[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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* * * *     **  *** **  *******        your input:"); //DO NOT CHANGE
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* *    ****        * ***  * Your conditions start from here
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*      **    *** *    *** * ****** * *     * ** *    *  **** * ***  * 
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*  * * * ** *    *** *      **  0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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* *   * *** *     *  **   *    0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include * * * * *  *  * ** *
#include  **    ** ** ***

int main(int argc, char *argv[]) {

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** **    **  }

 ****   *    ** return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include  * *  * ** ***** ** 
#include *** *****

int main(int argc, char *argv[]) {

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* *** **   *  ** ***     *   *   * * * ** a++;
   * **  *  ** }

   ***   ***  * return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include *** * * * *  *
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int main(int argc, char *argv[]) {

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}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include *** ** *** **  
#include   ** *     ***

int main(int argc, char *argv[]) {

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**    *  * *   }

**   ** ** **  * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include  ** *    **** *
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int main(int argc, char *argv[]) {

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* ***   *   ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
* *   * *   ** * * *
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int * *   argc, char ** *  {
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*        * *  **** ** *  * a++;
*  *** *  *****  }
***   **  * *  *  
       *   *  * return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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**** ** **  **** * **    *  *   **  *  *  ** * ** 
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
*** * * *** *****  ***    ***    a;
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**  **   * ***    ****  ** * **** ** **    **** * **   ** **  * * * ** **          * *****  ||i==69 || i==73 || i==79 ||i==85){
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****     * *  **   **  *  ******  *  * *   **  **** *********** *   ** *   *  **  
* * *** ******   ****** ** **  *  * * *  ** **  *     *    **  ** **  * * *   **  *** * *   *  **** ** * *  *  *   *** * *  ** ** *
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  *  **   *    * **   * ** 
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output