0 like 0 dislike
8.5k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.5k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * * ** ** * x[] = {77,22,88,11,22};
***** * * * * * ** * * ** size = 5;
    
** ** ** * *** * *** print the array */
** ***** * * * * * * ** ** i = 0; i < size; i++){
* ** *** *** ** *** * ** * * * * *** ** ", x[i]); **** **** * * * ** * **
* ** ** * **** * ****
** *** ** *** * * * ** ** ** *** * **
***** * * *** * *** * **
** * * **** *** * I need this to happen size-times */
******** * * * ******** j = 0; j < size; j++){
**** ** * * ** * * **** ***** ** * * ** from left to right */
** * ** ** * * ** ****** ** * * **** **** * *** i = 0; i < size-1; i++){
* ** * ***** * * ** * * * *** * * ** ** ** * *** ** ** ** i-th element with its neighbor to check if they are in order */
*** * * * ********* * * * ** * *** * * * * ** ** ***** * ** * * * > x[i+1]){
** ** * ** * ** * * ** ** * ***** * * * * **** * *** * * * ** **** * exchange the values of x[i] and x[i+1] */
* * * ** * * * **** * * * * ** ** **** **** ** * **** * * * ** **** * * ** temporary; * ** ** * ** ***** **** ** * ** *
** * ********** *** ** ***** * ***** ***** * * * * ** *** * ** ** * * * * *** *** * * * * = x[i];
** ** *** * ****** * ** ** * * ** ** * * * * * *** ** *** * * ** * * ** *** * * ***** * * = x[i+1];
** * * * *** * * **** *** *** * ** * * * ******* **** ** *** ****** *** ** * **** ** ** * = temporary;
* *** * ** *** ** * ** * *** * ***** * * ** * * *** * ** *** *
* * ** * * *** * * * * * **** *
* * ******* ** * **
*** * **** *** *** **** **
*** ** ** * ** ** *** print the array */
** ** * ** * **** *** * * * * sorting: \n");
* ** * * * * ** * ** * i = 0; i < size; i++){
******* ** ****** ** * * * ***** * ** *** ** ***** ** ", x[i]); ** ** ** * ****** * * **** * * * *
* *** * * **** ** ***
** * * ** * * * ** * * * * ** ** * * * *
** * ** * * * *** *
* *** * * ** *
**** ** *** ***** ** *** ** ** *******
*** ** * ** ** ** ** *** * **** * *** **  
**** ** ** * ** ** ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** * * * x[] = {77,22,88,11,22};
* *** * * ** ** * size = 5;
    
*** ** * * * ***** * * print the array */
******** ** *** i = 0; i < size; i++){
*** ** *** *** * * **** ** ***** * * * *** ** * * * * ** ", x[i]); ** ** * *** * * * * * *** ***
** **** ** * ** ** ***** **
* * ** *** * ***** * * ** * * * **
* ** * ** * ** ***
* ** *** ** * * ******* I need this to happen size-times */
** ** ** * * * ** ** * * j = 0; j < size; j++){
*** * * *** *** ** ** *** * ** ** * ** ** * ** from left to right */
* ** *** ** * *** *** *** * * * ** * ** i = 0; i < size-1; i++){
* ** * * ** * * *** ** *** * ** ***** **** * * * ** * * * *** ** * * * ** i-th element with its neighbor to check if they are in order */
* **** ** *** ** * ** *** * * * * * * ******* * * *** ** * ** *** ** > x[i+1]){
* * * * *** ** ** **** **** ** * * *** * ** * *** *** * *** *** * ***** ** ** * * ** exchange the values of x[i] and x[i+1] */
*** * * ** * * * * ** * * * * * ** ** **** * * * ** * **** * ** **** * **** temporary; * ** * * * ** * * * *** * * **
* ** * * ******* ** **** ** *** ******* * *** ***** * ** ** * * * * **** * **** = x[i];
* * ** * * **** ** * ** * * ** * * ***** *** *** *** *** * * **** * * * * ** *** ** = x[i+1];
** ** * * * ** * *** * * ** * ** *** *** ** * * * ** * *** * * ****** * * = temporary;
** **** * ** ** * * ** * * ***** ** ** *** ** **** * ** * * ***
* * * * ** ***** ***** * * ******** ****** * **
*** ** * * * ** **** **
** **** * ** * ** ***
*** ** * * * * * * * print the array */
** * *** * *** ** * * **** * sorting: \n");
** ** * * * ** * * ** ** * i = 0; i < size; i++){
** * ****** ** *** **** * * ** * * ** * **** ", x[i]); * ** *** ** **** ** ** * ***
* * * * *** * **
** ** * *** * * * ******* *
* *** * ** **** ** *
** *** * * *** * * *
* ** *** ** *** * * * * * *
** ** ** ** ** *** ** ** * *** **** * * *  
** *** * * *** **** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * **** **** **** *** x[] = {77,22,88,11,22};
*** * **** *** * ** ** size = 5;
    
** ***** * **** * print the array */
** * *** * * * ** * ** * ** i = 0; i < size; i++){
* * * * **** * * *** ** ****** * * ** * * ** ", x[i]); * ** * * ** * * * *** * ** ** **
**** ** * *** * * ***** *
** * ** * * ** * * ***** * ***** *** * **
* * *** * * ** ** ****
* ** * **** ** ** *** I need this to happen size-times */
* * *** *** * *** ** *** j = 0; j < size; j++){
* ** * * ** * *** * * ** ** * ** *** * from left to right */
* ** ** ** *** ** * ******* ** * *** * ** * * i = 0; i < size-1; i++){
** *** * * * * ** * ** ***** * ***** ***** *** * ** ** ** * * * * * i-th element with its neighbor to check if they are in order */
* ** * * * * ** * ** * * * * * * *** ***** * ****** * > x[i+1]){
** ** ** * **** **** * ** * * * * ** *** **** * * ** * * * ***** * * ******* * **** ** * exchange the values of x[i] and x[i+1] */
*** ** * * ** ** ** * * * ** ** ** *** ** ** **** *** * * * * *** * **** ** temporary; * *** * * *** ** * * **
** * * * * * * * * ***** * ** * * * * * * ** * ** * ** * **** *********** * ** = x[i];
* * *** * ** ** * * ** *** * * * ** **** * * *** ** *** *** ** ** *** ** *** * * * * ** * * ** = x[i+1];
* ** ** ***** *** * ** *** * *** * ** **** ** ** *** * *** * *** * **** * * **** ** = temporary;
** ** ** **** * * * ** ** ***** * ** ** * *** * ***** * *** ****
* * *** ** ****** ** * ** ***** ** ** * ***
* * ***** * ** ** *** * **
** * * *** *** **
* ** ****** * * print the array */
*** ** * * ****** * * * sorting: \n");
* * ** * ***** * *** * i = 0; i < size; i++){
** *** *** ** *** * ** * * * ** **** * * *** ** *** * *** ", x[i]); * * * *** ***** *** ********* *
** * **** * * * * **
* * * ** * *** * * * *** * ** * ** ** *
* * ** ** ***** ** **
* * ** *********** * *
****** * **** ** * * * * **** *** **
* * ** * * **** * ** * * * * * * **** * *  
** **** * ** ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** **** ****** * ** * * x[] = {77,22,88,11,22};
* * *** * * ** *** * size = 5;
    
** * * *** ******* * ** ** * print the array */
* * * *** * **** * ****** i = 0; i < size; i++){
** * * ** * * ** * * * * ***** ***** ****** ** ** ", x[i]); **** * * * * * * * * ** ** * * **
* **** *** ***** * ** *
*** ** * ** ** **** * * ** **
* * *** * * *** **
* * * * * * * ** ***** I need this to happen size-times */
* ** ** *** **** * * * ** j = 0; j < size; j++){
** * * * *** ** * ** * * ** * ** ** *** * ** ** from left to right */
** ** *** * ** *** *** * ***** *** * *** * i = 0; i < size-1; i++){
* * ** * * *** * ** * * * * * * * * ** * ** * * *** * * * i-th element with its neighbor to check if they are in order */
* ** ** ** * *** **** ** ** ** * * ******* * ** * * * *** * > x[i+1]){
*** * * ** *** *** * ** ** * * *** * * **** * ** * * ***** ** * ** * ** exchange the values of x[i] and x[i+1] */
* *** *** *** *** * * * * *** * ** ****** ** ** ** ** ** * **** * * * * * * * * temporary; **** * * * * ** * * * * ** ****
* * **** * * *** * * *** ** ** * * * * * * *** * * * *** *** * *** * ** **** * = x[i];
* * ** * **** ** ** * *** * * *** * **** ** * * * * * *** *** ***** ** = x[i+1];
* ** ****** ** ** * * ** ***** ** * * ** * * * ** * ** ** ** * * ** * * ** *** * * * * = temporary;
**** *** ***** * ** **** * ** * ** ** * *** *** * ** *** ****** *
*** *** * ** ** * * * **** * * *** * * *
* ** * * *** * ** **
****** ** ** * * * * * ** *
* * * * **** * ***** print the array */
** * * * * * * * * sorting: \n");
* * * ** * ** * ***** ** i = 0; i < size; i++){
***** ** * *** * * *** * ****** * * * *** *** * ", x[i]); * ** ******* ***** ** * *
* ** * * * * *** *** *
***** *** * * * *** ** ** * * ******
*** *** ** * *
* ** * * ****** ** *** *
** * * * ** ** * * * * **** ***
** ** * ****** ** *** * ** ** *  
*** ** * * *** ****** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * * * * **** * x[] = {77,22,88,11,22};
** * ** * ** * * * * ** ** size = 5;
    
** * ** *** * * * * print the array */
*** **** **** * ** ****** i = 0; i < size; i++){
* * ** ** *** ****** ** **** * * ** ** **** * ", x[i]); * * * * * ********** *** ** ** ***
***** * * **** ** * *
** * *** * * ** * *** * * **** **** ** ** *
** * **** *** * * * *
***** * * * ***** * * * * * I need this to happen size-times */
* * ** * *** * **** *** ***** j = 0; j < size; j++){
* ** * **** * * * * ** * *** ** ******* * *** * ** from left to right */
*** *** * * ** **** ***** * * * * *** * ** * i = 0; i < size-1; i++){
****** **** ** *** **** ** ** * ** * ** * ** * ** * **** * **** * ******** i-th element with its neighbor to check if they are in order */
*** *** ** **** ** * *** * *** * *** * *** ****** * * * * > x[i+1]){
** * ** * * * ** **** ** * ** *** ** ** * ** ** * ** *** * * ** ***** * **** * * exchange the values of x[i] and x[i+1] */
* ** ** ** * * * ** **** * ** * * * ** ***** **** ** ** ***** * *** *** * ******* temporary; * * ****** * *** * * ** * ** *
* ** * ** ****** ** * ** **** *** * ** * * ** ** * ** * ** * *** * ** ** ** * ** = x[i];
* * **** ** **** * ***** * * * ** * **** * ** *** ** * ****** ** ***** * * = x[i+1];
* ** *** ***** ***** ** **** *** ** ** ** * * * * * * ** *** * * * * * * * * * *** **** * = temporary;
** * ***** * * ** ** *** * * *** *** * *** * * **
* ******* ** * * ** *** **** ** * * * *
* * * * * ** ***** ****
* * *** * ****** ** *** *
* * * **** * ***** * ***** print the array */
* **** * * * **** ** * * * sorting: \n");
** *** * * ** ** ** **** * * * i = 0; i < size; i++){
* * * * ** * *** **** * * ** ** **** ** ** ** ", x[i]); * ** * * * * * * ** * *
** * **** * * ***
* * ** ******* *** ** *****
*** * * *
* *** *** **** *** * * *
* * ** *** * * * *** * ** ****
**** ** * * ***** * *** ** * * **** ** * * *  
**** * ** ***** ** ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** ******* * * * x[] = {77,22,88,11,22};
** **** * * * * ** size = 5;
    
* * * **** ** ** print the array */
* ** * ****** ** ** ** * ** i = 0; i < size; i++){
* ** * * ** *** ** ** * ** ** * * **** *** ** ", x[i]); * *** **** * ** *** **** * *
** * ** * * ** * **
* * ** * * * ** * **** ** * ******
* * * **** * * ****
** * * ** *** * * * * * I need this to happen size-times */
* ** * *** * * * ** ** * * j = 0; j < size; j++){
** * *** *** * **** * * * ** ******* * **** from left to right */
* * ** ** ******* ***** ** * *** * ** ** ** ** i = 0; i < size-1; i++){
* **** *** * *** * *** * * ***** * * *** * *** * **** *** * * * **** i-th element with its neighbor to check if they are in order */
* * ** ** * * * * ** * * ** * ** *** * * * * *** * * * * *** > x[i+1]){
** * * * * * * * * ** *** * * * ** *** * * ** *** *** * ** ** * ** **** ** * * exchange the values of x[i] and x[i+1] */
** * ** * * *** * ** * * * **** * ** **** * * * * * * * ****** * * ** * ***** ** temporary; ** * * * ** ** * ** * ** *** * **
* ** * * ** *** * ** * ** * **** *** ** ** ** *** * ***** *** * * * ** *** * ** * = x[i];
*** * * * * **** ** * * * * ** **** ****** * * * * * * ****** * ** ** * ** = x[i+1];
********* ***** * * * ****** * * ** * * ** * ** *** * * * *** ** * ***** * ****** ** = temporary;
* ***** ** * ** ** **** ** * * ** ** * * * * * ***** *
***** *** * * * * **** * *** *** ** *
* * ** * **** *** **
** **** * *** * * *
*** * ** ** * ** ** print the array */
* ** * ** * ******** ** * * * * sorting: \n");
* * *** ** * * * ** i = 0; i < size; i++){
****** ** * * *** * *** * * **** ** *** ** * ", x[i]); * * * * *** *** * ** * **** ***
* *** * * ***** ** ** ***** **
* * **** * *** ** ** **
********** ***** ****** * *
** * *** ***** *** *
*** * ** ** ** * * *** * ** ** ** ****
* *** * ** * * ** * ** **** * **** * * *  
* ** ***** **** ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** * ** * * * **** x[] = {77,22,88,11,22};
* * * * * ** ** * *** size = 5;
    
* * * ** *** * * ****** * print the array */
* **** *** * *** * i = 0; i < size; i++){
***** * * * * * ** * * **** ** ** * *** ***** *** ", x[i]); ** *** ** **** ** ** * * * ** ** *
** ** * * * * * **** *
* ***** **** *** * * ** ** *** ** ******* * *
** ******* * * **
** * * *** * * * ** I need this to happen size-times */
** ** *** *** * * j = 0; j < size; j++){
* ** * ** * *** * * ** ** * * * * * * ** from left to right */
* ** ** * *** *** ** ** * * * ** ** *** ** * **** i = 0; i < size-1; i++){
* ** *** * * *** ** * * * * * ****** * ** * * *** **** * * **** * i-th element with its neighbor to check if they are in order */
* *** *** * * * *** * ***** *** *** ** ** *** ** ** * * * * * ***** * * ** > x[i+1]){
*** * ** ** * *** * * * ** * * * *** * *** * * **** * * * *** * ** ** ***** exchange the values of x[i] and x[i+1] */
* * ** *** ** *** ***** * ** * ** * ****** ** ** *** * ** * * *** * * ** ***** *** ** *** * temporary; ****** * ** ** * *** ****
* * *** * **** ** * *** ** * *** ******* * * *** * * * * ***** *** * ** ** * ** * = x[i];
* * * * * * * * * ** * **** * ** * * ** * * **** * * *** * * * ** ** ** * * *** * = x[i+1];
* * ** ****** ** *********** * ** ** * * *** ** * * *** * ** ***** *** * ** * * = temporary;
*** ***** *** * **** * * * * * *** *** *** * **** ** * *** ** ** * * *** *
* * * ** **** * ** ** * * ** *** * ** *
* ** ** ** ** * * **
* ** * ** * ** * *****
***** ** * * *** * *** ** * print the array */
* * ** *** * *** ***** * *** ** * * sorting: \n");
** **** * * ** ** * i = 0; i < size; i++){
* * * * * * * ** ** **** * **** * * ** * ****** ", x[i]); ** * * *** ** **** * ****
*** * *** **** ***
******* * ** * ** *** *** * **
* * * * * ** *
** * ** ***** * ** * ***
* ** * ****** *** ** ***** * * * * ****
** * ** * ** * * * * * * * ** ******* ** *  
**** *** ** ** ** ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ***** * *** ** x[] = {77,22,88,11,22};
** *** ****** ** **** size = 5;
    
* * * ** ********* * **** print the array */
* * * ** * *** *** *** ** i = 0; i < size; i++){
***** * * **** * * ** * * * * * * * ** ** * ", x[i]); * ** **** *** ** * * *** ** ** **
** * * * ** *** **
** * ** *** ** ** ** ** * ***
* ** **** * * ***** *** *
** ** * ** ** *** I need this to happen size-times */
* * ** * **** ** *** * j = 0; j < size; j++){
*** * * * * ** * * *** ** * * * * * * from left to right */
* ** * *** ** ** ** * *** ******* *** ** * * i = 0; i < size-1; i++){
** ********* * ** ** ** * * ********* * * * * *** * **** * ** * ** *** i-th element with its neighbor to check if they are in order */
* ***** * * * * **** * * *** *** *** * **** ** * ** * *** * * * > x[i+1]){
* * * * ** ** ** *** * **** * * *** *** * * * ** * ******** ***** * *** * * **** exchange the values of x[i] and x[i+1] */
*** *** ** ** **** * * ***** ** ** * ** *** **** * * ** * *** ** *** *** ****** * *** **** * temporary; ****** ** *** *** * * * ** ****
* * * * * ** * * * * * *** ***** **** **** ** *** * * * * * * * * * **** **** = x[i];
* * * ** * * *** *** *** * ** ** **** ** * ****** * ** ** **** **** * * * * *** * * * **** *** = x[i+1];
* *** * * * *** *** *** **** ****** * * * * * * ** * * * * * ** ** * ** = temporary;
**** * **** **** *** ** * ** ** ****** *** * * * * * ** * ** * ****** * * *
** ** * * ** * ** * * * * ** ** ***
* * * * * * * ** * * **
* * * * * *** ****
** **** * ****** * print the array */
* * * ** * **** ** ***** * sorting: \n");
***** ** * ** *** i = 0; i < size; i++){
* * * * ** **** ** * ** ** * ** * * ***** ", x[i]); * * *** * *** **** * *** * **** *
* * ** ****** *
*** * * *** * * *** ** *** * * ***
* * * * * **** * ** *
**** * * * **** *
******* ** * ** * ** ** * * ** ** * **
** **** ** * * * * **** ** ***** * * ** * ***  
* * * * * **** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * *** ** * ** x[] = {77,22,88,11,22};
* * * * * * * **** * size = 5;
    
** **** * **** **** print the array */
** ** ** ** * * * * * ** * * i = 0; i < size; i++){
* * * ******** ** **** * * ****** ** * * * * * ", x[i]); *** * * * * * *** ** * *** ***
**** ** * ** *** *
* * * * *** ****** ** * ***** **** ** *
* * * * ** * *
** * * * * * ** * ** I need this to happen size-times */
* * *** * * * * * * * j = 0; j < size; j++){
** *** *** ** ** *** *** ** * * * * *** * * from left to right */
* * * * * * ** * * **** * ** *** ** * * * i = 0; i < size-1; i++){
* **** * * ** **** *** * * * * *** * * ** *** * ** * * * **** *** i-th element with its neighbor to check if they are in order */
***** ** * * ** *** * ***** ** * *** * ** *** ** * **** *** * ** * ** > x[i+1]){
** * * ** * * *** * * *** ** * ****** **** * * ** * ** * * ** * * * ****** * * * * * * exchange the values of x[i] and x[i+1] */
** * ** * ****** * * ** * *** **** * ** * * ** ** * * *** * *** *********** * temporary; * ** * * * * *** ** **** *** ** **** * *
* *** * *** *** ****** * *** * ** *** *** *** ** * ** **** *** *** *** * * *** * *** * ** = x[i];
**** * * *** * * * ** *** *** * ** * **** ** **** * *** *** * ***** *** ** * * *** * ** * = x[i+1];
* ** ****** *** ******* ** ** ** *** ** **** * *** ** **** * * * ****** ** * * * * = temporary;
* **** *** ***** *** ** *** ** * * ******* * ** ** * *
**** * * * **** * * ** ** *** ** ******* * *** ***
* * ** ** * * * * * * ****
** * * * * * **
*** **** * * *** * ** print the array */
* * ** **** * ** * ** ** sorting: \n");
*** *** **** ** * * * i = 0; i < size; i++){
**** **** * * * **** ** ** ***** ** **** *** ", x[i]); ** ** * * ** * ** ** **
* *** ** * * ** * *** *
** * * *** * * * ** * ** * ** ** ** ** *
** ** * *** *
* *** ** * ***** * * *
** ** * *** * *** **** * ** * ******
*** ** ** *** * **** * ** * * **** *** * *  
****** * * * * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * * * * * x[] = {77,22,88,11,22};
****** ** * ** * * *** size = 5;
    
* ** * ** ** * * ** * ** print the array */
***** * * * ****** * ** * * i = 0; i < size; i++){
*** * * ** * * *** * * *** *** **** ******** * *** ** ", x[i]); * **** * *** * ** * ** ** **** *
** *** * * * * * *** *
* ** * * * ** ** *** * * *** * ** ****
** ** ** ** * * * * * * * * **
* ** * * **** * * ** I need this to happen size-times */
* * *** * **** ** ** **** * j = 0; j < size; j++){
* ** *** * **** * ** *** * * **** ** ** * ** ** * from left to right */
***** ** ** * * * *** ***** ** * * ** *** * * * i = 0; i < size-1; i++){
** * **** ***** * * ** *** * *** ** ** * *** ** ** ** **** ** i-th element with its neighbor to check if they are in order */
** *** ** * *** ** * *** **** **** *** * ** * * ** ***** * ** > x[i+1]){
* * * * *** ***** * * * *** * * ***** * *** ***** ** ** * ** ** *** *** **** * ** * ** * exchange the values of x[i] and x[i+1] */
* * *** ******** ******** * * *** * * * ** ** *** * ** *** **** * *** * * ** temporary; * * * ** ** * *** ** * * ** **** ** **
** * *** * ** * ** * ** * * * **** ** **** *** * ** * ** * ** * *** * **** = x[i];
* **** * * ** * **** * *** ** * * ** ** * * * ** * *** ** * * * ***** * * * *** ***** ***** * = x[i+1];
** **** * * ****** * *** ** * **** * * ** ** * * ** *** ** * * * * *** = temporary;
* ** *** *** * ** * * * * **** * * * *** ** *****
* ** ** ** * ** ** *** ** * *** ** * * ** * *
* ****** * **** *** *
* * *** **** * ** *
** ** ** * ** * *** * ** print the array */
* * * * * * *** * * * * ** * ** sorting: \n");
* **** * * * *** ** i = 0; i < size; i++){
* * * * ** * * *** * * * ** ** ** * * ** * ** * * * * * ", x[i]); ** * ** * **** * * * ** * *
*** * * ** ** * * **
** ** * * ** * ****** * * ** * * *
** ** **** *** ***
*********** * * * * *
* * ****** * ** * * * ***** *** * * * **
***** ** * ** *** * *** * * * * ****  
* ** ***** * ** * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.185
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.2k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users