[Exercise 9] Vowels detector

Question

Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

Answer 1

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
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*  *** *   *  * **** ** *   ***       * *  * *  ** *
    
*  * * *** ****** *******    ** Your conditions start from here
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** *   ***  *   *   **    **  ****  **    **  *******  **  * 
 * ** * *** * **  ** * **  *  *** *  * *    *   *   *** *  *  *  *  *  ** a == 'A'||a=='E'||a=='I'||a=='O'||a=='U'){
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  *         ** *  *** **  **   0;
}

Comments

prog.c: In function 'main':
prog.c:7:10: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'char *' [-Wformat=]
  scanf("%d",&c);
          ^

---

prog.c: In function 'main':
prog.c:12:11: warning: missing terminating ' character
  if ( a = '
           ^
prog.c:12:11: error: missing terminating ' character
prog.c:13:2: error: expected expression before '}' token
  }
  ^
prog.c:13:2: error: expected expression before '}' token

---

prog.c: In function 'main':
prog.c:10:15: error: expected ')' before ';' token
     if(a = 'A'; a <= 'Z'; a++){
               ^

---

prog.c: In function 'main':
prog.c:12:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:16:30: error: expected expression before '?' token
                printf("%c", &?);
                              ^
prog.c:20:34: error: expected expression before '?' token
                    printf("%c", &?);
                                  ^
prog.c:24:36: error: expected expression before '?' token
                      printf("%c", &?);
                                    ^
prog.c:28:33: warning: missing terminating ' character
                      printf("%c"' &?);
                                 ^
prog.c:28:33: error: missing terminating ' character
                      printf("%c"' &?);
                                 ^~~~~~
prog.c:29:22: error: expected ')' before '}' token
                      }
                      ^
prog.c:28:31: warning: format '%c' expects a matching 'int' argument [-Wformat=]
                      printf("%c"' &?);
                               ^
prog.c:29:22: error: expected ';' before '}' token
                      }
                      ^
prog.c:34:1: error: expected declaration or statement at end of input
 }
 ^
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input
prog.c:34:1: error: expected declaration or statement at end of input

---

Case 0: Correct output

Answer 2

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {

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***  ** *    *  ** *  * *  

*      *   ** *  ** ***  * * *  0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 3

Hidden content!
#include   *   * **  *
#include ** *** *** * ***  

int main(int argc, char *argv[]) {

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  ******  ****   return 0;
}

Comments

Case 0: Wrong output

Answer 4

Hidden content!
#include  ** ******* * *
#include  * *    ********* *

int main(int argc, char *argv[]) {

* **    *   * * char a;
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***  *** * *  ** *   * *  ***   ** *** a++;
*  * *   ***  }

* * * * * *     return 0;
}

Comments

Case 0: Wrong output

Answer 5

Hidden content!
#include **  * * **   * *** 
**   *   **  ***  * ***

int main(int argc, char *argv[]) {

**   *** *  ***  * char a;
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** *** ****** *   *** *  *  ** *   * * a++;
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***   *     **  return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 6

Hidden content!
#include   * *  * *     *
#include  **   *  * * 

int main(int argc, char *argv[]) {

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** * *  * *  ** return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  scanf("%c",&a);
          ^

Answer 7

Hidden content!
#include    * **    * *
**** ** *** **

int main(int argc, char *argv[]) {

*   **      *   int a;
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 * **        * * return 0;
}

Comments

prog.c: In function 'main':
prog.c:8:10: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int' [-Wformat=]
  scanf("%c", a);
          ^

Answer 8

Hidden content!
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int ****    argc, char **  *    {
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** * *     **  *  *  *   *  * **  else
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***  *      *   * * }
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**** *  *  ** ** return 0;
}

Comments

Case 0: Correct output

Answer 9

Hidden content!
#include<stdio.h>

int main(){
    char a;
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*** **    * *  **** * *        * *   * *** **** *  *   *  * 
    }
}

Comments

Case 0: Correct output

Answer 10

Hidden content!
#include<stdio.h>
#include<stdlib.h>
int main(){
int i;
     **       *  * **  **  * a;
**  *  *  ****   *  ** * * * **   * ***** * your input: ");
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**   *** ** * * *  *    **
}

//INPUT
//Enter your input: A

//OUTPUT
//Enter your input: A
//?BCD?FGH?JKLMN?PQRST?VWXYZ

Comments

Case 0: Wrong output