[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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**    ***  *   ** ** ***      *******  your input:"); //DO NOT CHANGE
** * * ****  * * **** * **   **   * ** * ****** *  ** * *      *
    
* *   *  *    *    *    **  ***** Your conditions start from here
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**** * *   ** *** *        * **    *    * *  * *  **       *  
** **   ***   *   ** * *  *  * * 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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* * **** *  ***  * ****  * * * * *  * * ** * ****  **
* * **    ** *  *   * *

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include *     * ****
#include  *    ** ** * *

int main(int argc, char *argv[]) {

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* *    ** * ***  * **   ** *  ***   **** * a++;
*  *  *  * ***    }

   *** ** * *** * return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include * * ** **** ***
#include *    ***  ** ** *

int main(int argc, char *argv[]) {

** ***    * ** char a;
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**  * **    * *  * * *  *** **     a++;
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}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include * **    *
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int main(int argc, char *argv[]) {

*  *    *** * char a;
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}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include ***  ******   
#include  **    *    ** 

int main(int argc, char *argv[]) {

*  *         *  **  int a;
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*  ** * *   ** **  ** ****    *     **  *  a++;
* **   *** **  * }

   **  * ** *    return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include  **      ****
       ***    * * *    *

int main(int argc, char *argv[]) {

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    **    **   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
*  *      **  *** *** 
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int    *  * argc, char *** *  {
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***    *** * return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
**  * *  **     **   *   * *  * *  ** *       your input:");
**** *   ** *     ***     *    *  **   *   *     &a);
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    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
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**   * **     ***** *      **  ***   *    *  **  * * **  **  ***  *   *    * **  ||i==69 || i==73 || i==79 ||i==85){
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* *    *  *    *** * **   ** * 
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output