[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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**     ** * * *****   *  *  *  *  **  * * *  your input:"); //DO NOT CHANGE
   ** * *   ** *     ***    ***** **  * * *   **
    
   ** * *   * **  *** *****  Your conditions start from here
*      ** *     * **   * * * * * *  = 'A'; a <= 'Z'; a++){
*   ***     *  * *  ** * * *  ** ** * *****  *******   * *** *     * 
**  *   **** * * * ** ** ** ***** * ** * *** * **   *   ** ***** a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
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    * * ** * *     *     *   * * *   ** *   ***  * *   * * * *  ** *      *  *     *   *    * * *   *  * * *
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** * *** *       **  ***     *   *  **  * ***     * * ***  *    ***  *** * 
* ***   * *     ** *  ***  * *  0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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** * *   * **** **     *** *

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include   *     ******  * 
#include   *   *  * *  * 

int main(int argc, char *argv[]) {

***  **      **  char a;
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***  * **    **   ****         **   ** *    a++;
***       *** ** }

*  *   *  * *** * * return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include  **  ** ** **
#include *    * *** * *   *

int main(int argc, char *argv[]) {

***   *  *** ** * char a;
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** **    * **  ******* *  **** *   **  *  *  a++;
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 *    ***    return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include   ** ***  * 
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int main(int argc, char *argv[]) {

***  *  * *  * *  char a;
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*  *** *     * **  * ** * ***  * *         * * a++;
    *   ** * * *   * }

*  ***    * *  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include * **     ** 
#include   **  ***** * * 

int main(int argc, char *argv[]) {

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   **    *** * }

 **   **   *     return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include  *  **  ** ****
   ***    *       **

int main(int argc, char *argv[]) {

*   *  **  ** int a;
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***  *  ** ** *  ** *   ***  *** ***  * **   a++;
* *   * * * *    }

 *  **   *   **   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
*       **  * * **** 
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int * * * argc, char **** {
* ** **   *  **   char a;
**    *** *   * 
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*   **    *  *  **  **  *  * a++;
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* *  * *  return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
  *    *      ****    ***  a;
**   * * *       *   *  ****** *  **   *  **  your input: ");
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 * *  *   * * *** *   * * *** ** * **  ** **  *         ** *****      ******* *  * ||i==69 || i==73 || i==79 ||i==85){
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**   **  *   ***       * * ** **** **      ** * * ***  * *   *** * **    *   *** ** **** * *    *  ** **    *    **** ***   * * **
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**      * ***   **  **  ** ** *       ***  **
    *          ** **** *  **  
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output