11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
11.4k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 11.4k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
*** ** **   * ** ****       * * ** *  ** * %d",&a ,&b );

 * ** ******   *** * * ***      i=a;i<b;i++){
  * *** *   ** *  ****  *  ** ***  ** **** * ****  * ***** *   *  j=2;j<=b;j++){
** ** * * * *   *     *   *  **    * * ****     **   ** * *     ****  ** * ** *   && i%j==0) break;
  ** *  *   * * *  **  **  **    * ** *  ***********     * * *    *  *  **  ****   * * if(i==j){
 *****  *  ** ** **   * * *   *****  * *    *    *       ***   ** ** ****  ** * * *  *** * * * **   *  
*  ** *  * **** * ** *** * *    **  ** ** **** **      *** *** *  *  * * *   * * * ** * * * *** *    * *   ******* ** *  ***  *   ****   ** *** ** ********  * ** 
   *  **     **  *  *** **    ** *** **  *    ** *  **   ****         * * *  * ***  **   *  *      **  *  *   ***   *  **   * ********  *
*** * ** *** *   **       *    **      * *  * **** *** **  ***  **  * * ***   **     ** ** **  ** ****      * *  *    
*  *   *      * **  *  ***   * *** * ***   *** * *  *** * **** **    ** * *********  *       * *  *  **   *  * printf(" %d",i);
   **    ***** **   * * **      *    **** **** *  ***   **** **   * * ******
* *** * **** * *  ***  ***  ******* * *   * ******* 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* *  *** * *** * *
**** ***    ** *  *    * *  
  *  *** * *** *** * *

int main()
{
int i,n,m;
** **  *  *      *   * **
  **** *  *  *  ** * ****  * * 
   *** *  *** *  

{



*  ***** * * *  ** *   *
{
** *    
  *  
}
****** * *** **

   *


 *** * *   **  *** **  *** 


}}
 *** * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***  **  * *  
* **** ***      *****  
***    * *  ***   * *

int main()
{
int i,n,m;
     * ** *      ** ** ** ***
** *   *  * *** **    *  *
**  * ** **  * ***  

{



* * *   **   *  ***
{
*  *   *
  *** 
}
  ** ****** *   *

 *


* * *  **  *  ****   


}}
***** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* * ****    * * **** * **  * * * ***  ** %d",&a ,&b );

 ***   **    ** ***     **   * **  * i=a;i<=b;i++){
***    *  *    ***  *     * *     ****  *  *  ***  * j=2;j<=b;j++){
 * *****  *****  ** ***       * * *    * *********  *   ** ****   *  * *  *** * ***  *    *  && i%j==0) break;
**   * *  **** *  ******* * * ****** * * ****    *   * ***   *  *  ** *    **        ** * * if(i==j){
**   ** ****      *  * *  *      ** *   * ** * **    *     * ***  *   **  **  * *  *** * * **** * ** **   *  *  ** 
 ** ***   ** *  ** ** * **    **  * **  *  * * **** *   ** *     * ****** * ***   *   * ***  * ****   **      ***** * ** **** * ** *    *  *** ** * * *  ***  
* ***    **  ** *    *  * *** * ******* *   **   ***           *** *    ** **  ** *    * * * * *  *  *     *** * * **  *   * ** **      ** **   ** ** 
*** **  ********  **   *   * **   **    * ** *** ****** * ****  ** **   ** *******       *  *****   * ** **     
***  *     *****  * * ** **** * **   ***   **   *      *   *** ****  **  * *   **** *      **   **      printf(" %d",i);
* ****    *  * ****      * ***     * *** *     ********* ****  *   * *    *   * ***** ** ***
 * * *** * * * *    *****  **** *  *   *  ***** **** ** 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
*  * * *  **  ** ** *** *   ** *  a,b;
*  *  **   *  * ******** *  *       *  %d",&a ,&b );

* ** * ***** **  ********* *  i=a;i<=b;i++){
*  * * ** * *  * **** * **  *   *  * **  ***    *  *  j=2;j<=b;j++){
*  *******  *     * ***      *   ***  *  *         **** **  * *****    *    **     * **  && i%j==0) break;
**     * ***  * ** * **  ** *  ***  *  ** **  * *  *** * *** **   * *    **  *    ** * if(i==j){
*  *   **  ***   ******   ****   ***     ****  *  * *  ** ******  ****** *  **   *****   *** **     ***    ***  ",i);
* ***    *  *  * ******   ***   *** *   *  * *   * ***    * ***** *** * * *  ** * 
* * * * * *** * * ***  ** *  * *  *  *     ***   **   

* * *     *****  *  *   
***    *  *  * ***       *  *   0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *********** ** *
*  **** ** *  * * 
int main(){
    *  ****** **      ***** a,b;
  * ***** *    *      *  ******* * *** **    *  * **  **     ,&b );

  * * * *   *  * *        * ***  i=a;i<=b;i++){
 * *    *  **   *** * * * * *  * *****  ** *    * **  *   j=2;j<=b;j++){
  **  * ** ***      * *   *        ***  * *** *** * ********  ***  ** **     * *    * * *   && i%j==0) break;
*  *   * **  *  ** *  **** *    **** **** **   * * * ***   *** ** **  * ** * * ****** if(i==j) printf("%d ",i);
 * *  * ***  ***  ** ****   ** *** ** *    ***  *   ****
*    *  ** * * * * *   **
*  ********* * ****  **    ** ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    **    *** *  *  *  *    **   m, n, divider, prime[100], cnt=0, i=0;

   * **** **** * * *** ** * *  ** **       *  %d", &m, &n);

  **** *    ** *** ****    * * * ** = m + 1; m < n; m++)
  **  *** *  * ** *** * *** *
  *  ** ******* * **  ****   ** ***  ** *** **   *** = 2; divider < m; divider++)
*    *   ****** ***   * ** * ****   * *    ** *   *** * *  * 
 *** *** **  *    * ***  ** * **** **         *    ****** ******     *****    *  % divider == 0)
* * *  ***  *  *  *   *     *  **** **************      ** *  ***** **  *  ** ***  ***** **  * *  **      * *    * 
 ******* ** *****  *  *   ** *   *** *   ***  ** * * *
**  ******  ***** * * ** **     *** ** * *** **     == divider)
  *   **** * *  * *** *  **** * ** *   *  *  * * *** * *  
**    *     * *** **  * *****        *   ***    ** ********** *    *** * ** ** *  *** **     * **  = m;
 * ******* *        ***** * *  **   ** *  ****** 
*     *   ***     * * ****  
 * * ** **   *  ** *  * *    ** * i<cnt;i++)
   * * ** ***  * * ***    ****
* *   * *  *  * **** * **  *   *     * * *   *** ** **  ** ** ** **** * prime[i]);
*  *  **  **  * **  ***** *** * **  * *   **  ** **    *** ** +1 < cnt)
         *****  *  ** ** **  ******* ****  *  ****     ** ** * **** *    **  *  ****      * *  ");
    }

 * *** * * * **    *    ****  * *  * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
    ******* ** * *** ****** *   *  * ** **
 *  ****     *   **  * **     ******     * *   ** ***    **  *** ****    *****  * * 
  ********  * ***  **** **** * **   * **  ****     * *   **   *  ****       **   **   
 **   ***  ** ***** *  * ********* **    ***  ** ** ** * ** * * * * *  * **   **   * **  *   **
  *  * *** ***** *     *  *   *   ***         **    * **** *** **   ** ****      * 
 ** ** **   * * *** *   ***    *** ****     **   * **     * *    ** *      ***   * ** *  **  **** * ** * *** **  * ** *   *** ",i);
**** ***** **** * ***  **** ***    * *  *      ***   *      * **  *  **  *    ***   *   *    * * * *****  *
*******     * *     * ****  * ******* ******   *    *  *  *    *   ***  ** * **
*     * * * *  **  * *  ****  * * **    * * ** *  * *      * ******* **** * * *  ** if(k==0){
 * * **     *     * *** *  * * *    * ***  *  ** *  *****  * ** ****   * * *  ***    ***      * * *       *  *  * *  *   ****
    *   ** *   *****  * *     ***    *** * *** * * ***    **  *  *  * * * ** *
   **   *   ** *  * *  *  *** ****  *  *    *   * ** ********
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d * ** ******  * ** ,&b);

for ** * **** * ****
{
  *  ****  *** *  ** *** * * * * *   * is testing\n",i);
 **** *   ** * *  * ****   **  j=0;
 ****** ****  *     * *** *   *   = 1;
***  *     *   ***  ***  * *  **  (j=2;j<i;j++)
** ** ** *     *   * ***   **
* *  *   ***  *  *  **  * ****** *   **      *    *   *****  * ******   %d is mode\n",j);
 **  ** * **   ** *  ** **     **    ***       ** **  ** reminder=i%j;
* * **  * *  ********     ** *****  **    ***   *** ** *  (reminder == 0)
***     ***   * *      * **   **  * * *     * 
  *******  ** **  ** *   * *  **   * ** * * ** *   *** **** * * ** ***    *  ****   **   ** * *  ****   * *** ** *  *  ** 
 ****     ******** *  ***    * ** *   **** ***** * **    ** *** **   * *  **  *  ****** 
*  *   * * ** *  *  ***        *   **  *   ** *  ** * **  *  * ***** *** * * **** 
********  **  ** * *   **   *    ***         * **  ** ** 
   * *  * ** * ****** *
** ***    ** ***  *  (flag==1)
 ** * *   *     *        *  *    ***  *  *      ***  *****  **     ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.27
©2016-2025

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 7.7k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users