0 like 0 dislike
18.7k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m),找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 18.7k views

99 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* ** * ******* * ** * * * ** * *** * %d",&a ,&b );

** **** * **** *** ** **** * * i=a;i<b;i++){
* * ** * * ** *** * ** * * * * * **** ** j=2;j<=b;j++){
* * * ** * * ** ** ******* * * *** * * ** * * ** * * ***** * && i%j==0) break;
* * ** * * ** * * ** * ***** *** *** * ** * * *** **** ** * *** if(i==j){
* *********** * **** ** ** * * *** * ** * * *** * ****** * *** **** * * * * * ***** *
*** **** * ** ** * *** * * * * ** * ** ** * * ** ** * * *** *** *** * * * * * * *** ** **** ** * ***** * ******* *
* * *** * ** * * *** * ******* ** **** * * * * *** ** *** ** * ***** * * * * * **** ****** * ** *
* ** ** * * ***** * ** * ** * ** ** *** ** * ** *** * **** * **** * * ** *** *
**** **** * **** ******** ** ***** *** * ** *** *** * * **** ** * * * *** * * printf(" %d",i);
**** ***** * ** * *** ** ** * ***** **** ***** ** ***** * ***** *
**** * * ** * *** * ** ** ***** ** ** **** *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** ** ** * **** *
*** * * * ** * * ***
** ** * * *

int main()
{
int i,n,m;
****** *** * ** ** ** *
** ** * * *** * * *
* ** * * ** * *

{



** * * * * * * ****
{
*** *
***
}
* * ** *** *




** * * * * * ** ***


}}
0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * *** ** *****
* * ** ** *** ***
* *** ** * *** **

int main()
{
int i,n,m;
* * ** * * * ** * * ****
* * * ** *** ** ** *** *
** * * * *

{



** * ** * * ** **
{
** *
** *
}
*** * *

*


** ** * *


}}
* 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
**** ****** * *** *** ** ** ** * %d",&a ,&b );

** * * ***** *** * * i=a;i<=b;i++){
* *** ** * * *** * * * ** ** * ** * * * j=2;j<=b;j++){
*** *** * ** * * ***** ***** * ** * * ** ** * * **** * * && i%j==0) break;
**** * ** * **** * * *** * ** ** ** ** * ********** ** *** ** * ** * if(i==j){
** *** * ** ** * * * * * ******** *** ** * ** **** *** * *** * ** * * ** ** * * *** ***
* * * ** * * ***** ** ** *** * * ** ****** * ** * * *** **** ***** * * *** *** * *** * * * * ** ** * *** * * * * *
*** * * * ** ** * **** ** *** * * ** *** * ** * * ** ** * ** * *** *** * * * * * * * * * **
* *** * ** * * * * *** *** * * *** * ** * ** *** **** * **** * ***** *
** * ** * ** * * ** * * * *** * * ***** * * * * * **** *** * ** **** * *** *** * printf(" %d",i);
***** * * * ** ** * *** ** * ** *** * ****** **
** ** * **** ** ** ** * ** ** * ** **

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
* *** * * * * * ** * a,b;
** **** *** **** **** * * * * * %d",&a ,&b );

* * *** * * *** ** i=a;i<=b;i++){
* * *** *** **** *** * ** * * *** **** *** * j=2;j<=b;j++){
**** * ** * ** * * ** ** * *** ** *** ***** ** ** ** * * * * * * && i%j==0) break;
*** *** ** * ** * ** * * * * * * * * * * ** ** * ** * * * if(i==j){
** ** * ** * * * * ** * * ** * * * * ** * **** * * *** * * ** * * ***** ***** ** * ** ",i);
* * * ******* ** *** ** * *** * ** * * * * *** ** ** *
* * *** * *** *** * * * ** *** * *

* *** * * *** **
* * * * ** ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * ** *
* ******* **** *
int main(){
* * ** * *** *** * ** ** a,b;
******* ** * * ***** *** * **** * * * ** * ** ** ,&b );

* * * * ** ** **** **** * i=a;i<=b;i++){
***** ** ** *** **** *** *** * ** ***** ** *** ****** ** j=2;j<=b;j++){
** * *** **** ** * * * * **** * ** ** * * *** ** * ** * * * && i%j==0) break;
* ** ** ** ** **** ** * * * * *** * * ** * ** ** **** **** * if(i==j) printf("%d ",i);
*** * * *** * * *** * * * ** * ** * ** *
* * * * *** *** * ***** *
* ** * *** **** ** * * * ** *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
***** * * * ** ** * ** * m, n, divider, prime[100], cnt=0, i=0;

* *** *** **** * * * * * ** * * %d", &m, &n);

** **** ** ***** * * * = m + 1; m < n; m++)
* * * * * * **** *****
****** *** * **** * * ** * * **** *** * ** = 2; divider < m; divider++)
********* ** * ** * ****** * ***** *** ** *
* * * * *** *** * *** *** * ** * ****** ** * * * **** * ***** *** ** % divider == 0)
* * **** ** ** * **** * * * * ****** * * * ** **** ** ** ** **** ** * **
* * *** *** ****** * **** * *** *** * *** * * * *
* ** ** * *** * ** * *** ** ** ** * * * * ** == divider)
** ** ** ** * * * * ** *
*** * * * * **** * * *** ***** **** ******* * ***** **** * * * * *** = m;
* *** ** * ******* * * * * * *
* ****** * ** * * * *** *
** * **** ** * * *** * i<cnt;i++)
* ******* * * **
*** * ** ** * * ** * *** * * *** ** * * ** * ** ** ******* * prime[i]);
** ** * * * * ****** *** *** *** * * * * *** *** +1 < cnt)
* ** * ****** ** * ** *** * * * * ********* * * * ** *** * * * * * * * ");
    }

* *** * * *** * * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Nice haha
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* * * * * ** *** *** * ** *
*** *** ** * ******* ** * * * * * * * * * ** **
* * ** * * ****** ** ***** *** * * * ** * * * * * * * **** ***
** * *** * * * * *** * *** ** ** ** ****** *** * ** ** * *** * * * *
* * * * * ** * ***** ** * * * * **** ** * ** * * ** * * ** ******
* *** *** **** ** * * ** * * ** * **** * **** * * ** * *** * ** * ** ** * ** * * * ** ",i);
*** *** * * * ** *** **** * * * ** * *** * **** *** * * ** *** * ** * *
** **** * * * * ******* * ** * ** ** ** * ** * * * *
**** * * ** * * ** * ** * * * * *** **** ** *** * ** * * if(k==0){
* * ** * ** * ** ** * * * * ** ****** ** ** ** **** ** **** ***** *** ** **
** * * * ** **** * *** * * * *** * *** * ** * **** ** * **
** ** * **** *** *** ** ** ** * ** ***
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d *** ** ,&b);

for * ** * ** *
{
** * * ** *** * * ****** ** * is testing\n",i);
******** * * ** ****** j=0;
*** * * * * * *** * * ** = 1;
***** ***** ** * ** * * ** * (j=2;j<i;j++)
** ********* ** * * * *
*** * * ** * ** * *** ** * * **** ** ** * ** * **** ** * **   %d is mode\n",j);
** ** **** ***** * ** * ****** * **** ** reminder=i%j;
** * *** *** ** ** * * **** * *** (reminder == 0)
* ** * ***** * ** * ** ** * **
* ******** * *** * * ** * *** * ** ** * * ** * * * * ** * * * **** * **** * * ** *** ** *** *
** ** *** * ** * * * *** * *** **** * **** ** ** ** ***** ** * * *
** ** ****** * * * * **** ** * * * * ** *** ** * ** * * *
* * * * * * ** ** ** * ** ** *******
* * * * ******* **** ** *
* * * **** ******* *** (flag==1)
*** **** ** *** * * * **** *** * ***** * *** ** * **** * ** ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.58
©2016-2025

Related questions

0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13k views
0 like 0 dislike
93 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users