[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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   *** ** * ****  ***     *** * ** **  *** your input:"); //DO NOT CHANGE
     ** * *****  **** *** ***   ***  *** *    *    *     
    
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*  ***     *** ** *  ****  *** *   *         *  * ***  ***   ****   
 * ***  * * *  *  * ** *** * ******  0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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 *  * * ***  **   * *  **  **** 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include   **   *   * *
#include * * ***** *  * ***

int main(int argc, char *argv[]) {

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* ** ***      *  **  **  **  * * *  *     else
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*  ** **    ******       * *  **    *   a++;
**   * ***  }

 ***** *   *  * return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include * *     **   
#include  * *  ***  **  *

int main(int argc, char *argv[]) {

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*    *   *   **** ** *      ** * * * **    *     a++;
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 ***  **   * *  * return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include * ****        **  * 
 * *       * *    *    

int main(int argc, char *argv[]) {

*  **   *  **    char a;
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**   **** ****  * **** *** * * *****    ***  * * a++;
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* *    **     * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include  *  ***  
#include **    ** ***  

int main(int argc, char *argv[]) {

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  ***  * * *   }

   * **   * * * * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include **    **   *
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int main(int argc, char *argv[]) {

*   * **** * int a;
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  * ** *  *** }

* **  **     * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
    **  * * * * * 
*  * *     * ** * * **

int **  *  argc, char *** {
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** *  ** ** * * *  ***    **  *    else
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*****  **** }
  ***  *  *  * 
    * * * *** return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
*  ***   *   * ** *    *  **  ** ** *** your input:");
*     ** * *   * **  *  * * * ** * *** *  * *  &a);
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*** *  *   *   ***   *  *  ** ** * ****    * *****  
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    * ** *   ** *     ***    **  * ****  * ***** 
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
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* **    * *   **   * * *  ***  *****  ** ****  ***   *
*      **        ** ***** ** 
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output