11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
17k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 17k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
  * ****   * ** *  *  ** * **** *   ***  %d",&a ,&b );

  *   * *   *** ***** **  i=a;i<b;i++){
*  *  ** ***  *  **  *     *** ** * *   *    *  ***** ** ** ** * j=2;j<=b;j++){
* * * ***   ***   *    ** ** *   ** * ** * * ***  *** * *   *      ** * ** *  * *   *   * * && i%j==0) break;
 *** *  *    ** ** ** *** ****  ** ** *    **** *    * ***   * ** *****  **  ** **  *** * * if(i==j){
       * **  ****   ** ** *** *    **  * *   * * **  * ** ****** *     *  * *    *  * * ** *    *****   *
 *  ****  *** *  * *  * **  ***  * ***** ** ** *  * ** *  * **   ***   **    * *  **  * * * ** *      **  ****    **  *   *       **** * ************   *  
  ****** *  * ***   * *  ***      * *   *    *   ****     **   ** * ** ** * ***** *   ** *     **** * ** ***** *     * ** ** **  ****   *  **** ** *   * * 
  *   * **  *****  *****   ***   *  ***  **   *  *    ****  * * *   ****    **  *** * *  * *  ****** *   *   *    * *  * 
* * ** ****  *****  **     ***   *   *  * *  **  * **   ***** *      *  ** **** *  ** *** **** **** *   * printf(" %d",i);
    *** ****    *    *** *   **  **   **   *  ***     ****** *  ** **   **** * 
*    ** * ** *****     * ***   *       *  * ***  *   * *  * 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  *  *  ** * *****  
  ** * ** *********  * * *
 * *  *  *  * ****

int main()
{
int i,n,m;
* **** **    * **  ** *  * * 
**    ****  **  ***  * *  
* ** * *   ***  *

{



 *  * * *   *****    
{
***  **
**   
}
** *  ** * * * *

* **


 **** *   * ** * ***  ***  **


}}
** * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
    *        * ***  ** 
  *  ***      **     *
     *  ***  *  * * *  

int main()
{
int i,n,m;
**   *****  ** *     **
 ** **  *  ******* ***    
   **        *  *  **  

{



  ***  ****    * * **
{
** ***   
* * *
}
    **      *   

  **


**  ***  ** ****  *** * * ***


}}
 ****  0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
****    *** **     *  ****   * **  ** **   * %d",&a ,&b );

* *  ***  ** * ** *** * **** * * i=a;i<=b;i++){
    **    ***  **   * ******* ***  ****   *  *  *** ****  *  * j=2;j<=b;j++){
*** ** * *     ***  **** *   ** *******    *     *  ** *** *  *  *          *** ****   && i%j==0) break;
* **    * *** ** ** ***  *  ** ** *           * *   ***    * *   **  *   * * * if(i==j){
* * ***   *   **       **   *****  ***  *    * **   *** **  * *****   *  *  *   ** *  *****   * * *****  * * * *** *
***   *****    *** *** *  ** ****** * ** *      *   *** **** *****    *  ** * * ** ****  * *   **  *      * **   **    ***    *  ** *  * *   * * * * *     *   *
*  *  ** * * **  * ***  * *  ***       ***  *       **   *** ****  *** *   **  ***  * *  *      **   *****  **  ***** ** * *      ***  * *  ***  * *
 *  * *  * ** ** ** **** *  *   *** *  **  **  ** *   ***  *     **** *  **   ** *** *** *    * *   ** * * *       
   * ** **  **    ****  *   *** * ******** *   * **** *** ** **** **    * **  ***  *    *****  *  ** ** * printf(" %d",i);
    *** *  *   ** * **** *  *  * ****** *   *  ** ***  * * * ***  *     *     
**   * *  *****  *****  *    ***     *  *  ***   *  ** 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
   ** ** *  **  ****    * ***        a,b;
 *  ****** * ***    *** * *  **    *** ***  %d",&a ,&b );

** * *    ** *   * **  *****    i=a;i<=b;i++){
 * ** ** **  ** **** * * *  ** **       *  *** *****     * j=2;j<=b;j++){
*         ****  *   **   ** ****** *   * * * ** **  ** *  * **** * ****  * *     *  && i%j==0) break;
  * *  *  ***** *** *  *   **    * * * *****   * * *  *  * * * ** * ** *** if(i==j){
* ******  * **  ** ***      * *  **** ***  *    ***  *   *** *  *     *******  ** *    *****    *  * ***** ***** **  * *  ",i);
     *     * *  *    * ** * **  * *   ********* ** *  *    * *** ***** **  ** * *
 ** ** * *  * ***   ** ****  **  ***** * *  *  ***

*** * **  **  ** **** *    
 **  ** * *******    *  * *    *   0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* *  *     *   * ***** 
***  *     *** *  ******
int main(){
* ** **** **** *** *** ***  * a,b;
    ** *** **   ****  * *  **** ***  **  *****  * *  ****** ,&b );

 ** *** * *  * ** * *   *  * i=a;i<=b;i++){
 * ** ***  *******  * **  * *****   * *** *    ***   ***    * j=2;j<=b;j++){
* *  ** *  **  *  *   *    *** * *  * ***     *  *** *  *   ** *  ******* ***   && i%j==0) break;
    *     **   *    ***     *    ***  *   **   *  *** * ** *** * *    ** ***  if(i==j) printf("%d ",i);
** ** * *   *  ******** ***  * * * * *       *  ** * 
  * **   **      *  *   **   *
* ** * **  ***  *   ****    * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 * *  **** * *****    ***  * m, n, divider, prime[100], cnt=0, i=0;

 ***  ** *   * ** * ** * ***     *  *****  %d", &m, &n);

*  * *  * ***** * ** ** * *** *   = m + 1; m < n; m++)
 * **  **   **  ****    * 
**** ****  * *    ** *****      * ** ******  **   **  ***   * = 2; divider < m; divider++)
 ***** **** ****  ****    *   ** * ***   ** *  **  ** *  *
*       * ** *** * ***   **  *** ** **  *     * **** *** *          ****** * ******* * % divider == 0)
 ****   ***  **  *  ****  *  *     * *  *  * **  *    *** ** * **   * *    *   * * *   * *  *    ** * *   * 
*******  ***   ******* ***       *  *** * **  **     
****** * * **  * ** **********  ****  ** *  *       ** **    == divider)
*      ********       ** ****   ****  ******* **** * *  * 
   ** *  ** *  * * ***   *   *  *  * **   **   ** *** *****  ******    * * * *    *  ** = m;
 *   * * ** *    * * ** *  *     *   *** *    *
  **    **** *  * *  ** **
****** **** ** * **** **** ***** i<cnt;i++)
   ******* **  **   ****** **
  * ** ***  *   ****     *  *  *     **     *  ** ****   * * **  **    **  * prime[i]);
  **  * *****  *  *   * ** *     *  ** * **  **   *    +1 < cnt)
*** * ***   * *    ****    *  * *********  ** ** **** ****** ****  ****  *   ** *** ** ******** **    * ");
    }

**** **  *  *  **  ** **  ***  ** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
*  **  *** **********  ** ** * ****  **   
**** *  ****     * *** * ***  ** ***   *  *  * ** * * ** *   *  ***    
** * *   *   * *   * *  * ** *   ****  * * **** **      **   **   * * * *      ** ** **   
* ****     *  * **** * *   **********  **** **    * ** ** ** ****    ** ***   *****   *** **  *****      *  * **  
****   **   **   * *  ***    *****  *   **  **   *  *  *  **     *  **     **  * *  * *  
***     * * * ** **** **     * *  ****    *** *    **** *** *  * ***   ** * **** ***   ***   ***  *     * *     ** *  *  * * **** ",i);
   *   ** **  *** **  *  * * ****  **    ********   * ***        **     *****  * ** *  *    ** * *  * 
** * *    * **  * ***    * * **  **   ** * **   * ****  ***   * ***     *  *
* ** *  ********* *   ** * ****** **   *   ***  *   * **  ** ***** **    ***** ** if(k==0){
*  **    *     *   * **  *** *** * **  **** **     * *  **   ***    ** *  ******* * ** ***    * *   * *     
 *****   *** *** *    ** **        **  *   ***** * ****** **   *** **  * ***** 
*     * **  ***** * ** *  *   *  ****  *** *** ***   ****
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d  ** *   *  ****   ,&b);

for ***  *** **  *  
{
*  ** *    *   * ** *     ***** *  *    ** is testing\n",i);
   **     *  ** *  * *** *   j=0;
**** ***   * * *  * **  ***     = 1;
** *      ** *  * *** *** ***  (j=2;j<i;j++)
**** ** *  *** **  * **     * ****
***   **    * *  *  * *   **    *  ***  * *****    *  *** *** ****   %d is mode\n",j);
   ** * **** *  *  ** ** * ** * ***** * *   **  *  *      reminder=i%j;
******  ** * * ** *** **      ** *  *  * ***  **   *******   (reminder == 0)
    **  *       *   ** ** **** *    * ** **     *  * 
* **   * ***    * **  *   *   ** ***    ** **** * * **   * * *  *    ****   *******  * *  **  * * ***   **  ** *  **   ** * 
****  *   **   ** *   *****          ** * * ** ** *  ** *    * ****   *         * ** 
* * * * * *   ***    ***  * *       *  *      *  *  *** *   ** * * *   ****  *  *  *** **
*****   *   * **  *    * *****   *    *  **** * *  
***  ***   * * ********* *  *   
** ***** * * ***  *** * *** (flag==1)
** ** *    * * *  ***    ** *   *    ** *****   ********** *** ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.79
©2016-2025

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.6k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14k views
12,783 questions
183,442 answers
172,219 comments
4,824 users