0 like 0 dislike
26.4k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m),找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 26.4k views

99 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* ** * * * ** * * ** *** **** %d",&a ,&b );

***** * * * ** * *** * ** i=a;i<b;i++){
** ** *** * * *** * * * ** *** *** **** * ** ***** * j=2;j<=b;j++){
* *** * ** * * * **** * * ****** * * * * ** * **** *** *** * && i%j==0) break;
* * **** * *** **** **** * * * * * *** ** ****** * ** * *** if(i==j){
*** *** **** *** ** ** **** * * ** * * * * ** * *** * ** ** * * ** ** *** *** * ***
* * * * *** ** * * ***** * ** *** ** ** *** ** * **** * **** ** ** ** * * ** ** * * * * ** ** ** * ** * * ******
** * ** ** ** * *** *** ** **** *** * ** * * **** * ** *** * *** ** * ********* * *** * * ** *
* * *** * ****** *** *** ** ** ** *** ** * * ** *** ** * * *** ** *** * * * *** *** ** * ***
** * *** ** **** *** * * * * ***** * ****** * * * *** * *** * * ** ** ** **** ** ** * ** * printf(" %d",i);
* * ** ** *** * ** * * ** * **** ** * * * * ** * * * * ******
** *** ** *** ** *** ** * ***

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * *** **** ****
** ****** ***
*** * * * **** *

int main()
{
int i,n,m;
***** * **** ** ** ***
** ** ****** * **** * * *
** **** ** **

{



** *** * * **
{
* * *
** *
}
* * ** **

***


** *** * * * * *****


}}
0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** ** ***** ** *
**** * * * ** ** **
* * *** *

int main()
{
int i,n,m;
****** ** *** * * *
** *** * * **** **** *
* * *** * ****

{



** * * * *
{
** *
**
}
** **** **

*****


** * *** ***** **** ***


}}
** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* * * * * ****** * * ** * **** ** * %d",&a ,&b );

* ** * * ** **** * ** i=a;i<=b;i++){
** * * * ** * * *** ** ***** * *** ** * *** ** * * j=2;j<=b;j++){
* * *** * * * * * ** * * **** * ******* * * ** * ***** ** && i%j==0) break;
* * ** * * * ** **** ** * ** * * *** ** * *** ** * if(i==j){
* * * * ** **** **** * ** **** * ** * * * * *** * * * * ** * *** * **** * ******* **
** * *** * *** * * * * * *** ****** ** * * * ** * * *** ** ***** * * * *** * * ** ** * ** * **** ** *** *** * ** ** ** * *** *** *
* ** * * ** **** * **** * * ** ***** * *** * ***** ** * * ** *** *** * * ** ***** ****** * * ** ** ** * * * **
* * ** * ** * * ** *** * ** ** * * * **** *** ** ** ***** * * * * * ******* **
** * ** * ** ** ***** * ** ** ** * * * *** ** *** ** * * * * ** * ** * ** ** printf(" %d",i);
** *** ** * * ** * ***** * *** * * *** * *** **** * **
* * * ****** ** * *** *** * ** *** ** ** * * *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
* * * * *** * * * a,b;
** ** ** **** ** * ** * ** %d",&a ,&b );

* ** * ** ** ***** ***** * **** i=a;i<=b;i++){
* * *** *** * * * * **** * * * *** * **** * j=2;j<=b;j++){
*** *** * * * ** *** * * **** *** *** *** *** * * ** * * **** * *** && i%j==0) break;
* * * * * * ** *** **** * **** ** * *** ** * * * * * * * * ** * if(i==j){
* * ***** * * **** * ** **** **** * ***** ** ** *** ** * * * ** * * ** * ** * * ** * * ** ",i);
* ** * **** * *** ** ** ** **** * **** *** * * * *** ** *** ** * *
* * * ** * ** *********** ** * *** * * *** ***

** ****** ***** **
* *** * * * ** *** * *** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** * * **
* ** * ** * * * *
int main(){
* **** * * ** *** * *** * * a,b;
* * * ***** ** * * * * ** ** * * * * * ***** ,&b );

** * * * ****** * ** ** * * i=a;i<=b;i++){
* ** * * ** * * * *** ***** * *** ** * ** * * j=2;j<=b;j++){
** * * ****** *** * * * * ** ** *** ** ** ****** ***** * *** * * ** * ** && i%j==0) break;
** ** *** * * ****** *** ** * * **** ** * * ** ** * * if(i==j) printf("%d ",i);
** *** * ** ** * * * * * * ** *** **
* ** * * * * * *
** * ** ** ** * * * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** **** **** * * * * * ** * m, n, divider, prime[100], cnt=0, i=0;

* * ** ** ** ** * *** * * %d", &m, &n);

* **** * * * * ** = m + 1; m < n; m++)
** ** * ** * ** ** *
* ** * * * * * ****** ** **** ** * * ** ** = 2; divider < m; divider++)
* ** * ** * ** * ** *** ** ** **
** * * ** * *** ** * * ********** ** ** * *** *** *** **** * * * % divider == 0)
* ***** * * *** ** *** ** ** * * ** ** ** * ** * ** * * ** * *** * ** * * * ** *** **
*** * ** ** *** * * * ** * * ** * *
* * * *** **** ** * * **** * *** ** * * ** ** * == divider)
******* ***** *** *** **** ** * * ***** **
***** * * * * ** * **** * * *** ** * * *** ** *** ** *** * * * = m;
* * *** * * *** * **** **** ****** ***
** * ** * ** ****
*** ** ** * *** * **** ***** i<cnt;i++)
* **** **** *** * **
* * * * * * * * **** ** * * ** ** ** * ** ** ** ** ** *** prime[i]);
** *** ** *** * ** * ** ** * ** * *** * * * ** +1 < cnt)
*** *** ***** ** * *** * * * ** **** ** * *** * *** *** *** * * ** * *** ");
    }

* * ** * * ** * * * * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Nice haha
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* ***** *** ** * * **** ** ** * *
* * ** * * * ** * * * ** * *** * * *** * * *******
*** *** * * ** ******* * * * * ** ***** * ** * * * * * ** * ** *
* * ****** * *** ** ** * * * * * * ** ** ******* * *** * *** * ** * * ** * **
******** *** * ****** * ** ** ** * * * ** *** * ** ** *** ** * *
*** *** * **** * * ** * ** * ** **** ** * ** * * * * **** ** * ** *** * * ** * ",i);
** * * * ********* * **** * * * **** ** ** ** ** * *** * *** ** *** * * * * * *
** ***** * * ***** *** * *** ** * ** ** *** ** ** ** ** ** * ** *
* ** * * * ** ** ** *** * *** * **** ** * * ***** * * * ** * * if(k==0){
* *** *** ** ** * *** * ** * * * ** * * * ***** * * * ***** * *** * * ** *
* * *** *** ***** * ** * * * ** ** *** * ** *** *** * *****
** ** ** * *** * ** ** ** ** * * * *
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d ** ** ** * ***** ,&b);

for ** *** * ** *
{
* * ** *** * * * * * * **** * * * * is testing\n",i);
** ** * ** ** * * ** ** ** j=0;
*** *** ** * ******* ** = 1;
* **** *** ** *** * * * (j=2;j<i;j++)
** * ** *** ** ** ** *
** *** ** * * *** *** * * ** * * * **** **** **   %d is mode\n",j);
* * *** * * **** * ** * * *** * ** * reminder=i%j;
**** **** * *** * ***** * * * * ** ******* **** (reminder == 0)
* *** * * **** *** * *** * *** *** * *** *
* ***** * ****** * * * * * * ** *** **** ***** **** ** * *** * * * *** ** ** ** **** * * *** *
** ** * * * * * * ** * * ** ** * ** ** * * * * *
** ** *** * * * * ** ***** ** * **** *** * *** ** * * * **** ** * * *
* ** *** ** * * * * * * * * **** ** * * * * *
* * * ** ** *
* ** * * ** **** *** (flag==1)
* * * ****** * *** *** * ** *** * * *** * ** * ** ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 18k views
0 like 0 dislike
93 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 22.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users