[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
* ***  **  * * * *** *  * ** *** a;  ** * *   ** ** * * ** **    **   ***    ******    *  *** *   * * ** *     **      *  *  **    * *      * *****  **  * *  * * *   *   ** **  can be changed
*  * * * **    ** *  *****   **   *     your input:"); //DO NOT CHANGE
**   ** *  *   **** *    **  * * ***  ** **  ** *** * * 
    
**** * * * *   ** * *  Your conditions start from here
 * ******** *  ***   * **** * = 'A'; a <= 'Z'; a++){
*** ** **   ***** *    **  * ** ********   * **  * **  * **  * *   *  *
  *       * ** * ** *  * **     ***   ** *  *  **  **  **   a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
 **     *    ** *  *      *** *   * *   ** ***  *  * *   *   **   ** * ***   *****   * **   ***** ** *       *      *    * *  
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*     **** *   *   ***** * * *  *** * **   **  * **   *  ** **  *   **** a);
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 ****   * *  ***         *   ***  **   *   ** *    * ******   
*  *    *  **   * ** * ** *  0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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*   * *  **  * ** ** *** *  
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*** ***** ** ***** *** ***   * *     * *  **  *  *  * ** *
*  * * **    *  * * ***** *   * *  

     **** * * * *    ** **    *   * 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include  *   ** *  *   **  
#include *** * ***  * **

int main(int argc, char *argv[]) {

***   * ** *   char a;
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 *  *** *   ** * *** **  **  **  *  *   a++;
*** **   *  * }

***  *  * ***   return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include   ** * * * **  
#include  *       *** *  ** **

int main(int argc, char *argv[]) {

*      * * * ** char a;
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* *** *  *  *** **    * ** * **  *   *  *  a++;
   ** * *   * }

*    ** **     return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include  ** **   *   **  **
 *  *   * * * *   **  ****

int main(int argc, char *argv[]) {

 *  **   **    char a;
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*** ***   * *  }

*    * *   **    return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include *   * ** *   * ***
#include *   * **   ** *   

int main(int argc, char *argv[]) {

* * ** *   *   *  int a;
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*** *** ** ** ****    ** * **  *  ** *   *** a++;
* * ***     *   }

 ***    **  *  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include  * * * *   
* ** ***    **   * 

int main(int argc, char *argv[]) {

    * **   *  ** int a;
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   *  * *** * * **** ** **   ** * *   a++;
**  *  ******* }

 **  ***      ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
 *  * *** * ** *** * * 
 * *  *     * * ***** **

int  *  *** argc, char ** **  {
  *    * * *    char a;
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***  **   * *  ** 
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*    * * ***     **  **  *   * *  * * **    ** * **  *   ****** 
  ***    **  *  **  * ****   ** else
* * *   *     * *   *      * *  *     *   *** **      * ** ** a);
*  **    * * *   ***      * *  * a++;
  * **  *    * **  }
  * ***   *  *** 
*** * ******** return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
   *  *  ** *   ** ** **  * * *******  your input:");
   *******  **    ** *       *** ** *   * *   &a);
*****   *  **** *  ** ***   * *  **  ** **  *   {
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**       * *** *   *** * ** **  * ** * ** *  * * **** ***  ** *  **  *   *    **   ** **   * 
 *    * *  ***  * **    ***** *  **** *   *****  *
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** * *  * *   ************        *  ***  *   **  ***** * ***  *    * *  * * *   *        * * ** a);
      ****      ****    * ** **  ***     ** *  * **  **  
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
   *   ***** * *   * *  * a;
* ****  ***  * * ****  * **  **  *  *  * *  your input: ");
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* ***  ** **  *  * ****    ***  ** 
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   *  *  *  * ***   *   *  * * * *  *  **  **  *   * **   * ** ***   *  * * **** **  ||i==69 || i==73 || i==79 ||i==85){
  * ** *******   ** *  **  ** ******  *  ** *    * *      * * ** *    ** *****   **** ***** **   *** *    **  * * * *   * * **  
******    * **** ** ** *  * ***   * *** * *  ***       *   **** *  **  *  
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    * *   ** **   *** **   **  **** **  * ****  *  *********    ** ** * ****** *  *     * * *  *  *  * * *** * * *   * *** 
   ** *** *   * ** **   ****   ** ** * *    *** *  ***  * *  ***  *  *  * ***   *     
   **    *       * *   * ** * **  ******** ***  *    ** 
****** **  * *  **  ****    *
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output