[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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*** * ***** ** **   * **    Your conditions start from here
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}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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*** **     ***    *  **   *

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include *  *   * * * **
#include *  * * * *** * 

int main(int argc, char *argv[]) {

* **  * * ** char a;
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* **   * ***** ** }

***  *  ****    return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include      * *   ** * *  
#include   *** ** **  * 

int main(int argc, char *argv[]) {

*  * *   ** **  char a;
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* *** * ****    * *      * * * *  *   *** * a++;
*  **  *   ***   }

  * ***    *  *  return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include * *  ** *  *  *
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int main(int argc, char *argv[]) {

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  **** ** **   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include *** *** *  ** 
#include * * * ***** * *

int main(int argc, char *argv[]) {

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* ****   ** *  ** }

* ***   ** * **   return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include    * *** *** *  
** ****  * * ** ** ****

int main(int argc, char *argv[]) {

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*  * *  *  *  *  }

****** **** * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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int *** argc, char    *  {
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* * **** *  *  **    ***  *   * a++;
 **     **   **** * }
  *  * * ** 
     *  ***   * return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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* * *     *   *****  ****  ****    ****  {
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    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
* ****  *       *** *  ***  * a;
  ** **  * * *    *   * *    ****   *   your input: ");
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 * *   * *** * * **  ****    ***   *     * ***   ***  * *  * ****   *****  * **   *  *   ||i==69 || i==73 || i==79 ||i==85){
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 * * * ***   * **   ** ****  **  * * * * * * **   ******     *** ** * * ****   *** * ** *****
*  * **   * *  **     ** * **  * ****   * * **   *** ** ** *   * * *** **   ***
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** **** *   *  *** *    ** *    *  ****** **     ** **   ****  *  *  *    *    ***  *
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 **  *  * ***** *  **  *      ** *
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output