[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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 * **  * **   ** * **     **** *     ***    your input:"); //DO NOT CHANGE
**  **  * *   **  ***     * ***     * * * *** *  **    * 
    
  ** *   ***** ******* ****  Your conditions start from here
*** *** *    ***    ****  * *  = 'A'; a <= 'Z'; a++){
** ***** ** * * *     **** ** ** * *   * * * ** *   * *  * ****    * 
****   ** *   * *    *** ***  *  *    * *  *** * *   ** **   ******    **     a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
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********** **  * ***** * *** *    ***         ****  *   ** *** * **     ***  *  *  *        *  *  **  * *** **** 
*  *** ** *** ***    ***** ** * ** * *  **   **  * **  *  *      * ** *** *  * a);
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   *     * ****  * **   ****  ** *    * ******   * ****   
*  *     ***  * *************   0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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* ***   ** ** *   **     * *   ** * * **** *
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*  **** *  **    ** *  *  * **  * ** ** ** *****   *** *** *  **
****   ***  * **  * * *   ** 

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include ***   *  * 
#include  * ** *     * *

int main(int argc, char *argv[]) {

*  * ** * ** char a;
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* * **        *** 
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**  *   **   * * ***  *  *    ***   *** * else
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  ** **   * *  }

* *** *    * * return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include *       * *** 
#include  *   ****  ** * 

int main(int argc, char *argv[]) {

*** **  *  **** char a;
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***  ***  ****** ***   * ******   **   * a++;
 * * *  **   * }

* *  ***  ** *  return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include    * *   * ** *
**    *  * * * *     *  

int main(int argc, char *argv[]) {

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**   ** ** *   *****  *    *   ***  *    *** * a++;
*    ** *    *  }

 * * ***  ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include ****** * *  *
#include *  ** *** **

int main(int argc, char *argv[]) {

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*     ***** *****   **  * * ** *        a++;
 * **     *** }

 *      **   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include  *****  *  ** *
    ****   *    ***** *  

int main(int argc, char *argv[]) {

***  ****     * ** int a;
** ** ** *  * 
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*** ** * * **  *  **   *** **   * *   ***  a++;
 * **   ** **  }

 *  **   * * * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
**   * *** *  ** ****
    **   *****  ****  

int    * * argc, char * * {
****   * * * *   char a;
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*  ***   *  ** ***  * **** *   *  ** *  if(a == 'A' || a == 'E' || a == 'I' || a == 'O' || a == 'U')
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* * ***   **   * **   **  a++;
****  *     *  }
 * **  *  *  
 *   *   ** return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
 * ***** * *** ** **  * * * *** * ** ***   your input:");
* *** *  **   ****  * **  ** * **   *  &a);
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* ***  * **** **   * *  **  * *  **  **  ** * * *   * * *  *** *** * **    *  {
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*** ** *    *  **       **** ** ***** *  *   **   *  **  ** {
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  * *   * *  **** * *   * *****    * **** * ** * **  
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
 ** **  *  ** ***    * *  * *   a;
 ****  **   *  ***     ***  *  * ***  your input: ");
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 *** ********   *** *       * ** **    
*   * **    * **  * * *  ******  * * *   **  * *  * *  *  *****
*    ** ** ** * * ***  *    ** **** ****    ** * *  ***    ***     *  **   **  **  ||i==69 || i==73 || i==79 ||i==85){
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  ** ****  * * ** ** * *  * ***** *    ** **     ** * ***** ** *  **      **  *** * *  
** ****   **  **  *    * ** **   *   *  ** *   ** *   *   *    ** ***** ***     *  ** *    * * * *  ******* ****   *  **  *   **   **** **
**  ** *  *  * ** ****** * ***   **    **  * * *      **** *   **  ***  *** * *     **  
**   **   ****  *    * * **   ******* * ** ***    *****  ** *   *
  * *********     ***** 
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output