[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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   **           **      ** **  ****  ***** ** * your input:"); //DO NOT CHANGE
** ** *  ****    *  *   ***   *   **    **   ***** 
    
 * * ** * ***  **    ****** Your conditions start from here
   *  *  ** *   *    *** ***  = 'A'; a <= 'Z'; a++){
 ** **      * **   *  ** *  *  *   ** *   * ** *  * * *    ** * ***
       **     ****   * * *   ** *  * *   * *   ** * ** **       * *  *   * ** a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
*  ** *********    **      ****   *    * *   ** ** ** ****      **  ** *  **    **    *  *    *  *      ***  
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* ***  * * **     * *    * *** *  *    *  * *****  **  *** *****      * a);
*   *******  **    * *  **  ** **** * ** **   **    *
***    ***** *    *****  *** **  * *  ******* **  *  ***  ** * ****    *
    ****** * * *      **** * 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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*  ** * * *  ** *** *****  
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*   **     * ** ** *  ***    *
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** *****   *** *  **** **  ***   **  *  ***** *  * *  *   
***  * ***** ****   ** * * * 

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include **  ** ***  **** 
#include    *  * **  * * ***

int main(int argc, char *argv[]) {

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*** ** ** ** * *    ****   **** * * ***   a++;
* *  **    **** }

*  *  * *** *** return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include * **** * *** ***
#include    *   * ****

int main(int argc, char *argv[]) {

** * *** *   * * char a;
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* ****     *  * *  * *     *  * **** * a++;
*    **     * **** }

 * **      ***  return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include   * *** **  ** ** *
**   *       *  **  **

int main(int argc, char *argv[]) {

*  ***  *** ** char a;
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   *  *   **  * }

  *  * ** * * * * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include ***  **********
#include ** *** ***** * 

int main(int argc, char *argv[]) {

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**  *** * *  * }

*      **  * **   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include  **  * * *****
*******   *         **    *

int main(int argc, char *argv[]) {

*       **** int a;
*       ** ***   
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** ** ** ***    *   *  ******    *   *  else
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*  * *  * **** ******* **    ** *  *  *     a++;
  *     *   **** * }

   *  ***  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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int ***    argc, char * * {
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* * *  *** * *** *  * *    your ** ***   *    
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  **        *   }
 ** * *   *  *  ** 
 * *  *  ***  ** return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
     * *  **  *   *  ******     ***** *  **   * * your input:");
   * ** * * * *** * *  ** **** **  **      ** * &a);
* *   *   *       * **  *  *** ** *  ** * ** {
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  * *  **   **   *****    *     **  ** *  ** *  
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*** ** *     *   * **    ** **    *  **    *  ** *        ** ** ***** ***  ****    *** *           *  a);
* * *  ***    * *   * * ** *    *****  *   *** **** * 
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
***    **  *** *   ******  a;
  ** *** * *******     * *    **     *** * * * your input: ");
   * * *  * **   * * ******* ** *  *** * **** **  &a);fflush(stdin);
*** **** *** * ** ***** * **    *
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****** ****   * *  *  ** *  *   *  ***** *     **   * * **     *  *    * ** *** *   *   ||i==69 || i==73 || i==79 ||i==85){
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 ** * ***         ****** * ********* **** ** *   * ***  *** *  * * *      
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* ** ******     ********* *  *   * ** *  *** ***   ***** 
*   *    *** *     * ***
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output