[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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***  **  *  ** *  **  ** * **  *   **  *** ***  *** 
    
 * * ** *  ***  *** **   **** Your conditions start from here
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* **   ******* * * * ** *  **** * * *  ***  *** *  ***    *  *  ** *  a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
* ***  ** **  * ***  ** ** ** **** * *  **   * *      * * *        *** *   * ** * ** ** *    * *** *  
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**    **   *  *    ** ***** *   *    *** * *** ** 
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     * * ** ** ** *   *  *  * 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include ** * ***   * *
#include  * *** ** **  * 

int main(int argc, char *argv[]) {

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   * ** * **    return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include  **  **     * 
#include  *  *    ** ** ** 

int main(int argc, char *argv[]) {

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* ****** **** return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include  *** * *    **   
****  *** **    ***

int main(int argc, char *argv[]) {

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***** *** ***  *   * ** *      * ** * * * a++;
* ** ** **** * }

*   *   *  ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include   *********** 
#include * **** *** *  **

int main(int argc, char *argv[]) {

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 **      ** *   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include ***  * ****    
**   *  ***  ***** * 

int main(int argc, char *argv[]) {

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** *    **  **  *  }

**  ***  * * **** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
*** *   *** * *** *  ****
**** *  ***  ** *  **

int   *** argc, char   *  * {
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**            * *   ****   a++;
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* *** ** *    *    
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}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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***** *    * * *  *      * * **** ** *** *   &a);
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**** * ** * *  ** ***  *** ** **   ***     *   *** *    
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
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**  ***   * * ** *    *   ***    **** *    your input: ");
* ***  *   * ****  * ***   *******  *  * **     * ** &a);fflush(stdin);
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***  * ** ** ** * ** ****** **   ** ***     *    *  ***   ***   ** *    * 
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*  *** **    *  *** ** ****
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output