ** * ** * ** **** **
*** * * ** * **** * **** ***** * ** ** *
** * * ** *** ** ** *
* ** * ** ** * **
* * *** * ** * * * ** ** print the array */
* * * * * **** * ** * * ** ** sorting: \n");
* *** * ** * * * i = 0; i < size; i++){
* *** * * * ** ** * **** *** * * ** * ** ** * ** * * * ", x[i]); * * **** * **** ** * * *
** * ** * * ******
** ** * **** *** ***** * ** ** ** * * *
*** ***** * * ****
** ** ** ** * * * * * ****
** ****** ***** ** * *** ***** **
******* * * * *** * * * ** * ****** * ** ** ** **  
* * * ***** ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * ** * ****** *** * x[] = {77,22,88,11,22};
* *** * ** ** size = 5;
    
* * **** **** * **** ** *** print the array */
* * * * **** * *** *** * i = 0; i < size; i++){
******* * * ****** * * * * * * ***** ** * * * *** ", x[i]); ***** * * ** ** * * ** * ** *
** * * * * **** *** * * * ** *
* * **** **** * ** *** * * * * ** *
**** ** ***** * ***
** ** **** ** **** * *** I need this to happen size-times */
* * * * *** * ** * * j = 0; j < size; j++){
* ** **** * * * * ******* ** *** * * * **** * ** ** from left to right */
** **** *** ** * ** * ** ***** ** *** *** **** * i = 0; i < size-1; i++){
* *** ** ******** *** *** ** ***** *** *** * * * * *** * i-th element with its neighbor to check if they are in order */
* * * ** * * *** * * *** *** **** * ** * * * * * * * ** * * * > x[i+1]){
* ** ** * * ** ** * ** **** * * ** *** *** ** ** * *** * * * * * ** * * ** ** ** ** exchange the values of x[i] and x[i+1] */
** * * * **** *** * * * * ** * * * ** * * * ** ***** * * ** **** * * * * ** **** temporary; *** *** ** ** * * * * * * * ** * **
* *** * *** ** * ** ** ** * * ******* ** * *** * * ** * * ** * ** ***** * * * * ** = x[i];
* *** * * *** * ** * * * **** *** *** ******* * ******** ** **** * **** *** * * * = x[i+1];
**** ** ** ** **** * * * * ** ** * * * ** * **** ***** * * * ** * = temporary;
* * ** * ** * * ** ** ** * ** * * ****** * * ** * *** ** * * * * *
** * * ** * * * * ** ** ** * *** *
** ** ** * * * * ** *** *
** *** ** ** *
* * *********** * * * * print the array */
* * * ** * * ***** ** * * * * ** sorting: \n");
* * * *** * * * ** *** i = 0; i < size; i++){
* ** * *** * ** * * **** * ** ** *** ** * * ", x[i]); * ** ***** * ** * *** **** * ** *
*** * **** * * *** *
** ** * *** ** ** *** * * * * * ** ***
* * * * ** ** *** **
* *** ** ****** ***** *
** ** * ** *** ** * **** * *****
* ****** ** *** ** ** * ****** *** * * **  
** * * * ***** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
********* ** **** ** ** * x[] = {77,22,88,11,22};
**** * * **** ** * * *** size = 5;
    
*** * * *** * * ***** * **** print the array */
****** * * **** ** ** i = 0; i < size; i++){
* * * * * ** * ** * * * ***** *** * *** * ", x[i]); * ***** ** * *** * ** *** *
** ** ***** * * * **
* * * *** ** *** * * * * * * *
*** * *** * * * **
** * *** * * * ** I need this to happen size-times */
* ** * * * **** * * * j = 0; j < size; j++){
* * * ** * *** **** ** * * ** * ** ** from left to right */
** ***** * **** * * ** ***** ** ** *** * * * **** i = 0; i < size-1; i++){
* * * * ** ** ** * * * ** * * ** **** * ** *** * * * ** ** * * i-th element with its neighbor to check if they are in order */
** * * * ** * * * * * * ** ** ** ** ****** *** * * ** ** * * ** ** > x[i+1]){
** * *** ** *** ** *** * * ** ** ** ** ****** * *** ** * ** * * * *** * **** exchange the values of x[i] and x[i+1] */
* * * * * * *** * ** * ** * * *** * ***** * *** * ** *** * ** ** ** * ** * temporary; * ******* * *** * *** ****** *
* * * ***** * *** * * * ** **** ** ** *** * *** * * ** * * ** ** ** **** * ** ** = x[i];
****** * * **** ******** * *** * * *** ** *** * ** * * ** * **** ** ******** *** * ** * = x[i+1];
******** ** * ** * ****** ** ** ** ** **** *** **** ** * ** * ** * * ** * ** **** * * = temporary;
* * ** ******* * * * * ******* * ** * * *** * *** *** * ** **
* * * * * *** * ** ** *** * *** * ***** *
** ** * *
** ** * ** *
*** *** ** * * * * print the array */
*** * * ** * *** *** * ** **** * ***** * sorting: \n");
* *** * * ** ** * *** ** * i = 0; i < size; i++){
*** * **** * ** * * * * ** ** ** * ****** ** ** * ** * ", x[i]); * *** * * * * ** * ** ** * ***** *
**** **** ****** *****
** ** * *** *** * ** ***** *** * *
****** ******* * * * *
* * * * ** ** ** *
** ** * ** ** * * * ** ** * *** **
* ** * * ***** ****** ** * * **** * ** * **  
* * * * ** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * *** * **** * * x[] = {77,22,88,11,22};
** * * ** ******* *** ** size = 5;
    
* * ***** * ** **** print the array */
** *** * * ** ***** * * i = 0; i < size; i++){
*** * * **** * * ******* **** ** * * * * * * ", x[i]); **** ** * *** **** ***** * * ** **
* * * * * * * * * *** ***
*** * ** ***** * ** *** * ** *** * ****
* * ** * * * * * *
* * * *** * * * I need this to happen size-times */
* * ** ** * ** ****** * j = 0; j < size; j++){
* ** ** * ** * * *** * * **** from left to right */
** * ***** * * ** ** * **** **** ** * * * ** * i = 0; i < size-1; i++){
* * ***** *** * * *** * * ** *** ** **** ** *** * ** ** i-th element with its neighbor to check if they are in order */
* * **** * ** **** * ** * **** * **** *** * ** ** ** ** *** ** * * > x[i+1]){
* *** ** * ** **** * ***** ********* * ******* ** * * * ****** ** ** * * * ** * * * exchange the values of x[i] and x[i+1] */
* **** * *** ** * *** *** * * ** *** ** * **** * * **** * ** ** * * ** *** ** * ****** **** temporary; *** * * ***** ** * ** *
* ** * * ** **** ** * * * *** * * * * ******* * *** * ** * ******* * ******* * ** * ***** = x[i];
** * *** *** * ** *** ** *** *** * * * ** ** *** * ** ** * * * ** * **** * * * *** * * = x[i+1];
* ** ** ** *** **** * ** ** ***** ** ** * * *** * * ** * ** ** ***** * ** *** * = temporary;
*** * * *** * * *** *** ** ******* ** * ***** * * * * * *** * * * *
*** * * * * ** * ** * * * *** * ** ****
**** ** *** *
*** ** ** ** * **** **
** * *** * * ** ** *** * print the array */
** * ** * * ********* ** ** * * * sorting: \n");
** * * ***** **** ** * * * i = 0; i < size; i++){
** * * * * * * * * *** ** ***** * * ** * * **** *** ", x[i]); *** **** * * **** ** * ****** **
* * * *** ** *
** * * * *** * ** ** * **
*** * * * * * ***
* **** *** * ** *** **
** ** * **** * ** * * * ******* ** * **
** * *** * * * ****** * ** ** * *** ** * *  
** *** * ***** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.168
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.8k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 3.4k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.8k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users