0 like 0 dislike
8.7k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.7k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** ** * ** * x[] = {77,22,88,11,22};
** **** * * * *** * size = 5;
    
** ****** ** *** ****** print the array */
**** *** * * ** * ** * *** * * * * i = 0; i < size; i++){
** ***** * ** ** * * * ** * * * * * ** * *** ** *** * * * ", x[i]); * * *** * **** ** *** * *** * **
* * ***** * * *
* *** * * * ** * *** ** *** * * **
* * ** ** * * * *****
* *** **** * ******** * I need this to happen size-times */
**** *** *** ******* * j = 0; j < size; j++){
***** * * ** ***** * *** *** * **** * * from left to right */
*** ** *** ** * * * * * * * ** * * **** * ** i = 0; i < size-1; i++){
* * * ** ** ** * * ** **** **** * ** * ** ** * * * * i-th element with its neighbor to check if they are in order */
* * ** * ** * *** **** *** * * **** ** * * ** **** *** ****** **** * * > x[i+1]){
* * * ** *** * ** ** ** * * * * * ** * **** ** * ** *** ** ** * *** ** * *** exchange the values of x[i] and x[i+1] */
** ** **** *** ** ** * *** * * * ** ** * **** * * * ** * ** * * * ** * * temporary; ** ** * * ** ** *** *
** *** * * * ** * ** * *** **** * ** ** * ** * *** *** ** * *** *** **** *** * ******* = x[i];
* ******* * **** *** * * ** * ** * * ** ** *** * *** * * * * **** ***** ********* * * * * * * * = x[i+1];
* ** ** * * **** * *** ** * * * * * * * * * * * * ** ** *** ** = temporary;
** *** * * * ** **** * * **** * * *** * * * * *** ** * ****** * **
** *** ** * *** * *** ** * * * ** ** ** *
**** **** **** ** *** *
** *** ** * * * ***** *
* * * **** * *** * ** ** print the array */
**** ** * ** * * ** * ** * ** * sorting: \n");
*** * * * ** ** * i = 0; i < size; i++){
** *** ** *** * * * **** ** *** * * * * * ", x[i]); *** * ** * * *** ****** * ***
**** * ** ** *** **** ***
** *** * * ***** * * **** * **** * **
*** ** ** * * *** * **
*** * * *** **** **** **
* * ** ** *** ***** *** ** **** * **
* ** ** **** * * **** * *** * * * ** * * *** * ** *  
** * ** ***** * * *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** * *** ** * x[] = {77,22,88,11,22};
*** * ******** ** * *** ** size = 5;
    
** * *** ** *** **** print the array */
**** * ** ** *** * * * **** * ** i = 0; i < size; i++){
** * * ** ** * * ** * * * ** ** * ** * *** * * * ", x[i]); ***** *** * * * * * * *
* ** ** * * *** ** *
* * *** * ** * ** ***** *** ** *******
* *** ** * ** **
* * * ** * ***** * * I need this to happen size-times */
* ** ** * * * ***** j = 0; j < size; j++){
*** * * *** * ** * *** *** * *** * * ** ** from left to right */
* **** ***** * ** *** *** * * ** ** ***** * i = 0; i < size-1; i++){
* * * ** **** ** ******* * *** ** *** ** *** * ** ** * ** * * ** i-th element with its neighbor to check if they are in order */
* ** ** *** * **** * * **** * *** * ** * ********* * *** * * *** > x[i+1]){
* * ** * * ****** * **** * * * * * **** ** **** ***** * * * * ** * * * **** * * exchange the values of x[i] and x[i+1] */
** * ** **** * * ** ** * * * *** * *** ** ** * * * ***** * * * ** * * * temporary; * **** *** * * * ** * * *
* ** * * *** *** **** * * ****** ****** ** ***** ** ** * * * * ** *** ** = x[i];
* ** * * * * * * * * * ** * * * *** *** * *** ***** ** ** * * * * = x[i+1];
** ** *** ***** * * * *** ** * * ** ***** * * ** * * * ** ** * ** **** * * = temporary;
*** ** **** ** *** * * ** ** ** ** * * *** **** * * ** **
** *** ** ** ** *** ** ** * *** ** ** *
** *** * * * * ** **
** ** * * * * * **
* ** * * * * ***** * *** print the array */
** * ** ** * * ****** ******* * sorting: \n");
* ***** * ***** * * * i = 0; i < size; i++){
* * * * ** ** ******** ** * * * *** * * * *** ** *** ** ", x[i]); * * * ******** * *** *** **
* *** * * * *
* * ** * * * * * * ** * ***** * *
*** * ** ** ** *
* * *** ** *** ******
** * * ************* * * *** * *
**** * ***** * *** ** ** * *** **** * ** ***  
****** ** * ** *** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * *** **** * ** x[] = {77,22,88,11,22};
** ** ***** * * ** size = 5;
    
* ** ** ***** *** * print the array */
* * ***** **** ** * * i = 0; i < size; i++){
** ** * * ** * ***** ** *** * **** * ** **** ** ", x[i]); *** ** * * * * * * * * * * *
**** * *** ** *** * *
* *** * ***** * ****** ** * * * **** *
** * * **** ** ********
* * ******** * * *** I need this to happen size-times */
* ** ** ** * ** * * * *** j = 0; j < size; j++){
* ** * * *** * * * ** *** *** * * ** * *** **** ***** from left to right */
**** ** * * **** ** ***** ** *** ** * * i = 0; i < size-1; i++){
* * * * * ** * * * * *** * ** * * ***** * * *** *** * * ** *** i-th element with its neighbor to check if they are in order */
*** * **** **** * ** * * ***** ********** ** ***** * *** * *** *** ** ** * > x[i+1]){
* **** * * * *** ** ** **** * * * ** * ** *** ** *** *** * ****** *** ** * * * ** exchange the values of x[i] and x[i+1] */
*** ******* *** ** ** *** ** * ** ** **** ** ** * *** * ** ** ** * * ** * ** * * * temporary; * * *** * * *** * * *
** * * **** * * ** * ** * * * * * *** * *** ** ** * * ****** * **** ** * ** * = x[i];
** ** ** **** * ****** * *** * * * * * ** * **** **** ** ** * * **** * *** ** * * * = x[i+1];
* * ** *** * * * ** ***** * * * *** * * ** *** ** * * ** * * **** * * * ** *** *** ***** = temporary;
** * ***** ** * * * * **** * *** ** * * * * *** ** * *
*** * **** ******** *** *** * * *
** * ******* **** * *
** * **** * **
*** ** ** * *** ** print the array */
** ** * * ** ** *** * * sorting: \n");
*** * ** * * i = 0; i < size; i++){
* * * * ** **** **** *** ** ** ** ** ** * **** ", x[i]); * * * * * ***** * * * ** * *********
** * ** * ***** ** *
**** ****** ** ** ** * * ** ** *
* *** * ** ** *** **
* * * ** ***
* ** * ** ** **** * ** *** ** *** * *
*** ***** ** * *** ** * * * * ** ** * * ***** **  
* * **** ** ** ***** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * **** *** **** * x[] = {77,22,88,11,22};
* ** * * * *** ** * * *** size = 5;
    
* * * * * * * **** print the array */
***** * *** *** * ** ** **** ** i = 0; i < size; i++){
* * * *** **** ** **** * * ** ** *** * * * *** * ", x[i]); * **** ** * ** * * * * ** ** **
** * * * * ***
* **** ** ****** * * * * *
** * * *** *** **
* * *** **** * ** I need this to happen size-times */
* * ** ** * * * j = 0; j < size; j++){
* ** *** ** * * * *** * *** * ** *** * * ** from left to right */
* ** ** * * ** * * ** * * * * * * * ** **** * i = 0; i < size-1; i++){
*** * * ************ * ** ****** *** * * *** * ** ** **** ** *** i-th element with its neighbor to check if they are in order */
*** ** ** *** * * ** *** * ******* *** * ** *** ** * * * * * * > x[i+1]){
**** ** **** ** **** * * *** ** * ** *** ** ** * * * ** ** *** * ***** *** *** ** * * * ** exchange the values of x[i] and x[i+1] */
* *** * ** ***** ** * ** * **** * *** ** ** * * * *** ** *** * ** * * *** * ** * *** * temporary; * * ** ** * * * ** *
* *** ** * * ** ** **** ** **** * * * * ** * * * * * **** ** * * * ** *** **** * * = x[i];
* * *** * * ***** * * * ** * * *** *** ** * ** * * *** * * * ** ** * *** * ** = x[i+1];
* ** ******** *** * *** * * ** ***** * * ***** ** * *** *** * **** * * * ** * *** * = temporary;
* ** * *** * * ** * *** * ***** ** * *** * *** * * * * *** *** **
***** **** * * ** ** ***** * ** ** *** *** *
*** * ** *** * * * *
** * * ** **** *** *
* * ** ** ** ** * * print the array */
* * *** ** * * * *** * * * * * * ** sorting: \n");
***** * ** * ****** ** * * i = 0; i < size; i++){
* * * * ************* * * **** * ** ** * * * * ***** * * ", x[i]); *** ** * **** ** ** ** * *
* ** * ** *** *
** ** * * * ** *** ** * ** *
* * *** * **
*** **** * * * * ***
* **** ** * * **** ** ***** *** *** ***
* * * * **** **** * ** *** **** ** * *  
*** * * * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** * * * * * * * x[] = {77,22,88,11,22};
* * * * * * *** * * size = 5;
    
* *** ** * ****** print the array */
* * ** ** * * ** * * i = 0; i < size; i++){
** * * ** * ** ***** ** **** * * *** * ** * **** ", x[i]); ** ** * ** * * * * * ** **
**** * * * *** ** ** * **
*** ** *** *** * * * ****** * **** **
* * ** **** *** ***
* * * ** * ***** ** ** * I need this to happen size-times */
******* * ** * **** * j = 0; j < size; j++){
* * ***** ** ***** * ** ** * ** * * * * ** * from left to right */
* * ** ** ** ** * ** ***** *** **** * * i = 0; i < size-1; i++){
*** ** * * * *** ** ** * * ***** ******** * ** * ** **** i-th element with its neighbor to check if they are in order */
* * ***** ** * * * ** * ***** *** * * * * *** * ** * * *** * * > x[i+1]){
*** * * * ** *** * * * * *** *** ****** **** *** ** **** * **** * * ***** * ** exchange the values of x[i] and x[i+1] */
** * ** * *** ** * ** * * *** * * ** ** ** ** * * * **** * * * **** * * * ****** temporary; ** * ** * ** * ** ** * **
* ***** * * * **** * * * * * * * ** ***** * *** *** ***** *** * *** *** ****** * = x[i];
** ** ** * * *** *** * ** * ** * * ** ** ** * ******* * *** * ** * **** * = x[i+1];
** * ** *** ** * ** ** * * ** * * ** * *** * ******* * ** *** * ***** **** * * * ***** * = temporary;
* **** * ** * * * ** * * * *** ***** ** * ** *** ***** *
*** **** *** * * ** ** * * * * * * ** * * **
* ** **** * * * *** *
* **** *** * * * *****
*** ***** *** ******** ** *** print the array */
******** * * ** * * ** * ** ****** sorting: \n");
* * ******* *** ****** * i = 0; i < size; i++){
*** ** * * * * ** * ** * ****** * ***** * * * *** * ** * *** ", x[i]); * *** ** * * * ******* * * ** *
* *** ** *** *** * *
** * *** ***** * * ** * *** ** ** **
* ** * * ** * *** ***
******* ** *** ** *** * ***
*** * *** *** * *** * *** ** ** * *****
* *** * * ****** *** *** * **** ** * **  
* *** * ***** ** ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** **** * **** * * x[] = {77,22,88,11,22};
** * ** * ** * * ** size = 5;
    
****** * * *** ** ** * * print the array */
*** * * * * * * i = 0; i < size; i++){
* * * * * **** * *** * * ** * * * * * ** ", x[i]); * * **** ** *** * * ** ******
* ** * ** * * * ****
** * ** * *** *** * ** ** *** ** **
* *** * * ** * ** **
****** ** * * * ** *** * * I need this to happen size-times */
* * ** ** ** * * ** j = 0; j < size; j++){
* * *** * **** ******** * ***** **** **** ** ***** * *** from left to right */
** ** * * ** ** *** * * **** ** ** ** **** * * i = 0; i < size-1; i++){
* ***** * ** * ** *** ** ** * ** * * * ** ** * ** ** ** ** * i-th element with its neighbor to check if they are in order */
* * ** ** * * * ** ** ** * *** *** * ** * **** ******* ** * * * * * > x[i+1]){
***** * ** *** * * *** ** * * * ** ** * * ** * ** * * * ** * **** exchange the values of x[i] and x[i+1] */
*** * ** **** *** * * *** ** * ****** * * *** *** ** *** *** * * * * *** * temporary; * *** * ** ** * * * * * * **
* * ** ** * **** * * ** * * * * * ** * * ***** * ****** * * * * * *** ** * ** * * ** = x[i];
***** ** **** *** ****** ** *** * * ******* * **** *** ** **** *** * ** * ** *** * * ** * = x[i+1];
**** * * * ** * ** * ** ***** *** * * * ** * ** ** * *** * * * * ** ** * **** = temporary;
******* * * ** *** * ********* * ** *** * ** *** ** * *** * *** ****
* * ** ** ** * * ** ******* ** *** * * * ** *
****** * * * *******
* ******* ** * ***
* * ** * * * * * print the array */
* ** * *** *** * ** ** sorting: \n");
* * ** ***** * * * *** i = 0; i < size; i++){
* **** * * * ** * * *** ** *** ** **** * * ***** * * ", x[i]); * ** *** *** * * * * *
* * * * ** **
* * * * ** ***** * **** *** ** * *
* * * * * * **
**** * *** ** * ****
** * ** * * * * * * * * ***** ** *****
* * ** *** * * * ** * * **** * * *  
** * * *** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ****** *** ** ** x[] = {77,22,88,11,22};
**** * * ** ** * * * * size = 5;
    
***** ** * * ** ** * ** ** print the array */
* ******* * ***** ** * ** * i = 0; i < size; i++){
* * * * ******* * * * ** * ** ** * * * ** * * *** ", x[i]); ** ** * * * * ** * ** * * * ***** *
**** *** * * * **
* *** * * * *** * ** ** * ** *** ** *** *
** *** ** * *
**** * *** * ** * * I need this to happen size-times */
* * * * ** * ** * j = 0; j < size; j++){
** * ** * ** * * * * ** * * ** *** * * from left to right */
** **** * * ** ** ** **** ** * **** * * * i = 0; i < size-1; i++){
** * * * ** * * * * ** * * * ** * ** * * * * *** * * ** * * * ***** i-th element with its neighbor to check if they are in order */
* *** * * * ********* ** ** * *** * * * * * * ****** ** * ** > x[i+1]){
* * * ** ********* ** * * * * * ** ****** ** * ** ** **** * * ** *** ** * **** * *** exchange the values of x[i] and x[i+1] */
* *** * * ** * * *** ** ***** * * ** ** *** *** * * * ** *** ** * *** *** * **** * temporary; *** * **** ** * * ** ** * ** ***** **
* * * * ** * * * * * * * * * * * *** * * * * * ** * ** ** *** * * ** * * * * ** = x[i];
** * * * * * ** ** * ******* * * * * ***** ****** * ** ******* ** ***** *** *** ** * ** ** = x[i+1];
**** *** * *** ** * * ** * ** * *** * * ** * **** * * * *** * *** ** * * ** ** * *** ** * = temporary;
* * * **** * * * ** * * *** ** * ****** * * * **** * *** * **
* ** * ** * ***** ** * ** ***** **** ** *
* ****** ** * *
** * * ** ** *
* * ** ** * * * * print the array */
** * ** * * ** * * * sorting: \n");
***** ***** **** ** * ** i = 0; i < size; i++){
* * * * ** * * * * * *** ** *** * * *** **** * * *** ", x[i]); ** ***** **** ****** * ******* *
*** *** ** * ***
*** * * * *** * *** ** ** **
* * *** *** * * ** **
* * ** * * * ** ** **
* ** ** * ** ****** * * ** ** *** *
* * ***** * * * ******** * * ** *** * ** ** **  
* * ** * * ***** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * *** *** * ** * x[] = {77,22,88,11,22};
*** * * * * * * * * size = 5;
    
*** ** * *** * ** * print the array */
** *** * ** * * * * * * i = 0; i < size; i++){
** * * **** * ** * * * ***** * * * * * *** * *** * ", x[i]); * * * ** * ** * *** * **
*** ** * *** * ** **
** * ** **** *** ** * ***** * * * ** *
* * *** * * * * *** **
** ******** * * * ** ** I need this to happen size-times */
*** *** * ** * * * *** *** j = 0; j < size; j++){
** ***** * **** * *** * * **** ** * * ** * from left to right */
* ** * *** *** ** ** *** * ** ** ** * * * * * * i = 0; i < size-1; i++){
* * ** * ** * ** ** *** * * **** ** * ****** * * * * *** * *** i-th element with its neighbor to check if they are in order */
* ** * * * * ** * * * *** **** ** ** * ** * * * * * * * * *** > x[i+1]){
* * ***** * * ** * * ** ** * * * ** * *** * ** ** * ** *** ** * ** * ** *** ** exchange the values of x[i] and x[i+1] */
* ** * ** * * * * **** *** * ** *** ** * * ** ** * * * ******** * *** *** *** *** temporary; * * **** ***** * * * * ** *** ***
* * ** * *** ** ** *** * * * *** ** * * * **** *** **** *** * * ***** *** * * ** *** * ** * * ** = x[i];
* **** *** ** * * ** ** * * ** **** * * ** * * *** * **** * * * *** * * * * = x[i+1];
** *** *** ** * * *** * ***** * * **** * * ** * * * * * * * * ** * * ** **** *** * = temporary;
** * **** * * ** **** * *** * * **** * * **** ** ******** * **
****** *** ** * ** ***** * * * ****
*** * * *** *** * * ** * ***
*** * ** ***** ****
* * *** **** *** print the array */
****** ** * ** *** **** * * * ***** sorting: \n");
*** ** ** * **** ** i = 0; i < size; i++){
** ** * *** * * * * * * * * * ****** ** * ", x[i]); * ** ** * * ******* * * * * **
* *** * **** * * ** ** *
* * * * **** * ********* ***** **
***** * * * *****
* **** ** * ** *** * *
*** ** * *** ** * *** * ** * * *
**** ** * **** * * *** * ** ****  
******** * ** * ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** **** ** * * x[] = {77,22,88,11,22};
* ****** ** * ** size = 5;
    
* * ** ** * * **** print the array */
**** **** * * * ** i = 0; i < size; i++){
***** * * ** *** ** * * ** *** ** *** ** ** ***** * * * ", x[i]); *** *** ** * * * ** ** ***** *
** * ** * * * * ***
** ** * ** * * * * * ** * * *** ** *
* * **** * *** ** *
* * ** ** **** * * I need this to happen size-times */
** * ** *** * * * j = 0; j < size; j++){
*** ** * ** * * * *** **** * * * * * * * from left to right */
** **** * * * * * ** *** **** ** **** * ** i = 0; i < size-1; i++){
* **** * ** ** ** *** * * * ** * *** * * * ** ***** * ** ***** *** *** i-th element with its neighbor to check if they are in order */
*** * ***** * ** ****** ***** ** * *** ** *** ** * * * **** * * * * * ** * * > x[i+1]){
** * * *** ** * *** * **** * ** * *** * * * ** ** *** ** * *** ** * *** * * * *** ** exchange the values of x[i] and x[i+1] */
*********** ***** * * * *** * **** *** * *** * * ****** ****** ** * ** * * * ******* * temporary; * *** * * *** * *****
** * * * ** *** **** * ** **** * ** *** **** * * * * * **** ** * * **** ** *** * * * = x[i];
** *** *** * * * ****** * ** * * ** *** *** ** * ** * ** * ** * ***** * * = x[i+1];
*** * ******* *** * ** * *** * * * * ***** * * * * ** **** * ******* * *** *** * * = temporary;
** ** * **** ** *** * **** *** * * ** *** ***** ** ** **** * *** * ***
*** * ** ** * ** * * * ** * * ***** * ***
* ** * ** * ** ***** * **
* * **** * * * * ** *
* * ** * ** ** * **** * print the array */
** * ** * * ***** * ** sorting: \n");
** * ***** * ** * ** ** i = 0; i < size; i++){
******* * **** * * * * **** * ** * *** *** * *** *** * * ", x[i]); * ** ** * ** * * * *** * ** *
* * * * ** * * * *
**** ** ** * ***** * ** * ** ** * **** **
* * * *** * * **
* * * * ** ** **
* * ** *** ******* **** * * ** * * * ** *
** *** ** ****** **** ** * * * ***** *** * ***  
** * *** *** * ******* 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** ** * * *** * ** * x[] = {77,22,88,11,22};
*** ***** ** **** *** * size = 5;
    
** * * **** * ****** * **** print the array */
** ** * * * * * *** ** ** *** i = 0; i < size; i++){
* * * * * ** **** ** * ** ******* * ***** ** ** ", x[i]); * * ** *** ** * **** ** *** *
** * * ** * ** ** *
* ** * *** * **** * ** ** ******* *
* *** ** * ** * **** **
** * *** * *** * I need this to happen size-times */
* * * *** *** * ** * *** * j = 0; j < size; j++){
** * ** ** **** * * * ** * *** * *** from left to right */
***** * ** *** * ** * ** **** * * ***** * **** * i = 0; i < size-1; i++){
** * * * * *** **** * *** ***** * * * * ** * *** ** * *** * i-th element with its neighbor to check if they are in order */
* ** *** *** * *** ***** * ****** * * * **** * * * * * * * * ** ******** > x[i+1]){
* * * * * ** * * ** *** * ** * * ** ** ** ***** * * ** ** * * ** ** **** * *** ** * * *** exchange the values of x[i] and x[i+1] */
** * * * * ****** *** ** ** * ***** * * ***** * * ** ** **** ** * temporary; **** * **** ** ** ** ****** * **** *
* * * ** *** * * * * *** * * * * ******* ** ***** ***** **** *** * ** * **** ** * * * = x[i];
* ** *** ** **** **** ****** ** * *** **** * * * * * * ** *** *** * **** **** * * ** *** = x[i+1];
* * **** * *** ** ****** * * *** * * * * * * * ** * **** *** * * ** *** * * * * * = temporary;
* * ** * * * ** * * ** **** * ** ****** *** * * * *** *** ***
** ** ****** ** ** ** ** *** ***** * ** *** ** ******
* ** * * **** *****
* ** * * * ** *
* * * ** **** * print the array */
*** * * * * ** * **** ** ** ** * ** sorting: \n");
*** ** ** * ** ** * i = 0; i < size; i++){
* * *** * * * * * ** ****** ** * ****** ****** ", x[i]); * * * ** * * ** *** * *** ***
******* * * * ****** *
****** * ** * ** *** * ** * ***** **
*** * ** * * ** ******
*** **** * ***** * ** * **
* * * ** ** ** *** *** **** **** * * * *
* ** * **** * **** *** * * * ** * **** ** * ** ** * *  
* * ** ** * *** ******* 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.172
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.7k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.7k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users