[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
*        ** ***          a; ****   *****     *** *****        **  **  ** ** * *   *   * *****    ** **     *  * ** *****  ***   *** *    ***  * * **  *  **   * *     ******** ** ** *  * can be changed
*********  * *   **  *  ***  *******   *  ** your input:"); //DO NOT CHANGE
** ****   **  ** **** * *******         * *  *** *  * *
    
* *  *   * ***  * *   *   * * Your conditions start from here
** *   *     * *  *        * **  = 'A'; a <= 'Z'; a++){
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 * * * *          *    *  * ****  *  0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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* * *  * ** *  * **** * * ********
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    *    * *    **** **     * * ***   *   **  * ******* **
***   ***     * **   **   *

**   * ******** * *** *  * *  0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include    * * * *     *
#include   * ** *****  *

int main(int argc, char *argv[]) {

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* * * * **   **** 
*  * ** *      while(a <= 'Z')
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* **** *** ** ****   ***   *  ** * * ***** else
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**   * * * ***   *  ** * * * **    *    ** a++;
*   * ** * * ** }

*  *  **    **  return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include *   ******** * **
#include *      * *  **

int main(int argc, char *argv[]) {

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***   *    *** ** ** * **    ***  *   *  **** *   **   * **   * *  * **** * **** *  * ****
* * *  *** *    *      *  *  **     * **   ** ** else
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  * ***  ****  **     **** *  *   *  ** *    *  a++;
*** **  ***    }

** *** * * ** * return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include ****  ** * **  *
****   **  * *   ******  

int main(int argc, char *argv[]) {

 *   *      ** char a;
*  *      *** ** * 
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*   *   * *  ** 
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*     *  ** }

****  *   * *  * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include **** *     *  **
#include    *  ***   *

int main(int argc, char *argv[]) {

 * *  *    *   ** int a;
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***   *    * ****   ** *  *   ** **  a++;
      *  *  *  * }

 * ** **    ** ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include      *** **  *  * 
 ***   *****  *** *  ** **

int main(int argc, char *argv[]) {

  **  ** **   ***  int a;
* ** **   * *  
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* * *   *  * *  ** ***     ** * *** ** * *    a++;
** *   * ** }

*   *  *  **  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
 ** *  **     **  * ** *
*   *   *** *   **** ***

int    * argc, char ** * * {
* * * ****   char a;
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**  **      **  
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* *   ** **   *       **  ***    *  *  **  *  *      **** * *  * ***
*  ***   *** *   ****       * ** else
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*  ***   **  *  *     *** a++;
 *   **   ****     }
  **     *  *  ** 
*** * **  * return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
**     ** ** * ***       ** * ** *      * * your input:");
    * ** *  *    **      *   ** ****** ** **   &a);
* * ** ** *     **       *   ****  *** *** *   {
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*** **  * ** * * * * *  * **  *      ** **** **  * * ** * *  *** * * ** *      *  * ** 
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* * ** ******   **** **** *  ***  *     ***  ***  *
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
*  **    * ***    * * ****  ** **  a;
*  ****   * *  ***  **    *** ***    ****    your input: ");
** ** * ** ****  * * * * ** *    *  *   &a);fflush(stdin);
*     *   * * **   *** **   *   *   **
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  * ***   *  ** *** *  ** ** * *  **   *      *     **   *  *  * *  *  * ** * * ||i==69 || i==73 || i==79 ||i==85){
  ***    ** * *****  **       * *  ***  ***   ****   **** * *    ******** *  **   *** *** ***** *** *  **  *****   ** *** *  *
**  * ******      ***  * *   *  *** **  *   **  ***   ** *     * *****    * ***
*** ***  **  * *  ** ***   *   *** * * *     *  * ** ** ***  *  ***    ** *  ** 
*   ** *** ** * * *     * * * **  *** **  ****  ** * *  ** * *****   * *** * * **  *   * **    *  *** *****  * *     *  ** 
** *  ******  * **** *  ** ***  ***     *  **  ****  * * ***   *  **       *  *   
  ****   * *   * ***   * ***   ****  * *** * ** *****  **
*   ** ***  ** * * ***   * **
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output