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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 4.3k views

24 Answers

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Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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}
100/100 answered by (283 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^
0 0
prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token
0 0
prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^
0 0
prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
0 0
Case 0: Correct output
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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}
answered by (153 points)
edited by
0 0
Case 0: Wrong output
0 0
Case 0: Wrong output
0 like 0 dislike
Hidden content!
#include *** ** **
#include * **** ** * **

int main(int argc, char *argv[]) {

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*** * * * ** }

* ** * * * return 0;
}
answered by (153 points)
reshown by
0 0
Case 0: Wrong output
0 like 0 dislike
Hidden content!
#include *** * **** * *
#include **** * * **

int main(int argc, char *argv[]) {

** * *** char a;
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*** * * ** ** return 0;
}
answered by (153 points)
reshown by
0 0
Case 0: Wrong output
0 like 0 dislike
Hidden content!
#include * ** **
* * * **** * **

int main(int argc, char *argv[]) {

* * * ** ** char a;
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}
answered by (153 points)
reshown by
0 0
prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^
0 like 0 dislike
Hidden content!
#include ** * * *
#include * ** * ** **

int main(int argc, char *argv[]) {

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* ** * * **** * return 0;
}
answered by (153 points)
reshown by
0 0
prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^
0 like 0 dislike
Hidden content!
#include * **
* * * * ***

int main(int argc, char *argv[]) {

** * * int a;
* * * * * *
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** * * **** return 0;
}
answered by (153 points)
reshown by
0 0
prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^
0 like 0 dislike
Hidden content!
** *** *** ** **
*** ** * ** * *** *

int * * * argc, char * {
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}
100/100 answered by (269 points)
0 0
Case 0: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main(){
    char a;
*** * * ** * *** * * **** ** * your input:");
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}
100/100 answered by (273 points)
0 0
Case 0: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
* * * * *** ** *** a;
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}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ
100/100 answered by (290 points)
reshown by
0 0
Case 0: Wrong output
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