0 like 0 dislike
9.5k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 9.5k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * * * ** * * x[] = {77,22,88,11,22};
** * *** * ***** *** * * size = 5;
    
*** ** * * * * print the array */
** * * ** *** ****** ** i = 0; i < size; i++){
** *** * ** **** * ** * **** ** * * * * * ** * *** * * ", x[i]); * ** * * ***** ** ** ** * * **
* * **** ** * * * * **** * **
** ** ** *** * * ** ** ** ** ** ***** *
* ** * ***** * * *****
** *** * * * *** I need this to happen size-times */
***** ** * **** *** * j = 0; j < size; j++){
** ** * *** * * ** *** *** * * * ** from left to right */
* * * **** * * * * **** * ** *** ** * * **** i = 0; i < size-1; i++){
** * **** * * * * ** ** **** **** *** * * ********* ** **** ** * **** *** * i-th element with its neighbor to check if they are in order */
* **** ***** *** * * * **** * * * * *** * * **** ** ** * * ** * > x[i+1]){
** ** ** **** ***** **** * ** * ** * *** * * * ** ** * * * ** ** * * * * * exchange the values of x[i] and x[i+1] */
**** * *** ****** * ** * * ** *** * ***** * * * * ** * * * *** * * ** *** * **** ** ** temporary; * * *** * ***** * **** *
* ** * * *** * ** * * ** ** * * * * * * * * ** * * * ** * * ** **** * *** * ** *** **** = x[i];
**** **** * ** * *** * * * * * *** ** * * *** ***** * *** ** ** ** *** * * **** * = x[i+1];
* ************ ** * * * *** ***** ** ** * * * * ***** ** *** * * * = temporary;
****** **** * * * * ** * ***** ******** * * * * * ** **** * ** ***
* * * * ** * * ** * * ** * * ** **
* * * * ** * * ******* ***
* ** **** **** * *** * *
* * ***** ** ** * **** *** print the array */
* ** * * * * **** * * * ** ** **** sorting: \n");
**** * ** ***** * * * * * * i = 0; i < size; i++){
*** * ** * *** * * ** ** ** * ** ** * ****** * *** * ", x[i]); * ** * * * ****** *********** *
* * * * * * * * *
* ** * **** ** ***** * * * ***
* **** * * * *** * *
*** **** * *** * * **
* * * * * ** ** *** * * **** * * *
**** * ** * * ** ***** * * * * * * *  
* * * ** * **** * * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ***** * * *** x[] = {77,22,88,11,22};
* * ** * * ** ** ** **** size = 5;
    
* ** *** **** ** * * * print the array */
** * ***** * ** * * * ** i = 0; i < size; i++){
** * ** * ** ** * **** ** * *** * * * *** ** * * * ", x[i]); ***** * * * ** *** * *** *
* *** * ** * ** *** *
****** * * * ** * ** **** ** **** *
*** ** * * ** * *
*** ** * ** **** * ** I need this to happen size-times */
* * * **** * ** *** j = 0; j < size; j++){
* * *** * * * * * * * ** ****** * from left to right */
* * *** ** * * ** ** * * ** * i = 0; i < size-1; i++){
* * * * * * **** ** * * * ****** ***** * ** * * ***** ** *** * ** * ** * ** i-th element with its neighbor to check if they are in order */
* * ***** * * * * * **** * ****** * ******** * * ** ** **** ** *** > x[i+1]){
*** * * **** * ** *** * **** ** *** * ** * * ******* ** *** * *** ** *** * ** *** * * ***** exchange the values of x[i] and x[i+1] */
* *** ******** ** * ** *** ** * ******* *** * * * *** * * *** * * ** * ** ** * ** ** ** temporary; * * * * * * *** ** * * **** ** ** ***
* **** * ** * * * ** * *** * ** ** ***** * *** ** * ****** * * * *** **** * **** **** = x[i];
* *** ** **** * ** ** * * * * *** **** *** * ** ** ** * * ***** ** ** * * * * ** * * **** = x[i+1];
* ** * *** ** * * * * * **** * ** * ** *** ** ** * * ** * * **** * *** ** * * ** = temporary;
*** ** * ***** **** * * *** * ** ***** ** ** * ** * * *** ***
* * * ******* * *** ***** * * * * *
*** * * ***** * * **
* **** * *** * * * * **
** * * ** * ** ***** ** print the array */
* * ** * * * ** ** * ** sorting: \n");
* * * ** ******** **** i = 0; i < size; i++){
*** * * *** ** ** * ** * **** ** ******* * **** ", x[i]); * * * **** ** ** * ******* **
**** **** ***** *********
* * ** * * * * * *** * * *** ** **
**** ***** ** ** ** ****
** * *** *** *** * ** **
* * * ** * *** * * ** ** **
** * * ** * ** * * ** * * ** * * **** * **** ****  
*** ***** ** ** ***** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * * *** ** * **** x[] = {77,22,88,11,22};
* * ** **** * ** * size = 5;
    
* ** ******** * * * print the array */
***** * * ************ *** * ** i = 0; i < size; i++){
** *** * ** * * ** *** * *** ** * ** ** * ***** ** ", x[i]); * * * * * ** * *** ***
* * ** *** * * *
* * * ** ***** ** ** *** * * **
*** * **** ** *
*** * * ** *** * * I need this to happen size-times */
* *** * *** * * * * *** ** j = 0; j < size; j++){
* ** * * **** **** * * ** * **** * * ** from left to right */
*** * * ** *** * ** ** * *** ** ****** * ** **** i = 0; i < size-1; i++){
** * * ** ******** ** ** *** * * ** * * * ** ** * **** * * * * * * i-th element with its neighbor to check if they are in order */
** ** ******* ** *** **** * ** *** ******** * * ** **** *** *** > x[i+1]){
** *** ***** * ** ***** ** *** * * **** * * * *** * * * ** * ** ** * * ** * * exchange the values of x[i] and x[i+1] */
***** ** *** * * * * ** * *** *** **** * * * *** * * * ** *** * *** ******** ** **** * * * temporary; ** ** ** * ** * ** * * ** *
***** ******* * * * * * * * ** ** * ** ** * * **** * ****** **** ** ** ** ** ** = x[i];
** ** ** * * *** * *** *** *** * * *** ** *** *** * * * * *** * * * * **** = x[i+1];
* * * ** ** ** ** * **** ******** *** ** **** ** ** * * ** ** ** * ***** ** * * * ** ** = temporary;
** * ** * * * * * *** * **** * *** * * * * *** **
**** * ** * * ** ****** * * *** * * *
** * *** * * *** **
****** ** * * * ***
** ***** * * ** * * **** print the array */
* * ****** *** *** * ****** * * sorting: \n");
* * * *** * ** * * i = 0; i < size; i++){
* * * *** * * ** ** ** ** ** ** ** * *** * * * ** ** ", x[i]); * ** ** * * * ** ** * * ** * *
*** * * * * ** **** * ** *
*** * *** *** * * ** * ** * * * * ** **
*** * * * * ** ** * * **
** ** ** ***** **** *
* ** * * * * ** ** * * ** * * ****** *
*** ** * * * * * * ** * * * * * * ** *  
*** * ****** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** * * * * * * **** x[] = {77,22,88,11,22};
*** *** ** * ** * size = 5;
    
*** * *** ****** * ** ** print the array */
**** * *** * * * ** *** i = 0; i < size; i++){
* * * ** * * * ** *** * * * ** * *** * ** ", x[i]); ****** * *** * ** * ** ** * **
** *** *** *** *
* * ** *** ** * * * ** * *
* **** * ***** * * *
* * ** * * * ** I need this to happen size-times */
** *** **** * *** * * * j = 0; j < size; j++){
* **** * * ** * * ** * *** ***** * ** * ********* from left to right */
* ** * * ** * * * *** *** * * ** ***** * **** i = 0; i < size-1; i++){
** * * * ** * *** *** *** * *** ** ** * **** * * *** ** * * * * i-th element with its neighbor to check if they are in order */
* *** * * ** * * * * *** * * * **** *** * * * * ****** *** * * > x[i+1]){
* * * ** ***** **** * ** ** *** **** ** * ******** ** *** ** * * ** * ** * * * * * * exchange the values of x[i] and x[i+1] */
**** ** ** *** **** *** ** *** * *** * **** * *** ***** ** * * ** *** * * temporary; * ** ** * * * ** ** *
* ** **** * * * * * * * * ** * *** * * * *** *** *** *** * * * * * * ** ***** * = x[i];
* * ******* ** ** *** * *** ***** *** ******** ***** ** * * * ** * * *** **** * * = x[i+1];
*** * *** ** * * **** ** * * ** ** * * **** * ** * * * * * ** * ** * * **** **** *** * * ** = temporary;
**** **** ** ** * *** ** *** ** ** * ** ****** * ** * * * ** *
***** ******** * *** * *** ***
** * * * * * * ** **
** * ** * ***** * * *
* * * * *** **** ** print the array */
* * ** ** * ** * *** **** *** * sorting: \n");
*** *** * ***** * * * *** i = 0; i < size; i++){
** * * * **** * *** ** * **** ** * * * * * ** ", x[i]); ** * ** *** ****** * * ** *
* ** * *** * * * * * **
* * * * ****** **** *** * * * ** * * *
* **** **** *****
* * * **** *** * ** *
* * ** * * * ***** * *** * ** * ***
* * ** * * * **** ** * * * * ** *** *  
* * ** *** ** **** ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * *** ** * ***** ** * x[] = {77,22,88,11,22};
** ** * **** * ** * size = 5;
    
* * * * ** * * print the array */
*** * ****** ** **** ** i = 0; i < size; i++){
* ** * *** * **** **** * * * * *** ** * ***** ******* * ", x[i]); *** ** * * *** * * *** * *** * *
* * ** * * *** * ** **
* * *** * * * ** * ** * **** * ** **
***** ** ** ** *** ** ****
** * ** *** * ** ** *** I need this to happen size-times */
* * ** * ** **** ** * j = 0; j < size; j++){
** * ****** * ** * * ** * ** * ** * * * ** ** ** from left to right */
* **** * *** ***** ** * * *** * ** * * * i = 0; i < size-1; i++){
*** **** ** ** * * ** **** *** ** * ** ***** *** * * ** *** * ** ** * i-th element with its neighbor to check if they are in order */
* * ** ** * * ** ** * *** * ** * * *** * **** ****** ** *** * *** > x[i+1]){
*** ** * *** * * * **** * * ** ** *** ** ** *** ** *** ** *** ** * * *** ** * ** * exchange the values of x[i] and x[i+1] */
* * * * * * * * * *** * * **** ******** * * * *** *** ** * * ** ** * * ** temporary; * * **** *** ** **
* ** ** * * ***** * * * * * ****** * * ** ****** ** * **** ************ **** * *** = x[i];
*** ** **** *** * * ** ****** **** ** * ** ******** * *** * *** ** * * * ** ******** * * = x[i+1];
** *** * ** * **** ** ** * *** ** * * * *** ** ** * *** * * *** ** ** *** * = temporary;
* ** * * * ** * * *** *** **** * *** ** * *** ********
* *** ** **** * * * * * *** * ***
*** ** ** *** * * ***
**** * * * * ** *
* * ** **** ** ******* print the array */
***** ** * * * * * * * * ** * ** sorting: \n");
* ** * ** * *** i = 0; i < size; i++){
**** * **** **** *** * ** * ** * * * ***** * ***** * *** ", x[i]); ** **** * * ** **** * * ** * *** * * *
* * * *** *** * ** ** *
** * ** ** ** * *** ******* * *****
*** * * * * *** ****
** * * **** * ***** * ** * **
** ** * ** ***** *** ** * *
* * *** ***** ** * ** ** * ** * ***** ** *  
**** * * ** * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * *** * **** * ***** * *** x[] = {77,22,88,11,22};
* ** ***** * * * * * * size = 5;
    
* * * * * * ** ** * * print the array */
*** ** * * * * * * *** i = 0; i < size; i++){
** *** * * ** * *** * * * ** * * ** * * ** * * * ** * ", x[i]); * *** * * * ** ** * * ** * ** **
* *** ** ** * * * ***
**** * *** * * * *** * * * ** ***** *** *
***** * ** * ** * **
* * ** * ******* ** I need this to happen size-times */
* * * ** ** * * * * ** * ** j = 0; j < size; j++){
*** **** * * * * * * * *** * * **** ** ** from left to right */
** * * * * ** * * * *** * * *** * * i = 0; i < size-1; i++){
* **** * ****** * *** * * * ******* * ** ** ** ** ** * ** i-th element with its neighbor to check if they are in order */
******* ** ** **** * * ** * ** * * *** ** ** *** ** *** ** **** * * * * * *** * > x[i+1]){
** *** ************** * ** ***** * * * ***** *** * * * * * *** * *** * * * * *** * **** ***** * exchange the values of x[i] and x[i+1] */
* * * * * ** * * *** * ******* * ****** ** *** ** * ** * * ** ** * ******* * * temporary; ******* ** *** *** ***** * * *
* ** * * ******* **** * * * * * ** ** *** ** ** * * * ****** * * * * ** * ** = x[i];
* ** *** *** * *** * * * * * * * ** * * * **** *** ** **** **** * **** ** ** * **** *** = x[i+1];
* ***** *** ** ***** ***** * * ** ** *** * *** ** * * ** *** *** * * *** ** **** * *** *** **** = temporary;
* * ** * ** * * * * * ** * **** * ** * * * ** ** * * * ****
* * * *** ** *** * * ** * *** *** * *
* * * ***** *** *** **
** * * ******
* **** * * ** * **** print the array */
** ***** * * ** ** * * sorting: \n");
**** ***** ******* i = 0; i < size; i++){
****** * * * ** ** * * * * **** ** * **** ***** ", x[i]); ** **** * * ** * ** **** *
*** * * * * **** **
**** * * * * * * * **** * * * * ** **
* *** ** * ** * ******
* * ** * *** ** ** *
*** ** * * ***** ** * *** * ** * ***
** * **** ** * *** ** * *** * * * * ** **  
* * * * * * ****** * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** *** * ** * ** ** x[] = {77,22,88,11,22};
***** **** *** ** * *** *** size = 5;
    
***** * * * *** *** ** * print the array */
* *** **** * **** ** i = 0; i < size; i++){
*** ** ** * * ** **** ** * * ** * * **** ", x[i]); * * ****** * * *** **
* * ** * * * * * * * *
** ** * * ** *** *** **** * ** * ** **
***** * ** ** * * * *
* *** * *** ** * * ** ** I need this to happen size-times */
* * ** *** *** * ** * * j = 0; j < size; j++){
* * *** ** *** ** **** * * * * * * **** *** ** * from left to right */
** ** * ** * * * * * **** ** * * * *** * i = 0; i < size-1; i++){
* * * * * *** * ** **** * * ** *** **** ** ** * **** * *** * * * i-th element with its neighbor to check if they are in order */
* * * ** * ** ** *** ** * ******* ** * **** ***** * * ** * ** * > x[i+1]){
* * * * ** * ** *** **** ** * ** * *** * * * ** ** * * * ** **** * ** * exchange the values of x[i] and x[i+1] */
* * * **** *** ** * **** * * * ** **** ** ** ***** * * * ** * * ** * * ** ** ******* temporary; * * **** *** * * * * *** * * *
* ** * ** *** * ** *** ******** * *** * * * * * * ** ** ** ** **** * * * * * * ** = x[i];
** *** * * ** ** ** * **** ** ** ** ***** * ****** * ** * * * *** * * *** * *** = x[i+1];
* ***** ****** * * * * *** * * * ** ** * ** * * ** * ** **** * * * * * * * * * ***** ** = temporary;
*** ** ** *** * * ** *** * * ** * *** ** * ** ******** * * * ** * * *
**** *** * * * * *** ** ** ******* * * ** ***
* * * * * * * ***
* * ***** *** *
** * * **** * * * ** print the array */
* * *** * *** **** ***** ** **** sorting: \n");
****** ***** * ** * * i = 0; i < size; i++){
**** ** * *** ** ** ** * *** * ** *** * **** **** * ", x[i]); ***** ** * ** * * ** ** ***
* * *** ****** ** ** *
** * * ** * * * ** * ** *** * *
* * * * * * ** * ** *
* ** *** * ** * * *** *
**** * * ** * **** * * * *** * * * ** *
** **** * * * * * * * **** ** *** ** ** ** * **  
*** * * *** ** ** ** * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ***** **** * * ** x[] = {77,22,88,11,22};
*** * * * ** * * ** ** size = 5;
    
* ** ** *** *** * * print the array */
* * * ** *** * ******* ** * * i = 0; i < size; i++){
*** * **** ***** * ** * ** ** * ** *** *** *** ", x[i]); * **** * * * * * * * * *** **
** ** * * ** ** ** ****
** * *** * ** ** ** * ** ** ****** * *
**** ** * * *
* * ******* ** * ** * * I need this to happen size-times */
** ** * ******* * * **** ** j = 0; j < size; j++){
**** *** ** * * * ** **** **** *** **** * * from left to right */
* ** * * *** * ** *** * ** * * i = 0; i < size-1; i++){
* * **** ** * * ** *** * ** * **** ** * * * **** ** * ***** *** i-th element with its neighbor to check if they are in order */
** * * * *** * * ** *** * ** ** * ** **** * * ** ** ******* * > x[i+1]){
*** * ** * * **** **** ******* ***** ** ** * *** * * ** * *** * * ** *** * *** ** * *** ** exchange the values of x[i] and x[i+1] */
** * ** * ** **** ** *** * * ** ** * * ** ** * ** ** * **** * * ******* ** ***** temporary; * * *** * * * *** *** * *** * ** * **
***** * * *** * * ********* * *** * ** ** * ***** ***** **** *** ***** * ***** = x[i];
** * ** * * ** *** * *** *** * **** *** *** * ** * * * * * ** ** ** ** ** ** * **** = x[i+1];
* ** *** * ** * * ** * * **** * * ** ** *** * ********** * * * *** ** *********** ** = temporary;
* ***** * * * ** * ******** * * **** ** * * * ** ****
** ** ** * *** * * **** * *** ** * *
* ** * ***** * ** ****
* * ** * ** ** * *** **
* * *** * *** print the array */
* ** * *** * * * * * * **** *** *** ** sorting: \n");
***** * *** * * i = 0; i < size; i++){
* * * ** **** **** * * **** *** ** *** * * * * **** ", x[i]); * * *** ** * * * * * * * *
* ** **** * ** *
* *** * * ******** * *** * ***
* * *** * ** ** * * ***
***** *** * ***
* * **** *** * ***** ** * ***** **
** * * ** *** ** ** * ***** *** * * ** *  
* * * *** * ********* ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * *** * *** *** x[] = {77,22,88,11,22};
** *** *** * ***** ** size = 5;
    
****** ** * **** *** print the array */
* *** * * * * * ****** i = 0; i < size; i++){
* ***** * * * ** ** * * *** *** ** * ** * **** * * ** * ", x[i]); *********** *** ***** * * *** * *
* * *** * * ** *
** * *** ** * ** ** * * *
** * ** *** * ****
* *** ** * *** *** * I need this to happen size-times */
** ** * ** * **** *** ** j = 0; j < size; j++){
* ** * * * * * ** * * *** ** ******** from left to right */
* ** *** * *** * * * * ** **** *** * ** * * * i = 0; i < size-1; i++){
* * * ** * * ** *** * ** ** * *** ** * ** * * * ****** i-th element with its neighbor to check if they are in order */
****** * ** * ** ** * ** ** * * * * ** * * * * * ** * ** * *** * * > x[i+1]){
** ** ** * * * * ** ***** ********* * * ** ** ** * ***** ******** * * exchange the values of x[i] and x[i+1] */
* ** * ** ** * * ******* * * * * ** ** ** ** * * * **** ** * ****** ** * ** * ** temporary; ** * ** * * *** * * ** ** * *** *
*** * ****** ** * ** *** ** **** ** * * ** * * *** * ** * * * *** ***** ** * * * * ** = x[i];
* * ** * ** * ** ** ** * *** **** * * **** * *** **** ** ** *** * ********** = x[i+1];
*** *** * *** * **** *** ** *** * * *** *** ** ** ** ********* * *** * ** * ***** * = temporary;
***** * * ** * ** ** *** **** * *** ** * ** *** *** **
* * ******* ** * * ** * ** *** * ** **
* ** ** ****
****** ** ** * *
* **** * ** * print the array */
* * * * ****** ** ***** *** ** sorting: \n");
* ***** *** * ** * * ** * * i = 0; i < size; i++){
*** **** *** ******* * ** **** ** *** * ** * ***** ** ", x[i]); *** *** * * *** *** * ****
* * * ** * * * *
** * * **** * * *** *** ** * ** *
* * * ****** * ** ***
**** ** **** * * ** **
** * * * * *** **** ** *** * * * ** **** ******
* * * * **** * ******* ***** ** **** * ** ***  
*** * * * *** * * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** * * * * * * x[] = {77,22,88,11,22};
** ** * ** * * * * size = 5;
    
** * **** * * ******* *** * print the array */
* ** ** * ** ** * * * i = 0; i < size; i++){
****** ** ** ** * ** * ** *** * * *** *** ** * ** ", x[i]); * ** * ** *** * ***** ***
***** * * * ***** *
* *** * *** * ** * * *** ** *** *
** * * * * **
* * * ** ** *** ** I need this to happen size-times */
*** ** * * * **** j = 0; j < size; j++){
** * *** * *** *** * * **** ** ** *** **** * * * ** * * from left to right */
** * * ****** ** * ****** * * **** *** * ***** * ** i = 0; i < size-1; i++){
**** ** ** ** *** ** ** *** ** *** ******** * * ** ***** ** **** * * * ***** **** i-th element with its neighbor to check if they are in order */
*** *** * ***** * *** *** ** *** ** *** ** ** * *** * * * ** * > x[i+1]){
* ** * ** * *** ** ** * * * ** *** * ** * *** * * * * * * ** **** * ** * * * * ** ** * exchange the values of x[i] and x[i+1] */
** * * ***** *** * * * * **** * *** ***** * * ** ** * * ** **** * ** ****** ** * ** * * temporary; * **** ** *** **** ****** *** ** **
* ** * * * * ***** * * ****** *** ** * * * * *** ** * * * * * *** * * * ** = x[i];
* ** * * ** * * ** * * * *** * *** * ** ** ** * * ** *** ****** ** ** = x[i+1];
*** * * *** ***** **** ***** * ** * * * * * ** ** * * * * ** * ** ** * * = temporary;
** * ******* ** *** * * * ** ****** * * * **** **** **** * *
****** * ** *** * * ** * * * ** *** * *** * *
** ** * * *****
* ** * * * * * ** * * *
**** ** * * **** * print the array */
** * * ***** **** *** ** ** * * * sorting: \n");
* ** ******* ***** * **** i = 0; i < size; i++){
* * * * **** ** **** * * * * **** * ** * ** ", x[i]); * ***** * * ** **** * ** **
* *** *** * ** ** *** *
* * * * * * **** * * * * ****
**** * ** **** * *** *
* **** * * * * * ** **
** * ******* * ** ** * ** ** *
** ** *** *** ***** ** * * * ***  
* * * * *** * * * *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.194.142
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.9k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5.3k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users