0 like 0 dislike
1.8k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 1.8k views

46 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ***** ** * * **** * * x[] = {77,22,88,11,22};
* ** * ** ** * ** size = 5;
    
* ** * * ** * * *** print the array */
* ** ** *** ** ** ** i = 0; i < size; i++){
** ** ** ** ****** * *** *** * ** ** ***** * *** ", x[i]); ******* ** *** * * *** * ** * * *** *
* ** * * ** * *** **
*** * *** *** ***** **** *** * ********* ** *
*** ** * * * *** **
** *** ** * ** * I need this to happen size-times */
** ** **** ** * * j = 0; j < size; j++){
** * ** * * *** * * ** ** **** * * ** *** ** ** from left to right */
*** ***** ** * * ** * ** * ***** **** * * * i = 0; i < size-1; i++){
* * ** * * * * * * ** ** ** * * * ** * **** * * **** * *** *** * i-th element with its neighbor to check if they are in order */
** * ** * * * ** * * * *** * ** * * ** * * * *** **** ** * ** > x[i+1]){
* ** ** * * *** ** * * * ** ** * ** ** * **** * * ** * * * ****** **** * * * exchange the values of x[i] and x[i+1] */
******** * * ***** ** * *** ******** ** ** * * * ** * * ** ** ** * * * ** temporary; * ** *** ** ** * * * ** * *** **
**** * * ** * **** * ** **** * * *** * ** *** ** * * * * ** * ** ****** * * * * ****** **** = x[i];
* ** * ** * ** * * ** * * ** ** ** * *** * * * *** ** * ** ** **** * * * * ** *** *** * ** = x[i+1];
** *** ***** ** * * * ** * ** ** ** *** * ** * * * * ** * * ** ** *** ** * * ***** = temporary;
* ******* * ** ** * ****** * ** * ** * * * * * * *
* * ** * ***** * ** ***** **** ** * * ***** *
** * * ** *** * * ***
** *** *** *** ** * * ** *
** * * * ** ****** print the array */
* ** ** ** ** * * ** *** * ** *** sorting: \n");
* * *** * * ***** * ** * ** i = 0; i < size; i++){
*** ******* *** * ** ** *** ** * * ***** * **** ** * *** ", x[i]); * * ** ** *** * *** *** * ** **
* ** *** ** * ** **
*** * * ** * * ** *** * * * ** ** ****
** * * * * * *
**** * * * *** * * * **
* * ***** ** ** ** ** ** * ** **
* **** * * ** ***** ** * * * ** * * * * *  
** * ** *** ********* * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** **** * ** ** * * * x[] = {77,22,88,11,22};
******* * * * ** * ** ***** size = 5;
    
* ** *** *** *** ** ****** print the array */
* * ******* ******** * ** ** i = 0; i < size; i++){
***** ** ****** ** * *** ** * * *** *** ** ** *** **** * ", x[i]); * * *** * * ** ** ** *** *** *
***** **** *** * * * * **
*** * * *** * * * *** * * * * *** *** * ** *
** ** ** * * **** * *
****** ** * *** ** * * I need this to happen size-times */
*** ** * * ** ** * * *** j = 0; j < size; j++){
**** ****** * * * * ** ***** * ** * *** * *** from left to right */
* **** * * * * * * * *** * * * * ** ** *** ***** i = 0; i < size-1; i++){
*** * **** * * **** *** *** ** * ** * * ** * ** * ** * * * ** * * * * i-th element with its neighbor to check if they are in order */
*** ****** * * ** * * **** *** ** ** * ** *** * * * * > x[i+1]){
* *** * ** ** * ** ******* ** *** * * * * ****** *** * *** ** * * ** * ********* exchange the values of x[i] and x[i+1] */
* * *** *** * *** * * * ****** * **** ** * ** * * * ** *** * ** **** ** * * temporary; ** * * ** ** * * ******* *** ****
* ** * * ***** ** * ** *** * *** * ** * * * * * *** **** ****** * * *** ******* * **** * = x[i];
*** ** * * * * ** * ** ****** ** * * *** ** ** ** * * ** * * * * * * ***** **** * ** ** ***** = x[i+1];
* * ** * ** * * * ** ** ** ** * *** * ****** * ***** **** ** * * ***** ** * * * **** * * * * = temporary;
* ** * ****** ******** * * * ** *** ** * * ** * * *** * ** *
** * * * * ** **** *** * * * ** * * **
* ** ** ** * ** **
** *** ** * **** * *
* * * * *** ** * print the array */
* ** * * * * ** ** *** * * * * sorting: \n");
* * ** **** * * i = 0; i < size; i++){
******** *** ***** * * *** *** * ** ****** * * * * * * * * ", x[i]); * * *** * ********** ** *******
* ********* * ** * *
*** ******** **** * *** * * ** ***
*** ** * *** ** ** ** *
* *** ******* *
***** ** * * ** * ***** * ** * *
* **** * **** * * * * * * * * *** ** ** ****  
* * * * * * *** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * ***** * * ** x[] = {77,22,88,11,22};
* **** * * * * * * ***** size = 5;
    
* * *** ** **** * * * print the array */
* * ** * * * **** * * i = 0; i < size; i++){
** ** * * **** ***** * * ** * * *** ** * **** * ", x[i]); * * * * *** ** * ***** ** * ** **
* * ********** * ****
*** ** * * ** ** * **** *** ** * ** ** * *
*** * * * *** ** *
* * * ** ** * ** ** ** ** I need this to happen size-times */
** * * * ** * * ** * * ** j = 0; j < size; j++){
* * * * * ** * * * ** ****** * ** *** * * *** from left to right */
* *** * * *** ** * * * * * * **** ** * ** * ** i = 0; i < size-1; i++){
* ** * ***** * ** *** **** *** *** *** ** *** * *** * ** ** ** ****** ** * * i-th element with its neighbor to check if they are in order */
******* **** ** ** * * * ***** *** * * **** * * *** * ** ** * > x[i+1]){
* ** *** *** * * * *** ** * ** * * * * * * * *** ** * *** ******* * * * *** * exchange the values of x[i] and x[i+1] */
**** * ** ** *** *** * *** * * ** * ** ****** ** * * ** *** * *** temporary; * ** ** * * ** * **** **** *** ***
**** ****** ** * **** * ** * * * * * * * ******* ****** * *** * * * ************ * * * * = x[i];
** ******* * ** *** * ** ** ** * * * ** ** * * **** * * *** * * * * ** *** ** ***** ** * * * * = x[i+1];
* * * * * **** ***** * * *** * * * ***** * * ** ** * * ******** ** * * **** * ** * = temporary;
*** ** *** * ****** * ** * *** * ** * * * *****
*** *** * * *********** *** * ** *** *
******* *** ** ***** * ** ** *
**** *** *** * *** ****
* **** * * print the array */
* * * ** * ** * * *** * ** * sorting: \n");
** *** * *** *** * * * ** * * i = 0; i < size; i++){
* * * * * * * * ** *** * * * * * * * ***** * * ** ", x[i]); * * * * *** ** * *****
* ** * * * * * * *** *
* *** **** * * * *** * * * * * *
** * * ** * *
* ** * * * *
* * * ** ** * * ** * * * ** * ** *** *
* ************** * * * **** *** *** * * ** * *  
* * *** * * * * ****** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** * * *** * * * ** x[] = {77,22,88,11,22};
****** ** * * * ***** ** * size = 5;
    
* **** * ** * ** * print the array */
* * * ** ** ** *** * * i = 0; i < size; i++){
** * ** ** * ** * ** ** * * * * ***** * ** * ", x[i]); ** * ** * ** * * ** ** ** * * *
* ** * * **** *
**** * * *** ** *** *********** *** * * *
* * * * * * * *** * **
* ** ** ***** * **** I need this to happen size-times */
** *** * * * ** ** *** j = 0; j < size; j++){
* **** * * ** **** * ** ***** * ** * * from left to right */
** *** * * * * * ** * * *** * ***** * **** i = 0; i < size-1; i++){
** * * * * ** ** * * ** * * ***** **** *** ** *** * *** * ***** i-th element with its neighbor to check if they are in order */
****** **** *** * * ** *** ** * * * ** * ***** * *** ** *** * > x[i+1]){
* *** * ** * * *** ** **** * ** * * * **** * * * ***** * * * **** **** ** **** exchange the values of x[i] and x[i+1] */
* * *** ** * ** * *** ** * ** ** * *** * **** **** ******** ** * *** * ** * * * temporary; *** * * * ***** **** ** ** ******
* ** ******** * ** * ** * * ** * **** ** * * * * ** **** * * * * * * ** * * * *** ** **** = x[i];
** *** * *** ** * * * ** * **** *** * ** ** * ** * * ** ** * *** * * ** = x[i+1];
* ** ** * * ** ***** * * * * * ** ***** * ****** ** * **** *** *** * * * ** **** * = temporary;
* ** * * *** **** * * * *** * *** *** * ** * * *** ***** ** ** * **
* * * ** * **** * * * * * ** * ****
* ** * ** * * * * ****
**** * *** * * * *
* ***** ** ***** print the array */
* * * ** * *** *** ***** ** sorting: \n");
* ** * *** *** * * * ** i = 0; i < size; i++){
* **** * *** ** ** *** * ** *** * * ", x[i]); * * * * ** ** * * *** * * * *
**** * ** * * * *
*** **** * **** * * * * ** * ** * * *
** *** *** ***** * * * ****
* * *** * * * *
*** * * *** ** ** * ** * * *
* * **** **** ** ** * ***** **** * **  
* * * * * **** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** *** * * * * * * ** * x[] = {77,22,88,11,22};
* * ** * ** * ** * * size = 5;
    
* * * **** ***** * print the array */
*** * * ** *** *** *** i = 0; i < size; i++){
*** ** * ** * * * * ** ***** * ** * ** * * ", x[i]); * * * **** * *** * * *** * * ****
* * *** * ** * * *** **
******** **** * * * * ** **** ** * ** *
***** * * * * * ** ** * *
* * * * ** * ** * * I need this to happen size-times */
*** * *** *** ****** **** j = 0; j < size; j++){
** * * ** * * * ** ** *** **** * * ** * * from left to right */
* **** * * * ** * * * * * * * ** ** * i = 0; i < size-1; i++){
* ** * * * * * **** ** ** ** ** * * * * * *** ** *** *** * i-th element with its neighbor to check if they are in order */
* ** *** * * * * ** ** ** * *** * ** * * * * *** ** ***** * *** > x[i+1]){
* ** ******* * *** * * ** *** ** *** *** *** * * * * ** *** ** **** * * * * * exchange the values of x[i] and x[i+1] */
* *** ** *** * **** ** ****** * ** * *** *** ** *** * * * * * * * *** ****** ** temporary; * **** ** *** * **** * * ** **
** * * * ** * *** ** * * * * **** * * ******* * * *** ** * **** ** *** ***** * * * = x[i];
**** ** ** * ****** * * ** *** *** **** * ** ** *** ** ** ****** ***** * * * * * *** ** * = x[i+1];
* **** * ******* ***** * ** ** *** * ** * * * * * *** * * *** * * *** ***** = temporary;
**** * ****** ****** ** * ** * * ** * * * * ** * *** **** **
** *** * * **** *** * * * * * ** ** ** *
* * * **** * * * *****
* * **** * * **** * **
* * * *** * * * ** * * *** print the array */
****** * * *** * *** ** * * * ** * sorting: \n");
* * * * * ** *** * ***** i = 0; i < size; i++){
*** *** **** * * ** * ** ** * ** * * * * * * ** * ", x[i]); * ** * * * *** ** ** ** **
* **** * * ***** *
*** *** * **** *** ***** * ** *
* ** *** ** * ***
* * * * * * ** * **
******** *** ** * * * ** **** ** ** **
*** *** * * * * * **** * ** * ** * *  
* **** *** * ***** ******* * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** ** *** * ** x[] = {77,22,88,11,22};
** ** * * * ** * ** *** size = 5;
    
* ** * *** * *** * * ** print the array */
* ** * * * * i = 0; i < size; i++){
* * * * * ** *** ********* ** * * * * * **** * ", x[i]); * *** * ** * * * * ***** *** *** * *
*** * * * ******
* * ******* *** * * * * ** * *** * ****
** * *** * ***
* ** * ******* ** * * * I need this to happen size-times */
** * * * ****** *** * j = 0; j < size; j++){
* * ** * * * ** * ** * * * *** ******* from left to right */
**** ***** ** * *** * * * * ** * **** ** * * ******* i = 0; i < size-1; i++){
* *** *** *** ** ***** * ** **** *** * ** * * *** *** * * * * ***** * i-th element with its neighbor to check if they are in order */
****** * * ** *** ** ** ** * ** ** ** **** * * ** ** *** * * > x[i+1]){
* * * *** * * ** * * **** * ** **** * * * * ** * **** **** **** * *** * * * exchange the values of x[i] and x[i+1] */
* ***** ** * * ** * *** * **** ** * * ** * * *********** * * ** * **** *** * temporary; * * **** * ** * * * * * *
** *** *** ***** * * * *** ** ** * * ** ** * *** * * **** * * * ***** ****** = x[i];
* * * *** ******** *** ******* ** * ** * * * ******* * * ** *** ****** ** ***** ******* = x[i+1];
* *** *** ** *** ** * ****** * ** * * * * ** *** ** **** * ** * * ***** * **** *** * ** ** = temporary;
** * * *** * *** * * * * ** ***** * * * ** *** * * * * *** *
*** * *** ** * ** * ** * * * * * * ***
* *** * ** ** *
*** **** ******* * *
* ***** ***** * * ** print the array */
* *** * * * * * * * * *** * *** sorting: \n");
* ** ** ***** ** * * *** i = 0; i < size; i++){
** ** * * ** * * * * * ******* * ** ** * ", x[i]); **** * * * * * * ** **
* * * * ***** ****
* * * *** **** * *** *** ** * * * * *
* * * ** * ***** ***
** * ** * * * * * * * *
* * ** ** * * * * *** ** * * *
*** * * * **** * *** * * ** ** * ***  
* * ***** * ** **** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** * ** * *** x[] = {77,22,88,11,22};
**** **** * **** * * size = 5;
    
* **** * **** ***** * * print the array */
* * * * * *** ** i = 0; i < size; i++){
* ** *** * * * * *** ** * ***** * * *** **** ** *** * ", x[i]); ** * * * * ******* ** *** **** **
* **** * * ****
* ** * * * *** * * * ** *** * * **
**** * * ** * ****
* ** *** ** * * * I need this to happen size-times */
* * ********* *** ** * j = 0; j < size; j++){
* ** * ** * ** ** * *** * ** from left to right */
** * * *** **** * * * *** **** ** *** ****** * i = 0; i < size-1; i++){
* * *** ** ***** * ***** ** ** * * ** * ** ***** * ** * * i-th element with its neighbor to check if they are in order */
* ** ** * ****** * * *** * * ** ** ********* * * * > x[i+1]){
* * * ** * * * ** *** * * *** * * * ** * ** **** **** ** **** ** *** * * exchange the values of x[i] and x[i+1] */
* * ***** ** **** * * *** * * * ****** ** ** ***** ** * ***** *** * *** ** * *** * ** temporary; *** ***** *** ***** * *** ****
* ** * ** ** * * ** * * * * ** * ** * *** * * ****** ** * * ** ** * * * **** * * * **** = x[i];
** **** * *** **** ** * ** ***** *** **** ** * * * * * * ****** * ** = x[i+1];
*** * * * * *** * ** ** * * * ** *** *** ** *** ** * ** ** * ** ** ** * ***** *** = temporary;
******** *** * ** ***** * * * ** ** **** * * * * *** ** **** ** *
* * **** * ** * * ** * **** * **
* ********** * **** * *
* ***** * * **
* ** *** **** * * * ** * print the array */
* * ** ** * **** * ** sorting: \n");
** *** ** * * * * ** *** i = 0; i < size; i++){
*** * * * * *** * *** ** * * *** ** * * ** ** *** ** *** ", x[i]); * * * ***** **** *** ***
* ** * *** ** **
* * ********** ** * * *** *** * * * *
* * * * * *** ****
****** *** * **** ***
*** **** * *** * * * ********* **** * *
* * **** * * * * * * * * * * ** ****** **** *  
* * * * ** * ** * * * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ********* ** * * * x[] = {77,22,88,11,22};
*** ** * ** **** * ** size = 5;
    
******* ** **** *** print the array */
*** * * * * ** **** * i = 0; i < size; i++){
* ** * * ** * ** *** ** ** ** *** *** * *** ** ", x[i]); ** * ** ** ***** * * **** **
* ** ****** ** *
** ** * *** **** * * * ******** *** *
* **** * * ***** *** *
* *** * * * ** ** * * * I need this to happen size-times */
** * * ** ***** *** * * j = 0; j < size; j++){
** ** * * * * * * **** * ** **** * * ** ** from left to right */
* * * * **** * * **** ** * * *** ** * * ** *** * * * * * i = 0; i < size-1; i++){
** *** ** *** * * ** **** *** * * * * ** * * * *** * * **** * * * i-th element with its neighbor to check if they are in order */
* * *** * *** * *** * **** **** *** *** *** *** *** **************** ** **** > x[i+1]){
******* * ** * *** * * ** * **** ** * * *** * * ** **** ** * * * ** * * ** * * * ** * exchange the values of x[i] and x[i+1] */
**** * * * * * ** * *** * * * ** * * * **** *** ** * * ******** ** **** temporary; * * * * ** **** * * * *
** ** * * * * * * * ****** *** * * * * * * * * * ** *** * **** ** *** ***** = x[i];
* ** * ** ** * ** ** * * *** ** * * ** * * *** * * * *** * * * *** ** *** = x[i+1];
** * *** *** * * ** ** ** * ** ** ** * ** ** * ***** * * * * *** ** * ****** * * *** * * ** *** = temporary;
** ** * **** *** *** *** * ****** ** **** * ** ** ****** * *
* ** * * *** * **** * ** ***** * * ** **
***** * *** * * ** *
* * * ** * ** ** ** *
*** ** ** * * ** ** *** * print the array */
** * * * * * * * *** * ** sorting: \n");
** ** ** * * ** *** **** i = 0; i < size; i++){
* * *** ****** * ** ** * ** * * * * *** ** ** ***** ** ** ", x[i]); ****** ** * *** * * *** * * **
* ** ********* *** **
**** * *** * ** *** **** *
* * * * * * *** *
* * * * * ** *
*** ** ** * * * * * *** * *** *** *
* * ** * ** * * * * *** * * * ** * ** ** ***  
** ** *** * ** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** ** ** * *** *** x[] = {77,22,88,11,22};
*** * * * ** *** **** *** size = 5;
    
* ** **** ** * ** print the array */
**** **** ** **** * * *** * i = 0; i < size; i++){
** * **** ****** * * *** *** **** * * ***** * *** ", x[i]); ** * ** * * ** * ** * **** **
* * ** ****** * ** *** **
* * * *** * * * * **** ** * * * * *
** * *** * ** **
* * * * *** * * ** * ** I need this to happen size-times */
** *** *** * ** *** * j = 0; j < size; j++){
* * * * ** * *** ** * *** ****** * *** * from left to right */
* ** * **** * * * ** * ** *** * *** ** ** * * * ** * i = 0; i < size-1; i++){
* * ** * * ** * * * * ******** * * * **** * * *** * ** * * * ** i-th element with its neighbor to check if they are in order */
* *** * ** * * * ***** * * * ** * *** ** ** ***** **** ** ** ** > x[i+1]){
* * * ** ** * * ******* * ** ** * * **** ** * ** ****** ** ** *** *** * * **** * * exchange the values of x[i] and x[i+1] */
** ** *** * * * * * * ***** * ** * * **** * * ** * **** * * ** * * * * ** * * ** temporary; ******* *** ***** * **** * * * * *
********* * *** *** ** ** * ** ** * * * *** *** *** * *** *** * * ** * ** ***** ** * = x[i];
* * * ** * ** ** ** ** * * ** * * ** *** **** * ** ***** ******* ******* *** ** ** = x[i+1];
* **** * * *** * * * * ** * * * * * * * * ** ** ** * ** * ** * ** * = temporary;
* * * ** ** * ** ** ** * ** ** * ******* *** *
* ** ***** *** ** ** * ** ** * *** * *** **
* ****** * ** * * * * *** *
** ** * **
* ** * ** ** * * * print the array */
*** * ** ** **** *** * * * *** * sorting: \n");
**** **** * * * ** ** **** i = 0; i < size; i++){
** * **** ** * * *** * * *** ** * ** * * * * * * ", x[i]); ** * **** *** * * ** * * **
* ** * * * **** **** ***
**** ** *** * * * ** * * * * *** *** **
* ** **** **
* *** ** ** ** * ** *
* ***** * *** * * * * * * * * * ***
** ** **** * ** * ** ** ***** * * * * *  
*** * ** * * * ** * *** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** * *** ** **** x[] = {77,22,88,11,22};
* * *** ** * ** ** * ** ** size = 5;
    
* * * ** ** * * * ***** print the array */
*** * ** ** *** ** **** ** *** i = 0; i < size; i++){
** * *** * * * **** *** * *** ** * * ** ** * * * * * * *** ", x[i]); * * ** * *** * ** * * * * **
** *** *** ******** **
**** * *** * ** **** **** * * *** * * *** ***
* ** * * * *** **
* ***** ** ** ** ** * I need this to happen size-times */
* * * * * * ** * ** * * *** j = 0; j < size; j++){
** * *** ** * *** * * ** **** * ****** from left to right */
* ** **** * ***** ** * * * * * **** * *** i = 0; i < size-1; i++){
* ** * * *** * **** * *** *** ** * **** * * ** * * * * i-th element with its neighbor to check if they are in order */
** ** ***** ** *** * ****** *** *** * * ** ** *** ** * * * * * ** * > x[i+1]){
* ****** ** ** **** ** **** * * * *** * * **** * * * * ** * * * **** * ***** ** * **** exchange the values of x[i] and x[i+1] */
** *** ** * ****** ** ** ** * * ** *** *** * ****** * * * * ** ** * *** ** temporary; ** ** *** ** * * * * ** *** ***
** *** * ***** * * * ** *** *** ** * *** * ******* * *** * ** *** * * * * *** *** = x[i];
* * * ** ** **** * * ** * * ** * ** * * *** ** * * * * *** ***** ** ** *** * * * = x[i+1];
* *** * **** ** * * * *** * ** *** ****** ** ** * **** *** * * ***** * ** = temporary;
** *** ** * * ***** **** * *** * ** *** ** ** * * * * * ** ** * *
** ***** * *** * * * **** * * ** *
* ** * ** ** * * ** *
* *** * * * *
** *** * **** * * ** * * print the array */
* * ** * * * * ** * * sorting: \n");
* * *** *** * i = 0; i < size; i++){
* **** * * * ** ** ***** ***** * * * ***** * * ", x[i]); * * ** * ******** * ** * **
** ** ** * * * *
*** ** * * *** *** * * * * * ** *
* *** * * ** * **
* * * *** * * * * * **
** * * ** * ***** ** ** * * * * * ** * *
**** * ** * ** * * * ** * * ****** ******** *  
***** ** ** * ** * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.71
©2016-2024

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 651 views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 924 views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 578 views
12,783 questions
183,443 answers
172,219 comments
4,824 users