0 like 0 dislike
1.9k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 1.9k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** * ** * **** * x[] = {77,22,88,11,22};
*** ** ** * *** * * ** size = 5;
    
** ***** ** *** **** ****** * print the array */
**** * ** *** * * * i = 0; i < size; i++){
** * ** * ** * * ** ** ******* ** * **** * * * ", x[i]); **** *** ** * * *** *** * * *** * *
* * ***** * ** *
*** ***** * ******* * ** ******* * **
* * **** * *** * ** ** *
**** ** * ** ** * * ** I need this to happen size-times */
** ** ** ** ***** * *** j = 0; j < size; j++){
***** * * * * * ****** * * * * * * ** from left to right */
* *** ** * **** ** * * * ** *** ** ** * * *** * i = 0; i < size-1; i++){
* **** ** * * ** *** ******* * ** * *** * * ** * *** ** * * ** * * * ** * i-th element with its neighbor to check if they are in order */
* * * ** * *** * * *** * **** * * * * * ** ** * * * * ** ** * > x[i+1]){
** ** * **** ** ** *** ** * * ** *** * ** *** * * * * ** ********** ** * * * ** ** exchange the values of x[i] and x[i+1] */
*** ** ** **** ** ** * **** ** * ****** *** ** ** * ** * * ** * * ** * * * ** temporary; * *** *** ** * * ** *** * ** ***
* ** *** ** ** **** *** ** * * ** * *** *** *** * * ** * *** ** *** * * ** ***** = x[i];
* * * ****** * ***** * * * * ** *** * * * * * * *** * * * * * ****** *** * * **** * *** *** = x[i+1];
* **** * * ** * **** * **** ** *** * ****** * ** * * * * ****** = temporary;
*** ** * * * * * **** ** ** ** * *** * * ** ***** * * * ** ** * ***** *
* **** ** **** **** * * * * ***** * ** *
****** * * * * * *** *
**** * * *** **** * *
* ** * ******* * *** *** print the array */
* ** **** * *** ** * **** ** * sorting: \n");
* *** *** * * * ** i = 0; i < size; i++){
* * * **** * ** *** ** * * * *** * ** ** ** ", x[i]); * * * **** * ** **** ** * * * *
* ** ** * * * *
* * * * * * ** ************ ******
** * ** ** ** *****
** * ** * * * * **
** * * * ** *** * ** * **** * * * ** *
* * * *** * *** ** ** *** **** **** **** *  
** * * * *** ** *** *** *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ***** * * * ** * * x[] = {77,22,88,11,22};
* * * *** **** size = 5;
    
* * ** *** * ****** *** print the array */
* *** *** **** ** * ******* * * i = 0; i < size; i++){
****** * * * * * * ** * ** * * * ** * * ** *** *** ", x[i]); ** * * * *** * * ** ** * * **** *
** ** * ** ** * **
* ***** * * ** ** * **** * ** ** ** *** * **
* **** * ** * * * **
** ** ***** * * * * * I need this to happen size-times */
** * * * **** * *** j = 0; j < size; j++){
* * * * * * * * * * ** *** * **** * ** ** * from left to right */
* * **** ** ** * *** * *** *** * **** **** i = 0; i < size-1; i++){
**** * ** * * ** ** * ** ** **** **** * * *** ** ** ** i-th element with its neighbor to check if they are in order */
* **** ** **** ** *** ***** * ** * ** * ****** ** ***** *** * * * * * > x[i+1]){
***** * * * ** * * * * * ** ** * * * ** ******* ** * * * ** exchange the values of x[i] and x[i+1] */
** ** * ** ** ** * **** * * * ** * * * * * ** * ****** * * * *** * * * ** * * *** ** temporary; * * ** * * * * ** ** * * * * * *
** ** * ** * * * * ** ** **** ** * ***** ** * * *** ** ** ** ***** * * ** ** * * * **** * * = x[i];
******* **** * * *** * ** * * *** * *** ** * * * ** * * ** * ** *** ** * * ** = x[i+1];
* *** ** * * **** ** ** * ** * * * ** * ** ****** **** ** * ** ** * *** * ** = temporary;
** **** * * ** ** ** * * * * ***** * ** ** * ***** * * ** *
***** ****** ** * ** ** *** ** * ** ** **** *
* ** * * * ** *
* * * * ****** **** *
* ** * * * ** * * *** print the array */
* * * *** ** * * ** * sorting: \n");
*** ** * *** * * ** * * i = 0; i < size; i++){
****** * * ** ** ** ** * *** * * ** ***** *** ", x[i]); *** * * * *** * * * * * ** **** * ***
* * ***** ** *** *
* * * *** * *** *** * ** * ** ** * * * * **
** * * * ***** ***
***** ** ** *** **
* *** * * * * *** * ** *** * * *** * **** **
*** * * ** ** **** **** ** ** * * *  
* * *** * * *** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** *** * *** ** x[] = {77,22,88,11,22};
** ** ** * * * * ** size = 5;
    
** ** * * * * * * ** print the array */
** ******* ** * *** *** ** i = 0; i < size; i++){
** *** * ** * * ** ****** * * * ** * * * ** ", x[i]); * ** *** **** * * * ** *
* *** * ** * * *
*** *** * ** ** ** * * ** *** *
*** * * ** * ***
* ** ** * * * **** ***** I need this to happen size-times */
*** * ** * *** * ***** * * j = 0; j < size; j++){
* ** ** *** * ** ** * ** * *** *** ** *** from left to right */
** * ** ** * * ** ** * ** * ** * **** * ** ** * * i = 0; i < size-1; i++){
** **** *** ** * * ** *** * ********* ** *** ****** * * * * **** i-th element with its neighbor to check if they are in order */
** *** *** * * * * *** * * * ** * * * * * ** * * * * * * ***** * * * > x[i+1]){
**** ** * * * * *** * ** * * *** * * ****** *** *** * *** ***** * ** **** ** * * * exchange the values of x[i] and x[i+1] */
* * * * * * ***** * ****** * ***** * ** * ** *** ** **** *** * ** * *** ** temporary; * ****** *** *** **** *** * *
* ** * *** ** * * * ** * * **** ** * * * ** ** * ** ** *** *** *** *** * * **** ** = x[i];
* * ** * ** ** ** ** *** * ** * ** * * ** * ** * * * *** * * *** ** *** * * * * = x[i+1];
* * ** **** *** * * ****** * * **** * ** * * * * * * * ****** * * * *** * * * * * * * = temporary;
* * *** ******* * * * ** * ** ***** ** * * ** * ***** * **** ** *
** * * * ** ** ** * * ** * ** * * * * ** ****
** *** * * * *** *** **
* * * *** * * * ***
*** * ** * *** * print the array */
* ** * * * ** ****** * * * **** sorting: \n");
* * * ********* *** * i = 0; i < size; i++){
* * *** * ** * * * * * * ** *** * * * ** * * *** ", x[i]); * ** * *** **** ** * * ****
* * ** * * *****
* **** *** * * * * * * * * *
* ** * * * **
** *** ** * *** ***** ** *
* * * **** ** * ** **** * * * * *
* ** **** * * * *** *** * * *** * ** ** ** ***  
*** * * * ** * ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ********* * * * ***** * ** x[] = {77,22,88,11,22};
* * * * * *** * * size = 5;
    
***** * * ** **** ** * * ** print the array */
* *** * * * *** * i = 0; i < size; i++){
**** *** ******* ** * *** *** **** * *** * * * * * ", x[i]); * * ** **** ** * * * *** * * *
** * * *** *****
* *** * * * * * ** ** ** * ** *
* ** **** ** * * **
* ***** ** * * ** *** * I need this to happen size-times */
**** ** * * *** ** * * * * j = 0; j < size; j++){
*** ** * ***** * ** *** * * * ** * from left to right */
* * ** ** * ** * * * * * ***** *** *** * * i = 0; i < size-1; i++){
*** ** ***** * *** * * *** * *** **** *** **** * ** ** ***** ******* * ** * i-th element with its neighbor to check if they are in order */
* * * * **** * ***** ** * ******* * *** ***** ******* * * ** * * > x[i+1]){
*** *** * * ** * * *** *** * *** ** * * * **** ** * ** * *** ** * * *** *** **** * * ** * * exchange the values of x[i] and x[i+1] */
** * * * ** ** *** * **** *** ** ** * * *** * * * ** ** * * ** ***** * ***** * temporary; *** ** **** * * * ******** * **
* * * * * ** * *** *** * * * *** * ** * ***** ** ** * * * * ** * **** * = x[i];
** *** * ** *** ** * * ** ** * * * * *** **** **** * ** * * * * ** **** * * * **** * * * = x[i+1];
** ** * * ** * *** ** * ** ** * ****** ***** **** * * * ** **** * **** *** * ** * * * = temporary;
****** **** * ** **** * ** * *** *** ***** * **** * * * * ***
** * *** * *** ** * ** **** ** ** * * ******
*** * * ****** *
** *** ** * * * * ***
* ** * ** ** *** ** print the array */
* * * *** *** *** * * * * ** * * sorting: \n");
* * ** * *** * * * * * i = 0; i < size; i++){
** * * * ** **** * ** * *** * ** ** * * ** * *** * * ** ** ", x[i]); * **** * * * * *** **
** ** * * *** ** * *
** ** * *** * *** * ******** * *** * *** *
** ** **** **** * *
** ** * ***** * * ** ** * *
* * ** *** *** * ***** ** ** * *
* **** * * **** ** *** * * * ****** ******* * *****  
* * ** * **** * *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** * * ** * *** * ** * * x[] = {77,22,88,11,22};
* * **** * * ** * **** size = 5;
    
* *** * ** * * * ** print the array */
* *** **** * *** * ** i = 0; i < size; i++){
* ** * ** * *** ** ** **** * * *** * **** *** * * * * * ", x[i]); ******* ** * * ** * * ** ** **
* ** * ** ** * *** *
** ** ** ** * * * * * * ** *** * ***
** ** **** * *
*** ** ***** ** * I need this to happen size-times */
** * **** ** ** ** **** j = 0; j < size; j++){
** * * * * * ** ****** ** **** * ** * from left to right */
* ** * ** *** **** * * ***** ** ** *** i = 0; i < size-1; i++){
* ***** ** ****** *** *** ** ** **** ** * * ******* **** ** i-th element with its neighbor to check if they are in order */
* * ******* * * ** ********* * *** ** ** * **** **** * * **** ** > x[i+1]){
******* *** * ** ** ** * ***** * * * ************* ** ****** ** * * * * ***** *** exchange the values of x[i] and x[i+1] */
** ** * *** ** * ** * ** * ** **** ***** * ** ** * * * * * * * ***** ** * * * ** ** * * *** ** temporary; * ** ** ** ** *** ** ****** * ***
** * ** ** *** * *** *** * ******** ** * *** * *** * ** * ** ******** ***** * *** * = x[i];
* * ** *** **** ** *** *** * * * * * ** ** * * * * * *** ** ** * *** ** = x[i+1];
* * **** * ** **** *** * **** * *** ** * *** *** ******** * * * ** *** **** = temporary;
* ** *** *** * ***** * ****** *** ** * ** * * ****** * * * * *
** **** *** * ** * * * ** * * * * *
** *** *** *** ** ****
* * ***** * *** * *****
** ** * ** *** * * * * ** print the array */
*** * ** ** ** *** ** * ** **** * * ** sorting: \n");
* ***** ** * * ***** * i = 0; i < size; i++){
*** * *** ** **** ** ******* **** ** * * * ** **** ", x[i]); * * ** * * **** ***** *** *
* * * ** * **** *** *
* *** * ** **** * * * ****** * *
* ** ******** * ** **
** ** ** * ** *** ***
* ** ** * ** * *** * ** **
* * * ** ** * * ** ** * ***** ** * *  
* * * * ** * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** *** ********* x[] = {77,22,88,11,22};
* ** ***** * * ** * size = 5;
    
* * ***** * * ** ** print the array */
* * **** * * * ** * ** i = 0; i < size; i++){
*** * *** **** ** ** * ** * ********* *** ** ** * ", x[i]); * **** * ****** *** * * ****
* ** ** ***** * *** *** *
* ** ** *** * * *** **** * * **** **
* *** * * ** *** *
* ** * ** **** **** **** I need this to happen size-times */
** * ********* * j = 0; j < size; j++){
* ** * * * **** * * ***** ***** * ****** * * ** *** * * from left to right */
* * * * * * * * ** ** ** * **** i = 0; i < size-1; i++){
* * ** *** * * *** *** *** *** * * ** ** * **** ********** i-th element with its neighbor to check if they are in order */
** * * * ** * * *** * * ** ** * * * *** ** > x[i+1]){
**** * *** ** ** * * ** *** * * * **** * ** * * * *** * ** * * ** * ** * **** * exchange the values of x[i] and x[i+1] */
* ** ***** * ** *** * * ** *** ** * ** * ** ** * *** *** ** ** * * ** temporary; **** * ** ** ** * ** *** *** ***
***** ** * * * ** ** ***** ** ** * ** ** ** * ** * **** ** ** *** * ** ** ** * = x[i];
** ** ** ******* * **** * * ** ** * * ** * ***** ****** *** *** **** ** * * *** * * ****** * * = x[i+1];
* * ** ** ** * ***** ** * * * ***** *** **** * ** ** * ** ********** * *** ** *** = temporary;
** *** * * * *** ** ** ** ** **** * * * * *** * ** *** *
***** **** *** * ** ** ** ****
* * ***** * *** * ** *
* * *** *** **** * * *
* * * ** * ** ** print the array */
*** * * * * *** * *** * * * * sorting: \n");
*** ** ** *** ** * * * i = 0; i < size; i++){
***** ** * * *** *** * * * * * ** **** * ** ** * ** ", x[i]); ** * * *** *** ** * ** ** * **
** * ** * * * **
** * * * *** * * ** * * * * *** * *
** * * * *** ****
* ** * *** * * ***
**** *** *** ** ***** * * ** * ** ** ****
**** * * ****** **** * ** * * * *** ** * **  
** ** ** * * ** * ***** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * *** * ** * * x[] = {77,22,88,11,22};
* * * * *** ** size = 5;
    
* * * * * * **** ** * print the array */
** * * ** ***** * *** i = 0; i < size; i++){
* ***** * * * ** ** ** * * * *** ** ****** ** * * * * ", x[i]); ** * * * * * * **** ** **** *
** ** **** ** * * ***
* * * * *** * * *** ** ** *
** *** ** * * * * ** **
* * *** **** ******** ***** I need this to happen size-times */
** * *** * * *** * ** * ** * * ** j = 0; j < size; j++){
* * *** ** * * * * * * ** ** ** * * ** * * * * from left to right */
* * **** * ** * * * * * *** *** ** * * i = 0; i < size-1; i++){
*** * ** * *** * * ** ** * *** ** **** **** * * * * ** ** * * i-th element with its neighbor to check if they are in order */
* ** * *** ** * **** ** * **** ** ** ****** *** * * ** * ** ** ** ** > x[i+1]){
* * *** * * * * * *** * * *** ***** **** *** ** **** ** * * * * ** * * ** * * exchange the values of x[i] and x[i+1] */
* * **** ** *** **** * ***** * **** ***** * *** * * ** * * * * * ** *** ** * ***** * temporary; * * ***** * * * * *** * * *
** **** **** * * * * ** *** ** * *** ** * ** * * **** * * ** ** *** ** *** ** * * * = x[i];
***** *** **** * * * ** **** ** * ** ***** * ** ** * * ** *** ** *** * ****** ** * *** * = x[i+1];
*** ****** **** * * * * ********* *** **** * * * ** * * ****** * **** ***** = temporary;
***** ** * *** **** *** * **** ** * *** * * * * * ** **** * **
**** * * ***** *** * ** ** * **** ** * * *
* ******* * * * ** * **
** ** * * * * ** *
*** * * * * * print the array */
** *** * * ** ** * * * sorting: \n");
** * ** ** ** ** ** **** i = 0; i < size; i++){
* * **** * * ** * *** * ** *** * ** *** * *** * ** *** * * ** ", x[i]); * ** *** * * ** ***** ***** * *
*** ** ***** ** ** **
***** *** **** ** ** **** * ** **
* * ** * ** * ** ******
* * ** ** ** * **
* * * * * ** ***** * * * * ** ** ** **
** * **** *** * * ** * * * * ** * * * * * *  
*** * ** * ** *** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * *** * ** *** *** x[] = {77,22,88,11,22};
* *** * * **** ** **** ** size = 5;
    
** * * * * *** *** * *** print the array */
***** * ** * * *** ******* * * i = 0; i < size; i++){
**** *** *** ** ** * ** ** * *** * ** *** ** ******* ", x[i]); * ** * * * **** *** **** **
** ** ** * * ** ** * ** *****
** *** ** * * **** ** * ** ****
* *** * ** ** ***
* *** * * ** * * * * I need this to happen size-times */
** ****** ** **** ***** ** * j = 0; j < size; j++){
* *** **** ***** * *** * ** ** **** ** **** from left to right */
*** ***** *** ** ** * * * ***** * * * * i = 0; i < size-1; i++){
* * ** * * *** **** ** ** ****** * *** ** * * ** * ** * *** * * **** * i-th element with its neighbor to check if they are in order */
**** ** *** * * ** *** * * * **** * ** **** ** * ** * *** ***** * > x[i+1]){
* *** ** * ** *** * ** ** * *** * * * ** * ** * * ** * **** * * *** **** ** *** exchange the values of x[i] and x[i+1] */
*** ** * *** * * * * ** ** * *** ** ** * * * **** * ** ** * ** *** * ** *** *** * * temporary; * * * * **** ** ** * * ** ***
** * ** ****** * ** * * *** * ** *** ** ** * ** * * * ** **** * * ** * * * ** **** * * * * = x[i];
* ** * * * * ** **** * * *** ** * * ** * *** * * * * **** * * * ** **** ** * * * *** = x[i+1];
* * ** **** ** * * * **** *** * * * ** ** *** * * ******* * * ** * ***** = temporary;
* *** ******* *** * **** ***** *** **** * * *** ** ** *** * *
*** ** ** ** * * * * * * * * * ** ** *****
* ** ******* * * **
* ** * * *** *** *
* *** *** **** *** * ** print the array */
** ** *** * * *** * ** * sorting: \n");
* * ** * * ** ****** * ****** i = 0; i < size; i++){
** ** * * * * * * *** **** * * ** **** * * *** ", x[i]); *** * * * *** * * ***** * ***
* **** * *** * ** * *
*** ***** * * *** ** * ** * *** ***
*** ****** * **** *
** * ***** * ** *****
* ** * * ** ** * * * * * ** *** * ***
* ** * * ** ** * * *** ******* ** *** **  
* **** ***** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
****** **** * * * ** * * * x[] = {77,22,88,11,22};
** ****** * * * ** * size = 5;
    
* * * * * * ** ** * ** * print the array */
**** * * **** *** ** * * * i = 0; i < size; i++){
* * ** *** * * * ** *** *** * * * ** ** ** * ", x[i]); * ***** **** * * * ***** **
** * * * *** *
* **** ** **** * * * * * *** *
* * ** *** ** *** **
** * * ** ** ** ** * I need this to happen size-times */
* ********* * **** * j = 0; j < size; j++){
* *** * * *** ****** ** * **** *** * * * ** from left to right */
*** * * * ** * ******* ** ** * * ** **** * i = 0; i < size-1; i++){
* * * * ** * * * * * *** ** * **** **** ** * * * * * * ** * i-th element with its neighbor to check if they are in order */
* * *** * * *** * ** * **** ** * * ** ***** * *** * *** ** ***** *** > x[i+1]){
** **** ** ** *** * * * * **** ** * *** * * * ** *** ** * ** * ** * * * exchange the values of x[i] and x[i+1] */
** *** * ** *** * * ** ** ***** ** *** ** ** * * ** * * * * ** ** ** * *** * temporary; * * * * ** * * ** ******** *
* * **** * ** *** ** ***** * *** * ** * * ****** ** *** * * * * * * *** * * * ******** * ** = x[i];
* ***** **** * * * **** * *** * **** * ** ** * ** ** * **** * *** * ** **** * = x[i+1];
***** * * ** ** *** ** *** * * ****** * * ******* * ** ** *** ** * * ** ***** = temporary;
* ** * ** * * * ** *** * *** * ** * ** *** * ** *** * * **
*** * * ** *** *** * * *** * **** ***** * *
*** *** *** ** * * * * *
* * * * ***** *** * ***
* * ** *** * * ** print the array */
* * * * * * * ***** ** * * sorting: \n");
* ****** * **** * * ** * * i = 0; i < size; i++){
***** ****** * * ** **** * * *** ** * * * * * * * * ** * ", x[i]); *** * ** *** *** ** *** ** ****
** * *** * * * *** * *** *
**** ** *** ** ** * ** ** *** * * * ***
* * ** ** ** ***** * **
* *** **** ** *
* * **** * ** * * ******** * *** * *** *
* * **** * ** **** **** ***** ** * ***** * ** **  
* ** * ** * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** **** ** * ** * * x[] = {77,22,88,11,22};
** * * * **** ** *** size = 5;
    
* *** * * * * * * *** print the array */
* * ***** *** * ***** * * ** i = 0; i < size; i++){
************ ****** ** * * * * **** ** *** * * ", x[i]); *** *** * ** * *** *** ** *
* * * * ****** * *
** * * ** **** **** ** ** ***** * * * *
* * ** * * * *****
* ** ******* * * * I need this to happen size-times */
**** * **** ******* * j = 0; j < size; j++){
**** * ** * * * *** * ** * * ****** *** * * *** from left to right */
**** * ** * *** * **** * ****** ** *** * * * ** i = 0; i < size-1; i++){
** ** * * ** * ** * * ********* ** * *** ** *** * **** ** ** ** * * * i-th element with its neighbor to check if they are in order */
* * ****** ** ** * * * ** * ** * ***** * * * **** * *** * * **** * * * > x[i+1]){
*** * ** ****** * * ** * * ** ** * * * * *** * *** * *** * * ******** * **** * *** **** exchange the values of x[i] and x[i+1] */
*** ** *** * ** ** ** *** ** * ** * * * * ** * *** * * * * *** ** **** * ** temporary; * * ***** ** ** * ** * ****
* * ** * * * ** * **** * *** **** ******* ** ** ** *** * * * ** * ** = x[i];
* *** * ** ** **** *** ** *** * * ** ***** ** ******* ** ** * * ** * * ** * * = x[i+1];
* * * * * ** * **** ** * * * ****** ** ** * ** * **** ** * ** *** **** * * * ** ** ** = temporary;
* *** * **** * * * * ******* ** * * ** * * *** *** ** ** ** * *****
* * * * * * **** * *** * * * ** * ** * ** ** *
* ****** *** * ** * *
** * **** * ****** * * *
* ** **** * * *** *** print the array */
* *** ****** ** * **** ** * **** sorting: \n");
* *** * *** * ** * * * i = 0; i < size; i++){
*** ** ** ** *** * **** * ** * **** ** * * ** *** ", x[i]); ** * * **** * *** * * ** *
* * * * * ** * * **** *** ** **
***** ** * * * * * * *** *
** ** *** * * ****
***** *** * ****
* * * * * **** * * * ** * ****** *
* * **** * ** * ***** *** ** * *** *  
** *** ** ** *** **** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.62
©2016-2024

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 651 views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 924 views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 578 views
12,783 questions
183,443 answers
172,219 comments
4,824 users