0 like 0 dislike
12.8k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 12.8k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** * **** **** ** x[] = {77,22,88,11,22};
** * ** * * * ** * * *** size = 5;
    
*** ** * *** ***** * ** ** ** print the array */
* * * ** * * ** * ** i = 0; i < size; i++){
** * *** * **** * * ** ** **** * * **** ** **** ** ** ** * ", x[i]); **** * ** ** * * ** **** * *
*** * * * *** ****
***** * *** * * ** *** * ** * ** * * **
* ***** * * ** *** * ** **
* * ***** ** * * **** I need this to happen size-times */
* **** ** * ** ** * ** ** j = 0; j < size; j++){
* * *** * * ** * ** * * * *** ** *** from left to right */
**** *** * * * * * ** * * * * * * **** **** * i = 0; i < size-1; i++){
*** ** * * ** * ** ***** * ***** ** *** ** * * ** ** * * * **** * ** * i-th element with its neighbor to check if they are in order */
*** * *** *** * * *** * * * * * *** * * ** ***** * * > x[i+1]){
******* ** * ** ** * * * *** * * * ** * * * * *** ******* *** ** **** * ** * ** exchange the values of x[i] and x[i+1] */
* * ** **** ** ****** ** ***** * * ***** ** * *** *** ***** ** ***** *** ** * ** **** *** temporary; * ** **** * *** * ** *** *
****** * ** * * * * *** ** ** * * ******* ** ** *** * * *** * *** * * * ** * * * = x[i];
** * * * ** ** ** ** * ** * ** *** * * * ** ** ** * * ** ****** * *** * *** = x[i+1];
** * *** *** ** * * ** * * ** * *** ***** * ** ** ** * * ** **** * ** ** **** * ** = temporary;
* ** ** * * ******* ** * * * ** * * *** ** ** *** ** *** * * * ***
** * * * ** *** * ** * * **** **** * *
** * *** * * ** *
* ** *** ** * * *** * *
* * ** ** **** * * * print the array */
**** * * *** **** ** ** ** sorting: \n");
* * * **** * ** * ***** * i = 0; i < size; i++){
* * *** *** **** * * *** ** * * **** ****** * * * ", x[i]); * * * ** ** * *** * * **
********* ** *
** * * * **** ** * * ***** * ** **
* **** * * *** ** *
** * * * *
* ****** * * * * * * *** **** ** * ***
* * *** ********* *** **** **** ***** * ***  
* ** * * ** *** ***** **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * * ** ** * * * x[] = {77,22,88,11,22};
** ********* *** ** * size = 5;
    
***** ** *** * *** *** * print the array */
** * * ** * * * * i = 0; i < size; i++){
***** * *** * *** ***** * * * ****** * * * * *** * ", x[i]); *** * * * *** **** * * * ** * * * *
** * * ** ***** **
****** * * * *** * * * * * * ****
** * * ***** ** *
** *** *** ********* * ** I need this to happen size-times */
**** * ** * *** *** * j = 0; j < size; j++){
* * * * *** * ** * * ** * * ** * from left to right */
** * ***** * ** *** * * * * * * ** * ** i = 0; i < size-1; i++){
* * *** ** ******** * * ** * *** * * * * * *** * * * * ** * i-th element with its neighbor to check if they are in order */
****** * * ** * *** * **** * ** * ****** * ** *** **** * * ** * * * * > x[i+1]){
* * * * ** ** * ***** ** ** ** * * * * *** * ****** ** * * * ** * * ** * * * exchange the values of x[i] and x[i+1] */
** * ****** ***** ** ** *** ** ***** * ** * * *** * * * * * * * * **** * * temporary; *** ** ** ** * *** * * ** *
* * *** **** * *** * * * ** ** * * * ** ***** ** *** ** * * *** * * * *** = x[i];
* * *** *** *** * * ** ** * ****** * * ** * *** *** * * ** ** *** * * ** * * ** * * = x[i+1];
* ** ** *** **** * * ** * * ** ****** * **** * * *** ****** * * ** * * **** ** * = temporary;
* * *** * * *** * ** * * * * * ***** ** ***** * ** * * ******* ** *
*** * * * * ** * * * ** * * * *** **** ***** **
* * *** * * *** *
***** ** *** *** *
* ** ****** ** * * print the array */
*** ** * ** * ** * *** * ** * * sorting: \n");
** * * * ****** * * i = 0; i < size; i++){
* ** * * * * * * **** ** * * * *** **** ** ", x[i]); ** *** * **** *** * * ** * * * ***
**** * * * * * ***** *
** * ** * * **** * * * **** ** * *
** * * ** **** * * * *
* * ***** * * *** * *
* * * * *** * * ** ** ** ** * * * * * *
** ** ** ** ** ** ** ** * * ** ****  
*** * * * *** * **** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** **** * ** ** * * * ***** x[] = {77,22,88,11,22};
* ** ** * ** ** **** * * size = 5;
    
** ** * ** ** ** * * *** print the array */
* *** ***** **** ** * ** ** * i = 0; i < size; i++){
** * *** ** * * * *** * * *** * *** * * * * * * **** * ** * ", x[i]); ** * * ** * **** * *** ****
*** ** ** * * * * *
* ** ******** ** * *** * **** ** *
* *** * *** * * ******* ***
** * * ******* * * * I need this to happen size-times */
* * * * *** * * * j = 0; j < size; j++){
* ** * * * * ** ** * * * * ******** * * * from left to right */
* * * ** *** * * * ** **** **** * ** *** * i = 0; i < size-1; i++){
* * ***** **** * * * * * * * * **** *** ******** * *** ** *** ** * * ** *** i-th element with its neighbor to check if they are in order */
**** *** * * * * * *** ** *** * * * ** * ** * * * **** * > x[i+1]){
*** * * ** * *** ** ** * * ***** * * ** * ** ** ** * * ** ** * ** *** * ** exchange the values of x[i] and x[i+1] */
**** **** * **** ** ** **** * * * ** * * **** *** * ** ** * ******** ** * ** * * ** *** temporary; * * * ** ** ***** * * *
** * * ** ** *** ** *** * * *** * * * * ***** ** * * * *** * ***** **** ** = x[i];
* * ** ******* ** *** * **** ** ** * ** * * * * *** * ** ** * ** ** * * ** *** * * *** = x[i+1];
** * * * * * * ** * *** * * * * ** ***** ** * * ******* ** * * *** ** * * * * *** = temporary;
** *** ****** * * * *** ** * *** * * ** * * ** * ** ***** * ** *
** *** * ** * * * * * ** * * * * * *** ** *
* * * ***** ** *
* * * ** ***** **
* **** *** * ****** ** print the array */
** ** ** * * ** ** * * **** * sorting: \n");
* * * * * *** * * ** i = 0; i < size; i++){
* ** *** * ** ** * **** *** ** ** * * * * **** ** ** ** ", x[i]); ** * * *** * * ** * **** *
* * * ** **
**** ** * ** * * **** * ***** *
* **** ** * * * **
** * ***** * *
*** * ** ** ** * ******* *****
** * * ** * ** * * ** * **** * *  
* * ** ** ** *** ****** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** *** * * * ** ***** * x[] = {77,22,88,11,22};
***** ** * ** size = 5;
    
** * * ** ** ********* print the array */
* * ** ***** *** * * * i = 0; i < size; i++){
***** ** *** * ** * * * * ******* * ** * ** **** ** * ", x[i]); * *** * *** * ** *** * ** *** ** ** ***
*** ** * ** * *
** * *** ** ** * ***** **** *** ** * *
** * *** ** * *
* * ** * ** ** ** I need this to happen size-times */
**** **************** * *** j = 0; j < size; j++){
*** * *** **** * ***** *** * ** * * *** * ** from left to right */
** ** * * * * * *********** * * ** * i = 0; i < size-1; i++){
** *** ** *** ******* ** * ****** **** * * * **** ** **** ** ** * ** * i-th element with its neighbor to check if they are in order */
** ** * * * ***** * * * ** *** ** * ***** ** * * *** * ** *** > x[i+1]){
** * * **** **** * *** * * * * * ** * ***** * **** * ***** **** * * exchange the values of x[i] and x[i+1] */
* * * *** ** ** * * * ***** * * ** *** ***** * * * **** ** * * * * *** * ** ** temporary; * * * * * * * * **** * *
* *** *** * ** *** **** **** ** * *** *** ** ***** ** *** ** * ** *** ** * * ** * ** **** = x[i];
** * * ***** **** ** * * *** ** * * *** *** * * * * * * *** ** *** * ** * *** = x[i+1];
******** *** * * **** ** *** * ** * * * ** * * *** *** * ** * *** * ** * * * * *** ** **** * * * = temporary;
** * ** * * *** * * * *** ** ** * ****** * ********* * ** ** ** * ** ***
* **** * * * *** ** ** ** * * * * * * **
*** ** * * ****
** * * * * * **
*** ** * **** * ** * * ** print the array */
* * ******* **** * ** **** ** sorting: \n");
* * *** ** ** * * * * ** i = 0; i < size; i++){
* * ** ** ****** * **** ** *** * * * * *** ** ******** * ", x[i]); * * **** **** *** ***** ** *
*** * **** * **** * * ****
**** * ** ** ***** ** ****** *** * * **
* ** ** **** * *** **
* * * *** ** * ** ***
** * * *** * **** * * * *** * *** *
* * * * * *** **** * * ** **** **** *****  
* ** ****** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ** *** ** * ** * x[] = {77,22,88,11,22};
* * * ** **** * size = 5;
    
* * * ******** * **** **** print the array */
* ** ** ** ****** * ** i = 0; i < size; i++){
* * * * * * * ** ****** ***** * * ** *** ** * * ** ** ", x[i]); * * * ** * ** ** ** * * * *
****** * * * * *** *** *
* * ** * * **** ** * ** **
* ** * ***** **** * *
* * ** * ** * * * I need this to happen size-times */
** * *** * ***** ** * j = 0; j < size; j++){
* * * ***** * *** * **** ** * *** ** *** from left to right */
*** ** ** * * * ** ** *** * ***** ** * *** i = 0; i < size-1; i++){
* * *** * * * ** * ** *** * ** ** * * * ** * * * *** * ** * * *** i-th element with its neighbor to check if they are in order */
** * * ** * * ** * * *** * ** ** * ** ** * * ** * ** *** * > x[i+1]){
* ** * * ** ******* * **** ******** ** *** ** ** * *** * ** * ** * * *** ** * **** ** exchange the values of x[i] and x[i+1] */
** * * * * ***** *** *** * * * * * ** * * * * **** * * ** *** temporary; * ***** * ** *** ** * * **
* ** ** **** * ** * * ****** *** *** * ** ** * * ** *** * **** ** ** ** * * = x[i];
* *** * ** ** *** * ** * **** * * * ** * ***** * * ** * * ** ** = x[i+1];
* *** **** * ** * * ***** * ** ** * ****** *** *** ** *** * *** ***** * *** * * ** = temporary;
*** ** * * * ** * * **** * * ** ** * ** * ***** ** * * * ** * *
*** ** * * * ** * ** **** ****** ** *
* ** * * ****** ** **
* **** * ** * ** *
** ** ** * * * * print the array */
** * * **** * * * * * * * *** **** sorting: \n");
** *** *** ******** * i = 0; i < size; i++){
* * ***** ******* ** ********* * * * ** * * *** * * ** ", x[i]); * * * * ** * * * ** *** * *
* * * ** * *** ** *** ***
** * *** ** * *** ****** * * ** *** **** *
* * **** * *** * * ***** *
* ** ** *** * ** * *
* *** **** *** * ** *** ** * * *
* * * * ** *** ** * ** ** * * ***** ****  
* * * ** * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** **** ** * *** * * * * x[] = {77,22,88,11,22};
** ** *** * * * size = 5;
    
* * * ***** * * * **** print the array */
** *** ****** * * ** ** ** * i = 0; i < size; i++){
* *** * * * *** * ***** * ** ********* ** ** * * * * ", x[i]); **** ** ** ** ** * ** *** * *
* * * * * * ** ***
** * *** * * * * ** * * ** **** *
*** ** ** * *** **
* * ** * *** ****** ** * I need this to happen size-times */
** **** *** * * ** j = 0; j < size; j++){
* *** * * * ***** **** **** ** * * * **** from left to right */
** ** * ***** ** ** * ** * **** * * ** * * i = 0; i < size-1; i++){
* **** **** *** * ** ** * * ** **** * * * ** ** * ***** ******* i-th element with its neighbor to check if they are in order */
** * ** ***** ** **** * ******* ** * *** * ** ** ** * *** ***** * > x[i+1]){
** ** * * ** * ** **** * ** * * ** * *** * ** * ** * * * * *** ** * **** * exchange the values of x[i] and x[i+1] */
* **** *** * ** ** *** **** ** ** * ** * * **** * * * * * ***** * ***** * **** * * ** temporary; * * ****** *** * * * ***** ** * **
* * * ** * ******* ** *** * ** * **** * ***** *** * ***** * ** * * ** * **** ** * * * *** ** = x[i];
** ** * ***** ** ** ** *** *** * * ** ** ** * * ** * * ** * ** * ****** = x[i+1];
* * **** ** * * ** ** * * **** * ********** * * ** ** * * *** **** * ** * = temporary;
** * *** ** * ** ** ** * ** * ** * **** ** *** * * * ** ** *** * * * ** *
** ** * **** * ****** * *** * * ** * ***
** *** * ** ** ***
** * * ** ***** * *
** * * *** ** *** * *** print the array */
******* *** * ** * * * ** * sorting: \n");
** * * * * **** * *** * i = 0; i < size; i++){
** **** *** **** * ** * * * *** ** ** * * **** ", x[i]); * * * *** * * ** ** ** * **
** *** * ** **** *** *
*** ***** * * ** * * ** ** * * *** *
** **** ** * ** **
* **** **** *** * ** *
* **** * * ** * * ** * ** ** * ** * * *
* *** * ** * ** *** ** * * ** * * *  
*** ** * * **** * ** * * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** *** *** * ** * * x[] = {77,22,88,11,22};
* * * * *** ** * **** size = 5;
    
* * ** * * ** * * * print the array */
* * * *** * * ***** * * **** i = 0; i < size; i++){
* ** ** ** **** *** * ** ** ** * *** ** * * ", x[i]); * * * * *** *** ** ******** **
* *** * *** * *** ** *
* ** ** **** * *** * ** ** *
*** ** * * ********* *
* ** ** ** *** *** I need this to happen size-times */
*** * **** *** ** * * ** *** j = 0; j < size; j++){
* ** ** *** ** ******* ***** * * * *** ** * from left to right */
****** ** ** * *** * * ** * ** *** i = 0; i < size-1; i++){
* ** * * ** * * * *** * * * *** ** *** * * *** * ** ** * ** **** i-th element with its neighbor to check if they are in order */
* ** * ** ** ** ** ****** * **** * ** ** * * * ********* ****** ** ** * > x[i+1]){
* * ***** * * * ** * *** ** ** * * ** *** * * * *** *** * *** *** * *** * * exchange the values of x[i] and x[i+1] */
* ****** * * * ** * ** * ***** * ** *** * * ** ** * * ** ** ******* ** **** **** **** temporary; ** * * *** **** *** *** * * *
** ** * * **** * *** * * ***** ***** ** *** * ** ****** ** ***** *** * ******** = x[i];
** ****** * *** *** *** * * ** ** * ** * ** * **** * * * ******* * **** ** * * ***** = x[i+1];
***** * * *** * * * * *** * ** ***** ** **** * ** *** *** *** * * **** * * * ** = temporary;
* * * * * * ** * * *** * * * *** * * ** *** * ** ** * *
* * * ** *** ** ** * * * * ** *****
****** ** * * * ***
* ***** ** * * * ** ***
**** * * * * * print the array */
** *** **** * * * * * ** * * * * * sorting: \n");
**** *** * ** *** * * ** i = 0; i < size; i++){
* ******* * ** ** * * ** * * ** *** * * * ** ", x[i]); ***** *** *** ***** * *** ****
*** ** * **** ** *** * * **
**** * * * *** ** * * *** * * * *
* ** *** *** *
* *** ***** ** * *
* * ** *** *** ** * * * ** * *** **
**** * ** * ****** * * *** ** * ** * *  
*** * ** * * * ** ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ************* * ** x[] = {77,22,88,11,22};
* * ****** * * **** * * * size = 5;
    
**** * ** * **** ** ** print the array */
****** ** * ** i = 0; i < size; i++){
* * ** * * **** * ** ** * * *** * **** * * ", x[i]); ** ** ** ** * * ******** * * ***** *** * **
* * * * * * * *** *** * *
** * **** * *** ** ** * ** ***
* *** ** *** *** * **
** ** ******* ** *** * I need this to happen size-times */
* * ** * ****** * ** j = 0; j < size; j++){
*** * ** *** ** *** ** * * *** *** * * *** from left to right */
*** ** *** * ** * * *** * * ****** * *** ** i = 0; i < size-1; i++){
** * *** ** * * * * *** *** * * ** * * *** ** ********* * ** ** i-th element with its neighbor to check if they are in order */
*** **** * ** *** ** ** * ****** *** ***** * * ** * *** *** * > x[i+1]){
* ** * ** * * ** *** * *** * * * * ******* * * * * ****** ** *** ** ** * ** * *** exchange the values of x[i] and x[i+1] */
* * * * * ** * * * **** **** * * * ** * ******* * * ** * * *** ****** * **** * * * *** temporary; ** * * * **** **** *** ** ** *
** * *** **** * ** * * *** ** * * * * * * * *** * * ** * ** *** * **** * * * ** ** ** = x[i];
* * **** * * * *** *** ** ** ***** * * ** ** * ***** ** *** *** ** *********** * * * = x[i+1];
**** ** * ** * * *** * ** * ** **** * ** ** * * * ** ***** ** * * * ****** ** * ** * = temporary;
* ** * ** * * * * * *** *** ***** ** * * * *** ** * ** ********** *
* * ** * * * ***** ** ** ** ********* **
*** * **** ** ******
* * * **** ****
*** ** * * ** *** print the array */
* * ** * * * * * *** * * *** sorting: \n");
****** *** * ***** ******* ** * i = 0; i < size; i++){
* * * * * ****** * * *** ** * *** *** ** *** ** * ** **** ", x[i]); * * * * ** * * * ********
* * ********** ** *
* * * ** ** * * ** * ***** * * ***** ***
* **** * *** * ** **
* * *** * * **** * *
* *** ****** * * * ***** * * *** * *
* * ** ** * * ** * * ** **** ***** * ****  
****** **** ** * * ** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * ** * * * ** ** ** * x[] = {77,22,88,11,22};
**** * * * * ** *** size = 5;
    
* * * * ****** **** ** *** print the array */
* * * *** *** *** * i = 0; i < size; i++){
* *** * * * * ** * *** * * ** * * * * * ** * ", x[i]); * * * *** * * ** ** ** **** ****
* * ** * *** * ***
* * ** *** **** * * * * *
* * * ** ** ** * *
* * * * *** ***** * * * ** ** I need this to happen size-times */
** ***** ** ** * * * * *** j = 0; j < size; j++){
* ** ********* * * * * ***** ** * **** from left to right */
** **** **** *** ****** ** ** * * * **** * * i = 0; i < size-1; i++){
** * *** * *** ** **** * * ** * ** ** * *** *** ** * ** * *** i-th element with its neighbor to check if they are in order */
*** * ** * **** * * * ** ****** ****** * ** * ** ***** ***** ** * > x[i+1]){
* * * * *** * * ** * * * * * * * * ** * *** * * * * * * ** * *** * ** * * * exchange the values of x[i] and x[i+1] */
** ** * * * *** ** ** * * * ** ***** * * * ** * * * ** ** * *** *** *** ****** * *** temporary; *** ** * *** * ********** **** **
*** * **** ** * * **** ** ********** * *** * ** * ******* * * ***** * * ** ******* * * **** = x[i];
*** * * *** * * *** ** *** **** * * ** * * ** ** ***** * * * * * * ** ***** ** ** * = x[i+1];
** * ** ** * * *** *** *** ****** * ** ** *** ** * ** ** ** *** ** * *** *** ** * * = temporary;
*** * ** * **** *** * * ** * ******* ** ** **** * * ** ****
***** * * ** * * ** * * * **** * * * *
** **** * ** ** ** * ***
**** *** * ** *** * ** *
*** * ** * * *** ** * print the array */
* * ** * ***** ** * * ** * sorting: \n");
** ** * ** * *** * * * ** * i = 0; i < size; i++){
* * **** ** * *** * * ***** * * ***** ** ", x[i]); * * * *** * ****** * * * **
* ** ** * *** *** * ** *
** * * ****** *** * * * * * * * *****
*** * ** * * * * *
** *** ** ***** *
******* **** ***** ** **** * * * * * * * * *
** ****** ** * ** ** ** * ***  
** * * ** * ** * * ** ** ******* 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** *** * * * * x[] = {77,22,88,11,22};
** * * * * * size = 5;
    
** *** ** ** ****** * print the array */
** ** * *** ** ** ** **** * i = 0; i < size; i++){
* * *** * * ** ** * * * *** * *** * * ** ** ** ** ** ", x[i]); ** * **** * * * * ** ** ****** * **
**** * ** * *** *
** ** * * * **** ***** * ** *** * * * ***
* * *** * ** * * *
* *** ** * * * *** * I need this to happen size-times */
* * *** * *** * j = 0; j < size; j++){
* * * * * ** ** ** * ***** ** * * *** *** *** from left to right */
**** ** * * * ** ** *** **** **** * *** ** i = 0; i < size-1; i++){
* * * * ** * * ** * * * * * *** * ** ******* ** ** ***** ** **** *** * ** i-th element with its neighbor to check if they are in order */
*** * * * * ******* * ***** * * **** * * * ** * ** * ** * ** > x[i+1]){
* * ** **** * * * * ** * *** ** **** *** * *** * **** * * **** * *** **** * *** * * * *** exchange the values of x[i] and x[i+1] */
*** *** ** * * * ** * ***** ** ** *** ** * * ***** * ** ** * ** * *** * * * *** **** temporary; ** * ** * *** * * *** ** * *
* * *** * * * * * * * * * ** * * ** ** * ** * ** * *** * *** * ** * * * ***** ** ** *** ** = x[i];
* * ** * ****** * * ***** ** * * **** **** * ** **** * **** * * * * * ** * * ** * **** ** = x[i+1];
** * ** * * ** **** *** ********* * * ** ***** ******** * ** * ** ** * *** ** * * * * *** = temporary;
*** ** * **** * ** * * ** * * * *** * *** ** *** * ***** *
** * *** ** * ** *** * * ******* * * *****
* * ** *** * *** *
*** ** * * * *** * * * **
** **** *** *** *** **** * print the array */
* ** * ** * *** ******* * * *** ** sorting: \n");
** ** * ** * **** * * * i = 0; i < size; i++){
** * * * * ** * ** * * * **** * * ***** ** *** ", x[i]); * * * *** *** * * * * *
** * * * * *** ** *
* * ** * * * *** * *** * *
* ** **** * ** *
* * * * * *** * * *
* ** * ** *** * *** * * * **** * ** *** * *
***** ** **** **** * ** * * * **  
**** * * *** *** ** * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 7.7k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 6.8k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 3.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users