11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
17.1k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 17.1k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
  **  **     ***** ***      ******  *****    %d",&a ,&b );

*  **  *** * *  ****  ****  *     i=a;i<b;i++){
 ** * *** ***   * *  *  *    * *********   ****** *   *  ****** * * *  j=2;j<=b;j++){
 * **   **  *** * * *  *   ******* *  *     * *** *  *****  ****     *** *  * *  **   * && i%j==0) break;
 * * *** * *   *******  *  ** *****  **  ** *** *    ******** *** **    ** *  **      if(i==j){
** * **   * **** **    * ** * *  *   *  *   * *  *  *** **  ** ***   * **  * * ** **   **** ***  * **   * *  **
 * *  * ***    ** * *     * * ** *     *   ** *** **** *  **  *** ***  *  * * ****  *   *  *   *** ****** * **    ***   **    ** * *  *  ***    **** *****  
    ** * * *    ********** ** *  *** *   *** ** **         *** **     * ** **  ********     * * *  *    **   * **   *  ** **   **** 
  *****  *   ** * ******** * *   ** ******  *  **   * **   ***  * ***   ***  ** * **   ***    **  *** 
*  *         * **  * * **  * ** * **   * ***  **  *   ****  **** * ********  * ***** *** ***  ** * * *    **  printf(" %d",i);
******* * ** *    * *  ****    **  ***  ****  * **     *  * ******* ***    **** * 
 **    * *   **      * *  **** * *** * ** * ***       * 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  *   **** * **  * **
*  **  ** * ***  *  *
   * *  *  *  *   *

int main()
{
int i,n,m;
** *  ** **   **   * **   ***
* ****  *** *** * *** *  *** 
  * ** * * *   *  ** 

{



** **  *  **** *    *
{
    *
* * 
}
*** ***  ** ** 

 *  


*  *   ****  * * * *** 


}}
   *  0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * ** * * *      ****     *
* ****  ***** *  *   *
 *  ****      ** *  * 

int main()
{
int i,n,m;
      *** * ** **    ***** 
***   * * *** * ** * *  ** 
*    ******  ** *    

{



   ** ***   * * *** ***
{
 *   * 
  *
}
  *     * *  

** 


*** *    ******   *** * *  *


}}
   0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
 * ***  **  **   * * ** ** * ***** ** ***** %d",&a ,&b );

  *    * ** ******* ** * **    **   * i=a;i<=b;i++){
*******    ** *** *******  ***   *  *  ******  **   **   j=2;j<=b;j++){
**      **** *   *  ***      * * * ***** *** ** * **     ** ****   * * ** ****    * ** ** && i%j==0) break;
** *   *  ** **  **  * *   *  *  **  *  **  **   *   ***   *** ***  ***   *  * if(i==j){
*  *  *   **     * **  * * **  *  *** ** *   * ** *    *           *  ** *** *    * *** ** *   * * **   *   **
 *   *   * *    ** ***  **  *    * ***  ********* ***  * *   * *  **   ** * *   *** * ******       *  ** ** * *** **  * **   *     *  **** * *      **
 *   **    **  *   *  * *   ****   ** **  ****  ** *          **** *   * * * *   ***  *** * ***  * *****  * * **   ***  *  * **  *   
*  * ** ****  ** * ***    *   *  **   * ** *  **** ** *   ****  *      * * * * *    **  ** ***** *** * ****
 *   * * ***  ** **   ***  * *   * * *   **** ******** *    ***** ** *** * **  ***** ** *  *   ** *** printf(" %d",i);
 *   *  *  *   ***** ***** ** ** *  *   **   *    ** ********* **    ** * * *** ***  
 *** *       * ** *    * *    ** *** *** *  * * *  

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
 * ** * **** *      ***  *    *  a,b;
* * * **  ***** *  *    ***   *     ***   ** * %d",&a ,&b );

**  ***  *  *       *   ***   * ** i=a;i<=b;i++){
*  * *     *    ** *   **  *  * *   *    * * * *** **  * ** * * j=2;j<=b;j++){
 **** *  *   * * *   *   *   * *  ***  ** * * ***   *** ****  ** ** ** *  *  * *** *** *   *** && i%j==0) break;
 ***  ** **** **    ****** *    *  * *    ****  *     ******  ***** **  * * * ***   if(i==j){
*  **   * ****  **  *     * *****   *  *   **** * *  ****  * * * ** *    **  ***    *  **  *   ** **** * *** *  **  **  ",i);
*  ** *** *  *  * ****    **   ****  **** ***   * * ** ** *  **    ** ** * *   *** 
*  **  **    **  ** *** *** ***  *  *  ** ****** * * * 

  *    ****  *** *  * ** * **
* *  ********* ***  *    ***   ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
  ****  **** **** * **
 ***   *   **  **** **
int main(){
*      *   ***  ***** ****** * a,b;
***  ***    **  ** **** **    ** *  *  * * ***    ,&b );

 *    ***  **      ** *** **  ** i=a;i<=b;i++){
 * *  *  *   *   **  *  *** * ** * ** *  * **      *  *      j=2;j<=b;j++){
 ****  **  ** **  ** *   **    * **    **** ** *   * ****    * *** ****  * * * *** **     && i%j==0) break;
 * **    * ***  * *** ***    ****** * *** **    *** *  * * *   ** * * ****   *     ** if(i==j) printf("%d ",i);
    *  ***  ** *   ***** * **   * * *  * * *    * * **
**   * ***  * *     *    *  **
  **   ****    * ****  *********  * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 *  * **    *** * **** **     * m, n, divider, prime[100], cnt=0, i=0;

* ***     *  ** ** ****  **** ** *   %d", &m, &n);

***  ** ** **  ***** ** **  = m + 1; m < n; m++)
  *     *  ***  **  *  ** 
* **      *** **  ** **** ******* *  *** *   *  *  *  ***  = 2; divider < m; divider++)
***** ***    *   *  *** ***   *   * **   * **   
 **     ****** ** *    **   ** * ** *     ****  *  ****  * * **** *  * ***   *** % divider == 0)
    ***** ** * ***   * * **  ** * ** *** *   ** *  *  **  * ** * *****    ** * * **  ** * *     *  
  **  *   *   ** *   *   ***  * *  *  * ** ***
* * **  ** * *  *       *    ** *   ** ** * * * * ****** == divider)
      **  **  **  * ***  * *   ** **  **   *  *  **  *
*   * *  *  ** ****  **** *  ** ****   *** * * ****  ****         *  * **** *  *** ***  = m;
  **  ** * *   ** **   ***  *** *****   ** *   * * 
***   ** * *    **** * *    
 *** *   *    ** ***   **    ** *  i<cnt;i++)
  *       * *  * ** * 
*  **    ***  ** *    ***  *   *******   ***  *** **  **** ** ** *  * * prime[i]);
*    * *  * * * ** *   ***  **   * ****   *****   * * * +1 < cnt)
 * ** ** *** ** *  * *    ******  *   * ***   ** * * **  ****  *      ***  * **   * **** *     *  ");
    }

   * ****   *****   * **** * ** * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
***   ***          ***    **** *** ** * ** **
**  * *   ********   *** *** * **   **   *   * * *   ******** * **  
**   *****    **    *  *  *  ** ***  ***   **  ********        ****** * * ** * *
***   * * *  ** ** *** ** **  ** *   *  * * *  *  *       ****    **  ** **   * * ** ******  ***  * ** * 
* **      * ** *   ***  *** *** ***   ** ****      ********   *    * *  **   *** * ** **
     **  **   **  ** * ****** ** * * **  ** * * *  *  **     * * *   * * *   *   **** *****    ** ** ** * ** **  * *** * ",i);
** *     ******* ** **        *** * **     ***     *  *  *   **** * **     *  * *    * ***  ** * **** ******   
* **    *  * * ** **  ** * *  * * * * *  **    * *** **    * **** *    * **   
    ***  ** ** ***   **  **    *  ***** *  ***   ****  * **  *** ***   ** **       * * * if(k==0){
*  ******   * * ** * *** * *** ****   * **** *   *    *****     **** *  *** *** ***   *    *  * *** *  *  
* * ***   ** **   *    ****  *  ***  *    * *  *  * ** *  **  ****  * ** *      * 
 ** ** * **    *   *  * * * * *     **  **      ***  * *
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d * **   * * *** ,&b);

for * *  ** * **
{
 * *   ***  ** **   **  ** * *   ** **** * is testing\n",i);
 **  *** **  ** *****  ** **   j=0;
    *  *    ***  *     *  **  = 1;
** ***  **    * ****  * * ****   (j=2;j<i;j++)
**** *** * *  ****** ***  ** 
*** *****   ** * ***  * * *  ***      ** * *  *    ****   **  *  *  *      %d is mode\n",j);
 ** ** *  ** ** ***  ** *     **  *   * *****   ** * **  reminder=i%j;
  * ** *  *     *******   *** * *****   *** * *  * ** (reminder == 0)
***   *  * *   *** *  ** **     * * *  * *  * ***  ** **  * ***
** **  ***  ** *       *   *    * *   ******* **** ** *  * *  *** * **  ** *  *   ******    *     *** **  ** ******* *   ***     *  *  
** * ****   ** * * **** * * ** ***** * *** **** * *    *** ******* * *******    * ***** *
**  *  * * * *  ** *    * *   * ** * ** * ******* *** **         *  *  * ** * 
*  ******   *** **** * * * * * *** *** * *  *     
 **  * * * * * ** *   **  ***  **
* **   *** **   *  * *** * * * (flag==1)
** * *  *       *      *  *   *   **** *  ** **   *   * ** ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.98
©2016-2025

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.8k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users