[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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*** * * **  **** ***** *  * **     **   *       your input:"); //DO NOT CHANGE
  * **    ** *  **      * *   ****   * * *   **   *  
    
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*    * *  * ****  **  ** **  **  *   *   * ***      * *  **** *   * ****   *    ***  * **   *   ** 
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** * **  ******* * ** **  * * **  0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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*   *** * *** * * **** *  

* * ** *   ** *** *  ********** 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include **   *  ****  *
#include **  ** * ***  *

int main(int argc, char *argv[]) {

*    *   ** *** char a;
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*  ** * * *   **     *  ** * *   ***  *  a++;
*  * *** *  * ** }

*   **** ** ** return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include  * **** *  **   *
#include   ** *      * *

int main(int argc, char *argv[]) {

* ** * *   **** char a;
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*******  ***** }

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}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include * *  ** *   **
 *  *      * **   * * ** *

int main(int argc, char *argv[]) {

**  **  *  * *  char a;
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*** *   ****   }

**** *   *     * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include   * *** *   *  * 
#include *     * *******   

int main(int argc, char *argv[]) {

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**    *   * *    * **        * * ***     *** a++;
* * *   ** * * }

  *  **  **  *  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include ***    *   ** **
 * ***   * ** ****  **  

int main(int argc, char *argv[]) {

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***   * *** * * *  ***    ** * ****    **   a++;
  * * *    *    }

*    *   ** * *  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
***** ****   ***** **
* ** *     **  * *  *** * 

int  ***  argc, char **    {
* *         *  char a;
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** *  *  *    ** ** **   else
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*****   ** *    * * * * *    *  a++;
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 * **  *  * *   
****** * *   return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
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        * **   ***   ** * **   * * * *** **    *    *    ** ** **   **  * *   ***     * ||i==69 || i==73 || i==79 ||i==85){
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** *** * * *  *  *     *****  *   * *  *   *   ** ****  * 
* ****  *       **   *  ** ****
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output