0 like 0 dislike
6.4k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 6.4k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * **** ** * * *** x[] = {77,22,88,11,22};
******* ** ** * *** size = 5;
    
*** ***** * * * * * * print the array */
**** ** *** ** *** * * * i = 0; i < size; i++){
** ** * ** *** *********** *** ** * *** *** * ", x[i]); ** *** ** * ** * *** * ******** ** **
** *** ***** **** ***
* ** **** *** ** * * * * ***** *** ** *
* *** * * * *
** ** ******* * **** ***** I need this to happen size-times */
* ** * ** *** *** ** * * ** j = 0; j < size; j++){
* * * **** **** * * ** ** ****** ** from left to right */
*** ** * * **** ** * *** *** ** * * *** * * i = 0; i < size-1; i++){
* * * ** *** *** * * * *** * ** ***** ** * * ** * * * ** ** i-th element with its neighbor to check if they are in order */
* ** * * ****** * *** ** *** * ** ** **** * * * * ** * * * * ** * * * > x[i+1]){
* * * * * ** ** * * ** ** * ** ** * * ** *** * ** *** ** ***** ** ** *** * ** * ** exchange the values of x[i] and x[i+1] */
* ***** *** ** ** ** ** ** * ** ** ** ** * * ****** * * ** * ** * ** * * ** ***** temporary; *** * * ***** ******* * ** * ** *
*** ** * ** * ** * * **** ***** * * **** * * * * * ** * ** ** ** * * ** ** ** ******** * ** * = x[i];
* * ** ** * **** * *** * *** ** * * ** * * * ** * * * ** * ** * * * * * * * = x[i+1];
*** *** * *** ** * * ****** ** * *** * * ** ** *** ** * * ** ** *** * ** **** * * = temporary;
** * * * * ** * *** * ** * ** * ******* ** * * **** *
* * *** *** ** **** * * ***** ** ****** ** *
***** * * *** * ****** *
** ** * ** * * **
* ** * * * * print the array */
* * *** ** ** *** * ** ** sorting: \n");
** * * *** ** * * * ** i = 0; i < size; i++){
** *** ** * ** * ***** ** * *** ** * ** ************ ", x[i]); *** ** * * *** * ** ** * *
* **** ** ****** *** *
**** ** **** * ** ** * ** ** ** ***** * *
* *** * *** * * ** **
*** ** * *** ** *** * *
* * ** ** *** ** * * ** *** ** * * *
**** *** *** * *** ****** ** * * *** *** * * * *  
* ** ** **** * ** * ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** * ** *** *** ** x[] = {77,22,88,11,22};
**** **** * * ** * **** size = 5;
    
* ** ** * **** * * **** * print the array */
* ****** * * * ** ** ** i = 0; i < size; i++){
** ** ** * ** ** ** * ****** * * *** * * * * * * ", x[i]); ** * * * * ** ** ** *** ** **
* * ** * *** ** **
* * * **** * *** * * *** ** * *
** * ****** ***** **
* ** ***** ** * * I need this to happen size-times */
** ****** * ** ******** j = 0; j < size; j++){
* *** ** * *** ** ** * * ** * *** * * from left to right */
* * ********** * ***** *** * *** ** ** ** i = 0; i < size-1; i++){
*** * ***** * * ** ** * *** * * * *** * * * ******** *** * * ** *** * i-th element with its neighbor to check if they are in order */
* ** ** * * ** * * **** * * * * * ** *** *** * ** *** > x[i+1]){
* * ****** ** *** ** ** * * ****** ** *** ** * ** ** * * ** **** * * ** * * exchange the values of x[i] and x[i+1] */
*** *** * **** ** * ** ** ** *** * ** ** * * * * * ** ** ********* * * *** ** temporary; * ** * ** * * * * ** *** ** ***
** * ** ** **** * * * * ** ** * * *** * * * ** ** ** ***** ** * * * ***** *** ** * = x[i];
** ** ** * * * * **** **** ** ** *** **** ** * *** * ***** ** ***** ** * * = x[i+1];
** * * **** * * *** ** * ** *** **** * ** * * *** ** * ************* ****** * *** ** * = temporary;
* * * * * ** * *** * **** *** * * ****** * ** ** * ** *** * *
*** * * * * ** * *** * *** * ** ****
* * * * * ** * ***
* ** * *** **** * *** *
* *** ** * * **** print the array */
*** *** * * *** ** **** * *** ** sorting: \n");
** ** ** * * *** * * * ** * i = 0; i < size; i++){
** **** * * * * ** *** * *** *** ** * ** **** *** **** ", x[i]); ** * * **** * * ** * *** * ** * *
* * ** ****** * ***
** * * *** * *** ***** ** * *** * * ****
*** *** ** ******
** ** ** * * ** ** *
* **** * ** * ** * * * * ** * **
* ** ** * * * * * *** * * * *** *** *  
* * ** ** **** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** *** ** *** * ** * x[] = {77,22,88,11,22};
** ** **** ** * * size = 5;
    
* * * ** * * ** * print the array */
* * ** * * *** * * i = 0; i < size; i++){
** ***** ** * ** * * * ** **** * * ** * * ** * ** ", x[i]); * * * *** ****** * ** *
* ** * * ** ** *
* ***** * **** * ** ***** *** * *** *
* * *** * * *** *
* ** *** *** * I need this to happen size-times */
* * ** *** * ********* * j = 0; j < size; j++){
*** * ******* * ** ** * ** ** * * from left to right */
* ** ** * ** * ***** **** * * * ** * * * ** * i = 0; i < size-1; i++){
* *** **** * ** ** * *** * * * * * * * ***** * * ** * * i-th element with its neighbor to check if they are in order */
* ** ** *** ***** * ** ** * * * ** ** ***** * * ******** **** * *** > x[i+1]){
** ** ***** *** * * ** ** * * ** * * ** * * * * ** ***** * * * * ** ** ** exchange the values of x[i] and x[i+1] */
* *** *** * * **** * * * * * *** ** * ** * *** * * * * * * ** * *** **** temporary; * * ** * ** * * *** * * ****
******* * * ** * * ** * * * * *** *** * ** ** * * ** ** * *** * * **** * ** *** ** ** *** ** ** * * = x[i];
*** * *** * ** * * * ** * * ** * *** *** ** * **** ***** * *** ** *** * ***** = x[i+1];
*** ** ***** ** ******* * ***** * ** ** ** * * **** * ** * * ** ** * ** ** *** ** * *** = temporary;
**** ** *** ***** * * ** ***** * ** ** ** * **** ** ** *****
**** ** * * ** ** **** * *** *** * ** *
*** *** **** ** *** *
* * * ** * *** *
*** **** * ** **** * ** * *** print the array */
* * *** *** * * ****** ** sorting: \n");
**** * *** *** * * * ** * ** * * i = 0; i < size; i++){
* * ** * ** ** * ** ** ***** *** *** ** * *** *** * * ", x[i]); * *** * ** * *** ***
* * *** * * * * * **
* *** * ** *** ** ** * **** * *
* ** * * * * * *** *
*** * ** *** *
** * *** *** ** ** ** *** **
* ** ** **** ** * ** **** ***  
* * ** *** * *** * * *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * **** * ** *** ** ** x[] = {77,22,88,11,22};
* * * ** * ** * **** * * size = 5;
    
* **** *** **** * *** * print the array */
* ** * * **** * *** i = 0; i < size; i++){
** * **** * ** * *** ** *** * * ** ** * ****** ", x[i]); ** ** *** * ** * * ** * **
** ****** * * ** * *
** ** ** **** * ** * * * ********* ****** * *
*** * * * *** ** **
* ** **** *** ** * ** I need this to happen size-times */
* ***** * ** *** * j = 0; j < size; j++){
* ** *** ***** ** ** *** **** ** * *** * *** from left to right */
* *** *** *** * * * * * * * ** * * i = 0; i < size-1; i++){
***** * ** ** * * * * * * **** *** * ** * * * * ** ** * ** * **** ** * i-th element with its neighbor to check if they are in order */
* * * *** * *** ** * * ****** * **** * ** * * * ** ******** **** ** * > x[i+1]){
*** *** ** * ** ** ** ** * * * ***** *** ****** *** * ** ** ** * * * ** * **** ** * exchange the values of x[i] and x[i+1] */
* * * * ** * *** * * **** * * *** * * ** *** * * * * * *** * * ****** *** temporary; * * *** * * * * **
* ***** ** ** * ********* ****** ** * * * * * * ** * ** ** ** * *** * ** ** * * = x[i];
* * * * *** ***** * ** **** **** * ** * ** ** * * ** * **** * ********* *** * ****** *** = x[i+1];
* * * *** * **** * ** ** **** ** **** * ***** ******** **** * **** * *** *** *** ** * * * * = temporary;
** * * ** ***** ** * * **** * * * **** ** * **** ** ******** * ** * **
* ** ** **** ** *** * * * ***** *
*************** * **** *
** * * *** * *
* * ** * ***** * ***** print the array */
* ** * *** ****** **** * * * * sorting: \n");
**** ** * * ******** * **** ** i = 0; i < size; i++){
* **** ** * * ** * *** *** * *** * ** ** * * * * ** * ", x[i]); * ******** *** * * * **
** * ** * *** * *****
** ** **** * ***** *** * * * * * * * * * *
** *** * ** * * * *
*** * * * * * * * *
*** *** * ***** ** * * *** * * ** * ***
* * * ** * * ***** ** *** * ** * * *  
* * * *** ** * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * * *** ** * x[] = {77,22,88,11,22};
** ** * ** * * * * * size = 5;
    
** * * ***** **** * print the array */
* * *** ** ** * ** * * i = 0; i < size; i++){
** * *** * * ** * *** * *** **** ** * ***** ** ", x[i]); * ** ** ** * * * * *** ** ** ***
****** * * * * **
**** ** ** ** * * * * * ** ** * ** ** ***
* ** **** **** ***
* *** ** * * * * *** I need this to happen size-times */
* * * ** * ** * ** * * ** j = 0; j < size; j++){
* ***** *** * * * * ** ** * ** * * ** *** from left to right */
** ******* * *** * *** ** **** * ** i = 0; i < size-1; i++){
* * * ** * ** ** *** ** **** * ** * * ** ** * *** * * * * ** ***** * * i-th element with its neighbor to check if they are in order */
** **** *** * * *** * * * * * * ** **** **** ** ** * * *** ** > x[i+1]){
* *** *** ** * * ** * *** * ** * **** **** ** * * ******** * ** * * ** * ** * ** exchange the values of x[i] and x[i+1] */
* ** * **** *** ** ** *** *** ** * ** * *** * **** * * * * **** * * * **** ****** * * ** temporary; * ** * * ** ** * * ** * **
** ** * *** * ** * *** **** ** *** ** * ** * * ** * * * *** * * * * ** *** * = x[i];
** * **** * * * ** ** * * *** ** * *** ** ** ** * ** * ** * *** ** *** = x[i+1];
* * * * ** * **** * **** ******** * * **** ** *** ** *** ** * **** * * ** * *** ** * ** * = temporary;
** * * *** *********** ** * *** ** ** *** ** * * * * ** * *** *
****** ****** * *** ****** ** ** * ** * ***
** *** ** *
** * *** ** * **
* ** * *** * ** * * **** print the array */
** * * ** * * * **** * **** * * sorting: \n");
** * ** * * * * * * ** i = 0; i < size; i++){
** ** * *** *** * * ****** *** * ** *** ******* * *** ", x[i]); * * ** * * ******* ** * *
** * * * * * *
** * ******* *** * * * *** ** * * * ** *
** * * *** * **
** * * ** *** * ****
* ****** **** * * * *** * ***** *
* **** ** * *** ** ** ** ** ** * * **** * * **  
* ******** ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** ** * * * ** **** x[] = {77,22,88,11,22};
* * ** ** ** ** ** * size = 5;
    
* ******* ***** ** * ** * print the array */
**** * * * ** * *** * * i = 0; i < size; i++){
*** * *** **** *** * ** ** ** * * ** *** * ** ** * * ** ** ", x[i]); ** ** * * *** * ** * **** *
* * *** ** * * * * *** *
** * * ** * * * * * * * * *** **
* * *** * * * ****
* * *** *** *** * ** I need this to happen size-times */
***** * * * ** *** ****** j = 0; j < size; j++){
*** ** * * *** * ** * ** *** ** ** * ** * * *** from left to right */
* ** ** ********* * * * **** ****** * ** * i = 0; i < size-1; i++){
* * * * * *** * * * * *** * * * ** ** ** * ** * ****** **** * * ** ** i-th element with its neighbor to check if they are in order */
* *** *** * ** * * **** **** * ** ** * **** *** * * ** * * * *** * *** > x[i+1]){
* * * *** ** * ** * ** **** * * *** * ** *** ** **** * ** * ** * * * exchange the values of x[i] and x[i+1] */
* * * * * ** ** * ****** ** * * * * ** * * * ** ****** ***** * * *** * * * * * ** *** temporary; * ** * **** * ** ** **** ** *
* * * * ** * * ***** **** * * ** * ** * ** * * *** * ** * *** * * *** * * *** = x[i];
* *** ** *** ***** ** ** * * * ** * ** * * ** * ** * ** * * * *** ** * ***** ** * = x[i+1];
** ** *** * * ** *** * * * ** * * * * * *** ** *** * * * ** * ** * = temporary;
* * * * ** * ** *** *** * ** ****** ***** * ** * * ** * * ***
* ** * * * * ** *** ** * * * * * ** *** *
* ** ** * * ** * * **
* * * ** ** ** * * **
** *** ** ** * * *** print the array */
* * * *** * ** * *** * **** *** sorting: \n");
**** ***** * **** * ** *** i = 0; i < size; i++){
* * **** * ** ** **** *** * ** ** ****** * * ", x[i]); ***** * * * * * ***
* * * *** ** ** **
* * ** * * **** * **** * ** *
** * * ** ** ****
* * ** * * * ** * * * * *
*** ** * ** * ****** * * * ***** ** *** ** * *
**** * * ** *** * * * * * * * * ** * * * ***  
* * * * *** * * * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * *** ** ** ***** x[] = {77,22,88,11,22};
* ** * **** ** ** *** * size = 5;
    
** *** * * ** * * * * print the array */
* * *** * * * * i = 0; i < size; i++){
* ** ***** * **** * * ** ***** * ** * * * *** * ", x[i]); ** * * *** **** ** * * ** * *
**** **** **** * * **
* * * * ** * * ******** ** * * *
** * ** * ** ** * *
** ** * ** * *** * *** ** I need this to happen size-times */
* * * * *** * *** ** * ** j = 0; j < size; j++){
* * ** ** * ** * * *** * *** * * * from left to right */
*** * ** ** * * *** **** *** ** ** ** *** i = 0; i < size-1; i++){
** *** ****** * * * ******** * ** ** * * * * * *** ****** * * ** * * i-th element with its neighbor to check if they are in order */
* * ** *** ** **** * * *** * * *** * * ** **** * ****** ***** * > x[i+1]){
** * * **** ***** * * **** ****** *** *** *** ** **** * * ** ** ** ** * *** *** *** **** * * ** * * exchange the values of x[i] and x[i+1] */
* * * * * ** *** ** * **** ****** * * * ** * * * ** ******* * **** * * * *** ** *** * * temporary; * ** ** * * ** *** * * * *** *
* * * *** * *** *** ***** * * **** ** * ** * *** ** ** * * **** * ****** * ***** * * * ** * * = x[i];
** * **** * **** ***** * *** ** ** ***** **** * * * * * * * * ** *** * * * = x[i+1];
* ** ** * **** ** ** ** * ** ** * * * * * * *** * * * * ****** * * * *** **** **** * = temporary;
* ** * * * ** *** **** ** ** ** ***** ***** **** * **** * * * **** *
* * * * * * * ** * * * ** * ** *
** **** ** *
* * * ** * *** *
**** * **** *** print the array */
** * * * * * * * * ** * sorting: \n");
* ** * ** ** * ****** * i = 0; i < size; i++){
* * * * * * * * * * * ** * *** * ", x[i]); ** * * * * *** * *** ***** ** ***
* ******** * ** ** ***
* * ** ** ** * **** **** *
* ** ** *** * * * * *
* * * *** * * * ***
** * * ** ** * * ** *** *** ** ** **** *** *
**** **** *** * * * * ** * *** * *** *** *  
* ** *** * ** *** * * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * *** ** *** * * * ** x[] = {77,22,88,11,22};
** ** *** * ** * * * *** *** size = 5;
    
* * ** *** * * * * ** *** * * * print the array */
* ****** * * ** * * * * i = 0; i < size; i++){
* ** ** * * ** * *** * * * * ** * *** * * ** ", x[i]); ** *** ** *** ** ** * * *** ** *
* *** ** *** ** * * ** *
**** ** *** * * * * *** * ***** * * *
* * * * *** **** ** *
* ** * * ** * * * * * I need this to happen size-times */
*** ***** *** **** ** **** j = 0; j < size; j++){
*** * * * * * *** **** ****** * *** * **** from left to right */
** ** * **** *** * ** * * * ** * ** * * *** ** * ** i = 0; i < size-1; i++){
*** * * ** * *** *** * **** * * * **** * * * **** * * ** * *** * i-th element with its neighbor to check if they are in order */
** ** * ** * **** *** ** * ***** * * *** **** * * * * * * **** ** > x[i+1]){
** * ***** ***** * * ** ** * *** * * * *** * *** *** * ******* *** ****** * * * * exchange the values of x[i] and x[i+1] */
*** **** * ** ***** ** **** *** * ** * ****** **** *** * * *** ** ** * * ** temporary; ** *** *** * ** * * * *** **** ***
*** * * * *** ** *** *** * * * * ****** * ** * * ******* * ** ** ** * **** ***** * * * * ** ** = x[i];
* ** * * ** * ** * * * * * * * * * ** ** ** * * * * *** * ** * ** * * **** = x[i+1];
* ** ******* * * * * * ** ** ** * ******* ** **** * * ** * * * * ****** ****** * **** ****** ** * = temporary;
*** * ** *** * * *** ****** ** * * ** * **
* ** ** ** ****** *** * * ***** * *** **
* * ** ***** *** * **
* * *** ** ** ** * * *
* * * ** * **** * * ******* print the array */
*** ** **** ***** * *** * * * * *** ** sorting: \n");
* * ***** * * * * i = 0; i < size; i++){
** ** ** * * * *** ** * ** **** * * **** *** * ", x[i]); ** * * * * ***** *** * ***** *
* ** * * *** * **** **
** ** ***** ** * ** * * *** ** ****
* * * * * * **
* ** * ** *********
*** **** * * *** * * ** ** * ** * * *
* * * *** * *** ** * *** ***** * ** * ***  
*** ** * ** * * * ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * *** * * * * x[] = {77,22,88,11,22};
*** * * ** * * *** * size = 5;
    
*** ** ** * * * * print the array */
* **** * **** *** * * ******* * i = 0; i < size; i++){
** * ** ** ** **** * * * ** * **** ** * *** * * ** ", x[i]); ****** ** * *** *** * *** *******
** ** * * *** * *** *** * ** *
* * ** **** * **** * *** * * ** * ** * * ***
* ** * **** * ** *
** * *** ***** * ** * I need this to happen size-times */
****** * *** ** *** ** **** j = 0; j < size; j++){
* * * *** *** * * *** ** * * ** **** * * * from left to right */
** *** ** *** ******* * * * * * * ** * * i = 0; i < size-1; i++){
* * * ***** ** ** * * **** ** * ** ** *** * ** ** * * *** ** * * * i-th element with its neighbor to check if they are in order */
** * ***** ** ** **** *** ** * * * ** ***** ** * * * * *** * ** ** ** > x[i+1]){
** * * * * *** ****** ** * ** * ** ***** *** * * ** *** * ** * **** * * * ** ** exchange the values of x[i] and x[i+1] */
* ** *** *** ** * ** * * ** ** * **** ** *** ***** ** * * *** **** * ***** * ** * * *** temporary; * **** * ** * ** * **** * ******* * **
*** ** **** * ** * * *** ***** ** * **** * *** *** * *** * * ** * * * * **** ** * * = x[i];
* * * ** * * * ***** *** * *** *** ***** ** * * ** * * ** *** ** *** *** ** * * * ** = x[i+1];
*** *** * * * * * * ***** * ** *** *** ** ** * * * *** *** ** * ***** * * *** = temporary;
* * * * * ** * ** * * * * ** * **** ** * *** ** ** * *
* * * ***** * * *** * *** * * ** *** *
* *** * * ** *
** * ** * * * ** *
* *** * * * ** *** print the array */
** * * ** **** ** * * * ** * * sorting: \n");
* *** ** *** ** ** i = 0; i < size; i++){
* ********* *** ** *** * ******** **** ** * ** * * * ** ", x[i]); **** ** * * * *** ** ** ** **** **
* * *** ****** ** ** **
*** ** *** * * * ** ** ** * * *** *
* ** * ****** ** ** **
* ** * ***** * *
* ** ***** * ** ** ********* *** *** ** **
* * ** ** ** * *** * **** ** * ** *** ** **  
**** * ****** * * ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** ** *** * ** * x[] = {77,22,88,11,22};
* **** * ** * * * * ** size = 5;
    
* * *** ** ** ***** print the array */
*** * ** ** * * **** i = 0; i < size; i++){
***** * * ** * * ** **** * * * * * * *** **** * *** ", x[i]); ** ** *** *** ***** ** * **
* * * ** **
** * * * * * ** * *** * * ***
***** * * * * * ** *
* *** ** ** **** *** I need this to happen size-times */
* * ** * * * *** j = 0; j < size; j++){
* * ***** * * *** *** * **** * ** * * ** *** from left to right */
** ** * ** * * * ** ****** * ** * * ** * ** ** i = 0; i < size-1; i++){
* * * ****** ** *** ** * ** * ********* ** **** *** *** ** ***** * ** ** * i-th element with its neighbor to check if they are in order */
*** * **** *** * *** ** * * **** ** * * ** ** * ** * * * > x[i+1]){
****** **** * * *** * * * * * ** * * * ** * * * * **** * *** ** * ** * * ** **** exchange the values of x[i] and x[i+1] */
*** * * ** * * ** * * ** * ** * **** * *** ** ** * * * **** * *** * * ***** * temporary; *** *** ** * * * * *** * ** **
* ** ** ** * ** ***** **** * ** * * * *** ** * ** * **** * ** ****** ******* *** *** * = x[i];
** ** *** *** ** * **** * * * * * *** **** **** * ** ***** **** *** * ** * * * = x[i+1];
** ***** ** ** * ***** * ** ***** * **** * * * ***** ** * * * * ** * * *** ** * ** = temporary;
* ******** ** ** * *** **** ** * ***** * ****** * ** *** **
* * * * *** **** ** * ***** * * ***** * * *
* * * * ****** * * * *
** ** ** * * ** ** ** *
**** * * ** * ** * print the array */
* * * * * * ** * * * **** * sorting: \n");
* * ** * ** * ** i = 0; i < size; i++){
* * * * * * **** * * ** ** * * * *** ** ", x[i]); * * *** ** ** * **** ** * * *** *
* ** ******* * * **
*** ** **** * ** * ** * *** * **** *
* * ** ** ****** * ****
**** ** * ***** ***
* **** * * ** ***** * *** *** * * *
* ***** ** ** * ** ****** * * * *** * *  
** * ** * * * * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.224
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 3.4k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users