[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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*     * *    **  **  *  ** *** *** ***   ***      * * * **
    
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* ** *    **** ** ****** ** **  **  * *  ******  *    **    *  ***** 
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*  *   *        *        * * *  *   *  *       **    * **  * 
*  *** *** *** *  ***  *** 0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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*  **  ***** **** *  *   ** 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include  * *** * ****    
#include   *      ** *   *

int main(int argc, char *argv[]) {

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*** * * *  * * }

 * * *  * **  return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include **** *  * ** 
#include  **  **  **   

int main(int argc, char *argv[]) {

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}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include  *** **  ***  ***
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int main(int argc, char *argv[]) {

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*  * ***  * **    return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include  * *   ***     
#include **  **   ** ** **

int main(int argc, char *argv[]) {

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* *     *****  }

**     ** ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include * ****   *   **  
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int main(int argc, char *argv[]) {

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*    ***            *   *    ***       * *  * a++;
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*    **** **   * * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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****    * * * **  ** **       a++;
****   * *** }
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*** **        ** return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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*  ** *** ** *** * *    ** * * * ** *   *** *  *     ***
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
* ***  *  ** *  **  *     *  a;
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}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output