0 like 0 dislike
7k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 7k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** *** **** ** ** * x[] = {77,22,88,11,22};
* * * *** * ** ** * ** size = 5;
    
* * * * * * * print the array */
* * ** * * *** * ** ** i = 0; i < size; i++){
** * * ** * * * *** ** * * * *** * * * ** * * ", x[i]); ***** * ***** * *** *** * ***
** * ** * *** *** *
**** ** * ** * * * ***** * * * ** ** **
***** ** **** * * * **** *
** * ** ** * ** ** * * I need this to happen size-times */
* ** * * *** *** ** *** j = 0; j < size; j++){
*** ** * *** ** ** *** *** **** * * from left to right */
* *** ** * ***** *** * * * * * * **** * * * i = 0; i < size-1; i++){
** * ** *** * * ** ** *** * ** ** *** **** *** * * * * * * * * ** i-th element with its neighbor to check if they are in order */
** ** **** * *** ******* * **** * **** * *** ** * * * * * *** *** *** * * > x[i+1]){
* ** * ***** ** * ** * * * ****** * *** ** ** * * *** ** * **** * ** * *** * ** * ** *** exchange the values of x[i] and x[i+1] */
* * ****** * ***** **** **** *** ** * ** * ** * * **** ** * * * * * * ***** * * temporary; * ** ** * *** ** *** **** ** **
* * * ** ** ****** ** * * ** ******** **** ** *** * ** * *** *** ** **** ** *** * *** = x[i];
*** * **** * * * ** ** * ** * *** ** ****** * * * *** * ***** ** ** **** ** = x[i+1];
* * *** * **** ** * ** ** *** * * **** *** ** ** * ** * **** * *** ** * **** *** * * = temporary;
****** * * * * * * ********** **** * *** * *** *** * ** * *****
** ** ** * * * **** *** * * *** *
** * *** ** * * * ** *** **
** *** **** * * * *
** ****** ** ** * * * * print the array */
** *** * * ** * *** ** * ****** *** * *** sorting: \n");
* * * * * ** * ** ** i = 0; i < size; i++){
** * * * ** ** ** * * ** * ** ** ** * ** *** ", x[i]); * ****** *** * * * * ** ***
* *** **** * ** ** * * *
* ** ** ****** * ** * ***** **** * ***
**** *** ** ** **
* * **** * ** **
***** * * * * ** * * ** * ** ****
** *** *** *** * ** * ******** *** * * ***  
**** *** ** * * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** * * *** *** * * x[] = {77,22,88,11,22};
* ****** ** ** **** * * * ** size = 5;
    
** ***** * * **** * print the array */
* ** ** ** *** * ** ** * i = 0; i < size; i++){
* * *** * * ** * * * *** ******** * ", x[i]); ** * ** *** ***** ** * ***** ** *** *
*** ** *** *
** * ** ** ****** * * * ** *
*** ****** ** * ** *****
* ** * * ** * * **** * I need this to happen size-times */
** * * * * ** ** * * * j = 0; j < size; j++){
** * * * **** * ***** * * ** **** * * **** ** * ** * from left to right */
**** ** * ****** ** * * * ** *** * ***** i = 0; i < size-1; i++){
** *** ** * **** * * * ** *** * * * ** * * **** *** * *** ** *** *** i-th element with its neighbor to check if they are in order */
* ** ** *** * ******* *** **** *** ** * *** * * * ** * * > x[i+1]){
* * *** ** ** *** ** *** * * *** *** * * * **** * ** ********** **** ** * ** ** * exchange the values of x[i] and x[i+1] */
** ** * * ** ** ** * **** * ** ** * *** ** * * ** * *** * ** *** * ** ** ****** **** * temporary; ** * * * * * * * * * *** *** *
* ***** *** * *** * * * * * ** * *** ** * *** **** * * ** ****** *** * ** **** ***** ******** * ** = x[i];
**** * * *** ** * *** **** * ** * ***** * ** **** * * *** * * ** * * **** * *** * ** = x[i+1];
* * * * ** * ** * * ***** ** *** ***** * * *** * ** * * *** ** * * ** ** ** * * = temporary;
* ****** ** * **** * *** *** * **** * ** *** ** * * *
** **** *** * *** * * * * **** * * ** * *
** *** ** **** * * * * **
** * ***** *** * * **** *
**** * * * **** ** * print the array */
*** * * ******** ** **** ** * * * sorting: \n");
****** *** ** * * *** *** * * i = 0; i < size; i++){
* * * * *** * * ** *** ** * ** ****** * * ** * ** * ", x[i]); * * * *** ** ***** * * * *** ***
* **** **** * ** * *
* * * * * *** * ****** * ****** ** **
* * * ** ** * ** ** **
** ** * * **
* ** * * * ** ** * ** ** * *** * ***
* * * ** * ***** ** * * * * ** * * ******  
** * * * *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * *** * * ****** x[] = {77,22,88,11,22};
*** ** * ** * * ** * * **** size = 5;
    
** ** * * * * * *** * * * print the array */
** ** * *** ** * * i = 0; i < size; i++){
** *** **** ******* * ** ***** ** ** **** ** *** * ** ****** ", x[i]); ****** * ** ***** *** *
** *** * * ** *
**** * * * * ** * * ** * ****
* * ** * *** ** ****
*** * * ** ***** ** * * * ** I need this to happen size-times */
** ** * * * * * *** ** j = 0; j < size; j++){
***** * ** **** * * ** ***** ******** * ** from left to right */
***** * ** * * * * * *** * * * ****** ** *** ** ** i = 0; i < size-1; i++){
* * *** * ***** **** **** * ***** ** * *** * *** *** * * ** ***** **** * i-th element with its neighbor to check if they are in order */
* **** * *** * **** * ***** *** * ** ** * * * * *** *** * ** > x[i+1]){
* *** * **** * *** * * *** * ** * ** ********* * ** * * * * *** *** * * * ** ** ** ** * exchange the values of x[i] and x[i+1] */
* **** ** *** * ** ** * * * ** * * * * ******* * ********* * ** ** ***** ** *** temporary; *** ** ** ** * ** *** * ** ******
* ** * * ***** *** * * ** ****** * ** *** * ** * * * ** * * * * ** * ** *** * * * ** = x[i];
** **** * * * **** *** * ** * * *** *** * * ** *** * * ****** * ** ** *** ** ****** ***** * = x[i+1];
** * ** * * * * * *** * * * ** ** * * *** * * ** *** ** ** ***** * ** ** *** * * * * * = temporary;
* * *** * * ** ** * * ** * * *** **** * * * * ** * ** *
** * **** ***** * * * * * * ** * * ** * * ***
** ** * * * * **** *** ** ***
*** *** * ******* *
* * ** ** **** ** * print the array */
* * ***** * * ** * *** * * * ** sorting: \n");
* **** * * ** * *** i = 0; i < size; i++){
* * * * * * * * * ** ** ** * ** ** ********* * *** ", x[i]); ** * ****** * * **** * **********
* **** ** ****** *** * * **
** **** * * **** *** * ** * *** * *
* **** ** *** ** * *** * * ***
* * * *** *
* * * ************ * **** * *****
* **** * * ** ** * * * *** * *** * ** *******  
** ** * ** **** ******* 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** ** * * * x[] = {77,22,88,11,22};
* * ** ** ** size = 5;
    
**** * * * * print the array */
* *** * ** * ** * i = 0; i < size; i++){
**** ** * *** * ** * ** * * * * * * ** * * * *** * * * * ", x[i]); ** *** * * * ***** ***** * ** ** * *
* * * * * ** ** ***
** ** *** ** * ** * * *** * **** * *
***** ** **** ** *
**** * * * ** ** * * *** ** ** I need this to happen size-times */
**** * * ****** * * *** ***** ** j = 0; j < size; j++){
** * * *** ** **** *** * **** ** * ** * *** * ** from left to right */
***** * * ******* * **** ** **** * * * ****** ** ** i = 0; i < size-1; i++){
* * ***** * * * *** * ******* * * * * ***** * **** *** **** ***** * * i-th element with its neighbor to check if they are in order */
***** ***** ** ** * **** * **** ** * * ** * * *** * * ** > x[i+1]){
* ** * *** ** ****** * * ** * * *** ** * *** * * *** *** * * **** ** * * ** * *** exchange the values of x[i] and x[i+1] */
* * ** *** **** *** * ** * *** * *** ***** *** * ** **** *** ** * * * ** ** * *** temporary; * * * * ** * ** * * ** **** ** *
* * * * * ** * * ***** ** * ** ***** ****** ** * ** * ** * * * * * **** ****** ** * = x[i];
**** * ** * * * * * ***** ** **** * ** ** **** * ** ** *** ** * ** *** ** * **** * * = x[i+1];
* * ***** ** * * ***** * * ** **** *** * ** ** * * *** *** ** *** * *** * ** * * ****** = temporary;
** * * ** ** *** *** * * *** ** * ** ** * * ** ******* ** * ***
** **** * * * * * * * * * ** * *** **** **** *
**** *** * ***
* ** * * * * *
* * ****** * * ** * print the array */
* ***** * * *** ** ******* ** * sorting: \n");
** ** **** *** * ** * ** *** * i = 0; i < size; i++){
* * *** **** **** *** * * * * * * *** ** * * ** *** * ", x[i]); *** * ** *** **** ** **
* * ** ** * * * ** * *
* * ****** ** ** ** **** ** **
* ** * * * ** ** *
** * ******* ** ** ****
*** ** * * * ****** ** *** ** * ** ** * *
* * * * * ** * ****** ** * *  
******* * * * *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * ***** * * * * x[] = {77,22,88,11,22};
** ** **** * ** *** * * size = 5;
    
* * * * * * ** print the array */
* * **** ** ** *** ** ** ** i = 0; i < size; i++){
* ** ** * ** *** ** * * * * * *** ** ** *** * * ******* ", x[i]); ****** ** **** * **** ** * ****** * *
**** ** ***** * * ** * *** ***
* ** * * ** * * * * *** ** *** **** **
*** ** * ** * * ***
** ******* * *** * **** ** I need this to happen size-times */
* * ** *** ** ** ** * *** j = 0; j < size; j++){
* * ** * ** * * **** ** * ** * from left to right */
* * **** * * * * ** * * ** *** ** * ** * * i = 0; i < size-1; i++){
*** ***** * ** ** ** ** *** ** * * ** ** ** * * ****** * ***** ***** * i-th element with its neighbor to check if they are in order */
** ** ****** ** ****** * *** * ** * *** ****** *** ** * ** * ** * > x[i+1]){
********* ** * ** * ** * * **** **** *** * ** * **** ** ** * **** * ** ***** ** * exchange the values of x[i] and x[i+1] */
******* *** * ***** * ** * ** * * ** ***** *** ** *** * ** * * * * * ** *** ** * ** ****** temporary; * ** * * *** ** * * * * * **** * **
*** ** * * ****** ******** * * **** * * *** * ** * ** **** ****** ***** **** ****** * * * * = x[i];
* ** * *** * ***** * * ** * ***** *** ** * * * * ********* * ** **** ** * ** *** * *** = x[i+1];
*** ***** * * * * * *** * **** ** * * * * * * * * * ** * * ** ** ** ** * * * = temporary;
* ******* * ** *** * * * * * * * **** * **** * * * * * * * ***
** ** * * *** * * * * * * * * * **
* * ** * ** * ** * * *
** *** * *** * ** *
* * **** **** **** ** print the array */
** ** ** * * *** ** * * * ***** sorting: \n");
* * * *** * **** *** i = 0; i < size; i++){
* ***** * * ***** * ***** * ** * * * ** * * * ", x[i]); * ***** * * *** * * * ** *
* ** ** * **** * ** * *
** * * * ** * * **** ** * * * ** * **
* * ***** ****** ** * *
** * * ** * * * *
** ** ***** ** ** ** * * * * ** ** *
* * * *** * * * *** *** ** *** **  
** ** ** * * ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * * * * **** * ** x[] = {77,22,88,11,22};
** ** * * * ** ** * size = 5;
    
* **** ***** ** print the array */
*** ***** * * * i = 0; i < size; i++){
*** * ** ******** ** * *** * ** * *** * * *** ", x[i]); ** * *** * * * * * * * * * * *
* *** ** ** *** * * * ** * *
*** * * * ** * *** ****** *** * * * * **
* *** * * ** ** * * ********
* * * * * *** * * * * I need this to happen size-times */
*** * * *** * * *** * * * *** * j = 0; j < size; j++){
* **** * * * * * *** * *** * *** *** * from left to right */
** **** * * * * ** ** * ** **** * ** *** * i = 0; i < size-1; i++){
* * * ** ** *** *** **** **** ** * ** * * *** ** ** ** * * ** i-th element with its neighbor to check if they are in order */
* ** * * ***** **** * * *** * ** * * * * * * ** * ** *** * > x[i+1]){
** * ** * *** ** * * * ** * * ***** * * * ** ** * ** *** * * ***** * ***** exchange the values of x[i] and x[i+1] */
* * *** * * *** * *** * * * * ** * * * * ** ***** * ** * ** **** * ** **** ********* ** * **** temporary; ** * *** * **** * * ***
***** *** **** * * * * * ** * ** * * **** *** ** *** ********* *** ***** * * *** * ** = x[i];
* * ** ** **** * * *** ** * * **** * ** *** * * **** ** ** ** *** * * ** ** * ***** = x[i+1];
***** * ** ** * ** *** ** *** * **** ** * * * **** ** * * *** **** ** * = temporary;
*** ** ** ** ** * ** ***** *** *** ** * ***** ** * *
** * *** ** * ** ****** *** **** ** * * * *
** * *** * * ***** * * *
* **** * * * ** * *** * *
* ** ** **** ** *** print the array */
** * **** * *** * ** ****** * * sorting: \n");
* * ** **** *** * ** i = 0; i < size; i++){
* * *** ** * *** ** * * ** * * *** * ** ** ***** ** ", x[i]); * *** **** ** * ** * **
**** ******* * **** *
** * ** ** * *** * * * * * * * *
* ** ** ** ** ***
** * * ******
* ** * ** * * *** * * * ** ** ** *** * **
** *** *** ***** * * ** * ***** *** ** ** *** *  
**** * ** *** * * ***** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * **** * * *** x[] = {77,22,88,11,22};
* * *** * ** * **** ** size = 5;
    
* ** * * ** * * * print the array */
* ** * * *** * ** * i = 0; i < size; i++){
****** **** * *** ** * ** * ** *** * ** * *** ** ", x[i]); * * * * ******* * ** * ** * * *
***** * * *** * * **
* ** * * ****** * ** * ** * ** * * * * **
* * * *** *** ** * ** * ***
* * ****** * *** * I need this to happen size-times */
** * *** * ** *** ** * j = 0; j < size; j++){
* * *** ** * * * * *** ** *** ** ***** *** *** * from left to right */
* *** ******* ** * *** ****** ** * * * * ** * i = 0; i < size-1; i++){
* ** * ** * ** * * * **** * * * * * * ** * ** * * ** * *** * ****** ** i-th element with its neighbor to check if they are in order */
*** ** *** * ** *** ** * * * *** * *** * **** **** ** ** ** * * ** **** * > x[i+1]){
**** *** **** ** * * ** * * * * * *** * ** * ** ****** ** ** ***** ** * ** exchange the values of x[i] and x[i+1] */
* *** **** ** ** * * ** ** **** * * ****** *** *** * * * * *** *** * ***** *** * ** * ** * temporary; * *** ** * * **** * * * *
** * * * * *** * * **** * ** ** *** *** * * **** ** ** * *** *** *** * * *** * = x[i];
**** * * * * * * **** * ** * * * *** *** * * * **** * * ****** * * *** * ** **** *** *** **** = x[i+1];
** * * * * *** ** * * * * ** * * *** ** * ****** * * *** * * ** * ** * *** ***** ***** * = temporary;
* ** * * ** ******** ** * * * * *** * ** ** * ** ** * *
* * ** * * * * * *** * * * ******** ***** * *
* * ** * ** ** ****
****** * **** ** ** ***
** ** **** * *** * ** * * * print the array */
** * * * * * ****** * **** ** ** * sorting: \n");
********* * * * * *** ** i = 0; i < size; i++){
****** *** ******* ** *** ** * ** **** **** ** * * ", x[i]); ** * ** ***** ** ** ** ***
* * * ** *** ****** *
** * * * *** ***** **** * ****** **** * * *
** ** **** * * ** * *
* * **** ***** ** ** *
* * **** * ***** ** ** * *** ** ** ****
***** ** ** **** * ** ** **** ** ***** ** ***  
****** * ****** *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** *** * **** **** ** * x[] = {77,22,88,11,22};
* * * ** * ** *** * *** size = 5;
    
* *** *** ** *** * print the array */
**** *** * ** ******* * i = 0; i < size; i++){
** ** * * * * *********** ** ** * ***** * * ** * ** ", x[i]); ** * * ****** * *** * * * * * *
** * * ** * ** ** **** *
**** ** * * * ** * **** ** * ****
* ***** * ** **
* **** ****** *** ** * * * * I need this to happen size-times */
**** * ** ** ** * *** j = 0; j < size; j++){
* **** **** * * * ****** * ** * *** *** *** * from left to right */
** * ** * ** * *** * * ******* * *** * **** ***** i = 0; i < size-1; i++){
* * * * * ** * **** * * ** *** ** ** *** * * ** ** * * *** * i-th element with its neighbor to check if they are in order */
* ** ** * * * ** **** ****** * *** ** * * * **** * * ** ** * * * ** > x[i+1]){
*** * *** * * * ** *** ** * * * *** * *** ** *** ** * * * * * **** * ***** *** exchange the values of x[i] and x[i+1] */
** * * *** ** ** ** * * * * * * ** * *** ** ** **** * * * * *** ** * temporary; ** * *** ** * *** * *** * ** ** *
* *** * * ** * * * * * **** ** ***** ** ** *** * * * ** * * **** *** * * * = x[i];
**** * * * *** ** **** * ** ** * **** *** **** ** ** * ** ** ** * ** * * * * ** * = x[i+1];
**** * *** ** * * * ** ** ** * ** * * *** * * ** ******* **** ***** * *** * * *** ***** = temporary;
* * *** **** * * * ** * * *** ** ******** * * * *** * * * ***
* * * ** * ******* * **** * * * * * * * *
*** * *** ** * **
** * ** * ** * * *** *
* ****** * * ** ** * ** print the array */
* * * * * * ** **** * ** *** *** * * *** sorting: \n");
*** ** ** * * ** * i = 0; i < size; i++){
** *** * * ** ** * * *** * * ** * * ** * * ** * * * ", x[i]); * * ** * * * ** ** * **
** ** **** ** * *
* * ** ** ** **** ** ** **** * * * *
******* ** * * * *
* ** ** *** * *
* ** *** ***** * * * ** * ** *
*** **** ** * * * * * ** ** ** * * ** * * * *** *  
** ******* * *** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
******* * *** ** * ***** x[] = {77,22,88,11,22};
** * ***** * * **** *** ** size = 5;
    
*** * ** ** ** * ** print the array */
** * * ** * ** * * *** * i = 0; i < size; i++){
**** ** ****** * ** ** * * * * ** *** ** * * ** ", x[i]); ** **** * *** * * ** *** * **
* *** * **** * ***** **
* ******* * * ** ***** ** * * * * * **
*** **** *** * * ** * ** *
** * * ** * ***** * I need this to happen size-times */
*** ** * * * ** * j = 0; j < size; j++){
* *** * * * * * * * ***** ** * * ** * * *** ** from left to right */
** * ** * * ** * *** * * *** *** * * * ** * i = 0; i < size-1; i++){
*** * * * * *** * ** * * ******* * * * * * * ** i-th element with its neighbor to check if they are in order */
**** * *** * * * * ** * * * ** **** * * * *** * ******** * * **** ** * * * > x[i+1]){
**** * * * * * *** ** * * * **** *** * **** ** * **** ** * * * * * * ** *** * * ** * * exchange the values of x[i] and x[i+1] */
* * **** *** * ** * * *** * * **** * **** * ** ** * **** * * * * * *** * * ** ** * temporary; * *** * * * ** ***** ** * **
*** ** ***** * ** ** *** * ** ** **** **** * **** * * * * ** ** ** * ********* * **** ** * **** * = x[i];
*** * * * ** **** ** ** * *** ** * * * * * *** * ** ** * * ** * * ** * ** ** *** = x[i+1];
*** * *** * ** ** * *** *** * ** * * * * * *** ** ** * * ** * ** ** ****** ****** = temporary;
*** * * * ** * * * *** ** ** * ** ** * * ** * * * *
*** * *** * ** ** ***** *
* * ** **** * * **
**** * * * **** * * * **
* **** * * * * * * * print the array */
**** ** ** ***** ** * * **** sorting: \n");
***** * ** *** * * *** i = 0; i < size; i++){
*** * ** * * * ** **** * **** * ** * **** *** * ", x[i]); * **** * **** * ***** * * * * ****
* * **** * ** *
****** *** * * ** ** * ** * ** *** *
* **** ** ** ***** * * * * *
* * * * ** * *
** ** * **** * * *** * * * *** ** *
* * ** ** * * * * ** ** * ** **** * ** ** *  
* * *** ** *** ***** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** *** ** ** * *** ** * ** * x[] = {77,22,88,11,22};
***** * ** *** * ** * * size = 5;
    
** * * **** * ** ** * print the array */
* ** * *** ** * *** * * * ** i = 0; i < size; i++){
* **** * ** * *** ** * ** ****** ******** * * ** * * ", x[i]); ** ** ** ** *** *** *** ****** *
** * *** * *** *
* * **** * ** * ** **** * * *
* * * * * * *** *
* ******* * *** * * * I need this to happen size-times */
** * * ** ** * * ** ** * ** j = 0; j < size; j++){
** * * *** **** * *** ******* * ***** ** ***** * ** * from left to right */
**** * *** * *** * ** ** ** * ** * *** *** * * i = 0; i < size-1; i++){
*** *** * * ** ****** ** ** *** ***** *** **** * ** *** * * * * ** i-th element with its neighbor to check if they are in order */
** ** ** *** * * * * * * ** * **** ****** * * * * * * ****** * > x[i+1]){
** *** * * * ** * ** * * ******** *** **** * * ** ** *** * ** * * * * * * * * exchange the values of x[i] and x[i+1] */
* * ** **** *** * * * ** * * * * ** ** * ** *** * *** * **** ** ** * * * * * * temporary; ** ** * * *** ** * **
** ** *** * * * * *** * * *** ** * ** ** * * ** ******** * ** * * * *** * *** * = x[i];
** * **** * ** *** ** * ********* * * * * * * ** ** ** ** *** * * *** ** * ** * = x[i+1];
* * ** * *** * * ******** * * *** ** * *** * *** ***** ** * ** ****** ** ****** * ** ****** = temporary;
* * **** ** * * * ** *** **** **** ** ***** * * **** ** *** *
* * * *** ** **** **** * ********** ** * ***
*** ** * **** ** **
** * * * * **** *
* *** ** * * * * ** print the array */
** * * ** * * ** * ** * ** sorting: \n");
* * * ** ** * ** i = 0; i < size; i++){
** **** *** ** * * * * * ** * ** ** * ** *** ", x[i]); * ** *** ** * * * ** ** * *
**** ** * * * * * *
* * **** * ** *** ** * ** ***
** ** * * ** *** * * ***
** ** * * ** * **** ******
** *** * * * *** * * ** ** * * *
* ***** * ** * ** ***** * * *  
* * ** * * *** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.135
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 4.3k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.2k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 3.7k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users