[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
** * * *   *   * * * *  *** a;     **** *  *** *** **** ** ** ***** **   **     *  **** *  ** *  **   *****  * *   ** *********  *  *** ******   ******* * * ***** **  ** **  can be changed
 * * **  *  *   * ** ** **  * **   *  *  * * your input:"); //DO NOT CHANGE
    *  *     ** * ***  * ** * **  ***   ***   * ***   
    
*  ** **   ** ** **** ****   *  Your conditions start from here
   **  ****     *   *  ** * = 'A'; a <= 'Z'; a++){
    **   ** *    ** ** ***    *   *  * * *** * *  * *****    
 * *  ** **  *  *** ****   *  *** ** ***  *   **** **  * * * **    *  ** a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
*   ** *    * *  *    * **     * *****            ** * ** ***       ***** ***  **** **  *  *   *   *** ** *****   *    
   ****   *****  *  **  * * ***   **  **          * * *     ****** *  *  *     **  ** ** **   ** **  
******    **    *  **       *  ****   ** **     *  * **  *    *   *  * * *  **** * *    *** *     * * **  * 
 * **** * **** *      **   *    *  * ****  * * **   * * **   * **  ** a);
 *   ***  **   ***  ** * **  * ***   **    *** *   *
* ** ** ** *      *****  *****  *  * *** *** *   **      * *   *  **
  *   ***  * * * * ** **  * ***** 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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*  * ***   * ***   ** * *   *
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*  *  ** * * ****  *    **   
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**  *  **** **         ** **
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* *****  *  **  * **   **          ** * **  * **  * **
*****    *** ******  ***   *

* ** ** ***  *** ***** *** *** * 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include  *    ***  ** * * 
#include   * ** *  *   *

int main(int argc, char *argv[]) {

* * **  * *    * char a;
******** * *   
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** *  ** *   ****  * **   *     * ** * * * * a++;
***   **  ** ** }

*  ****      * *** return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include    * *   ***** * *
#include     ** * *

int main(int argc, char *argv[]) {

**      ***  char a;
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*  *  *   **   **** *   *  **  ** *  **   a++;
 *** *      ** ** }

** *    ***     return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include  * * * *  *   *
   * * ****    ****

int main(int argc, char *argv[]) {

**  * *  **    * char a;
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**   *       ** * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include *  * *  ***       
#include   * ** * 

int main(int argc, char *argv[]) {

****     ** int a;
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*** *** ******  * *   **** ** * ** ** ** ***  * * else
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**  ** *    *  * }

*  * * *     * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include    *** *** *****
** *    ****  **     *

int main(int argc, char *argv[]) {

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   * *** ****  }

    ***         return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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int *   ** argc, char    ** {
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*** * *    ** **   * * * *  ** *  else
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** **   *  **     }
** ***  ***  
*  *  *    return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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 *  *    * *** ** ** *   ** **  **  ***   * *    &a);
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    *  *    ** * **    *   ***   ** *    **   * *  *** 
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
**** * * ******  ** ***  *  ** a;
 * *  *  *   **  * **    ** * *  * *  *** *   your input: ");
* ***  * * ***   *  ***     ***  ** * ****   **   *  &a);fflush(stdin);
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*** * * ***  * * *  **    * *** * *     * ********* * ****    * *  *   **** ***     *   *
* *  *** * *** ** **  * ** * ** **  **  ***  *  *  *   ** * * *    ***  **     * 
   ** * * ** *  *** *  **   *   ***  **  ** ****   **** *****  *  ** * *    *      * *   ***  *        * ** ***   **  ** *  ** 
**  *   ** ***  *** *** ****  *   **  *  ***      **   **  * * *  * * * ****  **     **
  ** **** * *  *****  * * *   *  ****      **** * ***** * 
***  * *    *****     *******   
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output