11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
7.8k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 7.8k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
*  *   ** **      **      *  **      *  %d",&a ,&b );

 *  * **** **   * *** * ****** * i=a;i<b;i++){
 * * ** * **** ** *     * * ** * *** *     **  * * **** j=2;j<=b;j++){
  *** * ****    ** *     *  ****   ****  * ** **   **      *****   **  ******  && i%j==0) break;
*           *  *** **  ** * **   **  ******  **    ** **    * *     **  ** * **  if(i==j){
       ***  **** *  *  ****   *     * *    * ***  ****** * *   ***     ** *** *     *  ** ***  ** *  *****
**  **         *** *****  *  *  **** * **  ** ****   * ** *       * *  * ******   ***  ** *  * *  **   * * **   **   *   * * **    *  ** * * *   *** *  
         * ***  *** **   ***  *  *   **  **  **  ** *   *  *** ***  *  * * *   ****     * ** *    * *     ***   **       **      ** **  * *  *
*   * *   ** ***  **     * * ****   ***   **  * * * ***  ***   ***  *  ***   * ** * *    * *******   *** ****   *****  **
   **    *   **  **   * ****  *      **     *  ** **  *        ***** *  * *    * *  ***  ** ***  **** *  * *   printf(" %d",i);
    *  **   * **** **  **  ** **** *    ** *****   *  ** * *   * **** **** *  * * *
 *   ** ** *  **   ** **   *  *  ***  ***  * *   *******   ** 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***      ***  *  **
   **    *   * * **  * *
 * ***   * **   ***** * * 

int main()
{
int i,n,m;
* * *    * **** *  * ***     *
*  *   * *  *    * ***  
****   ** *   * **  

{



 * **** **  ** * * **  
{
* *     
*  **
}
 **** *   * *

 ***


*   **  ** * *  *    *  *  


}}
* * * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
    * * **       *
 * **   ** * *  ******
    * *  ** *      **

int main()
{
int i,n,m;
** **     ***** ********** **
  *  *  *  *   * *      ***
 * * ** *  *** ** **

{



  * *** ** * *  * *  
{
* **  **
 *   *
}
 * ** *    *  *

 ***


   * * **   **    *   *


}}
**  0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
*  ** * **** * ** ** *   * *  *   ***      * %d",&a ,&b );

     *  ** *   *      ** **** * i=a;i<=b;i++){
 *  * * *   *  *  **  * * ** * * ***   * **** *   *   * *  * *   j=2;j<=b;j++){
  ** *** ***   * *  **  ** *** ****   ***   ***  *   **     * * * *  **  *  ****  ** && i%j==0) break;
   **   * ***    *   *   ***    *     * ** *   **  *   **      *  *****  *  **** **  * if(i==j){
* * ** *  ***  **** **    * **  * ***  *   ****   **   ** *   * * ** *  * *** *  *     ***   * * *  **** **  ****  **
 **  * ***     *      * * *  *****  *   *  * * * ** *  ** ** *   *  **** * ***  *  *  * * *** * **  * ****  *** ** * * ** **  * ** *    ** * ***** ****** *
** **    *   *  *   **  ***     * *   * ******  ***    *****     ** **   *  * ** *  ** * *** *  *** * * * ** *   * *     **  * *  **** *
*** **   * ** ****  *     **** * *     ** * ****** ** ** **  *    *  * *  *****  *  ** **  *  * *   ****** * * ***
*    *   *** * * * * ** *  * **    **    *****  ** ** ******* **        *** *  ** ** **  * ** * ***   *  printf(" %d",i);
** * * ** ***   *  * ***       *** ***   **  **  *** *   ***    * * * ** ** 
***** **  **   ****  **  ** *   *   * ** *******  * *  ****

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
*  ** * *  **  **** * ** *** a,b;
*** **  ****     ** *  * * *   * *** *   %d",&a ,&b );

*    * * **  *   **  ****** **  i=a;i<=b;i++){
 *** ***    *       ** *** *   * *  *   * * *  **  *    **        ***  j=2;j<=b;j++){
*   ******  *** * *  ** ***** *   *  *** ***     ** * **   ******** *****    ***     && i%j==0) break;
* *   ** ***   * ** ***   ** *    **  ***   ** * *********  ***   * * *    ** * ** * ** if(i==j){
  *** *   **  ** ** ** * ****** * *******   * **   ***   * * ****** **** **********   *  ****   *** *   *****  ",i);
**  *  * **  **   *** * *     * *   ** **  *****    *  * ***    *** * *  *  * **     
 **   ****  ** ** *  **** *   ******* * *  **  **** * 

 **** *  *   ****** *** 
  * ***  ** *** ***     * **  0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  * * *****  * ** *
  ** *  ****  ** * *  
int main(){
** *** ***  *  *    * * ***  a,b;
*  * ****         * **  **** ** * ** *    *  * ** * * *     ,&b );

* **  * ***    ** *** *  *** **   i=a;i<=b;i++){
   **     ***  * *  *** **** *   *  *** *** **  * * * j=2;j<=b;j++){
  * ***** ** * **  *  * * *** ************  * ***  *** **   ** ****  *  *****  * *** && i%j==0) break;
  ** *    ** *   * ***  ** ******* ** ** *** *  *  * **  ****  ********   *  *  *    if(i==j) printf("%d ",i);
* ***    *   ******  *        *   *  ** **  ** *    * *** **
 **    ***  ** * * * **  **  
*    ** **   ** **** * *  *    0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* **     **  ** * ****  *** m, n, divider, prime[100], cnt=0, i=0;

*  ***  * * * ** *     * *     *     ** %d", &m, &n);

*****  ***   ** ** ****** *  **** = m + 1; m < n; m++)
**  *** *** **     **   * ** * 
 **     *   *******  * *   *** ** **  ***********   **  **  ** * = 2; divider < m; divider++)
  ** ** ** *    *  **     ***  * * * * ** * ***** *
 *** * ***** *** **  **** ** **   * * * * *   ** *   ** **       **  **   *  % divider == 0)
* * **  *****  *** *  **   *  **     *   * * * ** *    **  *  *  * **       **  **      *** * ***  **  ****  
*** ***  * * *** * **** *** *   ** *   ** **      ***   * 
      *  *   **  ***   * **  **** *  *  * ** *        ***  == divider)
** * * ** **   *     ** *** ** * * **** *   ***   ****
***   **** * ****  *   *  *  * **  **         *   *    * *    **    * *  ******   * = m;
  ***    *  * *  ** *    * ***   **  *   ****   *
* *     ** * **** *** *****  **
*****   * * ** **   ***   *  i<cnt;i++)
 **  *  * ***  * ****  ***
******* **  ** **  ***  ***  * *    *     * **   **   ***  **    *  ** * **  prime[i]);
*     **  ***  **        *   ** **  ** *****   ** **  *     ** +1 < cnt)
**** *** * *       *      * *  *** * **  **** *     ** *  * *** *      **** ** ***  *   **  ********   *  ");
    }

****      *  **** ***** ***  ***  0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
** **** *   *  *    *** ** * *   * * *  *
   ***** *****          **** ** *  *  * ** ** *****     *  ***   
***  * * *  * ***    ** ***   ***** * **** ***** ** ***    **   * **** * ***  * *  *
**    * ** ***** * ** **  * ** ***** ***  ***  *   *     ** * ********     *      * *  *      *   
** ***   *** ** * *******  *    *   *   ***   ***  *  **    **       *** *** *  *  *  ***   **
  *  ***** * *   * ** ******** ** ** **        ** ******* ****  *  * *** **   * *******   *  * *** * ***** **  **     *** **   ",i);
 **   ********* **    *   *   * ***     *  *** *   * ***  *   * *  ** ** ****  *** * **** *** *** * * * 
* **** ** * **   *    *  ********  *   * **** ***** *  *  *   **   * ** **    ** *  * ****  *
*       *    * **   **  * **   ****** *   *   * *** **  * ***  **  *** ****    *     **** if(k==0){
* ****  **** *    *** **   * *    *   *    **    **   *****  **   * ****     * *    ***   ** *  ***   *  * *   ***
 **  ** *  ******** * **** * *   * ***  *  ***  * ** * * * * ** **  ** * *  ***  ** * * *  
     * ** *  ****** *   *    ** *  *** ** *  * ****  *   * **   *
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d    ** * ***   * ,&b);

for  *   *   *****  * 
{
         *   *** **       ***   *   *  *   **  is testing\n",i);
  * ***  ** ***    **** *** ** j=0;
*******   * **   *  ** ** ** * ** = 1;
* **  * *  ***** *** *   ***** (j=2;j<i;j++)
 *    * ***   * ***** ****   *
  **     * *    *** *         **** **  *  ****** *   * **  *   **    %d is mode\n",j);
  * **     **  ** ** ** * * **** * *****   * ** *  *  reminder=i%j;
*  *****  * ****   * ***   ** **  * * *   * **  * *  ** (reminder == 0)
 *** ***   *   **   ** *  **  **** ***** *   ***
*   * **   *** *    ***** * **    *  **** * **       *   * * ** ***  *    *******  **  * * *   ** *  *  *  ****** * *  *   *****   
** * **  ***  ***   ***** *** * *   **   * *   *** ****** *  *  *  **  **  ****   **   
 *   * *** *  **   ** ******* ** ** ***   * **   ****  ** *    ***** * * *   * *** * 
 **** *   **       *  ** **    **** *   *  * *  *  *   *
**   **** * *    **  *  *     
 * *** * *    **** ** **  ** (flag==1)
*     **   ***  * *****  * * ** **   *** * *  ** *** * **  *  **   **  ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.144
©2016-2024

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 5.3k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 6.6k views
12,783 questions
183,443 answers
172,219 comments
4,824 users