0 like 0 dislike
22.8k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m),找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 22.8k views

99 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* **** * * * ** ** ** * * %d",&a ,&b );

** * ****** * **** * ** i=a;i<b;i++){
* ** * *** ** * ***** ** * **** * ** ** * * * *** j=2;j<=b;j++){
** **** *** * **** ** * *** **** **** ** ** *** * *** *** && i%j==0) break;
* ** * * * ** ** ** ** * * ** ** * *** * * *** *** * * * ** if(i==j){
** * *** * *** * * * * ** * * * * **** ** * ** * ** ********* *** * *** * * * *** *** *********
* * * * * * * *** * ** * **** ** *** ** *** *** **** * *** ** ***** * ** * * * * * * * * * ** * ** * ** * * ** *
** * * * * ** * * * ** ** ** * *** ** ** * ******* * * * * ** *** ** * * * * *** * ** **** ** *** * *
** ***** *** **** ** ** * ****** * * * *** ** ** * ***** * ** * ** * ** * * **** ** * ** ***
* ** *** * * * * * ** * * * ** ** *** ** ** **** * *** * ** ** ** * * * ** ***** ** * printf(" %d",i);
* ********* * **** *** * *** ** ** * * * ** *** *** *** * * *
* * * * * * ****** * * * * ** **

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * **** * *** * ***
* * *** ** * ****
* *** ***** * * *

int main()
{
int i,n,m;
* ** * ******* * *
* **** ** *** ** ****** * *
* ** **** *** * *

{



* ***** ** ** *
{
* ***
* *
}
** * ** * * *

**


* **** ** * * **


}}
*** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** * *** * **
** * * * * * ** *
**** * ** **** *

int main()
{
int i,n,m;
* * ** * **** * ** *
* * ** *** ** * ***** **
* * ***** * * *

{



* * * * **** * **
{
***
** * *
}
* * * * * ***

*


* * * ** * **


}}
**** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
*** ****** **** * * * ** * ****** %d",&a ,&b );

* *** ** **** *** * * * i=a;i<=b;i++){
***** ***** * ** ******* ** *** * *** * * * * ** j=2;j<=b;j++){
**** **** * * **** ** ** *** ** *** * ******* * * *** * * && i%j==0) break;
** ** * *** * *** ** *** **** * * * * * * ** **** * * * * * * ** * * if(i==j){
***** *** **** *** ** ********* * * ** ****** ** ** ** * *** ** *** * * * *** ** * * ** ** **
* ** * *** *** * * ***** ** * * * * * * ** ** ** ** *** ** ** **** * * * ** ************ * * * ** ** * ** * * **
*** **** ******** * ** ** * * * * * * ******** * *** * * * *** * * * * *** *** ** *** *** * ** * * ** * * ** ** **
* ** **** ****** * * *** **** ** ***** ******* * ** * * * ** * * ** ** * *** **
** * **** ** *** ******* * * * * **** * **** ** ** **** * * *** ** * ** ** * *** ** * printf(" %d",i);
**** ***** *** * ** ** ** * * * * * ** * *** * * * * ** **
* ** * * * ** ** *********** *** *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
** * * * ** ** * * a,b;
** *** * * * **** * ******* * * %d",&a ,&b );

* **** * * * ** ** * * * ** ** * i=a;i<=b;i++){
** * ** *** * *** ** * ** ** * * ** * * ** ** ** j=2;j<=b;j++){
*** *** ** * ** * * ** ** *** * *** ** ** * * ** ** ** * ** && i%j==0) break;
* * * * * ** * **** **** ** *** * **** * ** ****** if(i==j){
* * ** * * ** * * **** * ****** * * ** *** * * * * **** ** ** * * ** ****** ** * * * * ** ",i);
* * ** * * * ****** * * *** ** * * ** * * **** * * *** ** * *
* ** * ** * * * * * * ** * *

* * *** * ** * *** * *
**** * ** ** * *** **** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** *** * *
* **** * * * * * * *
int main(){
* * **** *** ** ** * * a,b;
** * *** ** *** ** * * * *** ** **** * **** * * ,&b );

****** * *** ****** *** * i=a;i<=b;i++){
**** ** * * ***** ** ** ***** * * *** * j=2;j<=b;j++){
** ** * ***** ***** ****** **** * *** ** * * * *** *** ** ** * ** *** *** && i%j==0) break;
* *** ******* * * * * * * ** * * * * * ** * * * * * ** * if(i==j) printf("%d ",i);
* * *** * * * *** ** * ***** * ****
** * * ** * * ** ** * *
** * **** ** **** * * * * ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** ** * ***** ** * ** ** * m, n, divider, prime[100], cnt=0, i=0;

** ** * * * **** * * ** ** ** %d", &m, &n);

*** * * ** ** * **** *** * * = m + 1; m < n; m++)
* ** * ***** **** *****
******* * * * ** **** * * ** * ** * ** * = 2; divider < m; divider++)
* * * ** ** ****** * * ** * * ** * ** ** * ***
** * ** * *** **** *** * **** ** * * * ** * * **** * * % divider == 0)
* * * ** ** ** * ***** * * *** *** ***** * **** * ** * ** * ** **** ** ** *
* ** *** * ******** *** ** **** * **
* ** ** * ** * * ** * * * ** * * **** ** == divider)
*** **** * ** **** *** ** ** ***** ******** *
* ** * ******** ** ** *** ** *** * * * *** * * = m;
* * * ** * * * * * * ** * * * * * * *** *
* **** *** ** **** **
**** * ** **** * * ** i<cnt;i++)
*** * * ** * ***** ** **
* ** ** * * ** * * * *** * * ****** ** * * * * **** * * prime[i]);
******* ** * *** **** * ** ***** * * ** +1 < cnt)
* * * * ***** * * * * ** *** * * * * *** * *** * * * *** ** * ****** ");
    }

** * *** * * ** *********** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Nice haha
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
*** *** ** * * *** * **** * * *****
* ***** *** *** * * ** *** * * * * ** *** *** * ** * **
*** * * * ** * ** *** * * ******** * * *** * * ** **** *** ***** **
* *** * * ******* ** ** **** * * *** * * * * * **** * * * * ** *** ** **
*** * * ** * * ** ** * * ** ** * *** * * ***** * * * * ** * **
* ** * ***** * * ** *** ****** *** * **** ** * * * ****** * * * ** ***** * ** * * * * ",i);
* * * ** *** ** * ** *** * ** * **** * ** * * * *** * * *** ** *** *
* * *** ******* * ** * * *** *** * **** * **** *** ** ** *** * **
***** * * ****** ****** * * * ** * * * **** ** **** ***** * ** ** if(k==0){
*** ****** * ** * ** ** * * ** ***** * *** **** ** ** ** ** **** ** ******* * ** ** * *
* * * *** * ** ** **** * **** ** * * * * *** * * * **
* * ** ** * *** * ** * * *** * * * * **** ***
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d ** ** * ** ,&b);

for * * ** * ***
{
* ** ** ** * * ***** * * ** ** * is testing\n",i);
** *** ****** ***** ** j=0;
* * * * *** * *** *** *** * = 1;
* * * **** *** *** ** *** (j=2;j<i;j++)
* * * ** **** **
* * * ***** * **** ** * * ** ** * * *** * *** **** *** *   %d is mode\n",j);
** * ** *** ** * * *** ** * ** *** ** * * * reminder=i%j;
* * * * ******** * * ** * * *** ** ** *** (reminder == 0)
* ** * ** ** * * **** **** * ****
* * * * **** * ******** ** ** * * ***** *** * ** * * * *** **** * ** * * ** * ** ***** * ***** * *
* ** ******* * * * * * ** *** ** *** * * ** ** **** * * * *
* ** * **** ** * ** ** *** **** * *** *** **** **** * * * *
** *** * **** **** * * ** *
************ *** * ** ***
** **** * ** *** * (flag==1)
**** * ***** ** *** ** ***** * * ** * * ** * * * * ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.165
©2016-2026

Related questions

0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.6k views
0 like 0 dislike
93 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 19.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users