[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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***** *   **     **  *   *    **  *    ** **  *   your input:"); //DO NOT CHANGE
  *  ***  *  *    ** *  **  ** **** * * ** ** *   * **
    
*  **   *  ** ** *     ****   * Your conditions start from here
*  ** * **  * **  **  * ** ** = 'A'; a <= 'Z'; a++){
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* *** **    * ** *     * *   ***    * *     *     **     *   * **     **** * ***   **  ** *  * *****  ** *  
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**  *  *** ****  ***  **  **** **   * * ***     ***  * *    *   
 ****** *   * *  *  *******   0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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** *  ** * * ** *****   * *
*** **   **       **  **    ** * *  *    &a);
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*   * **  **   * ***     ***    * ****  **** * **  *     
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***  *      **  *     *** *** *  ** *   ****** *    **
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     ***   *  *** * ***** ** * 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include   **  *   *   *  
#include * * *  *  * *

int main(int argc, char *argv[]) {

** ** **  * * *    char a;
*   *** *  * *  
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*    *   ***     ** *** * * * **   ** ** if(a == 'A'|| a == 'E')
* **  *   * ******  **  **  ** ** *  * *  **     *    * *   * * ****     ***** * *  
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* ******    *  *  ** *   ****  *     * a++;
    *  * * *  * *  }

 * *  ** *   return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include      * *  **    *
#include  **    *    ** 

int main(int argc, char *argv[]) {

*  * **   * *** char a;
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*****       **   *     *** ** **  *    ** else
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****  ** *      ****  * * *    **     ** *   * a++;
  ***     **** }

*  * ***  **  *  return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include **************  **
     **  * *  *** * ****

int main(int argc, char *argv[]) {

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*       *** **       * *  * *  ****        a++;
*     * * **** ** }

*** ** **  **   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include **  *******    
#include  ** **  *   ****

int main(int argc, char *argv[]) {

* ***  **   ** int a;
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*    * * *    ** ***   **   * **        * ** a++;
*  ****** * **   *  }

*   **      * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include *  *** ** * ** * 
 *** * ****  ** *    * *

int main(int argc, char *argv[]) {

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*  **   ***    ** **** **** ***  **    *   a++;
**** ** *  ** *** }

 * ** *     return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
*  *** * * * ****  **
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int   * *  argc, char  **  * {
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*   * *  *      * * * *     else
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 * ** * ** *   *  * *   ***    a++;
** ** *   *** }
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*   **  *   * return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
 **  **     * *  * * *   ** **  * ** *       *  your input:");
 *  *  * *    * **  *   ***  *  * *  ** *   ** &a);
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* ** * *    **      **  **  *   **  *     ***   *** ***  * *    * ** * *      * * *  {
** **   *    ******* *  *** *  *   * *******  ******   **   * * * *** *** ** *  ***  ** *    **** *
* *  ** *****   *  * *   ** ** *   *** * * * * ****    
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*  ****     **    ** *  * * *      *      ***    *  * * *   **   *  * ** **** *    *** **  *** ****   **** a);
**   ***  ****** *****  ****    ***  *  **      * **  
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
****  **   *  * *  *   **    a;
   *  ******** * ******** * ******  **   your input: ");
**  * ** ***  ******  *   * ***** **  * *  &a);fflush(stdin);
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***  * **  *  *  ** * * * *****  *    **  ** **   * ** * *  ** ***    * *  *
  *** * * ***  ** *  * * ** * ** * ****  ***  *     ** ****  * * ** *   * *   * *  ||i==69 || i==73 || i==79 ||i==85){
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* *** ****    ***   *     * * *  ** ** *    * **** *    * *   **  * * *  **  ** ****  ** 
   * **  **  ** * *   * **  *       ** **   *    ***    * * ******   ** *  **   *  * ** * *  *  *  ***** **  * *** *** * 
*  * ** * * ** *   **  ** **  *    * ** ***  ** ** ***** **  *  ***    ***  
*  ** ** ****   *   * * **** *** * ****  ****  *  
**  * ***  * ** *  **  * **
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output