0 like 0 dislike
12.8k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 12.8k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** * * * ** x[] = {77,22,88,11,22};
* *** * * ** ** * *** size = 5;
    
**** **** ****** ****** *** * * print the array */
* * *** * ** ** * * i = 0; i < size; i++){
*** *** * ** ** **** *** ** ** * ** * ** **** ", x[i]); * * * * * * **** * * ***** * *
* * **** ** * ******
*** * ** ***** * *** ** * ** **
* ** * * *
**** **** * * * * I need this to happen size-times */
** ***** ******** * ** **** j = 0; j < size; j++){
* * ** * * * * **** ** ** * ** **** **** from left to right */
***** * ***** * ***** * * * * *** * * * * i = 0; i < size-1; i++){
****** * * ** * * * *** * * ** ** *** ** * * * ** **** * ** ** i-th element with its neighbor to check if they are in order */
*** **** * *** *** *** *** * ** * * * * * ** * * * ** **** *** * > x[i+1]){
* ** ** *** ** * * * ** ** * **** * * * *** *** * * ** * ** ****** * ** * ******* * * exchange the values of x[i] and x[i+1] */
** ** ********* * * ** * * ** * *** * * ** * * * * ** ** ** * * ** ** temporary; * ** ** * * ** * * *** * ** ****
* * * * *** ** * ** ** * ** *** ** * ** ******** ** *** *** ** * * * *** * * = x[i];
** * * *** ** ******** **** * * ****** *** * ** ** * *** ****** ** *** * * * * * * * ***** *** ***** = x[i+1];
**** ***** *** * ** * * ** ** * * * * ****** ** *** ** *** * ** ** ** **** * ** * *** = temporary;
* * ** ********** * ** * *** * * * ** * **** ***** * * ** * * * *
*** * ** * ** * * * * * * * ****** ** ** * *
* * * *** * ** *
** * * * * * ** * *
* ** ** * *** **** ** print the array */
***** ** * * **** ***** ** * * ** sorting: \n");
* ** ** ** * ** ** * ***** i = 0; i < size; i++){
* * * * ** **** **** * * * ** ** * * *** **** * * * ** ", x[i]); * ** *** **** ***** *** *
* * *** * ** ** ***
***** * *** * ***** * * ** *** * * * *
* * ** * * *** *
** * * * **** * * *****
* * ** * * * * * * ** * ** ** * * *
** **** ****** * * ** *** * *** * ** ** ** **  
** * *** *** * * ** * ** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ****** * ** * * x[] = {77,22,88,11,22};
* * * ** * ** * *** *** ** size = 5;
    
* *** *** ***** ***** print the array */
* ** *** * ** * * * i = 0; i < size; i++){
* ** * * ** ** *** * ** ** * **** * *** * * * ", x[i]); *** ** * * ****** * * * * *** * *
* **** ***** * ** * ****
** * * * ** * * **** **** ** **
** * ** ** ****
* * *** ** ** * ** ** I need this to happen size-times */
****** *** ** ** ** * ** ** * j = 0; j < size; j++){
***** * * ***** * ** * * * *** *** * * * *** from left to right */
* * * * * * **** * *** * *** ** * * ** i = 0; i < size-1; i++){
*** * * * * ** ** *** ** * ** **** ** ***** * * *** ******* *** i-th element with its neighbor to check if they are in order */
*** * * * *** *** * ** * * * * ** ** * *** * *** * * ** > x[i+1]){
* **** * ** ** *** * * ***** ** * *** * ** ***** *** * *** ** ****** * ** * ** * * exchange the values of x[i] and x[i+1] */
*** * ******** * ** ** * *** *** * * * * **** *** * ** **** * ** *** ** * * * temporary; * ** *** * * **** ** ** * ** *
******* ** * * ** *** * * ** ** * * ** ** ****** ** * * ** **** * ** ** * * * ** = x[i];
** * *** *** * ** ** * * *** * ** ** ***** ** * * * **** ******* * ** * ***** * ***** * = x[i+1];
* * * *** ** *** * * ** * * * * ** ***** *** *** * ****** *** ** * * ***** * * ** = temporary;
* ** *** ** * * **** ** * ** * ** ****** * * ** ** * * * * ** * * ***
* ** * ** ***** ***** ** **** *** ***
*** ** ** * ** **** * *
* ** *** * * ***
*** * * *** *** ** ** print the array */
*** * ** * * * * * * * * **** * * sorting: \n");
* **** * * **** * * * * i = 0; i < size; i++){
* * * * ** * **** **** * *** ****** ** * *** *** ** ** **** ", x[i]); * * * * * ***** ** ** * * *******
* *** **** * * ** *
* * * * * * *** * * *** **** ** * *** * *
* * * * * * * * *
************** * * **
** * * **** **** ** * ** *** **** *****
* *** * ** * *** * ** ** *** * **** ** ***  
*** * ** *** ** * * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** *** ** ** x[] = {77,22,88,11,22};
** ** * * * * size = 5;
    
* ** ** * * * * *** print the array */
*** * * **** *** *** * * *** i = 0; i < size; i++){
* * * ** * * ****** *** * ** * * ***** * * * ", x[i]); * ** * *** ** * * * ** *** * **
** *** ** ** * * *
***** *** ** * * * *** * ***** ** * * * *
* ** * * ** ****
*** ** * * ***** * ***** * I need this to happen size-times */
* * * *** * * * * ***** * j = 0; j < size; j++){
* * * *** *** **** * * * * **** * ** * ** * from left to right */
* ** * ** * * * * *** * ****** ** * **** i = 0; i < size-1; i++){
* * ** * * ** * *** * * *** * ** ** ** * * *** *** ** * ** * ** i-th element with its neighbor to check if they are in order */
** *** * * * *** * * *** * * * ** *** * ** ** * **** * * > x[i+1]){
* ** * *** ****** * *** * * * * * ** * *** ** * ** * ** * ***** * ** * exchange the values of x[i] and x[i+1] */
** ***** * ** * * ** ********* * * * * * ******* * *** * * **** * * ** *** **** ***** temporary; * ** ****** ** **** * **** ** * *
* ** * ** *** * * *** * * * * * ** * * ** * * * ** * ****** * *** * * * *** = x[i];
* * ***** * *** *** ** ***** * * * * ** * *** ** *** ** * **** * * * * * ** ** *** = x[i+1];
* * * * ** ** *** * ** * * * **** *** ** * * * *** ** * * * *********** ** **** = temporary;
**** **** * * ** **** * * ***** * ***** * * * * ** ** * ** **
*** **** * * ** * ***** * * ** * ** ** * **** * *
* * ***** * *** * * *
* **** * *** *
* ** ** **** * **** print the array */
* * ** * * ** * * * sorting: \n");
* ** ** **** *** **** * i = 0; i < size; i++){
***** * * ** **** * * * ** *** * ****** * **** ", x[i]); **** * ** ** ** *** * ** ** *
* * ** ** ** * *
* *** *** *** * ** * * ** ******** * * **
** * ***** ****** ** * *
** * *** *** *
*** * *** *** *** * **** *** **
* * * * * ** * ** ** * *** * ** *** ** * *  
* * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ****** * * **** ****** x[] = {77,22,88,11,22};
** *** * ** ** ** *** * size = 5;
    
* ** ***** * * ** print the array */
* * ** * ** * * * * * *** i = 0; i < size; i++){
* ***** * * ** *** * * * **** * **** *** ** * ** * * * * * ", x[i]); **** ** **** ** * * * *** ***
** * * * * ***
** **** * * * ** * **** * * ***
** * * * ** * ** *
** * * ** **** * *** * I need this to happen size-times */
* *** ** **** ** * ** * j = 0; j < size; j++){
* * ** ** * ** *** *** * **** * * * ** from left to right */
** ** * ** ** ***** **** * *** i = 0; i < size-1; i++){
* * ***** * *** ** *** * **** * ** * *** *** * ** * * * i-th element with its neighbor to check if they are in order */
* * *** *** * ** ** * ** ** *** ******** ****** * ** * * ** * > x[i+1]){
** * ** ***** * ** * *** *** ** * *** * ***** * * * ** * ***** * * **** *** ** exchange the values of x[i] and x[i+1] */
* ** * * * *** * **** * ** ** *** * **** ** * * * * *** * ** *** * ** * * ***** * * * *** temporary; * * ** *** * * * * **** * ** * **
* ** ** *** **** ** ** ** *** * * ** * * * * *** * ** * * ***** **** ** * * * * * * *** = x[i];
* * ** * * **** * ** ** * ** *** ** ** * * * ** * *** * ** *** * ** **** ** *** ** *** * ** = x[i+1];
** * * ** ***** ** * ** ** * * * * * *** * * **** * ***** * ***** * ***** * * * * * ** = temporary;
** * ** ** * * * *** * * * * *** * *** **** * *** * *
* * * * * **** *** **** * ** ***** * *
* * * ****** * *** *
*** ** ** ** ***** **
* *** *** * * ** * print the array */
* ** * * *** * *** * **** * sorting: \n");
* **** * *** ** * *** * ** i = 0; i < size; i++){
** ** * *** * **** * ***** * ** *** **** * ** ", x[i]); * ** ** *** *** ** * * * * ** *
* * *** ****** *** ** * *
* * *** * * ** *** * * ****
* **** **** * * *** **
* ***** * ** * * **
* * **** * * * * * ***** *******
** **** * * *** ****** * * * ** * ** **** * *  
*** * ** ** * ***** * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** * * * * ** ** x[] = {77,22,88,11,22};
* ** **** *** * * * size = 5;
    
** * * *** ** *** *** print the array */
* *** * * ** ** i = 0; i < size; i++){
** * *** * * * * ** * * ** ** * ** *** * * ", x[i]); **** ***** **** ** *** * *** ** **
******* * * *** ***
* * * * *** * ** ***** * * ** * *
* ** *** * ***** * *
*** * ** *** * ** * ** * ** * I need this to happen size-times */
* * *** ****** ** * * j = 0; j < size; j++){
** *** ** ** *** ***** * ** * ** * *** * *** from left to right */
*** * * * ****** ***** ** ** * ** * * *** ** * ** * ** ** i = 0; i < size-1; i++){
** ** * * * * * * * ** ***** ** ** ****** * ** * ** * ***** *** **** i-th element with its neighbor to check if they are in order */
* ** * * * * ** * * ** *** * **** * * * * * * *** * **** ** > x[i+1]){
* ** * *** ** ** **** * * * *** * * * * *** ****** ****** ** ** ******** ** * ** ** exchange the values of x[i] and x[i+1] */
* * * **** ***** ** ***** ** ** * ** * ***** ** ** * ** * * * * ** temporary; *** * ** * * ***** * ** *** *
**** * * * **** * * * * **** **** * ***** **** ** ** * ***** * * * * ** ****** * = x[i];
*** * * * *** * * * ***** * * * * **** * ** *** *** *** ******* ** *** ** ** * ** * ** * ** * = x[i+1];
* **** * * * *** * *** * * ** **** * ******** * * * * * ** ** ** *** ** ******* ** = temporary;
* * ** ****** ** * * *** *** ** *** * ** ** **** ** *** ***
* ***** * * ** * * * **** *** ** ** * *
* * ** ** ** * *** *
* * *** **** ***
*** * * ****** ** *** print the array */
* * ***** **** * * * *** * * ** *** * sorting: \n");
****** * * ***** ** *** * i = 0; i < size; i++){
** *** * *** ** *** * * ******** **** * ** ", x[i]); * *** * * ** *** * * * * *
****** * *** * **
* ** * *** * ** * ** * ** * **** **
** * ** *** * * **
**** ** * *** * ** * *
** ** ** *** * ** * * * * ***
* * * * *** ** * * * * * * * * ** * *  
*** ** * * ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** * * * * * * *** x[] = {77,22,88,11,22};
* * * * *** *** *** * size = 5;
    
****** *** * * ** * * print the array */
***** * * * * ** *** * ** i = 0; i < size; i++){
* * ***** * * * *** * * * * * ******** * *** ", x[i]); * ** * * * * * *** * * *
*** *** *** *** ** * **
* * * * * * * * ****** * * * * ** ** * ***
* * * * * * ** **
* * ** * * * ** * * * I need this to happen size-times */
* * * * **** * * * * * j = 0; j < size; j++){
* * * * ** ** ***** * * * * * ** ** ***** ** **** from left to right */
* * * * ** * * * *** * * * *** **** * ** i = 0; i < size-1; i++){
**** ** * ** * * * * *** * * ****** * * ** **** ** *** **** ** * i-th element with its neighbor to check if they are in order */
*** ** ****** ***** ** *** ***** ** * * *** * ** ***** **** ** ** ** * * > x[i+1]){
* * * * * * * ********* * ** **** * * ** *** * *** *** ** * * * * * *** * ** *** exchange the values of x[i] and x[i+1] */
** ** ** ****** * ** **** **** *** ** * * * * * ** * ** * * * * *** ******* * temporary; * ******* * **** * ** * *** ** * * * *
** ***** * * * * * ** * **** **** * *** ****** * * *** * ** ** * ****** * * * = x[i];
** ** *** ** * *** * * * * ***** ** * * ** * * * * **** * * * * * **** ** ***** ** = x[i+1];
** * * ** * * ** * * *** * **** * ** ** ** ** * * ** * * ******* * * * * ** *** * * * *** = temporary;
* ** *** * *** *** * * * * * * * * *** ***** ***** **** ** * *
** * ** * ** * *** *** ** * * ** * * *** * *
* * ***** * ** ** *
* ** * ** * * ** ** *** *
* ** **** * **** ** * print the array */
* ** * * * * * ** **** * sorting: \n");
*** * *** * **** ***** ** i = 0; i < size; i++){
** ***** ** ** * ** *** * *** ***** ** *** * ***** ** ", x[i]); * ** * * ** ** * *** * ** **
******* * ** ***** **
* * *** *** * ** *** ** * ** *** **
* *** * * ***** **** **
*** ****** **** * * ** ***
* * ** **** ** **** * * *** * *
** * *** * * * ***** * *** * * *** * * *  
* * * *** ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * **** * * * * ** ** * x[] = {77,22,88,11,22};
*** **** * * * **** *** * size = 5;
    
* ** * ** print the array */
* * * ** ** * ** * * **** i = 0; i < size; i++){
** ******* *** * *** * * ** * **** * * * ****** * ** ", x[i]); * ** * * ***** *** * *** **
* * *** * * ** * ***** *
**** * * ** * * **** *** * *** *
* * ****** * * *** *
* * * ** ** ** * * * * I need this to happen size-times */
* * * ** ** ***** ** j = 0; j < size; j++){
** **** ** ** * * * ***** ** ** ** ** * * * from left to right */
* * * * * * **** * * *** ** * **** ** ** * ** i = 0; i < size-1; i++){
* * * * * * ** *** **** ******* *** *** ** * * *** *** *** * i-th element with its neighbor to check if they are in order */
** ** ** *** * * * * * * *** * * ** ** *** **** * *** * ** > x[i+1]){
* * * ** * * ** ** ** * * * ** * ** * ******** **** *** * *** * ** ** ** * * * exchange the values of x[i] and x[i+1] */
** * * ** * * **** * *** * * ** * ** * * ** ** * * * *** ** * **** ***** * ** * temporary; **** * **** * * ** * *** * **
* ********** * ** * ** *** * * ** ** * * ** * * * ** * **** ** * ** ** * *** * * * *** *** = x[i];
** * *** * * * * ** * * * * **** ** * * *** *** * * ** ** **** * *** ** * * * *** ** *** = x[i+1];
* * * * ****** * *** * * * *** * ** * * *** * **** *** * * * ***** * ** * * * * = temporary;
* * * ******** * ** ** ** * * ** ** **** * *** ** * * *** * * * **
* * * **** * * **** ** * * * * ** * *
* * ** *** * *** * * *
**** * * *** * **
*** * * ** ** ** ****** print the array */
** * **** *** * * *** * * ** * ** sorting: \n");
********* * * * ** * * ** * * *** i = 0; i < size; i++){
* * ** ***** * * * ** * ** * ** * * ** ** ** ", x[i]); * * ** ** ** * * ** ********
****** ** * ** *
* ** ***** ** * ** * **** * ** * * * ****
******** * * *** * *
** * * * * ***
** ** * * ** * * ** *** *** ** ** * * *
** * **** ** *** * * * ** * * * * *** *** *  
* * **** ** **** *** * * ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * ** ** * * * * x[] = {77,22,88,11,22};
* * ********* * * * * * size = 5;
    
* * *** **** * * ** ***** print the array */
* * * **** * *** * * ** i = 0; i < size; i++){
* * ** * * * * * *** * *** * * * ** * **** * * *** * * ", x[i]); ** **** * ** * * * * ** ** * * *
* * **** * * ****
* * **** * ** * * * ***** *** *** * * *
* *** * * ** ***** **
** * *** * * **** ** ** I need this to happen size-times */
** * *** * **** * ** * j = 0; j < size; j++){
*** * * *** * * * * * * ******* * * * ** from left to right */
**** * *** * * **** ****** ** *** * * * * * i = 0; i < size-1; i++){
* * ******* * * *** * * ** ** * *** * *** * ** ** * * i-th element with its neighbor to check if they are in order */
* *** * ***** ** * **** * * *** * **** * * * * * * * ** * *** * *** * ******* * > x[i+1]){
* * * * * * * * * ** * ****** * * *** * ** * **** * * ** **** * ** ***** ***** ** **** exchange the values of x[i] and x[i+1] */
** * ** ****** ***** ** * * ***** ** ** ***** * * * * * ** *** ***** *** * * * ** *** * ** temporary; * * ** * * **** ** * * ** * ** **
* * * * *** * *** ** ** *** * * * * ** * ** * * * *** * * * ** * *** *** * * **** * ** * = x[i];
****** **** ** ** *** *** ***** ** * **** ** *** * *** * * * * **** ** *** *** * * **** = x[i+1];
*** **** ** ** *** **** * ** * ** * ** **** * * *** * * * * **** ** * *** = temporary;
* * ** * *** * ** * * * *** * * *** ** * ***** **** *** ** * *
* *** ** * **** *** * * ** *
** * **** * * * * * *
* *** ** *** * * * *
** ** ** ** * ** *** print the array */
* * * * * * ** * ******* * ** ****** sorting: \n");
** ** * * * * * * * * *** * i = 0; i < size; i++){
** * ***** * ** ***** * ** **** **** ** * ***** * ** ", x[i]); * * ** * *** ** *** ** * *
* * ***** *** * * ***
** ** * ** ** * * ** * * ** * *** ** * * **
**** ** * *** ** ** *
**** *** * * **
** * *** ***** ****** * * *
** * * * ** *** * ** * * *** ** * *  
* ** * * * * **** ** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * **** * ** x[] = {77,22,88,11,22};
* *** ** ** * *** *** size = 5;
    
*** * * ** **** * print the array */
** ** ** * * * * *** ** i = 0; i < size; i++){
** ** * ** * ** * *** * **** * * ** ** * *** * * ", x[i]); ** ** * ** ****** ** * ** **
** ****** ** *** ****
* * * * ** * * * * *** *** **
* ** ** ** * * *** *
*** ******** * * **** * *** I need this to happen size-times */
** * * * ** * * * j = 0; j < size; j++){
**** * * *** ** **** * * * ** *** ** **** ** from left to right */
* * ** * * * **** ** ** * * * * ** * * ** ** i = 0; i < size-1; i++){
*** * * * * ****** ***** * **** * * ** ** * ** *** * * * ** i-th element with its neighbor to check if they are in order */
** * * * *** * * ** * * ** * ** * *** ** * * *** *** ** *** * ***** > x[i+1]){
** * ******* * *** ** ** * ** * * * ** ** ** * * * *** *** ** * * ***** * *** * *** * exchange the values of x[i] and x[i+1] */
*** *** * *** ** * * * * * * *** *** * * * ** ***** ** *** * * * * ** * temporary; * *** * *** ** ** * * * * * * * ***
* *** * * * **** ** ** ** * * * **** ** * ** * * *** * * * ** ** ** * ** * * = x[i];
*** *** * * * * * *** * * * ** ** ****** ** * ***** * * * **** * *** * *** * ** * * * = x[i+1];
* * * ** ** ** *** * * * * * * ** ****** * ** * ******* ** **** * ** * *** ** *** *** = temporary;
**** **** * * * ** *** **** ******** * * * ** **** ****
* * *** * ** ** ***** **** * * * **** **
** **** **** * ** * * *
** ** ** ***
* ** * * ** ****** * print the array */
* * * * ** ** *** * * *** * * ** ** sorting: \n");
* * **** ** * ** ** i = 0; i < size; i++){
* * ***** * * * * ** * **** ** * * * ** * **** * ", x[i]); *** * * ** ** * * ** * * *** *******
** ** ** * * *** * *
* * ***** ** * * * ** * ** *** *
* ** *** ** * * * **
******** ** * ** ** *
** * * *** **** ** * * *** * * * *
***** * * * ** * ** ** * ** * ***** * * ****** * *  
***** * * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** *** * *** **** x[] = {77,22,88,11,22};
** *** ** *** * * ** ** * size = 5;
    
*** * * * ** *** ** * print the array */
*** * * * ** * * *** * i = 0; i < size; i++){
* *** **** ** ** ** * * *** **** ** *** ", x[i]); * *** * * * ****** * ** ** **** *
** * ** * ** * * ** *
* *** **** * *** *** ***** *** ******
* *** ***** * * *
* * ** ****** * I need this to happen size-times */
** ** ** ** ** *** * ** * j = 0; j < size; j++){
* * * * ** * **** ** * ** ** * * from left to right */
** *** * *** * *********** ** * *** i = 0; i < size-1; i++){
*** ** **** **** ** * * * ******* ****** * ** * * *** *** *** * i-th element with its neighbor to check if they are in order */
* ***** * * *** * **** * * ** * ** * ** ** * * * * ** ** * * **** > x[i+1]){
*** *** * * ** ** * * * * *** ***** * *** ********* ** * * * * * ** * *** * exchange the values of x[i] and x[i+1] */
** *** ** *** ** *** * * * * * * * * * * ** ** *** ** ** ** * * ** ** * ***** temporary; **** ***** **** * ** ** * * **
* ***** ** * * ***** * ** *** * *** * * ** *** * * ** ** *** * * ** * ******* * * = x[i];
* ** * * *** ****** * ***** **** * ** ** * *** **** * *** * * * *** ** ** * * * * * *** = x[i+1];
** **** ** * * * ***** ** * *** ******** * * ** * * ******* **** * * **** **** * * ** * * = temporary;
* *** ** * *** ** ** * ** *** **** ** ** ******* ** ** * *
* * * ** **** *** * ** *** * * ** * * **
*** ** ****** * * **
* **** ** ** * **
** *** * * * * print the array */
* ***** * ** * ***** * ***** sorting: \n");
* * * * * * * i = 0; i < size; i++){
*** ** ***** **** * *** * * ** * * * * ** ** ***** ** * ** ", x[i]); * * *** * * * * ** ****** *
* * * * * * *
* ** * ** ** **** * ** *** * ** * * * * *
** ** * ***** * * *
** * * ** * * * *** *
*** * ** *** * * * *** ** ** ** ** * ****
** ** * **** * * ***** * ** * * ** ** ***** * * * * *  
* * **** * *** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 7.7k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 6.8k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 3.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users