0 like 0 dislike
11.8k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m),找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 11.8k views

99 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* * ***** ******* ** * *** ******** %d",&a ,&b );

*** * * * * *** **** *** ** i=a;i<b;i++){
* * * * *** ** *** * * ** ** *** * ** j=2;j<=b;j++){
* * ** * * **** * ** * * * * *** ** ** ** * * * * *** ***** * * * && i%j==0) break;
**** * **** * *** ***** * ** ** * * ************ ** * * * * * ** ** ** if(i==j){
***** ** * ** ***** * * *** * ** * *** * ** ** * * **** ** ** * * *** *** * **** ** *
*** * ** * * * * ** * *** ** ** * ****** * * **** ** * *** * ** * * ** * **** * * *** * ** *** **** **** * * **
** ****** **** * *** * * * ** *** * ** * ** ** *** **** * * *** ****** ******* * * * *** * * * * *** **** * ** ****
******* ** * ** ** * ** ** ******* **** * ** * * ***** * * * * * * * **** *** * * * *
* * * ** *** * * *** * * * * ** ** * ** * *** * * **** * ** * ***** ** *** printf(" %d",i);
* * ** **** ***** * ** * **** ** ** * ** ** * ** **** * ***** *
** ***** * * * *** * * ** * * ** * * **** *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ** *** ** *
*** ** * *** * * **
* * * * *** *** ** *

int main()
{
int i,n,m;
* * * ** *** * ** * **
* ***** ** *** **** * *
* * *** * * **

{



* *** ** * * **
{
******* *
* *
}
* ***** **

* *


*** * *** * * * *


}}
** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** * * ***** ** **
** *** * * * * * **
** *** * *** * * *

int main()
{
int i,n,m;
* *** ** ** * * *** *
** ***** * ** * *
** **** **** * *

{



**** * ****
{
******
*****
}
* * * ** * **

* * *


* *** * * * ** ***


}}
* 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* ** *** *** * ** ** * * * * %d",&a ,&b );

** ****** ** *** * *** ** i=a;i<=b;i++){
** * * * * * * ** ** ** * * * ** * * ** j=2;j<=b;j++){
* ** ** *** * * * *** * *** ** * ** ** ** * ****** * **** * ** * * * * * *** && i%j==0) break;
** * * ** ** * ******** * ** * *** * ** ***** *** * ** *** **** *** if(i==j){
**** * **** *** *** * *** ** * * * ***** * * ** ****** ** * * ** ** **** *** ***
**** * * ****** * *** * * ***** * ** *** ** ** * * * ** * ** * ***** * ** * * ** ** * ****** * * ********* ** *
***** *** ** *** **** * * * * * * * *** * * * *** * * ** ** * * * **** ** * ******* ** ** * * *** ** *
** * * * * *** * * * * **** * * * * * * * *** ** *** * ** * ** * * * * * ** **
** * ** * * * * ****** ** * *** *** * ** * * * **** ** * * * ** *** ** ****** * * printf(" %d",i);
* * * * * * * **** **** * * *** ** * **** ******* *****
** ** * *** * * * * **** *** ** * ** ** ** * * *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
** * * ***** * * ** a,b;
* ** * * * ** * * * ** ** ** %d",&a ,&b );

** ****** * * * ***** * * * * * * i=a;i<=b;i++){
* * ** ** **** * *** *** *** ** *** **** * j=2;j<=b;j++){
* * ** **** ** * ********* *** ** ** * * ****** ****** * * * *** * * * && i%j==0) break;
**** * * * * **** *** ***** **** ** * * ** *** *** ** ** *** * if(i==j){
* **** * ** * * * * *** ** ** ** ** * * *** ** ** ** * ** ** ** * ** ** * *** ** *** * * ",i);
* ****** *** * * ***** ****** * *** **** * *** * * * *
**** ** * * ** ** * ** ** ** * * *

** * ** * *******
* **** * *** * * ** * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * *
* ** * **** ** **
int main(){
* * *** * ** * ** a,b;
* * **** * ** *** **** * ** **** * * **** **** * ,&b );

* ** * * **** **** * * i=a;i<=b;i++){
**** **** ** ** ** ** *** * * * * ** * j=2;j<=b;j++){
* * * ** ***** ** * ** * *** ** * * ** * * *** * * ******* * * * * && i%j==0) break;
* ** * * *** ** ** ** ******* *** * * * * ** *** * * ** * if(i==j) printf("%d ",i);
* *** ** *** ** ******* *** *** **** *
** * *** * * **
* ** * **** ***** * ***** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *** ***** * **** ******* m, n, divider, prime[100], cnt=0, i=0;

**** *** * * *** ** * **** %d", &m, &n);

** * ****** ******** = m + 1; m < n; m++)
** * *** * * * * ****
* *** *** * * * * *** *** * ** * **** ** *** = 2; divider < m; divider++)
** * *** * * **** * * * * * **** ** * **
* *** *** ******** * * *** ** * ** * * * * ** * *** *** ** % divider == 0)
* **** * **** * ** *** ** * ** * * *** * * ** * **** ** **** * * * * ** *** * ** * * *
** ** * * ********* *** ** * * * ** *** ***
* * * **** * * * * * * *** * * ** **** * *** ** == divider)
***** * * * * * ******** * ** * * * *
** ***** *** * * ** * ** ** * ** *** * * ***** * ***** * ** * * * * *** *** *** * = m;
** * ** ** * * * ** * * ** * * * * *
*** ** * * * *** *
** * * **** *** * *** i<cnt;i++)
** *** ** ****** * ***
* ** * * ** ** * * ***** * ** * * *** * * * * *** * * *** * ** prime[i]);
* ** * ** * * * ** * * * **** * * * * * +1 < cnt)
* * * * ** *** *** *** * * ** * ** * * ** ** ** * * *** ** * **** ");
    }

** * ** *** * ***** **** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Nice haha
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* * * * * ** ** * * *** ** ***
* * * ** ***** * ******* * * * * * *** *** ***** ***
**** **** **** ** * **** * ***** * *** ** * * ** ** * * * ****** * *
*********** * * ** ** * * ** * * ** * **** * *** ** * * *** * * ** * **
* * * * ** ** * * * * *** * * ** *** *** * * *** * * * *** *** *** *
** **** * ** * ****** ** * ***** ** ***** **** ** * ** ** * * * ** ** ** * * * **** * * *** ** * ** * ",i);
**** ** * ** *** * ** **** * * *** ***** *** * ** *** * * **** * ** * ** *** **** ** ****
**** ** *** * ***** ** * ** ***** * ** * *** ** ** ** * **** ** * * ****
*** **** ** *** * * ** * * * ** ** * * * * ** ** ** ** * if(k==0){
* ** ** ** ***** ** ** * * ******* * * **** * * ** *** * * ****** * * * * * * * *** ** **
* *** ** * * ** * ** ** * * * **** * ** * ** * * ** ** *** * **
* ** *** *** * * *** *** **
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d ** **** ,&b);

for ** * *** *
{
*** * * ** * * *** * ** is testing\n",i);
** ** * *** **** ** * j=0;
* * ** ******* *** * * * = 1;
* **** ** * * ** * ** * (j=2;j<i;j++)
* ** **** * * * **
** ** * ** * * * *** ** *** * * **** *** *   %d is mode\n",j);
*** * * * **** * ** ****** * * ** * * * * * *** * * reminder=i%j;
** * * *** ** * * ** ** **** ** * * * * * ******* * (reminder == 0)
* ** * * ** * ** ** ** * * * * * *
**** ** ** *** * * * ****** * * **** * ** * * *** ** * ** * * ** * * ** **** * * * *****
* * * ** * ****** *** ****** * * *** * ** * * * ****** * * ** * * * *
* ** ** *** ** * * * * * * ** ** * * ****** * * * * *
* *** ****** * * * ** * **** * **** * **
** * ** ** *** * * *
** **** *** *** *** ** (flag==1)
** * * * ** * *** * * * * *** ** * * * * *** * * * ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.10
©2016-2025

Related questions

0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 7.9k views
0 like 0 dislike
93 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 9.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users